2a²b+6ab²
WHAT
IS
THIS
I
GIVE
5
STARS!!!

Answer: 256

Step-by-step explanation:

2^8=2*2*2*2*2*2*2*2=256

The median of the stem-and-leaf plot is 23

The plane intercepts on the x,y, z axes are 1, ∞, and 1/2. Hence, the Miller indices for the plane inside the cubic unit cell is (102).

Miller indices are used to specify planes and directions. These planes and directions could be in lattices or crystals. The number of indices will correspond to the size of the lattice or crystal.

In the given graph, the plane intercepts are:

x-intercept : 1

y-intercept : ∞  (since the planes does not intercept y-axes)

z-intercept = 1/2

Take the reciprocal:

1/1 = 1

1/∞ = 0

1/(1/2) = 2

Hence, the miller indices are (102)

The graph in your question is missing. Most likely it was like on the attached picture.

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Answer:

Step-by-step explanation:

Sample Space

off  even numbers

= {2,4,6,8,10}.

There are 5 outcomes in the sample space,

a. An absolute value inequality to represent the water temperature is |T - 58| ≤ 15.

b. A graph of the inequality is shown below and the solution set represent the range of water temperature that the fish can tolerate.

c.  An absolute value inequality to represent the population of fish is |P - 200| ≤ 10.

In order to write and solve an absolute value inequality that represents the water temperature, we would assign the variable T to the water temperature. Therefore, the required absolute value inequality can be written as follows;

|T - 58| ≤ 15

-15 ≤ T - 58 ≤ 15

-15 + 58  ≤ T - 58 + 58 ≤ 15 + 58

43 ≤ T ≤ 73

Part b.

In this scenario and exercise, we would plot the water temperature on the x-axis of a cartesian coordinate by using an online graphing tool as shown in the image attached below.

Additionally, the solution set (43, 0) and (73, 0) is the shaded portion of the graph and it represents the range of water temperature that this population of fish can tolerate.

Part c.

In order to write and solve an absolute value inequality that represents the population of fish, we would assign the variable P to the population of fish. Therefore, the required absolute value inequality can be written as follows;

|P - 200| ≤ 10

-10 ≤ P - 200 ≤ 10

-10 + 200  ≤ P - 200 + 200 ≤ 10 + 200

190 ≤ P ≤ 210

In conclusion, the solution set (190, 0) and (210, 0) is the shaded portion of the graph and it represents a safe environment for the population of fish.

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The probability that a randomly selected graduate will have a student loan greater than $30,000 is 0.1587, the probability that the loan is less than $22,500 is 0.3085, and the probability that the loan falls between $20,000 and $32,000 is 0.8186.

Let X be a random variable representing the student loans of graduates. Then, X ~ N(μ = 25,000, σ = 5,000). To find the probabilities, we need to standardize the values using the standard normal distribution, Z ~ N(0, 1), where Z = (X - μ) / σ.

a. P(X > 30,000) = P(Z > (30,000 - 25,000) / 5,000) = P(Z > 1) = 0.1587

b. P(X < 22,500) = P(Z < (22,500 - 25,000) / 5,000) = P(Z < -0.5) = 0.3085

c. P(20,000 < X < 32,000) = P((20,000 - 25,000) / 5,000 < Z < (32,000 - 25,000) / 5,000) = P(-1 < Z < 1.4) = 0.8186

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Answer:

$0.30

Step-by-step explanation:

$0.60 = 12

0.60 divided by 2 is 0.30

$0.30

Answer:

6 pencils x $0.6 = $3.6

Step-by-step explanation:

hope this helps

Answer:

2. 12.08

3. 7.74

Step-by-step explanation:

a squared + b squared = c squared

2. 5 squared = 25, 11 squared = 121, 25 + 121 = 146, the squre root of 146 is 12.08

3.19 squared = 361, 421 - 361 = 60 60 squared = 7.74

Answer:

For 2 the answer is 12. For 3 the answer is 28.

Step-by-step explanation:

These may be wrong but hopefully they are correct

My work:

\(5^2+11^2=146\)   then \(\sqrt{146} = 12.08\)

\(\sqrt{421}=20.5\)    \(19^2+20.5^2=781.25\)  then  \(\sqrt{781.25} =28\)

(a) The probability of having all six children be girls is (1/2)^6, or 1/64.
(b) The probability of having all six children be the same sex (either all boys or all girls) is (1/2)^6 + (1/2)^6, or 2/64, or 1/32.
(c) The probability of having at least one boy is 1 - 1/64, or 63/64

The probability of having a child of a particular sex is 50%. Given a family with six children, we can calculate the probability of each event as follows:
(a) All the children being girls: the probability is (1/2)^6, or 1/64.
(b) All the children being the same sex (either all boys or all girls): the probability is (1/2)^6 + (1/2)^6, or 2/64, or 1/32.
(c) At least one boy being in the family: the probability is 1 - (1/2)^6, or 63/64. This can be calculated by finding the probability of having no boys (all girls) and then subtracting it from 1.
In summary, the probability of having a particular outcome in a family with six children depends on the number of children of each sex and can be calculated using the formula (1/2)^n, where n is the number of children of a particular sex.


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Complete question:

Assume that the probability of the birth of a child of a particular sex is 50%. In a family with six children, find the probability of each event.

(a) All the children are girls.

(b) All the children are the same sex.

(c) There is at least one boy.

Answer:

Hi there!

Your answer is:

Median: 23.5

Mean: 25

Step-by-step explanation:

The mean is the average of all the numbers in your dataset. You determine this by adding all the numbers together and dividing by the # of numbers in your set!

35+28+19+18 = 100.

100/4 = 25

The median is the middle number of your data set! This is determined by counting off the numbers from each side of the equation after setting them in order from least to greatest. If there are 2 remaining, you must find the average of those!

35 , 28, 19 , 18 from least to greatest is

18, 19, 28, 35

/. /

Now find the average of 19 and 28!

19+28 = 47

47/2 = 23.5

Answer:

Step-by-step explanation:

Find the median and mean of the data set below:29,39,28,5029,39,28,50

Answer:

C has no solution

Step-by-step explanation

A. x=7, y=8

B. x=2/3 +1/3

Answer:

Set this up as a proportion.

54/n = 75/100

Now solve for n and finish from here.

Can i also have brain or a heart :)

Answer:

x would equal 72

Step-by-step explanation:

you can find a percent but there is already a percent showing. So the answer should be 72.

When you're trying to find the answer to these problems you should check if there is a percent part and whole. In this question, there is already a percent and a part so you would just try to find the whole.

The limit of the sequence (1) {2}, (2) {(-1)^n}, and (3) {n sin(n)}, converges to DNE (does not exist) or the sequence diverges. The limit of the sequence (4) {sin(nπ)} is undefined, as it oscillates between -1 and 1.

In the case of sequence (1) {2}, the limit is a constant value, and the sequence converges to that value. However, in the case of sequence (2) {(-1)^n}, the sequence oscillates between -1 and 1, and there is no single value that it approaches as n tends to infinity. Therefore, the limit does not exist, and the sequence diverges.

Sequence (3) {n sin(n)} also does not have a limit as n tends to infinity. The term n sin(n) oscillates between positive and negative values without approaching a specific value. Hence, the limit of this sequence is DNE, and it diverges.

In the case of sequence (4) {sin(nπ)}, the term sin(nπ) oscillates between -1 and 1 as n varies. Since there is no convergence to a specific value, the limit of this sequence is undefined.

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9514 1404 393

Answer:

  vertical expansion by a factor of 2

Step-by-step explanation:

g(x) = 4ln(x) = 2(2ln(x)) = 2f(x)

g(x) is a vertically expanded version of f(x) -- by a factor of 2.

(a) Find the dual of the LP.Primal problem isminimize \($b_1y_1+C_1x_1+...+C_nx_n$\) subject to \($a_{11}x_1+a_{12}x_2+...+a_{1n}x_n \leq\) \(b_1$...$a_{m1}x_1+a_{m2}x_2+...+a_{mn}x_n \leq b_m$ and $x_1, x_2,\)..., x_n\(\geq 0$\)

Let us find the dual of the above primal problem.

Dual problem ismaximize \($b_1y_1+...+b_my_m$\)subject to \($a_{11}y_1+a_{21}y_2+...+a_{m1}y_m \leq\)\(C_1$...$a_{1n}y_1+a_{2n}y_2+...+a_{mn}y_m \leq C_n$\)

and\($y_1, y_2, ..., y_m \geq 0$\)

(b) Find the standard form of the LP and dual.Standard form of the primal problem isminimize \($b_1y_1+C_1x_1+...+C_nx_n$\)subject to \($a_{11}x_1+a_{12}x_2+...+a_{1n}x_n +s_1 = b_1$...$a_{m1}x_1+a_{m2}x_2+...+a_{mn}x_n +s_m = b_m$\) and\($x_1, x_2, ..., x_n, s_1, s_2, ..., s_m \geq 0$\)

Standard form of the dual problem ismaximize \($b_1y_1+...+b_my_m$\)subject to \($a_{11}y_1+a_{21}y_2+...+a_{m1}y_m \leq 0$...$a_{1n}y\)

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Monthly salary before taxes = $3500

Monthly salary after taxes and healthcare = $2482.15

Subtraction is an operation used to find the difference between numbers. When you have a group of objects and you take away a few objects from it, the group becomes smaller.

Given,

Annual salary in job = $42000

Monthly salary = $42000/12 = $3500

State and federal income tax = 12.86% = 0.1286

State and federal income tax on salary

= $42000 × 0.1286

= $5401.2

FICA tax = 8.65% = 0.0865

FICA tax on salary

= $42000 × 0.0865

= $3633

Healthcare estimate is $250 per month

Total healthcare estimate in year = $250×12 = $3000

Dental estimate is $15 per month

Dental estimate in year = $15×12 = $180

Annual salary after taxes and healthcare
= $42000 - $5401.2 - $3633 -$3000 -$180

= $29785.8

Monthly salary after taxes and healthcare = $29785.8/12 = $2482.15

Hence, $3500 is monthly salary before taxes.

$2482.15 is monthly salary after taxes and healthcare.

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Addressing issue at hand, we can state that the correct linear equation comparison symbol to the box. 10.09 10.9 f < = > is => 10.09 < 10.9

The algebraic equation y=mx+b is known as a linear equation. M serves as the y-intercept, and B serves as the slope. The previous clause has two variables, y and x, and is sometimes referred to as a "linear equation with two variables". Bivariate linear equations are those with two independent variables. The following are a few examples of linear equations: 2x - 3 = 0, 2y = 8, m + 1 = 0, x/2 = 3, x + y = 2, and 3x - y + z = 3. When an equation takes the form y=mx+b, with m denoting the slope and b denoting the y-intercept, it is referred to as being linear. The term "linear" refers to an equation having the form y=mx+b, where m stands for the slope and b for the y-intercept.

the correct comparison symbol to the box.

10.09 10.9

< = >

10.09 < 10.9

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A line is said to be flat when it has a small slope, while a line is said to be steep when it has a large slope.

Let's find the slope of both lines.

Apply the slope formula:

• Slope of line A

Take the points:

(x1, y1) ==> (-1, 1)

(x2, y2) ==> (-2, 4)

• Slope of line B

Take the points:

(x1, y1) ==> (4, -1)

(x2, y2) ==> (0, -1)

The slope of line A is -3( negative slope)

The slope of line B is 0

The greater the slope, the steeper the line.

• Since line B has a greater slope than line A, we can say it is steeper.

• Also since Line B is a horizontal line, it is flatter than line A

• The slope of a horizontal line is greater than the slope of a line with a neagtive slope, we can say that line B shifted upward

Thus, we can say:

Line B is flatter, horizontal and shifted upward

ANSWER:

Line B is flatter, horizontal, and shifted upward

The constant of proportionality in terms of dollars per hour is A 40.

The constant of proportionality is used to illustrate the constant relationship between the variables.

In this case, a 3 hour lesson costs $120.00 and the cost of a lesson is proportional to the duration, in hours, of the lesson.

The constant will be the division of the values. This will be:

= $120 / 3

= $40

The correct option is A

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Cost of renting a truck for one day = $96

Money Calvin can spend = $120

Money left with Calvin after he spends on the daily rent :

\( = \tt120 - 96\)

\( = \tt\$ 24\)

Cost charged per mile = 0.60

Number of miles he can drive the rental truck :

\( =\tt 24 \div 0.60\)

\( = \color{plum}\tt40 \: \: miles\)

Thus, number of miles he can run the truck = 40 miles

Therefore, Calvin can run the truck for 40 miles after he pays the daily fee.

The triangles ΔWNR and ΔBNR are congruent to each other by ASA postulates. Then the correct option is B.

The polygonal shape of a triangle has a number of sides and three independent variables. Angles in the triangle add up to 180 °.

The ratio of the matching sides will remain constant if two triangles are comparable to one another.

The line segment NR bisects angle ∠WRB and ∠WNB.

In triangles ΔWNR and ΔBNR, then we have

∠WNR = ∠BNR           (Given)

∠WRN = ∠BRN           (Given)

NR = RN                      (Common sides)

The triangles ΔWNR and ΔBNR are harmonious with one another as ASA proposes. Then the right choice is B.

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Answer:

r = 5:8

Step-by-step explanation:

5 pound to 8 people

Part A

The two factors are 5 and 4x+6.

Part B

The first factor, 5, has 1 term.

The second factor, 4x+6, has 2 terms.

Part C

The coefficient of the variable term is 4.

Answer: B = False

Step-by-step explanation: Doesn't need one mainly because a rational  function has an equation and no expression, most rational functions may have one. For example 2x + 7 x + 5x = ???