2w to the power of 0

Answer:

1. meters

Step-by-step explanation:

The smallest unit given in the choice is millimeters. Then comes the centimeters, then meters,  and the kilometers.

Liters is used to measure the volume of a liquid. For example we get 1 liters of milk but not 1 kilometers of milk.

The kilometers has a 1000 meters and

1m= 100 cm

1cm = 10mm

The kilometers is quite a large space and usually long distances such as length between 2 towns is measured in kilometers.

The area of the room or length is usually measured in feet but since feet is not given here.

1 feet = 0.3048 m

so the most suitable selection would be meters.

The millimeters is very small. 1 cm has 10 mm. A foot consists of 30.48 cm.

So meters is used.

Answer:

B

when you input the first value of y which is -2

-2+2=(4/5)(x+9)

0=(4x+36)/5

multiply both sides by 5

0=4x +36

4x =-36

divide both sides by 4

x=-9

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Answer:

V = 1,500 \(cm^{3}\)

Step-by-step explanation:

First off, we have to identify the formula in which we are using:

\(V = \frac{1}{2} a*c*h\)

Where:

a = 12

c = 10

h = 25

Next, plug in the numbers:

\(V=\frac{1}{2} (12)(10)(25)\)

Now, calculate:

V = 1500 cubic centimeters

Algebra

For example, (x)(x)=x^2

Add the exponents of the variable to get the correct answer.

(k^3)(k^5)=k^8

Answer and Step-by-step explanation:

When two values have the same base, have exponents, and are being multiplied to each other, then we add together the exponents.

So, we are given k to the power of 3, which is multiplied by k to the power of 5. The powers (exponents) are added together to make 8, and the bases combine to be only one of the bases, being k.

So, we are left with the answer being \(k^8\).

I hope this helps!

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In order to determine the required distributed service load for the cantilever beam, they are basically 5 steps which need to be taken care of.

Start by determining the dead load (DL) and live load (LL) for the beam. The distributed service load is calculated as 40% of the dead load plus 60% of the live load.

To calculate the dead load, you need to know the weight of the beam itself. In this case, the beam is a W12x26 section made of A572 Grade 65 steel. The weight per foot of this section can be obtained from the AISC manual or other structural design resources.

Multiply the weight per foot of the beam by the length of the cantilever beam to obtain the total dead load.

Determine the live load based on the specified design requirements. The magnitude of the live load depends on the specific application and can be obtained from building codes or engineering standards.

Calculate the distributed service load by multiplying the dead load by 0.4 (40%) and the live load by 0.6 (60%), then summing these values.

The final answer will provide the required distributed service load for the given cantilever beam.

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We assumed that the lateral supports are adequate throughout the entire span of the beam. Additionally, we based the design on moment strength, shear strength, and a live load deflection limit of L/300.

To calculate the required distributed service load for the cantilever beam, we need to consider the dead load (DL) and the live load (LL). In this case, the distributed service load is composed of 40% DL and 60% LL.

First, we need to calculate the DL. Since the beam is made of W12x26 A572 Grade 65 steel, we can find the weight per foot of this beam from the AISC manual. The weight per foot is 26 pounds.

To calculate the DL for the entire beam, we multiply the weight per foot (26 pounds) by the length of the beam (15 feet) and the percentage of DL (40% or 0.4). This gives us:

DL = (26 pounds/foot) * (15 feet) * (0.4) = 156 pounds

Next, we calculate the LL for the entire beam. The LL is 60% of the total distributed service load.

To calculate the LL, we multiply the weight per foot (26 pounds) by the length of the beam (15 feet) and the percentage of LL (60% or 0.6). This gives us:
LL = (26 pounds/foot) * (15 feet) * (0.6) = 234 pounds

Now, we have the DL and LL for the entire beam. To determine the total distributed service load, we sum the DL and LL:

Total distributed service load = DL + LL = 156 pounds + 234 pounds = 390 pounds

Therefore, the required distributed service load for the 15-ft long cantilever beam is 390 pounds.

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Answer:

x=10

Step-by-step explanation:

2/3+5/6x=9

5/6x=8 1/3

5/6x=25/3

5x=50

x=10

Answer:

9.42 (sorry if im late)

Step-by-step explanation:

I believe that if you take the radius and multiply it by pi (3.14), you get the circumfrence

3.14 x 3 = 9.42

Answer: the person above is wrong

Step-by-step explanation: Some ratios are not fractions.

and All fractions are ratios

The solution to the system of inequalities is:

x ≥ -3.8 and

x ≤ 3

This can also be expressed as

-3.8 ≤ x ≤ 3

solving the first inequality:

-2x - 3x ≤ 19

Combining like terms, we get:

-5x ≤ 19

Dividing both sides by -5 :

x ≥ -3.8

So we have found that x is greater than or equal to -3.8.

From the second inequality:

-8x ≥ -24

Dividing both sides by -8:

x ≤ 3

So we have found that x is less than or equal to 3.

Therefore, the solution to the system of inequalities is:

-3.8 ≤ x ≤ 3

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Answer:

13

Step-by-step explanation:

4^2 is 16

16-3=13

that's all that you have to do you replace the x with 4 and do a normal equation

Answer: y=13

Y=(4)^2-3

y=16-3

y=13

Answer:

5.04

Step-by-step explanation:

Angel receives 300 votes which is 60% of total votes.

Therefore we can determine 60% = 300

The next thing to do would be to determine 1% and we can do this by dividing both sides by 60:

60% = 300

1% = 5

Then multiply both sides by 100 to determine 100% of total votes (total amount of students who voted):

1% = 5

100% = 500

Therefore 500 students voted in the election.

Answer:

500 students

Step-by-step explanation:

300=60%

300x2=600

(turning the 300 into 600 helps it make sense)

600/3=200

200x5= 1000

1000/2=500

As the percentages of dropouts are different there is sufficient evidence that the dropout rate at this school is different from the state level.

A percentage is a value per hundredth. Percentages can be converted into decimals and fractions by dividing the percentage value by a hundred.

Given, In recent years, 3% of Ohio high school seniors drop out last year.

On the other hand Podunk, high school had 30 dropouts from their total enrollment of 600 students which is,

= (30/600)×100%.

= 5%.

So, there is sufficient evidence that the dropout rate at this school is different from the state level.

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Answer:

x = 31

Step-by-step explanation:

Given that the triangles are congruent, then corresponding angles are congruent, then

∠ D = ∠ A

The sum of the 3 angles in a triangle = 180° , thus

∠ A = 180° - (61 + 57)° = 180° - 118° = 62°

Thus

2x = 62 ( divide both sides by 2 )

x = 31

Answer: The given question is solved :

Step-by-step explanation:

correct solution in imaje

Answer:

B

Step-by-step explanation:

The domain is asking for all the values of x and according to the graph, the only values of x are in between 0 and 4, therefore B

Profit Maximizing Quantity (Q) is the output level at which a company generates the highest possible profit while maintaining its price and marginal costs. The formula for calculating the Profit Maximizing Quantity is MR = MC.In the first demand and cost function, the demand function is:

Q = 31.175-25P, where P is the price and Q is the quantity sold.

C(Q) = -689Q + 5075. Here, C(Q) is the cost function.We know that the marginal cost of the product (MC) equals the derivative of the cost function;

MC = C’(Q) = -689.

We also know that, since demand is a function of price and price is a function of quantity, we can use the chain rule to get the inverse demand function (P = P(Q)):

dP/dQ = dP/dQ * dQ/dP => 1/(-25) = dP/dQ => -0.04 = dP/dQ

We can use this relationship to obtain MR (marginal revenue) by multiplying both sides by P:

MR = P * (-0.04) = -0.04P.

The profit-maximizing quantity is determined by setting MR equal to MC:

MR = MC => -0.04P = -689 => P = 17225.

The inverse demand function (P = P(Q)) can be used to determine the quantity sold at the profit-maximizing price:17225 = 31.175-25Q => 25Q = -17193.825 => Q = -687.753

This solution is impossible because the quantity must be positive.

As a result, there is no profit-maximizing quantity in this scenario.In the second demand and cost function, the demand function is:

Q = -2,314-89P,

where P is the price and Q is the quantity sold.C(Q) = 12Q + 13.54. Here, C(Q) is the cost function.

The marginal cost of the product (MC) equals the derivative of the cost function;

MC = C’(Q) = 12.We also know that, since demand is a function of price and price is a function of quantity, we can use the chain rule to get the inverse demand function (P = P(Q)):

dP/dQ = dP/dQ * dQ/dP => 1/(-89) = dP/dQ => -0.01123595 = dP/dQ

We can use this relationship to obtain MR (marginal revenue) by multiplying both sides by P:

MR = P * (-0.01123595) = -0.01123595P.

The profit-maximizing quantity is determined by setting MR equal to MC:

MR = MC => -0.01123595P = 12 => P = -1066.13.

The inverse demand function (P = P(Q)) can be used to determine the quantity sold at the profit-maximizing price:-1066.13 = -2,314-89Q => 89Q = 1248.13 => Q = 14.

The profit-maximizing quantity (Q) is 14.

In the graph, we can see that the profit maximizing output is at 168.

To calculate the profit at the profit maximizing output, we need to find the point of intersection between the MR and MC curves and then multiply the quantity by the difference between the price (P) and average total cost (ATC) to get the profit.

The point of intersection in this case is approximately (168, 21).The price is 21 and the ATC is 10, therefore the profit is (21-10) * 168 = 1848. Answer: 1848

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Answer:

105°+75°=180°

X=180°

To find the limit of cos(x)/(1-sin(x)) as x approaches (π/2)+, we can use l'Hospital's Rule.

First, we can take the derivative of both the numerator and denominator with respect to x: lim cos(x)/(1 − sin(x)) x → (π/2)+ = lim [-sin(x)/(cos(x))] / [-cos(x)] x → (π/2)+ = lim sin(x) / [cos(x) * cos(x)] x → (π/2)+

Now, plugging in (π/2)+ for x, we get: lim sin(π/2) / [cos(π/2) * cos(π/2)] x → (π/2)+ = 1 / (0 * 0) = undefined

Since the denominator approaches 0 as x approaches (π/2)+, and the numerator is bounded between -1 and 1, the limit does not exist.

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Answer:

(5p-3q)(3p-2q)

Step-by-step explanation:

15p² - 19pq+6q²​

=15p²-10pq-9pq+6q²                  ∵{-10×-9=90, -10-9=-19 }and 15×6=90

=5p(3p-2q)-3q(3p-2q)

=(5p-3q)(3p-2q)

The two results are (3,4,5) and (3,4,5 - 3) respectively

The 3x3 matrix, e, that multiplies (x, y, z) to give (x, y, z x ) is:

[1  x  0]

[0  y  0]

[0  0  z]

The 3x3 matrix, e, that multiplies (x, y, z) to give (x, y, z - x) is:

[1  -x  0]

[0   y  0]

[0   0  z]

, the two results are (3,4,5) and (3,4,5 - 3) respectively.

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The probability that the person will receive one or two pieces of junk mail tomorrow, according to the Poisson distribution with an average of 4.3 pieces per day, is approximately 0.492 (rounded to 3 decimals).

To find the probability that the person will receive one or two pieces of junk mail tomorrow, we can use the Poisson distribution with an average of 4.3 pieces per day.

The probability mass function of the Poisson distribution is given by:

P(X = k) = (e^(-λ) * λ^k) / k!

where X is the random variable representing the number of junk mail pieces, λ is the average number of pieces (4.3 in this case), and k is the number of junk mail pieces we want to calculate the probability for (1 or 2).

Let's calculate the probabilities for both cases and then sum them up.

For k = 1:

P(X = 1) = (e^(-4.3) * 4.3^1) / 1! ≈ 0.156

For k = 2:

P(X = 2) = (e^(-4.3) * 4.3^2) / 2! ≈ 0.336

Now, we can sum up these probabilities:

P(X = 1 or X = 2) = P(X = 1) + P(X = 2) ≈ 0.156 + 0.336 ≈ 0.492

Therefore, the probability that the person will receive one or two pieces of junk mail tomorrow is approximately 0.492 (rounded to 3 decimals).

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50,400 different anagrams can be made from the letters in the word statistics.

Given word : STATISTICS

Anagrams are words formed by jumbling the positions of the letters given in the word.

For such problems we do factorial of number of words and divide by the repeated letters factorials.

Total number of letters = 10

They can be permutated among themselves in 10! ways.

Some letters are repeated in word STATISTICS

Since, there are 3 S's and 3 T's and 2 I's

So, Number of anagrams = \(\frac{10!}{3!.3!.2!}\)

= \(\frac{10 \times 9 \times 8 \times 7 \times 6 \times 5 \times 4 \times 3!}{3! \times 3 \times 2 \times 1 \times 2 \times 1}\)

= \(\frac{10 \times 9 \times 8 \times 7 \times 6 \times 5 \times 4}{3 \times 2 \times 2}\)

= 10 × 9 × 8 × 7 × 2 × 5

= 50,400

50,400 different anagrams can be made from the letters in the word statistics.

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Answer:

Step-by-step explanation:

write an equation to present total (T) that each team has raised after selling (x) number of raffle tickets

Volleyball Team:  T(V) = 2.50x(V)

The problem staes use x for the number of tickets, but I've noted these numbers as a function of basketball, x(B), and volleyball, x(V).

We know the amounts each team has raised, sio we can calculate the number of tickets:

Basketball

 $275 = $4.50x(B)

x(B) = 61.11  [There can't be 0.11 ticket, so round down to 61 and declay an error in making change]:  61 tickets from the Baseball team

 $500 = $2.50x(V)

x(V) = 200 tickets from the Volleyball team

---

"write an equation that would represent when the basketball team would have more money than the volleyball team."

We want the ratio of T(B) to T(V) to be greater than 1 [the total basketball sales are greater than the total Volleyball sales.]

T(B)/T(V) = ($4.50x(B))/($2.50x(V))

1 <= ($4.50/$2.50)*(x(B)/x(V))

1 <= 1.8(x(B)/x(V))

x(V) <= 1.8*(x(B))

The baseball team needs to sell 1.8 times the number of tickets sold by the baseball team.

----

The basketball team is jealous and wants to know how many more tickets they need to sell to catch up with the volleyballers.

To reach $500:

 $500 = $4.50*x(B)

x(B) = 111.11  (Another rounding problem, but we don't need to worry.  It wants to kniow "how many MORE."

(111.11 - 61.11) = 50 more tickets to reach the same $500 the Volleyball team has collected.

The actual value of the path loss exponent will depend on various factors such as the frequency of operation, terrain, and environment.

To determine the range of path loss exponent that will satisfy the given requirements, we need to use the path loss equation, which relates the received signal power to the transmitted power, distance, and path loss exponent:

Pr = Pt - 10n log(d) - L

where Pr is the received power, Pt is the transmitted power, d is the distance between the transmitter and receiver, n is the path loss exponent, and L is the system loss.

Assuming a fixed transmit power, we can rearrange the equation to solve for the path loss exponent:

n = (Pt - Pr - L) / (10 log(d))

To satisfy the given requirements, we need to find the range of values of n such that the received power at a distance of 100 meters is at least -70 dBm.

Let's assume a system loss of 2 dB and a transmit power of 20 dBm. Then we can plug these values into the path loss equation and solve for the path loss exponent:

-70 dBm = 20 dBm - 10n log(100) - 2 dB

-48 dB = -10n log(100)

n = 2.4

Therefore, a path loss exponent between 2 and 2.4 should satisfy the given requirements. However, it's important to note that the actual value of the path loss exponent will depend on various factors such as the frequency of operation, terrain, and environment.

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The standard form of the polynomial is given as follows:

x^6 + 53x^5 + 2x^4 - 2.

The degree of the polynomial is given as follows:

6.

The leading coefficient of the polynomial is given as follows:

1.

This is called a polynomial because it has more than three terms.

The first feature we want to obtain is the standard form notation of the polynomial, which means that the terms should appear in the order of the exponents, as follows:

x^6 + 53x^5 + 2x^4 - 2.

Then the degree of the polynomial is given by the highest exponent, which is of six.

The leading coefficient of the polynomial is the term that multiplies the term of the highest exponent, which is of x^6, hence it is of one.

Finally, it is classified as polynomial as the expression is composed by four terms.

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Answer:

x = 70.53 degrees

Step-by-step explanation:

equation:

cos-1 = \(\frac{adjacent}{hypotenuse}\)

⇒ cos-1 x = \(\frac{4}{12}\)

⇒ cos-1 x = 0.33

⇒ x = 70.528

round to the nearest tenth:

⇒ 70.53

The profit function is given as g(q) = -2q^2 + 7q - 3. To factor the profit function,  it is in the form (aq - b)(cq - d). The value of output q where profits are maximized can be found by determining the vertex of the parabolic profit function.

To factor the profit function g(q) = -2q^2 + 7q - 3, we need to express it in the form (aq - b)(cq - d). However, the given profit function cannot be factored further using integer coefficients.

To find the value of output q where profits are maximized, we look for the vertex of the parabolic profit function. The vertex represents the point at which the profit function reaches its maximum or minimum value. In this case, since the coefficient of the quadratic term is negative, the profit function is a downward-opening parabola, and the vertex corresponds to the maximum profit.

To determine the value of q at the vertex, we can use the formula q = -b / (2a), where a and b are the coefficients of the quadratic and linear terms, respectively. By substituting the values from the profit function, we can calculate the value of q where profits are maximized.

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