2.9030 has 4 significant digits.
TRUE OR FALSE

The x and y component of the ball's final velocity are respectively 7.35 m/s and  4.90 m/s.

The rate at which a body's displacement changes in relation to time is known as its velocity. Velocity is a vector quantity with both magnitude and direction. SI unit of velocity is meter/second.

Given that:

Mass of the ball: M = 6.35 kg.

Initial velocity of ball: U = 8.49 m/s.

Mass of the pin at rest: m = 1.59 kg.

Final velocity of pin: v = 20.1 m/s at a -77.0° angle.

Let the x and y component of the ball's final velocity are respectively V₁ m/s and  V₂ m/s.

Appling conservation of momentum along x axis:

MU + m.0 = MV₁ + mvcos(-77.0°)

⇒ V₁ = u - (m/M) v cos(-77.0°)

After putting the values we get:

V₁ = 7.35 m/s.

Appling conservation of momentum along y-axis:

M.0 + m.0 = MV₂ + mvsin(-77.0°)

⇒ V₂ = - (m/M) vsin(-77.0°)

After putting the values we get:

V₂ = 4.90 m/s.

Hence, the x and y component of the ball's final velocity are respectively 7.35 m/s and  4.90 m/s.

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Answer: 5990 kJ :)

Explanation: a p e x <3

The amount of thermal energy needed to boil 2.65 kg of water at its boiling point is 5990 kJ. So, the correct answer is option C.

Thermal energy is the energy that is generated by the movement of particles within a substance or system. It is a type of internal energy and is directly related to the temperature of the system. The faster the particles are moving, the more thermal energy the system has. Thermal energy can be transferred from one system to another through the processes of conduction, convection, and radiation. It is a form of energy that is used in many different applications, such as heating homes and buildings, powering engines, and cooking food.

Here in the Question,

To calculate the thermal energy needed to boil the water, we can use the formula,

Q = m x L

where Q is the thermal energy, m is the mass of the water, and L is the latent heat of the vaporization of water.

Q = m x L

Q = 2.65 kg x 2260 kJ/kg

Q = 5990 kJ

Therefore, 2.65 kg of water will require 5990 kJ of thermal energy to reach its boiling point.

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Answer:  1)Scientists seek to acquire: scientific hypothesis

2)A scale measures the weight of a light object: 0.240 lbs

3)What does the process of scientific inquiry: It starts with a problem to solve or a question to answer

4)A mouse in a maze scurries 41 cm south: 76 cm southwest

5)When might an object's average velocity be equal to its average speed in two dimensions:

If the object moves in a straight line in one direction represented as positive, then the magnitude of average velocity will be equal to the average speed.

6)Using the velocity versus time graph, calculate the acceleration of Object A: 3 m/s^2

7)What is the range of a bullet fired horizontally at a height of 1.5m: 66.4m

8)What two vertical forces act on a falling leaf: weight, friction

9)What is equal and opposite to the applied force: spring force

10)Using the free-body diagram, calculate the net force: 12N, right

11)How does the force of impact during a collision change: it increases

12)The threads of a screw used to fasten two pieces of wood: by increasing the normal force exerted by the wood on the screw thread

13)A 60 kg skier with an initial velocity of 12 m/s coasts up a hill: 2.5m

14)A 1,500 kg car’s speed changes from 30 m/s to 15 m/s: -506,250 (negative 506,250| NOT POSITIVE)

15)What is true about weather: The weather depends on so many conditions that it is not possible to account for them all in any model.

16)A student records the mass of objects A, B, C, and D:  A

17)Newton’s cradle is a contraption where metal balls: friction force

18)In a closed system, an object with a mass of 10 kg: 12kgm/s

19)Given the data, what is the kinetic energy of the: 3J

20)A wedge is a simple machine that is essentially two: A length of 12 in. and a thickness of 2 in.

21)Object A and Object B are at equal distances on opposite: 3/4

22)A geosynchronous satellite has an orbital period of 24: 35,900 km

23)Calculate the eccentricity for the planet if the: 0.0167

24)A planet travels in its orbit close to apogee : the same amount of time

25)If astronomers discovered a new planet and found its: 22.3 AU

Explanation:

Hope this helps you guys!!! <3 (this is for 'A Semester Exam')

Answer:

The net force required to bring the car to rest is 11,900 N. Since the car is slowing down, the direction of the net force must be opposite to the initial velocity. Therefore, the direction of the net force is opposite to the initial direction of the car's motion.

Explanation:

First, we need to convert the speed from km/h to m/s:

100 km/h * (1000 m/km) / (3600 s/h) = 27.78 m/s

The initial kinetic energy of the car is:

KE = (1/2) * m * v^2

KE = (1/2) * 1350 kg * (27.78 m/s)^2

KE = 535,500 J

To bring the car to a stop, the net force applied over the distance traveled must equal the initial kinetic energy. So:

work done = force * distance = KE

Rearranging this equation, we get:

force = KE / distance

Substituting the values we have, we get:

force = 535,500 J / 45 m

force = 11,900 N

The net force required to bring the car to rest is 11,900 N. Since the car is slowing down, the direction of the net force must be opposite to the initial velocity. Therefore, the direction of the net force is opposite to the initial direction of the car's motion.

The tension in the strings are 31.47 and 19.25 N respectively.

Mass of the block, m = 3 kg

From the figure, consider the vertical components,

T₁ sin45° + T₂ sin30° = mg

(T₁/√2) + (T₂/2) = 3 x 9.8 = 29.4

Also, consider the horizontal components,

T₁ cos45° = T₂ cos30°

T₁/√2 = T₂ x√3/2

T₁ = T₂ x √3/2 x √2

So,

T₁ = 0.612T₂

Applying in the first equation,

(T₁/√2) + (T₂/2) = 29.4

(0.612T₂/1.414) + 0.5T₂ = 29.4

0.434 T₂ + 0.5 T₂ = 29.4

0.934 T₂ = 29.4

Therefore, the tension,

T₂ = 29.4/0.934

T₂ = 31.47 N

So, the tension,

T₁ = 0.612 T₂

T₁ = 0.612 x 31.47

T₁ = 19.25 N

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Answer:

William Gilbert

Explanation:

first described the Earth as a giant dipole magnet 400 years ago. But, as Rod Wilson recounts, he did far more than this.

Answer:

william gilbert

Explanation:

first described the Earth as a giant dipole magnet 400 years ago. But, as Rod Wilson recounts, he did far more than this.

Using the formula F = G * (m1 * m2) / r^2, where G is the gravitational constant, m1 and m2 are the masses of the two objects, and r is the distance between them, we can calculate the gravitational force between Jupiter and the sun.

Plugging in the values, we get:

F = (6.674 x 10^-11 N * (m^2 / kg^2)) * ((1.9 x 10^27 kg) * (2 x 10^30 kg)) / (78 x 10^6 m)^2

Simplifying this, we get:

F = 1.98 x 10^27 N

Therefore, the gravitational force between Jupiter and the sun is approximately 1.98 x 10^27 Newtons.

The gravitational force between Jupiter and the sun, calculated using Newton's law of gravitation with their masses and distance, is \(1.95 * 10^{22} N.\)

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The speed of the wave can be measured in centimeter per second. Speed of the wave is defined as how fast the wave travels in a second.

Hence, the correct answer is (A)

It is not recommended to fire a gun straight up into the air.

When a bullet is fired into the air, it will eventually come down and can pose a danger to people and property below. The bullet can still be lethal when it reaches the ground, especially if it lands on a hard surface or hits someone directly.

Additionally, firing a gun in a residential area can be illegal and can result in legal consequences. In general, guns should only be fired in designated shooting ranges or in self-defense situations where there is an immediate threat to life. It is important to handle firearms responsibly and follow all safety guidelines to prevent accidents and injuries.

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Distance between two lines of grating is 4.85*10^-4 cm.

The act of bending light around corners where it spreads out and illuminates regions is known as the diffraction of light.

A optical element known as a diffraction grating splits light into numerous beams that move in various directions. The directions, as well as diffraction angles of these beams, depending on the wavelength of the incident light, the angle at which the wave strikes, and the distance or spacing between consecutive diffracting elements.

The distance between the two grating lines is calculated by taking the reciprocal of the grating value which is provided.

Distance between two lines of grating is, 1/2060 = 4.85*10^-4 cm.

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Answer:

For the aceleration we have:

Vf = Vo + a * t

Clearing "a":

a = (Vf - Vo) / t

Replacing and resolving:

a = (34 m/s - 0 m/s) / 21 s

a = 34 m/s / 21 s

a = 1,61 m/s^2

The aceleration of the vehicle is 1,61 meters per second squared

Answer:

The magnitude scale used in astronomy is logarithmic, meaning that each increase in magnitude represents a decrease in brightness by a factor of approximately 2.512. Therefore, if Star A has a magnitude of 1.0 and is 60 times brighter than Star B, we can calculate the magnitude of Star B as follows:

Brightness ratio = 2.512^(magnitude difference)

60 = 2.512^(magnitude of A - magnitude of B)

Taking the logarithm base 2.512 of both sides:

log base 2.512(60) = magnitude of A - magnitude of B

Solving for the magnitude of B:

magnitude of B = magnitude of A - log base 2.512(60)

magnitude of B = 1.0 - log base 2.512(60)

Calculating the value:

magnitude of B ≈ 1.0 - 2.799

magnitude of B ≈ -1.799

Therefore, the magnitude of Star B is approximately -1.799.

Explanation:

Using the magnitude equation, we deduced that given star A has a magnitude of 1.0 and is 60 times brighter than star B, the magnitude of star B comes out to be approximately 4.4. This computation confirms that the larger the magnitude, the fainter the star.

To find the magnitude of star B given that star A is 60 times brighter, we first need to understand the concept of magnitude in astronomy. In general, in the magnitude system, each difference of 1 in magnitude corresponds to a difference in brightness by a factor of about 2.512 (which is the fifth root of 100). This is represented in the equation m2 = m1 - 2.5 log(b2/b1), where m1 and m2 are the magnitudes of the two stars, and b1 and b2 are their brightness levels.

Given that star A has a magnitude of 1.0 (m1) and is 60 times brighter than star B (b2/b1), we can plug these values into the equation to get m2 = 1.0 - 2.5 log(1/60). Solving this equation, star B's magnitude comes out to be approximately 4.4. Hence, it is evident from this calculation that a larger magnitude signifies a fainter star, which aligns with the core concept of the magnitude scale in astronomy.

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Answer:

Falling from the Sears Tower

• After 5 seconds, the ball falling from the

Sears Tower will have fallen

distance = ½ • 32 ft/s2 • (5 s)2 = 16 • 25

= 400 feet.

• We can turn the formula around to figure

out how long it would take the ball to fall all

the way to the ground (1450 ft)

Ætime = square root of (2 x distance/g)

Explanation:

The  new mass of the man will be   7.0 x 10^4 kg.

Mass (symbolized m) is described as a dimensionless quantity representing the amount of matter in a particle or object.

Let us say that the density of the man's body remains constant,

we have the new mass to be  10^3 = 1000 times greater than his original mass.

New mass = 1000 x M

mass of an adult male = 70 kg (This value is an assumed value)

New mass = 1000 x 70 kg

New mass = 7.0 x 10^4 kg

New mass =7.0 x 10^4 kg

Therefore, the new mass of the man is found to be   7.0 x 10^4 kg.

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The final speed (in meters per second), given that the coefficient of friction between her skis and the snow is 0.38 is 14.65 m/s

First, we shall obtain the force. This can be obatined as follow:

F = μKN

F = 0.38 × 588

F = 223.44 N

Next, we shall obtain the acceleration of the skier. This can be obtained as follow:

a = F / m

a = 223.44 / 61

a = 3.724 m/s²

Finally, we shall determine the final velocity. This can be obtained as follow:

v² = u² + 2as

v² = 14² + (2 × 3.724 × 50)

v² = 196 + 18.62

v² = 214.62

Take the square root of both sides

v = √214.62

v = 14.65 m/s

Thus, the the final speed is 14.65 m/s

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The final speed right at the top will be 14.65 m/s and the coefficient of friction between her skis and the snow is 0.38.

The ratio between displacement to time is referred to as the velocity of the object. It is a vector quantity with SI unit meter per second (m/s).

According to the question, the given information is :

Skier's mass, m = 60 kg

The acceleration due to gravity, g = 9.8 m/s²

Initial Speed, u = 14 m/s

Distance, s = 2.5 m

Deceleration is given as, a = 3.724 m/s².

Normal reaction force (N) will be equal to mg.

N = 60 × 9.8

N = 588 N

The coefficient of kinetic friction is given as, μ = 0.38

By using the formula,

F = μKN

F = 0.38 × 588

F = 223.44 N

Now, let's calculate the acceleration of the skier :

f = ma

a = f/m

a = 223.44/60

a =  3.724 m/s².

Now, calculate the velocity,

v² = u² + 2as

v² = 14² + 2 (3.724) (50)

v² = 196 + 18.62

v² = 214.62

v = 14.65 m/s.

Hence, the final speed right at the top will be 14.65 m/s.

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The resultant of the displacement is 336.5m

The process of splitting a vector into its components is called resolution of the vector. The vectors are splitted into vertical and horizontal component.

For the first displacement;

The vertical component = - 150 sin45 = -106.1 m

The horizontal component = - 150 cos 45° = -106.1 m

For the second displacement;

The vertical displacement = - 85sin90 = -85

The horizontal component = 0

For the third displacement;

The vertical displacement = 550 sin55 = 450.5

The horizontal displacement = 550 cos 55 = 315.5

Sum of vertical component = 450.5-85-106.1 = 263.4

sum of horizontal component = 315.5 -106.1 = 209.4

Using Pythagorean theorem

R = √ 263.4² + 209.4²

R = √113227.92

R = 336.5m

The resultant angle = tan^-1( 263.4/209.4)

= tan^-1(1.26)

= 51.56°

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Answer:

I don't know but you got this!!

Answer:

Explanation:

F = GMm/d²

F = 6.67259 x 10⁻¹¹(2.39)(0.016) / 0.0681²

F = 5.5019685...x 10⁻¹⁰ N

round as appropriate, probably no more than 3 significant figures.

Value of G seems low, but well within the 3 significant figures of the other numerals. I typically see G = 6.674 x 10⁻¹¹

Answer:

I believe the answer is Mendeleev

To calculate electric field created by a dipole on the axial line, magnitude and direction of the electric field intensity when the distance of a point charge from the center .

All the measurement of distances are to be taken from the centre(O).

Let the distance between O to +q and O to –q be ‘l’. So, total length between +q and –q will be ‘2l’.

Take a point ‘p’ on the axial line at the distance ‘r’ from the center as shown in figure.

Electric field on the axial line of dipole is not 0

magnitude =E = 14πε0 2Pr2

An electric field  is the physical field that surrounds electrically charged particles and exerts force on all other charged particles in the field, either attracting or repelling them.

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Answer:

534.8 meters

Explanation:

Use T=(2*pi*r)/v

560=(2*pi*r)/6

3360=2*pi*r

1680=pi*r

534.8 meters=radius

It takes 560s for a runner to complete one circular lap, moving at a speed of 6.00 m/s. The radius of a track is 534.7 m.

Mathematically, it can be calculated as follows :

distance = speed × time

The formula relating distance (d), speed (s), and time (t) is

d = st

First, Calculating the distance,

d = 560 s × 6 m·s⁻¹

  = 3360 m

When, Calculating the track radius,

The distance travelled is the circumference of a circle,

C = 2пr

r = 3360/2п

 = 534.7 m

The radius of the track is 534.7 m.

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Answer:

The answer is "\(W= 100.44 \ KJ\ \ \ \W_{win}=7.23 \ KJ\)"

Explanation:

Please find the complete question in the attached file.

From of the ideal gas relation that initial and the last temperatures were determined:  

\(T_1 = \frac{P_1 V}{m R}\)

    \(= \frac{100 \times 0.8}{1.54 \times 0.1889} \\\\ = 275 \ K\)

\(T_2 = \frac{P_2 V}{m R}\)

    \(= \frac{135 \times 0.8}{1.54 \times 0.1889} \\\\ = 317 \ K\)

In the initial and final states, the internal energies for given temperatures are described from A-20 by means of intelmpolation and divided by the carlxon molar mass.  

\(u_1 = 141.56 \frac{KJ}{kg}\\\\u_2 = 206.78 \frac{KJ}{kg}\)

The real job is just the difference between internal energies:  

\(W = m(u_2 - u_1) \\\\\)

    \(= 1.54(206.78 -141.56) \ kJ \\\\ =100.44 \ kJ\)

In the initial and final states, the zero entries are as determined as internal energies:

\(S_1^{\circ} =4.788 \frac{KJ}{kg K}\\\\S_2^{\circ} =5.0478 \frac{KJ}{kg K}\)

From its energy increase, the minimum work required is determined:

\(W_{min} = m(u_2-u_1 - T_0(s_2 -S_1))\\\\=W-mT_0(S_2^{\circ}- S_1^{\circ} -R \In \frac{P_2}{P_1})\\\\= 100.44kJ -1.54 \times 298( 5.0478-4.788-0.1889 \In \frac{135}{100})\\\\=7.23\ KJ\\\)

Answer:

A

Explanation:

One of the main benefits of informational interviewing is that it allows the person conducting the interviews to gain insights and information about a particular career or industry.

The statement that is true about the theory of plate tectonics and the theory of continental drift C. The theory of plate tectonics gives the method by which continents can move as part of plates .

According to the scientific hypothesis of plate tectonics, the underground movements of the Earth create the primary landforms. By explaining a wide range of phenomena, including as mountain-building events, volcanoes, and earthquakes, the theory, which became firmly established in the 1960s, revolutionized the earth sciences.

The scientist Alfred Wegener is most closely connected with the concept of continental drift. Wegener wrote a paper outlining his notion that the continents were "drifting" across the Earth, occasionally crashing through oceans and into one another, in the early 20th century.

According to tectonic theory, the Earth's surface is dynamic and can move up to 1-2 inches every year. The numerous tectonic plates constantly move and interact. The outer layer of the Earth is altered by this motion. The result is earthquakes, volcanoes, and mountains.

Therefore, option C is correct.

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Answer:

4÷3

Explanation:

40 miles and 1 hour equals 30 minutes so 40÷ 30 gives 4÷3

Answer:

always same

Explanation:

velocity and speed are same upto some extend but velocity is vector while speed is scalar quantity

Givens.

• The mass is 20 kg. (m = 20kg)

• The applied force is 63 N. (F = 63 N).

First, we have to make a free-body diagram to visualize the problem and its vectors.

Use Newton's Second Law for the horizontal vectors and vertical vectors.

Use the equations for weight and friction force.

Where F = 65 N, m = 20kg, and g = 9.8 m/s^2.

Therefore, the kinetic friction coefficient is 0.33.

Answer:

A. 20.25J

B. 18.23J

C. 2.7m/s

equal in magnitude but opposite in direction