Answer:
Mass of water produced is 22.86 g.
Explanation:
Given data:
Mass of hydrogen = 2.56 g
Mass of oxygen = 20.32 g
Mass of water = ?
Solution:
Chemical equation:
2H₂ + O₂ → 2H₂O
Number of moles of oxygen:
Number of moles = mass/ molar mass
Number of moles = 20.32 g/ 32 g/mol
Number of moles = 0.635 mol
Number of moles of hydrogen:
Number of moles = mass/ molar mass
Number of moles = 2.56 g/ 2 g/mol
Number of moles = 1.28 mol
Now we will compare the moles of water with oxygen and hydrogen.
O₂ : H₂O
1 : 2
0.635 ; 2×0.635 = 1.27
H₂ : H₂O
2 : 2
1.28 : 1.28
The number of moles of water produced by oxygen are less thus it will be limiting reactant.
Mass of water produced:
Mass = number of moles × molar mass
Mass = 1.27 × 18 g/mol
Mass = 22.86 g
Answer:
22.88
Explanation:
correct have a g'day mate
A first order reaction B=C has a half life of
20 minutes. What percentage shall have reacted
after 47 minutes?
Answer:
90.46 well that's how I got the answer from my calculations
Which sound frequency with a human ear be able to detect? Select ALL correct answers.
100 Hertz
1,000 Hertz
10,000 Hertz
100, 000 Hertz
The answers are 100, 1,000, 10,000 if your are with K12
Answer:
100 HZ 1,000 HZ 10,000 HZ there you go :)
Answer:
100 hertz, 1,000 hertz, and 10,000 hertz
Explanation:
I took the k12 test :)
What are the products of the neutralization reaction between HCl and
Ca(OH)2?
A. Cl2, CaO, and H2
B. CaCl2 and H20
C. CaCl and H20+
D. Cal and HCIO
Answer:
opinion b
Explanation:
the product of neutralization reaction between hcl and CA(oh)2 is option b.
The circular flow model interacts between which sectors of the economy? Select THREE answers.
Private
Government
Foreign
Tech
Households
Answer:
2,3,5
Explanation:
mass of 1×10^25 molecules of water
Answer:
1.E25 it is the answer the answer to mass of 1×10^25 molecules of water
Explanation:
this is just EXPLINATION find your answer using this
first divide the number of molecules by Avogadro's number 6.022*10^25
you will
l get no. of Moles of water
multiply the no. of Moles with mass of 1 Mole of water 18g per mole
if get answer you comment
you should try on your own you will understand better
How do I find the average corrected and uncorrected freezing point from this data?
The average corrected freezing point is 1.5 °C and uncorrected freezing point is 2.5 °C.
Freezing point is defined as the temperature at which a liquid changes to solid when cooled.
Trial freezing point (°C)
Run 1 0.5
Run 2 4.0
Run 3 3.0
The average uncorrected freezing point is = ( 0.5 + 4.0 + 3.0 ) / 3
= 7.5 / 3
= 2.5 °C
corrected freezing points (°C)
3.5
0.0
1.0
The average corrected freezing point is = (3.5 + 0 + 1 ) / 3
= 4.5 / 3
= 1.5 °C
Thus, The average corrected freezing point is 1.5 °C and uncorrected freezing point is 2.5 °C.
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It is the outermost layer of the solid portion of earth
Answer:
Crust.
Explanation:
Its is made up hard rocks
Answer:lithosphere
The lithosphere is the solid, outer part of the Earth. The lithosphere includes the brittle upper portion of the mantle and the crust, the outermost layers of Earth's structure.
Explanation:
An atom or ion has 16 protons, 15 neutrons, and 17 electrons. Is it positive, negative, or
neutral? Why? What element is it?
Someone help me please!
Balance the following skeleton reaction and identify the oxidizing and reducing agents: Include the states of all reactants and products in your balanced equation. You do not need to include the states with the identities of the oxidizing and reducing agents.
CrO_4^2- (aq) + N_2O(g) rightarrow Cr^3+ (aq) + NO(g) [acidic]
The oxidizing agent is:_______.
The reducing agent is:_______.
Answer:
Oxidizing agent - CrO4^2-
Reducing agent- N2O
Explanation:
Let us look at the equation closely;
CrO4^2- (aq) + 3N2O(g) ------------> Cr^3+ (aq) + 3NO(g) [acidic]
The reduction half equation is;
CrO4^2- (aq) + 3e -------->Cr^3+ (aq)
Oxidation half equation is;
3N2O(g) ------>3 NO(g) +3 e
Note that the oxidizing agent participates in the reduction half equation while the reducing agent participates in the oxidation half equation as seen above.
How many neutrons are there in the following191Os
In the exercise, we are shown an isotope of Osmium, Os. Osmium has an atomic number equal to 76.
An isotope is a variation of a chemical element, which has the same atomic number but varies the number of neutrons, i.e. those particles that have a neutral charge.
There are two important terms that we must know, which are atomic number and atomic mass.
Atomic number: It is the number of protons present in the nucleus of an atom.
Atomic mass: It is the sum of the protons and neutrons present in the nucleus.
So, in an isotope, the atomic mass will vary but the atomic number will remain the same because if the number of protons is changed it will mean that we have a different element.
Now let's see the representation of an isotope in the following figure:
In the figure we see how an isotope is represented, as an example, we have carbon 11. The upper number gives us the atomic mass, i.e. the sum of neutrons and protons and the lower number tells us the atomic number, i.e. the number of protons. The number of electrons is determined by the number of protons since they are in the same quantity but with opposite charges, that is negative charge.
In this example we have as upper number 35, this is the atomic mass (neutrons + protons). And as lower number 17, this is the atomic number and equal to the number of protons in the nucleus.
If we subtract these two values, we will have the number of neutrons in the nucleus.
The number of electrons is equal to the number of protons.
So, if we want to calculate the number of neutrons, we have to substrate the atomic mass minus atomic number, as follows:
Neutrons = Atomic mass - Atomic number
Neutrons = 191 - 76 = 115
The answer will be: There are 115 neutrons
Suppose that you wanted to prepare a acetate ion/acetic acid buffer solution with a pH of 4.35. What is the value 34 Marks: 2 off [A l/IHA) for the correct buffer solution for this event? The Ka for acetic acid is 1.8 x 10 5.
a. 0.39
b. 0.407
c. 0.372
d. 4.74
Answer:
b. 0.407
Explanation:
Acetic acid / Acetate ion is a buffer (Mixture of a weak acid, acetic acid, with its conjugate base, acetate ion) with pKa = -log Ka = 4.74.
The simplest way to determine the pH of a buffer is using Henderson-Hasselbalch formula:
pH = pKa + log [Conjugate base] / [Weak acid]
For acetic buffer with pH = 4.35:
4.35 = 4.74 + log [A⁻] / [HA]
-0.39 = log [A⁻] / [HA]
0.407 = [A⁻] / [HA]
Thus, right option is:
b. 0.407atomic size of an atom is decided by_________
Answer:
The edge of its orbital
Explanation:
The size of an atom is defined by the edge of its orbital. However, orbital boundaries are fuzzy and in fact are variable under different conditions
Use the virtual lab to prepare 150.0 ml of an iodine solution with a concentration of 0.06 g/ ml from the bottle of 0.12g/ml iodine solution
Answer:
Explanation:
In 150 ml of .06 g / ml solution , gram of iodine = 150 x .06 g = 9 g
Let volume of given concentration of .12 g / ml required be V
In volume V , gram of iodine = V x .12 g
According to question
V x .12 = 9 g
V = 9 / .12 = 75 ml
So, 75 ml of .12 g/ml will be taken and it is diluted to the volume of 150 ml to get the solution of required concentration .
Given the reaction: Mg(s) + 2HCl(aq) → MgCl2(aq) + H2(g)
The reaction occurs more rapidly when a 10-gram sample of Mg is powdered rather than in one piece, because powdered
Mg has
1. less surface area
2. more surface area
3. a lower potential energy
4. a higher potential energy
Aqueous hydrobromic acid (HBr) will react with solid sodium hydroxide (NaOH) to produce aqueous sodium bromide (NaBr) and liquid water (H₂O).
Suppose 55.8 g of hydrobromic acid is mixed with 15. g of sodium hydroxide. Calculate the maximum mass of sodium bromide that could be produced by the
chemical reaction. Be sure your answer has the correct number of significant digits.
The maximum mass of sodium bromide that could be produced by the chemical reaction is 38.59 g.
Steps
The balanced chemical equation for the reaction between hydrobromic acid and sodium hydroxide is:
HBr (aq) + NaOH (s) → NaBr (aq) + H2O (l)
To determine the maximum mass of sodium bromide that could be produced, we need to first identify the limiting reactant. We can do this by calculating the number of moles of each reactant using their molar masses:
Molar mass of HBr = 80.91 g/mol
Molar mass of NaOH = 40.00 g/mol
Number of moles of HBr = 55.8 g ÷ 80.91 g/mol = 0.689 mol
Number of moles of NaOH = 15.0 g ÷ 40.00 g/mol = 0.375 mol
The stoichiometry of the balanced chemical equation tells us that one mole of HBr reacts with one mole of NaOH to produce one mole of NaBr. Therefore, the limiting reactant is NaOH, since it produces fewer moles of product (NaBr) than HBr.
The number of moles of NaBr produced from the reaction is equal to the number of moles of NaOH used, which is 0.375 mol.
Finally, we can calculate the maximum mass of NaBr that could be produced using its molar mass:
Molar mass of NaBr = 102.89 g/mol
Mass of NaBr = number of moles of NaBr × molar mass of NaBr
Mass of NaBr = 0.375 mol × 102.89 g/mol = 38.59 g
Therefore, the maximum mass of sodium bromide that could be produced by the chemical reaction is 38.59 g.
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 Please help me with this Chemistry problem! I’ve been trying to figure it out for hours and it’s driving me mad. I’ll be very grateful :) I made it worth 100 points!
Explanation:
Hope this somewhat helped:
a. The equation for the reaction of weak acid, C6H5CO2H, with water is: C6H5CO2H + H2O <=> C6H5CO2^- + H3O^+. We can assume that all the C6H5CO2H has reacted with water to form C6H5CO2^- and H3O^+.
The pH is defined as -log(H30^+ concentration), where H30^+ is the hydronium ion, a measure of the acidic strength of the solution. At the equivalence point, all the C6H5CO2H has reacted with the NaOH to form C6H5CO2^- and Na^+. The stoichiometry of the reaction can be determined by balanced the reaction using the information given.
C6H5CO2H + NaOH <=> C6H5CO2^- + Na^+
This reaction tells us that one mole of C6H5CO2H will react with one mole of NaOH to form one mole of C6H5CO2^- and one mole of Na^+.
number of atoms per unit cell in face centred cube is
Answer: 4 atoms is the answer. I hope it helped you.
Explanation:
How many atoms are in 3.5 L of Neon at STP? Show your work
Answer:
0.1734
this is the answer to the question
2H₂O₂(1) + N₂H₂(1)→ 4H₂O(g) + N₂ (g) determine how many grams of N₂ are produced from the reaction of 8.92 g of H₂O₂ and 5.53 g of N₂H4.
Taking into account definition of reaction stoichiometry, 3.67 grams of N₂ are produced from the reaction of 8.92 g of H₂O₂ and 5.53 g of N₂H₄.
Reaction stoichiometryThe balanced reaction is:
2 H₂O₂ + N₂H₄ → 4 H₂O + N₂
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
H₂O₂: 2 molesN₂H₄: 1 moleH₂O: 4 moles N₂: 1 moleThe molar mass of the compounds is:
H₂O₂: 34 g/moleN₂H₄: 32 g/moleH₂O: 18 g/moleN₂: 28 g/moleBy reaction stoichiometry, the following mass quantities of each compound participate in the reaction:
H₂O₂: 2 moles ×34 g/mole= 68 gramsN₂H₄: 1 mole ×32 g/mole= 32 gramsH₂O: 4 moles ×18 g/mole= 68 gramsN₂: 1 mole ×28 g/mole= 28 gramsDefinition of limiting reagentThe limiting reactant is the reactant that in a chemical reaction determines, discloses or limits the amount of product formed, and causes a specific or limiting concentration; that is, it is the reactant that produces the least amount of product.
Limiting reagent in this caseTo determine the limiting reagent, it is possible to use a simple rule of three as follows: if by stoichiometry 32 grams of N₂H₄ reacts with 68 grams of H₂O₂, 5.53 grams of N₂H₄ reacts with how much mass of H₂O₂?
mass of H₂O₂= (5.53 grams of N₂H₄×68 grams of K)÷32 grams of N₂H₄
mass of H₂O₂= 11.75 grams
But 11.75 grams of H₂O₂ are not available, 8.92 grams are available. Since you have less mass than you need to react with 5.53 grams of N₂H₄, H₂O₂ will be the limiting reagent.
Mass of N₂ formedConsidering the limiting reagent, the following rule of three can be applied: if by reaction stoichiometry 68 grams of H₂O₂ form 28 grams of N₂, 8.92 grams of H₂O₂ form how much mass of N₂?
mass of N₂= (8.92 grams of H₂O₂× 28 grams of N₂)÷68 grams of H₂O₂
mass of N₂= 3.67 grams
Finally, 3.67 grams of N₂ can be produced.
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Apex Leaming-Pre-Lab
4. The graph shows a plot of the amount of a radioactive material remaining in
a sample versus time. According to the graph, what is the half-life of carbon-
14? Explain how you used the graph to determine this information.
The half-life of the carbon-14 obtained from the graphical representation of radioactive material remaining in a sample versus time is 5730 years.
How do i determine the half-life of carbon-14?The half-life a radioactive material is the time taken for half the material to decay or disintegrate.
For example, if the initial mass of a material is 10 g and the material becomes 5 g after 2 days. Then, we can say that the half-life of the material is 2 days.
With the above information in mind, we can obtain the half-life of the carbon-14 as illustrated below:
From the graph, we obtain:
Initial amount of carbon-14 = 1Half the initial amount = 1/2Now, we shall obtain the time for 1/2 in the graph.
The time for 1/2 in the graph is 5730 years.
Thus, we can conclude that the half-life of the carbon-14 is 5730 years.
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What is the percent yield if 3.47 g of copper is produced when 1.87 g of aluminium is reacted with excess of copper (II) sulfato? 2Al(s)+3CuSO4(ag)-Al2(SO4)3+3Cu(s)
Answer:
copper is limiting
Explanation:
How does the addition and subtraction of subatomic particles affect the atom?
Answer:
Adding or removing neutrons from the nucleus are how isotopes are created. Protons carry a positive electrical charge and they alone determine the charge of the nucleus. Adding or removing protons from the nucleus changes the charge of the nucleus and changes that atom's atomic number.
Explanation:
Answer:
if you add or subtract a proton from the nucleus, you create a new element. If you add or subtract a neutron from the nucleus, you create a new isotope of the same element you started with. In a neutral atom, the number of positively charged protons in the nucleus is equal to the number of orbiting electrons
PLEASE HELP
Predict the Eº values for all (6) combinations of the following: Cu(s) and Cu(NO3)2(aq) Fe(s) and Fe(NO3)3(aq) Zn(s) and Zn(NO3)2(aq) Pb(s) and Pb(NO3)2(aq)
Answer:
Is this math? Cause as a fourth grader, I can do Algebra, but not this.
Explanation:
Which of the following is not an example of weathering?
Frost wedging
Destruction of rocks at convergent boundaries
Acid rain
Oxidation reactions
Answer:
Destruction of rocks at convergent boundaries
Explanation:
Duuuuuuuuude. Dude.
Let's think for a sec, because this confused me.
Acid rain is chemical weathering. It has acid in it, so it weathers rocks. (Ewwww.)
Frost wedging is a major duh, because frost can weather rocks.
Oxidation reactions are a yes yes because it becomes oxidized.
Under what conditions is n2o3 No gas + n02 gas
spontaneous?
The reaction is spontaneous under conditions of low pressure and high temperature
What is a spontaneous reaction?We can say that a reaction is spontaneous when we know that the reaction is able to go on on its own. This implies that there is a mnimum energy that is required for the reaction to proceed.
The reaction is thus a sort of a self propagating system that goes on freely of its own accord.. We can see that what is going on here is the decomposition of the nitrogen V oxide gas as shown.
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i. Three different representations of glucose are
given below. Identify each type
of model.
Answer:
Ball and stick model is 3D and has the atoms depicted as different Coloured balls Conected to each other by "sticks"
fischer projection has the atoms on the side coming out of the plane, the atoms at the ends going behind (going away from you)
bond line notation Is the most common it does not show the C or H bonds but instead carbons are represented by the bends
The three structures of glucose represent three different models, they are ball and stick model, Fischer projection and bond line notation, respectively.
Glucose is a type of simple sugar (carbohydrate) that does not further hydrolyze to give monosaccharides.
Ball and stick model: The atoms are portrayed as different colored balls connected to each other by "sticks." Fischer projection: The atoms on the sides of the plane are coming out of the plane, while the atoms at the ends are moving behind.Bond line notation: It is the most frequent representation method used; it lacks C and H bonds but instead depicts carbons through bends.Therefore, the three glucose structures reflect three distinct models: the ball and stick model, the Fischer projection, and the bond line notation, respectively.
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Empty crucible and lid
Crucible, lid and Mg
Crucible, lid, and combustion product
42.39g
42.66g
0419 Mo
42.39-41.98
1. (2 pts) Determine the mass of the magnesium used.
Directions: Show all work in the space provided and write your answers on the lines with correct
significant figures and units! Using the data below please perform the following calculations:
Mass:
41.98g
0.00168 mil Ma
2. (2 pts) Determine the number of moles of magnesium used.
0.410Mg
24 3glnel
3. (2 pts) Determine the mass of magnesium oxide formed.
0.41g Mg
0.0256g Mg0
0.0072150
10 g
0.0184 -0.0256
4. (2 pts) Determine the mass of oxygen that combined with the magnesium.
5. (2 pts) Calculate the number of moles of oxygen atoms that were used.
= 1 My
07. For 60
Copyright © 2018 MsRazz ChemClass
6. (2 pts) Calculate the ratio between moles of magnesium used and moles of oxygen used.
ON mil Ma
0.0184 m My
0.0073
O(£។
7. (2 pts) Based on your experimental data, write the empirical formula for magnesium oxide.
1
8. (2 pts) Calculate the percent error in your determination of the magnesium: oxygen mole ratio,
using 1.00 as the accepted value.
We can compute a number of values that are connected to the experiment's magnesium and oxygen thanks to the provided data. By deducting the mass of the empty crucible and lid from the mass of the crucible, lid, and magnesium, we can first calculate the quantity of magnesium that was really utilised.
The weight that results is 0.27 grammes. We determine that this equates to around 0.0111 moles of magnesium using the molar mass of magnesium.The mass of the magnesium utilised is subtracted from the mass of the crucible, lid, and combustion product to get the mass of magnesium oxide that is created. Magnesium oxide's mass is determined to be 0.41 grammes.
We may infer from this data that the combined mass of magnesium and oxygen is We may infer from this data that the combined mass of oxygen and magnesium is 0.14 grammes. We calculate the amount of oxygen atoms utilised in the process as 0.00875 moles by dividing this mass by the molar mass of oxygen.
The empirical formula for magnesium oxide, MgO, is then determined to be roughly 1.27 moles of magnesium to moles of oxygen.The error percentage in calculating the magnesium-to-oxygen mole ratio is finally calculated, and it is discovered to be roughly 27%.
In conclusion, 0.27 grammes, or 0.0111 moles, of magnesium were consumed. 0.41 grammes of magnesium oxide were produced. The mass of the oxygen and magnesium together was 0.14 grammes, or 0.00875 moles.
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Can someone please help me answer this
Answer:
yiur mom
Explanation:
d
Differences between voltage, current and resistance?
Answer:
Voltage is the measure of electric potential energy per unit charge, current is the flow of electric charge through a circuit, and resistance is the property of a material that opposes the flow of electric current.
Ohm's Law relates these three concepts by stating that current is directly proportional to voltage and inversely proportional to resistance.
Hope this helps!
Select the correct answer.
Which unit is used for measuring atomic mass?
A atomic mole
B. grams/mole
C. grams
D. atomic mass unit
E. atomic mass weight
Answer:
D
Explanation:
The unit used to measure atomic mass is the atomic mass unit (amu). A single amu is equivalent to 1/12 the mass of an atom from the carbon-12 isotopIsotopes with different numbers of protons and neutrons will have an actual mass slightly different from the atomic mass calculated in atomic mass units.