Answer:
4.9382716e+40
Step-by-step explanation:
PLS HELPPPPP!!!!!!!!!!!!!!!!!!!! 15 POINTS
The graph for the equation y = negative 2 x + 1 is shown below. On a coordinate plane, a line with negative slope goes through (0, 1) and (1, negative 1). If another equation is graphed so that the system has no solution, which equation could that be?
Options:
y = negative 2 (x minus one-half)
y = negative one-half (4 x + 2)
y = negative x + 1
y = negative one-half x + 2
Answer:
y = negative 2 (x minus one-half)
Step-by-step explanation:
The equation of a line is given as:
y = mx + c, where m is the slope and c is the intercept on the y axis.
The equation of a line going through (0, 1) and (1, - 1) is calculated using:
\(y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)\\ y-1=\frac{-1-1}{1-0}(x-0)\\ y-1=-2x\\y=-2x+1\)
The solution of two lines is at their point of intersection. The equation of the line that would not have any solution with y = -2x + 1 would be a line that is parallel to y = -2x + 1. Since the two lines would be parallel to each other, their would be no intersection and therefore no solution.
Two lines are said to be parallel to each other if they have the same slope. The slope of y = -2x + 1 is gotten by comparing with y = mx + c, therefore the slope m = -2. From the options the only line with a slope m = -2 is y = -2(x -1/2). Therefore y = -2(x -1/2) is parallel to y = -2x + 1 and would have no solution
Answer:
b
Step-by-step explanation:
i did test
What is the value of the expression?
2 + 4x32 - 7+1
-
this is timed..
Answer:
124
Step-by-step explanation:
Answer:
124
Step-by-step explanation:
2+(4)(32)−7+1
=2+128−7+1
=130−7+1
=123+1
=124
What is the Value of G?
The value of g in the intersected lines is 28 degrees.
How to find angles?When lines intersect, angle relationships are formed such as linear angles, adjacent angle, vertically opposite angles. Therefore, let's find the angle g in the intersected lines as follows:
Therefore,
g + 43 = 71
subtract 43 from both sides of the equation'
g + 43 - 43 = 71 - 43
g = 28
Therefore,
g = 28 degrees
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Lea
owhs 800 shares of ABC, Incorporated. On April 6, the corporation Instituted a 5-for-2 stock split. Before the split, each share was worth $42.60.
a. How many shares did Lea hold after the split?
b. What was the post-split price per share?
c. Show that the split was a monetary non-event for Lea. Pre-split and post-split market values=
Answer:
2000
Step-by-step explanation:
Number of shares after split is 5/2 times the pre split value =800*5/2 = 2000
PLEASE HELP !!! timed exam - will give brainlyest
A consumer owes $2,550 on a credit card with a 21.9% annual interest rate.
Assuming the consumer makes fixed payments and does not charge any more purchases with the card, what is the total monthly payment needed to pay off the card in three years? Show all work and round your answer to the nearest penny.
Answer:
The total monthly payment needed to pay off the card in 3 years would be $260.08
Step-by-step explanation:
The solution is : $97.25/monthly, is the total monthly payment needed to pay off the card in three years.
Here, we have,
given that,
A consumer owes $2,550 on a credit card with a 21.9% annual interest rate.
we can use the formula for the monthly payment:
P = r* A / 1 - (1 + r)^-n
where:
P =monthly payment
A =Total loan amount
r = monthly interest rate (decilmal)
n = total number of payments
so:
here, we have,
P =monthly payment = x
A =Total loan amount = $2,550
r = monthly interest rate (decimal) = 21.9%
n = total number of payments = 3
now, we have,
using the formula & calculating we get,
P = $97.25
So, $97.25/monthly, is the total monthly payment needed to pay off the card in three years.
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Find the value of r, if P(5, r) = 2P(6, r-1)
answer choices:
a. 3
b. 5
c. 8
d. 11
The value of r in permutation P(5, r) = 2P(6, r-1) is 11. So, option d) is correct.
We know that the formula for the permutation of r objects taken from n distinct objects is P(n, r) = n! / (n-r)!. Using this formula, we can rewrite the given equation as:
5! / (5-r)! = 2 * 6! / (6-r+1)!
Simplifying this equation, we get:
5! / (5-r)! = 2 * 6! / (7-r)!
(5-r)! / 5! = (7-r)! / (2 * 6!)
(5-r)! / 5! = (7-r)! / 12
Since 5! = 120, we can simplify the left-hand side to:
(5-r)! / 120 = (7-r)! / 12
Multiplying both sides by 12, we get:
(5-r)! / 10 = (7-r)!
Multiplying both sides by 10, we get:
(5-r)! = 10 * (7-r)!
We can now manually try different values of r until we find one that satisfies the equation. Trying r = 3, we get:
(5-3)! = 10 * (7-3)!
2! = 10 * 4!
2 = 240
Since this is a contradiction, we can eliminate option (a) from the answer choices. Trying r = 5, we get:
(5-5)! = 10 * (7-5)!
1 = 20
Again, this is a contradiction, so we can eliminate option (b) from the answer choices. Trying r = 8, we get:
(5-8)! = 10 * (7-8)!
(-3)! = -10
Since the factorial of a negative number is undefined, this is not a valid solution, so we can eliminate option (c) from the answer choices. Therefore, the correct answer is (d) 11. Trying r = 11, we get:
(5-11)! = 10 * (7-11)!
(-6)! = 10 / 24
Simplifying the right-hand side, we get:
(-6)! = 5 / 12
Since the left-hand side is undefined for negative integers, we can eliminate this solution. Therefore, the only valid solution is r = 11, which we can confirm by checking that both sides of the equation are equal when r = 11. So, the correct answer is option (d).
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Solve 6x+2y=26 for y.
Multiple choice question.
A)
y= –3x – 13
B)
y=3x – 13
C)
y= –3x+13
D)
y=3x+13
Answer:
The choice C) y = - 3x + 13
Step-by-step explanation:
\(6x + 2y = 26 \\ 2y = 26 - 6x \\ \\ y = \frac{26 - 6x}{2} \\ \\ \\ y = \frac{26}{2} - \frac{6x}{2} \\ \\ \\ y = 13 - 3x\)
y = - 3x + 13
I hope I helped you^_^
Answer:
C
Step-by-step explanation:
6x + 2y = 26 ( subtract 6x from both sides )
2y = - 6x + 26 ( divide terms by 2 )
y = - 3x + 13 → C
each student is classified as a member of one of the following classes: freshman, sophomore, junior, senior. find the minimum number of students who must be chosen in order to guarantee that at least eight belong to the same class. 37
The minimum number of students who must be chosen is 29.
In the given question we have to find the minimum number of students who must be chosen in order to guarantee that at least eight belong to the same class.
As we know each student is classified as a member of one of the following classes: freshman, sophomore, junior, senior.
The four classes are the pigeonholes. A group of 28 students could have 7 belonging to each class. But if there are 29 students, at least 8 must be members of the same class. Therefore, the minimum number of students who must be chosen is 29.
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The right question is given below:
help ME pls !!!!!!!!!!!!!!!
Answer:
y ≥ 14
Step-by-step explanation:
y - 27 ≥ -13
y ≥ 14
Hopefully this helps!
Brainliest please?
Dale can type 32 words in 8 minutes.
What is his rate in words per minute?
Answer:4 words per minute.
Step-by-step explanation:32 divided by 8 is 4.
What i 464 divided by 60 with a remainder?
(trying to figure out how many hour i 464 minute)
When we divide the 464 by 60 we get the following remainder in our answer that is 44.
What do math remainders mean?The Remainder is the name for the value that is left behind after division. If an amount (reward) cannot be divided completely with another number, we are left with only a meaning (divisor). The remaining is the name for this amount. For instance, 10 is not precisely divisible by 3. We can calculate 3 x 3 = 9 because that is the closest value.
Briefing :7.733333333333333
=7 44/60 ⇔ 7 R 44
464 divided by 60
=7 with a remainder of 44
Here, we provide you the outcome of the dividing with remainder, often known as the Euclidean division, along with a brief explanation of the following terms:
464 divide by 60 yields a quotient and residual of 7 R 44.
464 is the dividend & 60 is the divisor; the division (numeric division) of 464/60 is 7; the remainder ("left over") is 44.
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Consider a hypothesis test of the claim that using petroleum jelly to clean terminals reduces the likelihood of developing a faulty car battery Identify the type I and type II errors for this test. O A type 1 error is accepting that there was a significant relationship between using petroleum jelly to clean terminals and developing a faulty car battery. A type II error is accepting that there was not a signficant relationship between using petroleum jelly to clean terminals and developing a faulty car battery. O A type I error is concluding that using petroleum jelly to clean terminals reduces the likelihood of developing a faulty car battery, when in reality, using petroleum jelly to clean terminals has no effect on the likelihood of developing a faulty car battery. A type II error is concluding that using petroleum jelly to clean terminals has no effect on the likelihood of developing a faulty car battery, when in reality, using petroleum jelly to clean terminals actually reduces the likelihood of developing a faulty car battery. O A type I error is concluding that using petroleum jelly to clean terminals has no effect on the likelihood of developing a faulty car battery, when in reality, using petroleum jelly to clean terminals reduces the likelihood of developing a faulty car battery. A type II error is concluding that using petroleum jelly to clean terminals effectively reduces the likelihood of developing a faulty car battery, when in reality, using petroleum jelly to clean terminals does not effect the likelihood of developing a faulty car battery. O A type I error is stating that the likelihood of using petroleum jelly to clean terminals is reduced by developing a faulty car battery. A type II error is stating that the likelihood of using petroleum jelly to clean terminals is not effect by the development of a faulty car battery,
The type I error is assuming that cleaning terminals with petroleum jelly lowers the risk of developing a bad automobile battery when there is actually no discernible benefit. The type II error is assuming that cleaning terminals with petroleum jelly has no impact on the chances of developing a bad automobile battery when in fact it does. So the option B is correct.
A type I error is assuming that using petroleum jelly to clean terminals lowers the risk of having a malfunctioning automobile battery when, in fact, there is no difference between using petroleum jelly to clean terminals and not using it at all.
The conclusion that using petroleum jelly to clean terminals has no impact on the possibility of generating a defective automobile battery is a type II error, as using petroleum jelly to clean terminals actually lowers the possibility of doing so. So the option B is correct.
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The complete question is:
Consider a hypothesis test of the claim that using petroleum jelly to clean terminals reduces the likelihood of developing a faulty car battery.
Identify the type I and type II errors for this test.
A. A type 1 error is accepting that there was a significant relationship between using petroleum jelly to clean terminals and developing a faulty car battery. A type II error is accepting that there was not a significant relationship between using petroleum jelly to clean terminals and developing a faulty car battery.
B. A type I error is concluding that using petroleum jelly to clean terminals reduces the likelihood of developing a faulty car battery, when in reality, using petroleum jelly to clean terminals has no effect on the likelihood of developing a faulty car battery. A type II error is concluding that using petroleum jelly to clean terminals has no effect on the likelihood of developing a faulty car battery, when in reality, using petroleum jelly to clean terminals actually reduces the likelihood of developing a faulty car battery.
C. A type I error is concluding that using petroleum jelly to clean terminals has no effect on the likelihood of developing a faulty car battery, when in reality, using petroleum jelly to clean terminals reduces the likelihood of developing a faulty car battery. A type II error is concluding that using petroleum jelly to clean terminals effectively reduces the likelihood of developing a faulty car battery, when in reality, using petroleum jelly to clean terminals does not effect the likelihood of developing a faulty car battery.
D. A type I error is stating that the likelihood of using petroleum jelly to clean terminals is reduced by developing a faulty car battery. A type II error is stating that the likelihood of using petroleum jelly to clean terminals is not effect by the development of a faulty car battery.
matlab
For \( x=[5,10,15] \) Write the Program that calculates the sum of \( (1+x) e^{x}=\sum_{n=0}^{\infty} \frac{n+1}{n !} x^{n} \) the general term for the sum in this Program is an and \( n \) term Error
The final results are stored in the sum_result and error_term arrays.
Here's a MATLAB program that calculates the sum of the given series and calculates the error term for each term in the series:
% Define the values of x
x = [5, 10, 15];
% Initialize the sum and error variables
sum_result = zeros(size(x));
error_term = zeros(size(x));
% Calculate the sum and error term for each value of x
for i = 1:numel(x)
current_x = x(i);
current_sum = 0;
current_error = 0;
% Calculate the sum and error term for the series
for n = 0:100
term = ((n+1)/factorial(n)) * current_x^n;
current_sum = current_sum + term;
% Calculate the error term
error = abs(term - current_sum);
current_error = current_error + error;
% Break the loop if the error becomes negligible
if error < 1e-6
break;
end
end
% Store the sum and error term for the current x value
sum_result(i) = current_sum;
error_term(i) = current_error;
end
% Display the results
disp("Value of x: ");
disp(x);
disp("Sum of the series: ");
disp(sum_result);
disp("Error term for each term: ");
disp(error_term);
In this program, we define the values of x as an array [5, 10, 15]. Then, we iterate over each value of x and calculate the sum of the series using a nested loop. The inner loop calculates each term of the series and accumulates the sum, while also calculating the error term for each term. The inner loop stops when the error becomes negligible (less than 1e-6). The final results are stored in the sum_result and error_term arrays.
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what is the midpoint of the line segment with endpoints (3.2,2.5) and (1.6,-4.5)?
Answer:
Midpoint: (2.4, -1)
Step-by-step explanation:
Midpoint Formula: \((\frac{x1+x2}{2} , \frac{y1+y2}{2} )\)
With that in mind,
(3.2 + 1.6)/2 = 2.4
(2.5 - 4.5)/2 = -1
Answer:
(2.4, -1)
Step-by-step explanation:
To find the x coordinate of the midpoint, average the x coordinates
(3.2+1.6)/2 = 4.8/2 = 2.4
To find the y coordinate of the midpoint, average the y coordinates
(2.5+-4.5)/2 = -2/2 = -1
(2.4, -1)
Express 0.00419 in standard form
I need help with solving isosceles and equilateral triangles
Answer:
60º
Step-by-step explanation:
The interior angles of a triangle equals 180º. And 60+60+60=180, that is your answer.
please help, ill mark brainliest pleaseeee
John had a puppy that weighed 12 pounds. Over a year, the puppy gained a significant amount of weight and is now 35 pounds. Use the variable x to represent the amount of weight the puppy gained.
Answer:x=35-12
Step-by-step explanation:x equals 23
give the total number of isomers with the formula [pd(c2o4)2i2]2–.
The total number of isomers with the formula [Pd(C2O4)2I2]2– is 3150.
There are two parts to this answer: the first part is to determine the coordination number of the central palladium (Pd) atom, and the second part is to determine the number of possible isomers based on the coordination number.
To determine the coordination number, we need to count the number of ligands (the molecules that bind to the central atom) attached to the Pd atom. In this case, we have four oxalate (C2O4) ligands, each of which contributes two atoms (a total of eight atoms), and two iodide (I) ligands, each of which contributes one atom (a total of two atoms). This gives us a total of 10 ligands attached to the Pd atom. Since each ligand can only form one bond with the Pd atom, the coordination number is 10.
Next, we need to determine the number of possible isomers. Isomers are molecules with the same chemical formula but different arrangements of atoms. For this complex ion, there are two types of isomers: geometrical and optical.
Geometrical isomers arise from the fact that the ligands can be arranged around the central atom in different ways. In this case, since there are 10 ligands, there are a total of 10!/[(4!2!2!)x2] possible geometrical isomers, or 3150.
Optical isomers arise when there are non-superimposable mirror images of the molecule. However, since this complex ion has a plane of symmetry, it is achiral and does not have optical isomers.
Therefore, the total number of isomers with the formula [Pd(C2O4)2I2]2– is 3150.
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Tommy buys 12 cans of soda
for $6. At this rate, how much
would he pay for 48 cans of
soda?
Answer:$24
Step-by-step explanation: Since Tommy bought 12 cans for $6, we would need to know what to multiply for 12 to equal 48. If done as a division problem, 48 ÷ 12 = 4. Multiply 6 x 4 to get 24 as your answer.
Yo tenía $ 2.00. Mi mamá me dio $ 10.00. Mi papá me dio $ 30.00. Mi tía y mi tío me dieron $ 100.00. Yo tenía otros $ 5.00. Cuánto tenía? La respuesta correcta será eliminada. Gané contra: Vero verito
Answer:
$147
Step-by-step explanation:
$2.00+$10.00+$30.00+$100.00+$5.00
=$147
El dinero total que tenía será de $ 147.00
Dado lo siguiente
La cantidad tenía inicialmente = $ 2.00
La cantidad dada por mamá = $ 10.00
La cantidad recibida de papá = $ 30.00
La cantidad recibida del tío y la tía = $ 100.00
Si tuviera otros $ 5,00
La cantidad total que tenía será la suma de todo el dinero que tenía y los recaudados como se muestra:
Dinero total que tenía = $ 2,00 + $ 10,00 + $ 30,00 + $ 100,00 + $ 5,00
Dinero total que tenía = $ 147.00
Por lo tanto, el dinero total que tenía será de $ 147.00.
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Ms. Belk made this box and whisker plot
after a quiz she gave. Which statement is
NOT true about the data in the plot?
(answer choices)
A. the interquartile range is 20
B. the upper extreme is 95
C. the lower quartile is 65
D.the median score is 75
any scams or external websites will be reported.
Answer:
D is incorrect
Step-by-step explanation:
the median score is 70
I'LL GIVE BRAINLIEST TO WHOEVER ANSWERS THE QUESTION!!!!
For the inequality y < 8 which statement best describes the graph?
There would be a horizontal dotted line on (0,8) and shading would occur below the line.
There would be a horizontal solid line on (0,8) and shading would occur above the line.
There would be a vertical dotted line on (8,0) and shading would occur to the right of the line
There would be a vertical solid line on (8,0) and shading would occur to the left of the line.
Answer:
There would be a horizontal dotted line on (0,8) and shading would occur below the line.
I just took the test and got it right :) hope this helps!
For the given inequality, the best describes the graph is that there would be a horizontal-dotted line on the point (0, 8) and shading occurred below the line. Hence, option A is correct.
What is a graph?In math, graph science is the theory of geometric structures called graphs that are used to represent pairwise different objects. Vertices—also known as nodes or points—that are joined by edges make form a network in this sense.
Undirected graphs, where edges connect two vertices equally, and focused therapy, where edges connect two vertices unevenly, are distinguished.
When the is made, there is the shaded area provided that is made due to intersection of lines and the area below the both the lines and the common that is said to be the shaded area.
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A population of values has a normal distribution with μ=189.2 and σ=83.2. a. Find the probability that a single randomly selected value is between 195.2 and 214.1. Round your answer to four decimal places. P(195.2
The probability that a single randomly selected value from a population with a normal distribution, where the mean (μ) is 189.2 and the standard deviation (σ) is 83.2, falls between 195.2 and 214.1 is approximately 0.1632.
To find the probability, we can standardize the values using the z-score formula: z = (x - μ) / σ, where x is the given value, μ is the mean, and σ is the standard deviation.
For 195.2:
z1 = (195.2 - 189.2) / 83.2 = 0.0721
For 214.1:
z2 = (214.1 - 189.2) / 83.2 = 0.2983
Using a standard normal distribution table or a calculator, we can find the area under the curve between these z-scores, which represents the probability:
P(195.2 < x < 214.1) = P(0.0721 < z < 0.2983) ≈ 0.1632
Therefore, the probability that a single randomly selected value falls between 195.2 and 214.1 is approximately 0.1632.
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Complete question is in the image attached below
Will give Brainliest if right
The value of x is 14 and the value of y is 7√3.
What are trigonometric ratios in terms of a right-angle triangle?We know a right-angled triangle has three sides they are -: Hypotenuse,
Opposite and Adjacent.
We can remember SOH CAH TOA which is,
sin = opposite/hypotenuse, cos = adjecen/hypotenuse and
tan = opposite/adjacent.
We know sin is opposite/hypotenuse
∴ sin30° = 7/x.
1/2 = 7/x.
x = 14.
We also know that tan is opposite/adjacent.
tan30° = 7/y.
1/√3 = 7/y.
y = 7√3.
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Put these in order starting from the smallest
6^2 3^4 2^9
5^3
Answer:
6^2, 3^4, 5^3, and 2^9
Step-by-step explanation:
6^2= 36
3^4= 81
5^3= 125
2^9= 512
Please help, it’s not college math!!
Answer: The first answer choice
AKA: y = -1.74x + 46.6
Step-by-step explanation:
given the following measures of the side of triangles, which is a right triangle?
Answer:
Step-by-step explanation:
Essentially, we can use the pythagorean rule that:
a^2+b^2=c^2
c^2 resembles the hypotenuse, which is almost always the largest number. therefore, we simply have to find two which equal the largest side:
9^2+40^2=41^2
81+1600=1681
1681=1681
Based on this math, A is our right angle!
Hope this helps!
If A = 5 and B = 3, what will be displayed when code corresponding to the following pseudocode is run? (In the answer options, new lines are separated by commas.)
Do
Write A^2
Set A = A - 1
While A >= B
The output when the given pseudocode is executed with A = 5 and B = 3 will be "25, 16, 9, 4, 1".
The given pseudocode includes a loop that iterates as long as A is greater than or equal to B. In each iteration, the square of A is displayed, and A is decremented by 1. We are asked to determine the output when A is initially 5 and B is 3.
Step 1: Initialization
A is set to 5 and B is set to 3.
Step 2: Iteration 1
Since A (5) is greater than or equal to B (3), the loop executes.
The square of A (5²) is displayed, resulting in the output "25".
A is decremented by 1, so A becomes 4.
Step 3: Iteration 2
A (4) is still greater than or equal to B (3).
The square of A (4²) is displayed, resulting in the output "16".
A is decremented by 1, so A becomes 3.
Step 4: Iteration 3
A (3) is still greater than or equal to B (3).
The square of A (3²) is displayed, resulting in the output "9".
A is decremented by 1, so A becomes 2.
Step 5: Iteration 4
A (2) is still greater than or equal to B (3).
The square of A (2²) is displayed, resulting in the output "4".
A is decremented by 1, so A becomes 1.
Step 6: Iteration 5
A (1) is still greater than or equal to B (3).
The square of A (1²) is displayed, resulting in the output "1".
A is decremented by 1, so A becomes 0.
Step 7: Loop termination
Since A (0) is no longer greater than or equal to B (3), the loop terminates.
Therefore, The output generated by the code execution will be "25, 16, 9, 4, 1" as the squares of A (starting from 5 and decreasing by 1) are displayed in each iteration of the loop.
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