3. A soccer team played 160 games and won 65 percent of them. How many games did the team win?
a. 94
b. 104
c. 114
d. 124

Answers

Answer 1

Answer:

b.) 104

Step-by-step explanation:

Percent formula:

x/y = p/100

where x is the fraction, y is the total, and p is the percent

This means:

x = number of games the team won

y = total number of games

p = percent the number of teams won

Let's plug these values into the equation:

x/y = p/100

x/160 = 65/100

Solve by cross-multiplying:

x/160 = 65/100

100(x) = 100x

160(65) = 10,400‬

100x = 10,400

/100     /100

x = 104

Therefore, the team won 104 games.


Related Questions

Determine the first five terms of the sequence whose nth term is defined as follows. Please enter the five terms in the boxes provided in sequential order.Please simplify your solution an=(n-3(n(n=4)

Answers

The first five terms of the sequence are -2, -10, -24, -44, and -70.

It seems there is a typo in the formula for the nth term of the sequence. However, to interpret it as an = n - 3n(n). To find the first five terms, we will plug in the values n = 1, 2, 3, 4, and 5:

1. For n = 1, a1 = 1 - 3(1)(1) = 1 - 3 = -2
2. For n = 2, a2 = 2 - 3(2)(2) = 2 - 12 = -10
3. For n = 3, a3 = 3 - 3(3)(3) = 3 - 27 = -24
4. For n = 4, a4 = 4 - 3(4)(4) = 4 - 48 = -44
5. For n = 5, a5 = 5 - 3(5)(5) = 5 - 75 = -70

The first five terms are -2, -10, -24, -44, and -70.

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tufte discussed the concept of residuals. what is the residual in the context he presented?

Answers

The disparities between the actual and anticipated values in a regression model were referred to as residuals in the context Tufte provided.

American statistician Edward Rolf Tufte is a retired professor of political science, statistics, and computer science at Yale University.

Tufte talked about the idea of residuals. The discrepancies between the actual value and the projected value are known as residuals in statistics. Depending on whether the observed value is higher or lower than the projected value, they might be either positive or negative.

A model's residuals offer a gauge of how well it matches the data. According to him, residual plots are a great tool for seeing issues with the model fit and spotting outliers that might be skewing the results.

In contrast to relying exclusively on statistical tests, Tufte emphasised the significance of visually evaluating residuals since graphs can highlight patterns and correlations that may be missed in the numbers.

Overall, residuals are a key idea in statistics since they may be used to evaluate a model's reliability and point out its flaws.

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Imagine a player getting ready for a tournament. He has 4 games to play during the day: 9:00 a.M., 11:00 a.M., 1:00 p.M., and 3:30 p.M. He refuses to wear shorts until temperature rises to at least +5 degrees. Based on a starting temperature of -9 degrees at 6am and an increase in temperature of 2 degrees an hour, when might he be able to change from his pants to shorts? Provide explanations why he can/can't put his shorts on for Game 1, Game 2, Game 3 and Game 4.

Answers

Answer:

by game 3(at 1:00 p.m.)

temperature increases to 5 degrees at 1:00 p.m

PLEASEEE HELP ILL GIVE BRAINLIEST btw there are 2 attachments so u could see all the answer choices

PLEASEEE HELP ILL GIVE BRAINLIEST btw there are 2 attachments so u could see all the answer choices
PLEASEEE HELP ILL GIVE BRAINLIEST btw there are 2 attachments so u could see all the answer choices

Answers

Answer:

1) C

Step-by-step explanation:

Step 1)

First we have to plot ↓

2x ≥ y + 2

And that looks like Image 1

Step 2)

Second we have to plot ↓

2x - 5y ≤ 10

and that looks like Image 2

PLEASEEE HELP ILL GIVE BRAINLIEST btw there are 2 attachments so u could see all the answer choices
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Find the parametric equations for the tangent line to the curve with the given parametric equations at the specified point. V t2 + 3, y = ln(t? + 3), z = t; (2, In 4, 1)

Answers

The given parametric equations are given below:v = t² + 3 y = ln(t² + 3) z = tWe have to find the parametric equations for the tangent line to the curve with the given parametric equations at the specified point (2, ln 4, 1).

Explanation:Let (x₀, y₀, z₀) = (2, ln 4, 1) be the specified point.To find the tangent line, we need to find a point and a vector. We already have the point, we can find the vector by taking the derivative of each component of the vector function:(v, y, z) = (t² + 3, ln(t² + 3), t)Differentiating each component we get:(v', y', z') = (2t, (2t / (t² + 3)), 1)Now evaluating the derivatives at t = 2, we get:(v'(2), y'(2), z'(2)) = (4, 4 / 7, 1)Thus the tangent vector is (4, 4 / 7, 1).We can write the equation for the line in vector form as:r = r₀ + t vwhere r₀ is the initial position vector (2, ln 4, 1), v is the direction vector (4, 4 / 7, 1), and t is a parameter.We can write the parametric equation of the line as:(x, y, z) = (2, ln 4, 1) + t(4, 4 / 7, 1)

Multiplying the vector (4, 4 / 7, 1) by t and adding it to the point (2, ln 4, 1), we get the following equation:(x, y, z) = (2 + 4t, ln 4 + (4 / 7)t, 1 + t)The above equation gives the required parametric equations for the tangent line to the curve at the specified point.

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A Web music store offers two versions of a popular song. The size of the standard version is 2.8 megabytes (MB). The size of the high-quality version is 4.3 MB. Yesterday, there were 870 downloads of the song, for a total download size of 3381 MB. How many downloads of the standard version were there? b music store offers two versions of a popular song. The size of the standard version is 2.8 megabytes (MB). The size of the high-quality version is 4.3 MB. Yesterday, there were 870 downloads of the song, for a total download size of 3381 MB. How many downloads of the standard version were there?

Answers

Answer:

240 standard versions of the song were downloaded

(and 630 high-quality versions of the song were downloaded)

Step-by-step explanation:

Let the downloads of the standard version be x

And the downloads of the high-quality version be y

Since the total downloads were 870, so we get,

x + y = 870 (i)

Also, The total download size was 3381 MB

Meaning the size of the high-quality downloads + the size of the standard version downloads = 3381

so,

Solving these to get x and y,

\(x + y = 870 \ \ \ (i)\\2.8x + 4.3y = 3381 \ \ \ (ii)\)

Using (i), we get,

x = 870 - y

putting this value of x into (ii), we get,

\((2.8)x + 4.3y = 3381\\(2.8)(870 -y) + 4.3y = 3381\\2436 - 2.8y+4.3y=3381\\1.5y+2436=3381\\1.5y=3381-2436\\1.5y=945\\y=945/1.5\\\\y=630\)

Putting this into the equation,

x = 870 - y, we get,

x = 870 - 630

x = 240

Hence, 240 standard versions of the song were downloaded and 630 high-quality versions of the song were downloaded

Look at the image above:
Could someone please do this for me

Look at the image above:Could someone please do this for me

Answers

Answer:

the shapes below are similar because,

Step-by-step explanation:

36 divided by 4 is 9.

9 is also the length on shape 2.

(9x2) + (4x2) = 36

36 is also the area of shape 2

Answer:

I think it is the area and perimeter are the same

Step-by-step explanation: Shape 1: If the perimeter is 26. one side is 9. 26-18= 8. You divide that to get the measure of the other side which is 4. 9*4=36.          Shape 2: area is equal to 36, one side is for so the other side has to be 9. So the perimeter of shape 2 is 26 too.

Solve x2 12x = –11 by completing the square. which is the solution set of the equation?

Answers

The solution set of the equation will be x = - 1, or x = - 11.

What is a quadratic equation?

A quadratic equation is a polynomial with a degree of 2 or the maximum power of the variable is 2 in quadratic equations. It has two solutions as its maximum power is 2.

Expression in maths is defined as the collection of the numbers variables and functions by using signs like addition, subtraction, multiplication, and division.

To solve the equation x² + 12 x = -11, you can calculate this using the following steps:

x² + 12  x = -11

x² + 12 x + 11 = 0

(x + 1)  (x + 11) = 0

1. x = - 1

2. x = - 11

Therefore, solution set of the equation will be x = - 1, or x = - 11.

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Which expression represents the phrase 5+ the quotient of 12. 8 and 3. 2

Answers

Expression 5 + (12.8 ÷ 3.2) represents the phrase 5 + the quotient of 12. 8 and 3. 2 and option (a) is the correct answer.

Expressions refer to a phrase with at least two numbers or variables with any mathematical operations such as addition, exponents, etc. x - 6, 9 + 4y, and 6a are all examples of mathematical expressions.

Equations refer to a sentence when two expressions are equated with the help of '='. x - 6 = 6a is an example of an equation.

In phrase 5+ the quotient of 12. 8 and 3. 2

We divide the phrase into different mathematical operations.

The first operation is of addition with 5, we can write the beginning as 5 + ...

The next operation is division in the phrase the quotient of 12. 8 and 3. 2 which is added to the expression and we get 5 + (12.8 ÷ 3.2)

And we get our answer.

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The complete question might be :

Which expression represents the phrase 5+ the quotient of 12. 8 and 3. 2?

a. 5 + (12.8 ÷ 3.2)

b. 5 - (12.8 + 3.2)

c. 5 + (12.8 * 3.2)

d. none of the above

the perimeter of a rectangle is 800 inches. the width of the rectangle is 60% of its length. what is the area of the rectangle?

Answers

The area of that rectangle is 150 square inches. The result is obtained by using the formula of the perimeter dan area of pictures.

How to  find the perimeter and area of a rectangle?

A rectangle is a two dimensional shape consisting of four joints. It has also four angle points.

The perimeter and area of a rectangle can be expressed as follows.

P = 2 (w + l)

A = w × l

Where

P = perimeter of a rectangleA = area of a rectanglew = width of a rectangle l = length of a rectangle

The perimeter of a rectangle is 800 inches. The width of the rectangle is 60% of its length.

From that information, we have:

P = 800 inchesw = 60% × l = 0.6l

P = 2(w + l)

800 = 2(0.6l + l)

400 = 1.6l

l = 400/1.6

l = 250 inches

The area of the rectangle is

A = w × l

A = 0.6 l × l

A = 0.6 l²

A = 0.6 × 250

A = 150 square inches

Hence, the area of that rectangle is 150 square inches.

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Let f(x) = 5 / x3 − 1 and consider the limits lim x→1− f(x) and lim x→1+ f(x). (a) Use a table of values to evaluate f(x) = 5 x3 − 1 for values of x that approach 1 from the left and from the right. (Round your answers to one decimal place.) x f(x) x f(x) 0.5 1.5 0.9 1.1 0.99 1.01 0.999 1.001 0.9999 1.0001 0.99999 1.00001 (b) Use an analytical argument to find each limit. (If the limit is infinite, enter '[infinity]' or '-[infinity]', as appropriate. If the limit does not otherwise exist, enter DNE.) lim x→1− f(x) = lim x→1+ f(x) = (c) Sketch a graph of f to confirm your results. (A graphing calculator is recommended.)

Answers

From the given information provided, as lim x→1− f(x) = positive infinity and lim x→1+ f(x) = negative infinity.

(a) Using the given function, we can evaluate f(x) for values of x that approach 1 from the left and from the right using the table below:

x f(x)

0.5 1.5

0.9 1.1

0.99 1.01

0.999 1.001

0.9999 1.0001

0.99999 1.00001

Note that as x approaches 1 from the left, f(x) approaches positive infinity. As x approaches 1 from right, f(x) approaches negative infinity.

(b) To find the limits analytically, we can use the fact that the denominator of f(x) becomes zero as x approaches 1. Therefore, we can rewrite f(x) as:

f(x) = 5 / (x³ - 1) = 5 / [(x - 1)(x² + x + 1)]

As x approaches 1 from left, we have:

lim x→1− f(x) = lim x→1− [5 / [(x - 1)(x² + x + 1)]]

= [5 / [(1 - 1)(1² + 1 + 1)]] = positive infinity

As x approaches 1 from right, we have:

lim x→1+ f(x) = lim x→1+ [5 / [(x - 1)(x² + x + 1)]]

= [5 / [(1 - 1)(1² + 1 + 1)]] = negative infinity

(c) The graph of f(x) confirms our results from parts (a) and (b), as shown

graph of f(x).

As x approaches 1 from left, f(x) approaches the positive infinity. As x approaches 1 from right, f(x) approaches negative infinity.

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Find the term named in the problem.
-21, - 13, -5, 3, ...
Find a23

Answers

a(n) = a(1) + ( n - 1 ) × d

a(23) = -21 + ( 23 - 1 ) × 8

a(23) = -21 + ( 22 ) × 8

a(23) = -21 + 176

a(23) = 155

And we're done....

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how much work is done when a 100 lb rock is lifted to a height of 3 ft?

Answers

Work done when a 100 lb rock is lifted to height of 3 ft is 9652.215 ft-lb.

What is meant by work done?

The work done on an object is equal to the force applied to it multiplied by the distance over which the force is applied. In this case, the force applied is the weight of the rock, which is equal to the force of gravity acting on it.

The weight of an object is given by the formula:

W = mg

Where m is the mass of the object (in this case, 100 lb) and g is the acceleration due to gravity (approximately 9.8 m/s^2 or 32.17405 ft/s^2).

So the weight of the rock is:

W = (100 lb)(32.17405 ft/s^2) = 3,217.405 ft-lb

The work done on the rock is equal to the force applied (its weight) multiplied by the distance it is lifted (3 ft), so the work done is:

Work = (3,217.405 ft-lb) x (3 ft) = 9652.215 ft-lb

Therefore, the work done when a 100 lb rock is lifted to a height of 3 ft is 9652.215 ft-lb.

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Here it goes I had $5.00 My Mom gave me $10.00 while my Dad gave me $30.00. My Aunt and Uncle gave me 100.00. I had another $5.00 How much money did i really have?

Answers

I have $150

The total amount I would have can be determined by adding the money I have with the money my parents gave me with the amount of money my uncle and aunt gave me.

I am adding these sums of money together because the money I have increases with the monies I am given.

The money I have = amount I initially had + amount my parents gave me + amount my uncle and aunt gave me

$5 + $10 + $30 +100 + $5 = $150

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Using the CPT manual, code the following: Five MeV of radiation treatment delivery to a single area for primary breast cancer, right female breast

Answers

According to the CPT manual, the appropriate code for the treatment for primary breast cancer, would be 77427.

In medical coding, it is important to assign the correct CPT code to accurately describe the provided medical service. For the described scenario of delivering five MeV of radiation treatment to a single area for primary breast cancer, the appropriate code is 77427. This code specifically represents the radiation treatment delivery for breast cancer.

The CPT manual is a widely used resource that provides a comprehensive list of medical procedures and services, each assigned a specific code. These codes help healthcare providers communicate and document the services rendered to patients, as well as facilitate accurate billing and reimbursement. The codes in the CPT manual are regularly updated to reflect advancements in medical technology and practices.

By referencing the CPT manual, healthcare professionals can ensure that the services they provide are accurately coded, allowing for consistent and standardized communication across the healthcare industry. This helps in maintaining proper documentation, tracking patient care, and facilitating efficient billing processes.

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The CPT manual provides specific codes for radiation treatment delivery, including those for breast cancer. The appropriate code for the given treatment would depend on the specific technique used and can be found in the CPT manual.

In order to code the radiation treatment delivery for primary breast cancer, right female breast, we need to refer to the CPT manual. The CPT manual provides specific codes for different types of radiation treatment delivery. In this case, the treatment involves the delivery of Five MeV of radiation to a single area.

Based on the information provided, the appropriate CPT code for this treatment would be determined by the specific technique used for radiation delivery. The CPT manual provides codes for different techniques, such as external beam radiation therapy (EBRT) and brachytherapy.

Since the question does not specify the technique, we cannot provide a specific CPT code. However, a healthcare professional would consult the CPT manual and select the appropriate code based on the specific details of the treatment.

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Based on the following figure, determine which value below is correct.

Based on the following figure, determine which value below is correct.

Answers

The correct measure is given as follows:

x = 6.

What are vertical angles?

Vertical angles are angles that are opposite by the same vertex on crossing segments, hence they share a common vertex, thus being congruent, meaning that they end up having the same angle measure.

Over vertex C, the two angles are congruent, hence the value of x is obtained as follows:

12x - 9 = 6x + 27

6x = 36

x = 6.

(as the vertical angles are congruent, we can just equal the measures of the two angles and then solve the expression for the value of x).

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Find the final value of $2000 investment at an interest rate of 2%compounded quarterly (4 times a year) for 8 years

Answers

Answer:

\(\Huge \boxed{\boxed{\texttt{\bf{\$2346.09} } } }\)

Step-by-step explanation:

We can use the compound interest formula to get the final value of a $2000 investment at an interest rate of 2% compounded quarterly for 8 years, using:

\(\LARGE \boxed{\tt{A = P(1 + \frac{r}{n})^{nt}}}\)

The final amount is A.P stands for the initial principal, in this case $2,000The yearly interest rate is given as r (0.02 for 2%).The value of n determines how many times interest is compounded annually (4 for quarterly).t represents the time in years (8 years).

Substituting the values:

\(\tt{A = 2000(1 + \frac{0.02}{4})^{4 \times 8}}\)\(\tt{ A = 2000(1 + 0.005)^{32}}\)\(\tt{A = 2000(1.005)^{32}}\)\(\texttt{ A $\approx$ 2346.09 (rounded to 2 decimal places)}\)

So, the final value of the investment after 8 years would be approximately $2346.09.

________________________________________________________

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Find the final value of $2000 investment at an interest rate of 2%compounded quarterly (4 times a year)

Solve. 9/12 = x/40
Enter your answer in the box.
x=_

Answers

9/12=x/40
90/120=3x/120
90=3x
x=90/3
x=30

Which of the following is a basic assumption for a chi-square hypothesis test? All scores come from an interval or ratio scale_ AIl of the other choices are assumptions for chi-square. The population distribution(s) must be normal: The observations must be independent:

Answers

The basic assumption for a chi-square hypothesis test is that all scores come from an interval or ratio scale. This means that the data being analyzed should have a quantitative scale with consistent units of measurement.

All other assumptions for chi-square, including normal population distribution and independent observations, apply to different types of statistical tests.

Normal population distribution assumes that the data follows a normal distribution curve, which is not applicable to a chi-square test as it is a non-parametric test that does not make any assumptions about the underlying population distribution.

Independent observations assumption implies that the values of one observation do not affect or influence the values of other observations. This assumption is relevant for both parametric and non-parametric tests, including chi-square.

Therefore, it is important to ensure that the data being analyzed meets the assumption of interval or ratio scale to conduct a chi-square test accurately.

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What is the area of a rectangle with a length of x + 5
and a width of 4?

Answers

Answer:

\(area = (length \times width) \\ = (x + 5) \times 4 \\ = (4x + 20) \: square \: units\)

Work out the length of x.
Give your answer rounded to 3 significant figures.
8.6 cm+
x
The diagram is not drawn accurately.

Work out the length of x.Give your answer rounded to 3 significant figures.8.6 cm+xThe diagram is not

Answers

Answer:

12.2cm

Step-by-step explanation:

Follow the steps in the image I send you to learn it if you don't get it tell me.

Work out the length of x.Give your answer rounded to 3 significant figures.8.6 cm+xThe diagram is not
Work out the length of x.Give your answer rounded to 3 significant figures.8.6 cm+xThe diagram is not

find m∠ UVF if m∠ UVW = -6 +22x, m∠ FVW = 100°, and m∠ UVF = 7x + 14

Answers

The measure of angle UVF is of m<UVF = 36.19º, using the angle addition postulate.

What does the angle addition postulate state?

The angle addition postulate is a geometry axiom that states that if two angles share a common vertex and a common angle, forming a combination, the measure larger angle will be given by the sum of the measures of the smaller angles.

In the context of this problem, we have that the situation is described as follows:

The common vertex is of V.Angle FVW is the combination of angles UVW and UVF.

The measures of the angles are given as follows:

m∠ UVW = -6 +22x.m∠ FVW = 100°.m∠ UVF = 7x + 14.

Hence the solution for measure x is calculated as follows:

-6 + 22x + 7x + 14 = 100

29x = 92

x = 92/29

x = 3.17.

Hence the measure of angle UVF is given as follows:

m<<UVF = 7(3.17) + 14 =  36.19º.

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what’s the rate of change for this question?

whats the rate of change for this question?

Answers

I believe it’s 2/3

Hope this helps

4/10 + 1/2 please help-

Answers

Exact Form:

9 /10

Decimal Form:

0.9

Hope this helps :)

Answer:

4/10 + 1/2 would be 9/10 because 1/2 of 10 is 5 so 5/10 +4/10 would equal 9/10 hope that helps :)

Step-by-step explanation:

Ill give brainliest - please help ASAP

WITH THE WORK THO PLEASE?

Ill give brainliest - please help ASAPWITH THE WORK THO PLEASE?

Answers

Answer:

Solution given:

5.

we have.

11x=½(16x+16+50)

22x=16x+66

22x-16x=66

6x=66

x=66/6

x=11

6.

118°=½(6x-11+181)

236=6x+170

6x=236-170

x=66/6

x=11°

If there are six levels of Factor A and six levels of Factor B for an ANOVA with interaction, what are the interaction degrees of freedom? Multiple Choice 12 36 25 Saved Multiple Choice 12 36 25 10

Answers

The interaction degrees of freedom for an ANOVA with six levels of Factor A and six levels of Factor B would be 25.

In an ANOVA with interaction, the interaction degrees of freedom are calculated as the product of the degrees of freedom for Factor A and Factor B.

In this case, since both Factor A and Factor B have six levels, the degrees of freedom for Factor A would be 6 - 1 = 5, and the degrees of freedom for Factor B would also be 6 - 1 = 5. Therefore, the interaction degrees of freedom would be 5 * 5 = 25.

The interaction degrees of freedom represent the variability in the data that is attributed to the interaction between Factor A and Factor B. It reflects the unique information gained from considering the joint effects of both factors and allows us to assess whether the interaction is statistically significant.

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Use the graph shown below to identify the multiplicity of the roots of f(x)=0.

Use the graph shown below to identify the multiplicity of the roots of f(x)=0.

Answers

If the multiplicity of the roots was 3, the curve would still be tangent to the x-axis at -3 and 3, but the curve would cross the x-axis.

The graph below is the graph of the equation f(x) = 0. The equation is graphed on the x-y plane. To determine the multiplicity of the roots, one needs to look at the graph closely.

The multiplicity of the roots of a polynomial function is a way of determining the behavior of the function as it approaches a particular point on the x-axis. In particular, it tells us how quickly the function approaches zero at that point.

The graph shows a curve that intersects the x-axis at -3 and 3. At these two points, the curve is tangent to the x-axis. Since the curve is tangent to the x-axis at these points, this means that the roots are repeated.

The multiplicity of the roots of f(x) = 0 is 2. This means that the curve touches the x-axis at -3 and 3, but doesn't cross it. This is because the roots are repeated.

If the multiplicity of the roots was 3, the curve would still be tangent to the x-axis at -3 and 3, but the curve would cross the x-axis.

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Write the equation of the line that passes through
(6,-7) and is perpendicular to y = 2/3x+1.

Answers

Answer:

Step-by-step explanation:

y = (2/3)x + 1

m = 2/3

The slope of the perpendicular line = -1/m

                                         \(Slope = \dfrac{-1}{\dfrac{2}{3}}=-1*\dfrac{3}{2}=\dfrac{-3}{2}\\\\\\(6,-7) ; \ x_{1}= 6 \ ; y_{1} = -7\\\\\\Equation: y-y_{1}=m(x-x_{1})\\\\\\y -[-7] = \dfrac{-3}{2}(x - 6)\\\\\\y + 7 = \dfrac{-3}{2}x - 6*\dfrac{-3}{2}\\\\y +7=\dfrac{-3}{2}x+9\\\\y = \dfrac{-3}{2}x+9-7\\\\y =\dfrac{-3}{2}x+2\)

Give the value of M and C.

Give the value of M and C.

Answers

Answer:

y = 5x - 3, so M = 5 and C = -3.

sec beta * sin beta / tan beta = 1

Answers

Sure, I can help you with that!

First, let's break down the terms in the equation:

- sec beta: This is the reciprocal of the cosine of angle beta. In other words, sec beta = 1/cos beta.
- sin beta: This is the sine of angle beta.
- tan beta: This is the tangent of angle beta, which is equal to sin beta / cos beta.

Now, let's substitute these values into the equation:

sec beta * sin beta / tan beta = 1

(1/cos beta) * sin beta / (sin beta / cos beta) = 1

simplify by cancelling out the sin beta terms:

(1/cos beta) * 1 / (1 / cos beta) = 1

simplify further by multiplying by the reciprocal:

(cos beta / 1) * (cos beta / 1) = 1

cos^2 beta = 1

This is true because cosine squared of any angle is equal to one minus sine squared of that angle (cos^2 x + sin^2 x = 1). Therefore, the original equation sec beta * sin beta / tan beta = 1 is indeed true.

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