3 subtracted by 7 times a number

The coefficient of determination in this scenario is 0.747, which means that approximately 74.7% of the variation in the dependent variable is explained by the independent variable(s). The remaining 25.3% is unexplained and may be due to other factors or errors in the model.

The coefficient of determination, also known as R-squared, is a statistical measure that represents the proportion of the variation in the dependent variable that is explained by the independent variable(s).

It is calculated as 1 - (SSE/SST).

Given that the SST is 225 and SSE is 57, we can calculate the coefficient of determination as follows:

R-squared = 1 - (SSE/SST)
R-squared = 1 - (57/225)
R-squared = 0.747

Therefore, the coefficient of determination in this scenario is 0.747, which means that approximately 74.7% of the variation in the dependent variable is explained by the independent variable(s).

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Answer:

The correct answer is 30%

Step-by-step explanation:

21/70 = 30%

30%

Step-by-step explanation:

21/70 = 0.3

0.3 x 100 = 30%

Answer:

17.5

Step-by-step explanation:

17 1/2 - 1/2 = 17. We do this to isolate 1/2

1/2 = 0.5

17 + 0.5 = 17.5

Using geometric sequences, 20,480 rabbits are grown during the 12th month.

A geometric sequence is a sequence of numbers in which each term after the first is found by multiplying the preceding term by a fixed non-zero number called the common ratio.

At the end of the first month, there are 10 x 2 = 20 rabbits.

At the end of the second month, there are 20 x 2 = 40 rabbits.

Similarly, at the end of the third month, there are 40 x 2 = 80 rabbits.

This is a geometric sequence with a common ratio of 2 and a first term of 10. The number of rabbits at the end of the 12th month would be:

10 x 2^12 = 10 x 4096 = 40,960 rabbits

To find the number of rabbits grown during the 12th month, we need to subtract the number of rabbits at the end of the 11th month from the number of rabbits at the end of the 12th month:

\(40,960 - (10 x 2^{11}) = 40,960 - 20,480 = 20,480\)

Hence, 20,480 rabbits are grown during the 12th month.

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Answer:

d = 18, c = 56.55

Step-by-step explanation:

Solution

d=2r=2·9=18

C=2πr=2·π·9≈56.54867

in slope intercept form:

y=mx+b.

slope of line:

-3/4

y intercept:

(0, 5/2)

Answer:

it should be A and C

Step-by-step explanation:

peer reviews are supposed to help improve and edit unchecked writings, not improve relationships or socialize

Answer:

60 ft

Step-by-step explanation:

a² + b² = c²

20² + 15² = c²

c = √625

c = 25

total distance = 20 ft + 15 ft + 25 ft = 60 ft

22 positive integers n with  500 have square roots that can be expressed in the form a where a and b are integers with a 10.

An integer is the number zero (0), a positive natural number (1, 2, 3, etc.), or a negative integer with a minus sign (−1, −2, −3, etc.). A negative number is the additive reciprocal of the corresponding positive number. In math language, the set of integers is often denoted by bold Z or bold Z.

The set of natural numbers N is a subset of Z, which in turn is a subset of the set of all rational numbers Q , itself the real number R  is a subset of Z just like the natural numbers. Integers can be thought of as real numbers that can be written without a fractional part.

According to the Question:

sqrt (121) = 11sqrt(1)

sqrt (242) = 11sqrt(2)

sqrt(363) = 11sqrt(3)

sqrt (484) = 11sqrt(4)  

                =  22sqrt(1)

Therefore, 22 positive integers n with  500 have square roots that can be expressed in the form a where a and b are integers with a 10.

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Answer:

22

Step-by-step explanation:

Answer:

105

Step-by-step explanation:

2x17=34

17x2.5=42.5

1.5x17=25.5

1/2x2x2x1.5=3

34+42.5+25.5+3=105

Answer Po Ba Ay 11.33?

Step-by-step explanation:

Calc

Yes, q = -5 is a solution to the inequality q < -7.

We have,

To determine if q = -5 is a solution to the inequality q < -7, we need to plug in -5 for q in the inequality and see if it is a true statement.

Substituting q = -5.

-5 < -7

Since -5 is less than -7,

The inequality q < -7 is true when q = -5.

Thus,

q = -5 is a solution to the inequality q < -7.

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Answer:

c=6p

Step-by-step explanation:

you multiply

6 dollars per pound by p pounds

pounds cancel out and you are left with dollars

that is the cost

Answer:

19/40

Step-by-step explanation:

⅛ over 50

⅖ women

5 x 8 = 40

8 x 2 = 16

1 x 5 = 5

16 + 5 = 21

40 - 21 = 19

19/40

Answer:

19/40 are men under 50

Step-by-step explanation:

Given:

\(\begin{aligned}\textsf{Men under 50 yrs old} & = \textsf{total proportion of men} - \textsf{proportion of men over 50}\\\\& = \left(1-\dfrac{2}{5}\right)-\dfrac{1}{8}\\\\& = \dfrac{3}{5}-\dfrac{1}{8}\\\\& = \dfrac{3 \cdot 8}{5 \cdot 8}-\dfrac{1 \cdot 5}{8 \cdot 5}\\\\& = \dfrac{24}{40}-\dfrac{5}{40}\\\\& = \dfrac{19}{40}\end{aligned}\)

To check this, let's assign a number to the total number of players and use this to help us calculate the proportion of players who are men under 50 years old.

Let the total number of video game players be 400.

If 2/5 of all video game players are women, then the proportion of all video game players that are men is:  1 - 2/5 = 3/5

⇒ total number of men = 3/5 of 400 = 3/5 × 400 = 240

If 1/8 of all video game players are men over 50 years old then:

⇒ number of men over 50 yrs old = 1/8 × 400 = 50

Therefore:

⇒ number of men under 50 yrs old = 240 - 50 = 190

Finally, the fraction of men under 50 years old from all video game players is the number of men under 50 divided by the total number of men.

⇒ men under 50 years old = 190/400 = 19/40

Answer:

-x/3 ≥ 5

L.C.M= 3

3 × -x/3 ≥ 5 × 3

-x ≥ 15

-x/-1 ≥ 15/-1

x ≤ -15

The probability that all three wires will meet the specifications is approximately 0.173 .

Expected value (mean) of wire resistance = 0.13 ohms Standard deviation of wire resistance = 0.005 ohms

the probability for each wire, we need to standardize the range of resistance values using the expected value and standard deviation. We can use the Z-score formula:

Z = (X - μ) / σ

Z is the standard score (Z-score) X is the observed value (resistance) μ is the mean (expected value) σ is the standard deviation

For the lower specification of 0.10 ohms

Z1 = (0.10 - 0.13) / 0.005

For the upper specification of 0.17 ohms

Z2 = (0.17 - 0.13) / 0.005

Using a standard normal distribution table , we can find the probability associated with each Z-score.

Lower bound of standardized range = (0.10 - 0.13) / 0.005 = -0.06

Upper bound of standardized range = (0.17 - 0.13) / 0.005 = 0.80

Let's calculate the probabilities for each wire

P(z < -0.60) ≈ 0.2743

P(z < 0.80) ≈ 0.7881

Since we want the probability that all three wires meet the specifications, we need to multiply these probabilities together since the wires are selected independently.

P(all three wires meet specifications) = P(z < -0.60) × P(z < 0.80) × P(z < 0.80)

P(all three wires meet specifications) ≈ 0.2743 × 0.7881 × 0.7881 ≈ 0.1703

Therefore, the probability that all three wires will meet the specifications is approximately 0.173, or 17.3% .

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Answer:

Pata nahii!!!!!!!!!!!:)))))

Answer:

Redox is a type of chemical reaction in which the oxidation states of atoms are changed. Redox reactions are characterized by the actual or formal transfer of electrons between chemical species, most often with one species undergoing oxidation while another species undergoes reduction.  

Step-by-step explanation:

hope it helps

Answer:

0.270833333333333333333333333333333333333

Answer:

x^2y^5

Step-by-step explanation:

Simplify the expressions.

Answer:

1) You divide x measure by a2 and y measure by b^2 to equal 1 whole.

2) Using the vertices 0,0 we look for the negative (x-h^2)/ a2   and (y-k)^2/b^2

Which means distance from center to a vertices is 'a ' and means (hk)

3) So the parabola is a conic section (a section of a cone). Equations. x-squared is a parabola. The simplest equation for a parabola is y = x2.   Most renowned is the given y = ax2 + bx + c

For graphs the difference from the given x2 equation is we keep double 'x' x2 to y and multiply h to 4p;  we see (x - h)2 = 4p (y - k) usually focusing upright g k and p. Note below this focus changes from y to x if rotated on transversal.

Real life objects ;

Ellipses, including orbits of planets, satellites, moons and comets, and shapes of boat keels, rudders, and some airplane wings. A medical device called a lithotripter uses elliptical reflectors to break up kidney stones by generating sound waves.

Hyperbola;

Satellites, lenses radios, monitors Graphing a hyperbola shows this immediately: when the x-value is small, the y-value is large, and vice versa. Many real-life situations can be described by the hyperbola, including the relationship between the pressure and volume of a gas.

Parabolas; Are also used in satellite dishes to help reflect signals that then go to a receiver.From the paths of thrown baseballs, to fountains, this geometric shape is prevalent, and even functions to help focus light and radio waves.

Using Parabolic Reflectors to Focus Light

Flat surfaces scattered light too much to be useful to mariners. Spherical reflectors increased brightness, but could not give a powerful beam. But using a parabola-shaped reflector helped focus light into a beam that could be seen for long distances.

The idea that a parabolic reflector could produce an image was already well known before the invention of the reflecting telescope.

The name "parabola" is due to Apollonius, who discovered many properties of conic sections. It means "application", referring to "application of areas" concept, that has a connection with this curve.

Where the focus–directrix property of the parabola and other conic sections is due to Pappus of Alexandria. (c. 340) an encyclopedist where 8 volumes survived.

Galileo showed that the path of a projectile follows a parabola, a consequence of uniform acceleration due to gravity.

Step-by-step explanation:

The standard equation for an ellipse, x 2 / a 2 + y2 / b 2 = 1, represents an ellipse centered at the origin and with axes lying along the coordinate axes. In general, an ellipse may be centered at any point, or have axes not parallel to the coordinate axes.

The standard for a parabola is (x - h)2 = 4p (y - k), where the focus is (h, k + p) and the directrix is y = k - p. If the parabola is rotated so that its vertex is (h,k) and its axis of symmetry is parallel to the x-axis, it has an equation of (y - k)2 = 4p (x - h), where the focus is (h + p, k) and the directrix is x = h - p.

Answer:

The answer is a parebola

Step-by-step explanation:

1) You divide x measure by a2 and y measure by b^2 to equal 1 whole.

2) Using the vertices 0,0 we look for the negative (x-h^2)/ a2   and (y-k)^2/b^2

Which means distance from center to a vertices is 'a ' and means (hk)

3) So the parabola is a conic section (a section of a cone). Equations. x-squared is a parabola. The simplest equation for a parabola is y = x2.   Most renowned is the given y = ax2 + bx + c

For graphs the difference from the given x2 equation is we keep double 'x' x2 to y and multiply h to 4p;  we see (x - h)2 = 4p (y - k) usually focusing upright g k and p. Note below this focus changes from y to x if rotated on transversal.

Real life objects ;

Ellipses, including orbits of planets, satellites, moons and comets, and shapes of boat keels, rudders, and some airplane wings. A medical device called a lithotripter uses elliptical reflectors to break up kidney stones by generating sound waves.

Hyperbola;

Satellites, lenses radios, monitors Graphing a hyperbola shows this immediately: when the x-value is small, the y-value is large, and vice versa. Many real-life situations can be described by the hyperbola, including the relationship between the pressure and volume of a gas.

Parabolas; Are also used in satellite dishes to help reflect signals that then go to a receiver.From the paths of thrown baseballs, to fountains, this geometric shape is prevalent, and even functions to help focus light and radio waves.

Using Parabolic Reflectors to Focus Light

Flat surfaces scattered light too much to be useful to mariners. Spherical reflectors increased brightness, but could not give a powerful beam. But using a parabola-shaped reflector helped focus light into a beam that could be seen for long distances.

The idea that a parabolic reflector could produce an image was already well known before the invention of the reflecting telescope.

The name "parabola" is due to Apollonius, who discovered many properties of conic sections. It means "application", referring to "application of areas" concept, that has a connection with this curve.

Where the focus–directrix property of the parabola and other conic sections is due to Pappus of Alexandria. (c. 340) an encyclopedist where 8 volumes survived.

Galileo showed that the path of a projectile follows a parabola, a consequence of uniform acceleration due to gravity.

Step-by-step explanation:

The standard equation for an ellipse, x 2 / a 2 + y2 / b 2 = 1, represents an ellipse centered at the origin and with axes lying along the coordinate axes. In general, an ellipse may be centered at any point, or have axes not parallel to the coordinate axes.

The standard for a parabola is (x - h)2 = 4p (y - k), where the focus is (h, k + p) and the directrix is y = k - p. If the parabola is rotated so that its vertex is (h,k) and its axis of symmetry is parallel to the x-axis, it has an equation of (y - k)2 = 4p (x - h), where the focus is (h + p, k) and the directrix is x = h - p.

Answer:

x = 101

Step-by-step explanation:

We have given that,

\(x\times 11=1111\)

It is required to find the value of x such that the equation becomes true.

For this divide 11 in both sides of the above equation such that,

\(x=\dfrac{1111}{11}\\\\x=101\)

So, when the value of x is 101, the above equation becomes true.

We translate the independent variables x and y by amounts a and b, respectively, the Laplacian operator remains unchanged. This property is known as translation invariance.

To show that the two-dimensional Laplacian is translation-invariant, we need to demonstrate that if the independent variables undergo a translation to new variables x' and y', the Laplacian operator remains unchanged.

The two-dimensional Laplacian operator is given by:
∇^2 = (∂^2/∂x^2) + (∂^2/∂y^2)

Let's consider a function f(x, y) and its translated counterpart f'(x', y') after a translation in the x and y directions. The translated variables are related to the original variables as follows:

x' = x + a
y' = y + b

where 'a' represents the translation in the x-direction and 'b' represents the translation in the y-direction.

To show the translation invariance, we need to prove that ∇^2[f'(x', y')] = ∇^2[f(x, y)].

Let's compute the Laplacian of the translated function f'(x', y'):

∇^2[f'(x', y')] = (∂^2f'/∂x'^2) + (∂^2f'/∂y'^2)

Using the chain rule, we can express the partial derivatives with respect to the original variables:

∂f'/∂x' = ∂f/∂x
∂f'/∂y' = ∂f/∂y

Substituting these expressions into the Laplacian of the translated function:

∇^2[f'(x', y')] = (∂^2f/∂x^2) + (∂^2f/∂y^2)

This expression is equal to the Laplacian of the original function f(x, y). Therefore, we have shown that the two-dimensional Laplacian is translation-invariant.

In summary, if we translate the independent variables x and y by amounts a and b, respectively, the Laplacian operator remains unchanged. This property is known as translation invariance.

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Answer:

Step-by-step explanation:

x

+

2

y

=

6

Subtract  

x

from both sides of the equation.

2

y

=

6

−

x

Divide each term by  

2

and simplify.

Tap for more steps...

y

=

3

−

x

2

Answer:

x=2y-6

Step-by-step explanation:

To solve for x, we need to have one more equation, as there are two variables; x and y. But, we can still get it to this point.

First, we need to get x on to one side.

x=-2y-6

That is all we can do from here.

If you provide another corresponding equation, we can solve for x.

Hope this provides some guidance!!

~gloriouspurpose~

The logical expression that is equivalent to ¬∀x∃y(P(x)∧Q(x,y)) is ∀x∃y(¬P(x)∨¬Q(x,y)) i.e., the correct option is option D.

To determine the equivalent logical expression, we need to apply De Morgan's laws and quantifier negation rules.

Starting with the given expression ¬∀x∃y(P(x)∧Q(x,y)), let's break it down step by step:

Apply the negation of the universal quantifier (∀x) to get ∃x¬∃y(P(x)∧Q(x,y)).

This step changes the universal quantifier (∀x) to an existential quantifier (∃x) and negates the following expression.

Apply the negation of the existential quantifier (∃y) to get ∃x∀y¬(P(x)∧Q(x,y)).

This step changes the existential quantifier (∃y) to a universal quantifier (∀y) and negates the following expression.

Apply De Morgan's law to the negation of the conjunction (P(x)∧Q(x,y)) to get ∃x∀y(¬P(x)∨¬Q(x,y)).

This step distributes the negation inside the parentheses and changes the conjunction (∧) to a disjunction (∨).

Therefore, the equivalent logical expression is option D. ∀x∃y(¬P(x)∨¬Q(x,y)).

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Answer:

f(x)=2x-11

f(6)=2(6)-11

    =12-11

    =1

and the answer is c.

Explanation:

f(6) means you have to replace all x's in the function with 6.

For example, if the problem was asking you what is the value of f(10) you would have to replace all the x's in the respective function with 10 and so on.

Answer:

Step-by-step explanation:

Inequalities are used to express unequal expressions

The inequality that represents the scenario is \(x + 12.50 \le 20\)

The given parameters are:

Amount = $20

Spent = $12.50

Represent the amount left to spend with x.

So, we have:

\(x + 12.50 \le 20\)

Subtract 12.50 from both sides

\(x\le 7.50\)

Hence, the inequality that represents the scenario is \(x + 12.50 \le 20\)

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The false statement among the given options is "∃x(x/2 > x)." Let's go through each option and determine which one is false based on the given domain of all real numbers:

Option 1: ∀x(x^2 ≥ 0)

This statement asserts that for every real number x, the square of x is greater than or equal to 0. This statement is true because in the set of real numbers, the square of any real number is non-negative or zero.

Option 2: ∃x(x/2 > x)

This statement claims that there exists a real number x such that x divided by 2 is greater than x. However, if we choose any real number x and divide it by 2, the result will always be less than x. For example, if x = 2, then 2/2 = 1, which is less than 2. Therefore, this statement is false.

Option 3: ∃x(x^2 = −1)

This statement asserts the existence of a real number x whose square is equal to -1. However, in the set of real numbers, there is no real number whose square is negative. The square of any real number is always non-negative or zero. Therefore, this statement is false.

Option 4: ∃x(x^2 = 3)

This statement claims the existence of a real number x whose square is equal to 3. In the set of real numbers, there is no real number whose square is exactly 3. Therefore, this statement is also false.

In conclusion, the false statement among the given options is "∃x(x/2 > x)."

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Answer:

2 3/4

Step-by-step explanation:

the Smallest is 1/2

the biggest is 1 1/2

the most common is 3/4

Adding them all up will give you 2 3/4 or 11/4

Answer:

2\(\frac{3}{4}\)

Step-by-step explanation:

the smallest button is \(\frac{1}{2}\)

the most common button is \(\frac{3}{4}\)

the largest button is 1 \(\frac{1}{2}\)

add these buttons together

\(\frac{1}{2} + \frac{3}{4} + 1 \frac{1}{2} =\)

find the LCD of the denominators

factors of 2: 2, 4, 6, 8, 10

factors of 4: 4, 8, 12, 16, 20

find the factor that is the same in the two rows

factors of 2: 2, 4, 6, 8, 10

factors of 4: 4, 8, 12, 16, 20

2*2 = 4

\(\frac{1}{2}\)· 2 = \(\frac{2}{4}\)

\(\frac{2}{4} + \frac{3}{4} + 1 \frac{2}{4} =\)

1\(\frac{7}{4}\)

\(\frac{7}{4} = 1 \frac{3}{4}\) + 1

2\(\frac{3}{4}\)

The correct characteristic of matrices is (C) they are less valid measures of concepts.

The characteristics matrix is a technique used to explain how product qualities and process operations relate to one another.

It has historically only been used for descriptive reasons and has undergone very little intuitive analysis.

Now, given the question, we know that questions are:

Therefore, the correct characteristic of matrices is (C) they are less valid measures of concepts.

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