2. What is the force of gravity between two 1000 kg cars separated by a distance of 20 m on a highway?Fg=r2Gm1m1Where G is the gravitational constant and r is the distance between the two objectsNow we can start plugging in the valuesG = 6.67 x 10^-11m1 = 1000 kgm2 = 1000 kgr = 20 mPlugging these into the equation yields us:Fg = 1.67 x 10^-7 N3. Using the force, calculated in # 2 above, and the weight of the car, calculate: Force (from #2) divided by the weight of car

Answer:

V = 10 km / 1 hr = 10 km/hr

V = -10 j km / hr   if one were to use i, j, k as unit vectors with the usual orientation

Answer & Explanation:

We can use the following equation to solve the problem:

a = -μk*g

where a is the acceleration, μk is the coefficient of kinetic friction, and g is the acceleration due to gravity (9.8 m/s2).

We are given that a = -9.5 m/s2. We can assume that g is constant and equal to 9.8 m/s2. Therefore, we can rearrange the equation to solve for μk:

μk = -a/g

μk = -(-9.5 m/s2) / 9.8 m/s2

μk = 0.969

Therefore, the coefficient of kinetic friction between the bicycle’s rubber tires and the wet concrete is 0.969.

At the apex of the trajectory, the ball's velocity and acceleration are u (10i+15j) m/s and zero

The initial velocity of the ball is u (10i+15j) m/s.

Velocity at the top of the trajectory: Since the ball is thrown with an initial velocity, it will reach the top of its trajectory with the same velocity, since there is no air resistance. Therefore, the velocity of the ball at the top of the trajectory is u (10i+15j) m/s.

Acceleration: The acceleration of the ball at the top of the trajectory is zero, since the ball is not accelerating (there is no acceleration due to air resistance).

Therefore, the velocity and acceleration of the ball at the top of the trajectory are u (10i+15j) m/s and zero, respectively.

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When describing motion, speed indicates the pace at which an object is travelling. It has one scalar component identifying its magnitude, irrespective of direction.

The unit for measuring speed can be either meters per second (m/s) or miles per hour (mph). For velocity, it's a different story. Its definition encompasses both speed and direction since it's a vector quantity. Measureable just like speed using m/s or mph.

In plain physic terms, acceleration reveals how much speed changes over time; hence it is also a vector quantity with not only size but also direction. Depending on whether a physical item is increasing in momentum, slowing down or static, the value could be positive, negative, or zero. Acceleration is calculated using units metres per second squared (m/s2).

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The net force on particle q₂, located between particles q₁ and q₃, is approximately 189000 N. The force exerted by particle q₁ on q₂ is positive and equals 252000 N, while the force exerted by particle q₃ on q₂ is negative and equals -63000 N.

To find the net force on particle q₂, we need to calculate the individual forces exerted on q₂ by particles q₁ and q₃ and then determine their sum.

The force between two charged particles can be calculated using Coulomb's law:

F = k * |q₁ * q₂| / r²

Where F is the force between the particles, k is the electrostatic constant (k ≈ 9.0 x \(10^9\) Nm²/C²), q₁ and q₂ are the charges of the particles, and r is the distance between them.

First, let's calculate the force exerted on q₂ by q₁:

F₁₂ = k * |q₁ * q₂| / r₁₂²

F₁₂ = (9.0 x \(10^9\) Nm²/C²) * |(8.0 μC) * (3.5 μC)| / (0.10 m)²

F₁₂ ≈ 252000 N

The force is positive because q₁ and q₂ have opposite charges.

Next, let's calculate the force exerted on q₂ by q₃:

F₂₃ = k * |q₂ * q₃| / r₂₃²

F₂₃ = (9.0 x \(10^9\)Nm²/C²) * |(3.5 μC) * (-2.5 μC)| / (0.15 m)²

F₂₃ ≈ -63000 N

The force is negative because q₂ and q₃ have the same charge.

Finally, we can find the net force on q₂ by summing the individual forces:

Net force = F₁₂ + F₂₃

Net force = 252000 N + (-63000 N)

Net force ≈ 189000 N

The net force on particle q₂ is approximately 189000 N.

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When two objects held close together and then released, they move toward each other. The phenomenon can be explained by the Coulomb's Law. Coulomb's Law is given by: $F=k\frac{q_{1}q_{2}}{r^2}$ where F is the electrostatic force, q1 and q2 are the magnitudes of the charges, r is the distance between the centers of the charged objects, and k is Coulomb's constant.

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Explanation:

Finding the (maximum) respective prime powers would yield the answer. Also we need not ... Is perfectly divisible by 720^n? ... So we can say that for any positive value of n it not divisible.

Answer:

1 is 3 -1

Explanation:

yan po ang tamang sagot thank you four gave thise answer thise if iam rong sorry i dont gate thinking

Answer:

The tax rate you will pay is displayed in tax brackets for each category of taxable income.

Thus, For instance, in 2022, the first $10,275 of your taxable income is subject to the lowest tax rate of 10% if you are single.

Up until the maximum amount of your taxable income, the following portion of your income is taxed at a rate of 12%.

As taxable income rises, the tax rate rises under the progressive tax system. Overall, this has the result that taxpayers with higher incomes often pay a greater rate of income tax than taxpayers with lower incomes.

Thus, The tax rate you will pay is displayed in tax brackets for each category of taxable income.

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The separation distance in B is a number times greater than in A, then the force of attraction in B is less than A.

The force of attraction between two charged object is determined by applying Coulomb's law.

Coulomb's law states that the force of attraction or repulsion between two charged objects is directly proportional to the product of the charges and inversely proportional to the square of the distance between the charges.

Mathematically, this law is written as;

F = Kq₁q₂/r²

where;

From the formula given above, as the distance of separation increases, the magnitude of the force of attraction between the charges decreases. Also, as the distance of separation between the charges decreases, the magnitude of the force of attraction between the charges increases.

Thus, the magnitude of the force of attraction between charged objects is a function of the magnitude of the charges and distance of separation between the charges.

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A) There are 3.70 x 10¹⁶ Cs nuclei present initially and B) There are 2.27 x 10¹⁵ Cs nuclei present 2.6 min later.

A) To solve this problem, we can use the following equation,

\(N = N'2^{\frac{-t}{T_{1/2}}}\)), number of Cs nuclei present is N, initial number of Cs nuclei present is N', elapsed time is t, half-life of Cs-124 is T½. First, we need to convert the initial mass of Cs-124 to the number of nuclei present,

7.5 μg Cs-124(1g/10⁶μg)(6.022x10²³nuclei/1g)

= 4.52 x 10¹⁵ Cs-124 nuclei.

Using the equation above, we can find the number of Cs-124 nuclei present after 0 s,

\(N = 4.52 * 10^{15} * 2^{\frac{-0}{30.8}}}\)

= 4.52 x 10¹⁵ Cs-124 nuclei

Therefore, initially, there are 4.52 x 10¹⁵ Cs-124 nuclei present.

B) After 2.6 min (156 s), we can again use the same radioactivity equation to find the number of Cs-124 nuclei present,

\(N = 4.52 * 10^{15} * 2^{\frac{-156}{30.8}}}\)

N = 1.60 x 10¹⁴ Cs-124 nuclei

Therefore, 2.6 min later, there are 1.60 x 10¹⁴ Cs-124 nuclei present.

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Answer:

Explanation:

1. First draw a free body diagram of the scenerio (a block sliding down a a slant surface).
2. Then we analyze the forces and write equations that satisfy Fnet = ma. This will give us the acceleration as the block slides down the surface.

3. Last, we can use the kinematic equation (vf^2 = vi^2 + 2as) and to solve the final speed of the block.

Answer:

A)  θ = 3.36 10⁻⁴ rad

B) y = 8.4 10⁻⁵ m

C)  θ = 3.36 10⁻⁴ rad

D) the correct answer is 1 the value found is close to the experimental one

E)  the size of the cells is the one that most limits the minimum size of the object that we can see.  

Explanation:

A) The Rayleigh criterion determines what is the size of two objects that can be resolved due to diffraction, it establishes that the bodies are resolved if the maximum diffraction of one coincides with the first minimum of diffraction of the other, based on this it is get

for a slit      θ = λ / D

for a circular aperture, solving in polar coordinates gives the expression

                  θ = 1.22 λ / D

in our case the diameter of the pupil is D = 2.00 mm = 0.002 m                    

they tell us to use lam = 550 nm

              θ = 1.22 550 10⁻⁹ / 0.002

              θ = 3.36 10⁻⁴ rad

The angle that the object covers is

           tan θ' = y / x

           θ' = tan⁻¹ (50 10⁻³/25 10⁻²)

           θ' = 0.197

Since the angle supported by the object is greater than the minimum angle, it is resolved or is visible

B) The smallest size of the visible or resolved object

           y = x tan θ

           y = 0.25 tan 3.36 10⁻⁴

           y = 8.4 10⁻⁵ m

C) θ = 3.36 10⁻⁴ rad

D)  θ_exp= 1 min

we reduce to degre

     θ_exp= 1 min (1 ° / 60 min) = 1/60 °

we reduce to radians

     θ_exp  = 1/60 ° (π rad / 180 °)

     θ_exp = 2.9 10⁻⁴ rad

When comparing these two values ​​the order of magnitude is the same, even though the real value is a little smaller.

the correct answer is 1 the value found is close to the experimental one

E) The angle supported by the size of the retinal cells is 0.197 rad calculated in part A

the angle of resolution by diffraction is 3.36 10⁻⁴ radians

When comparing these two values ​​we see that the size of the cells is the one that most limits the minimum size of the object that we can see.

Answer:

Parallax is a displacement or difference in the apparent position of an object viewed along two different lines of sight, and is measured by the angle or semi-angle of inclination between those two lines.

The change in surface area of Gaussian surface with radius (r) is 8πr.

The electric field experienced by a charge is calculated as follows;

\(E = \frac{Q}{4\pi \varepsilon_o r^2}\)

where;

The electric field reduces by a factor of \(\frac{1}{r^2}\)

The surface area of a sphere is given as;

\(A = 4\pi r^2\)

\(\frac{dA}{dr} = 8\pi r\)

Thus, the change in surface area of Gaussian surface with radius (r) is 8πr.

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Answer:

The average acceleration is about 8.51 m/s

Explanation:

     We can use the formula for acceleration to solve.

a = \(\frac{velocity_{final} -velocity_{start} }{time}\)

a =  \(\frac{80-0}{9.4}\)

a =  \(\frac{80}{9.4}\)

a ≈ 8.51

The direction of a magnetic field can be accurately described as flowing from the north pole to the south pole,

When considering the idea of a magnetic dipole, it involves having two magnetic poles that possess equal strength but differ in polarity. This particular configuration results in the creation of a magnetic field that flows from the north to south pole. The magnitude of this field is determined by the size of the magnetic dipole moment, which serves as a distinctive quality of the magnet.

The idea of a magnetic field pertains to a specific region in space that can exert magnetic force on either a magnet or a charged particle in motion. The orientation of the magnetic field lines indicates the direction of the force that would affect any magnetic object within the field. It's important to note that these lines always form closed loops, originating from the north pole of the magnet and extending through surrounding space before ultimately returning to enter at its south pole. This implies that without fail, magnetic field lines travel from north to south pole, with this directional flow being reliant on the magnet's magnetic dipole moment.

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Answer:

7.7 km 26°

Explanation:

The total x component is:

x = 2.5 cos(35°) + 5.2 cos(22°) = 6.87

The total y component is:

y = 2.5 sin(35°) + 5.2 sin(22°) = 3.38

The magnitude is:

d = √(x² + y²)

d = 7.7 km

The direction is:

θ = atan(y/x)

θ = 26°

Answer:

The value is  \(k = 51.34 \ N/ m\)

Explanation:

From the question we are told that

   The  mass is  \(m = 1.3 \ kg\)

   The needed oscillation time is  \(T = 1 \ s\)  

 Generally the spring constant is mathematically represented  as

         \(k = \frac{4 \pi^2 * m }{ T^2}\)

=>      \(k = \frac{4* 3.142^2 * 1.3 }{ 1^2}\)

=>      \(k = 51.34 \ N/ m\)

Answer:

1960 joule

Explanation:

Given data

*The given speed of the car is u = 4.4 m/s

*The given acceleration of the car is

*The given time is t = 5.4 s

The formula for the final speed of the car is given as

Substitute the known values in the above expression as

Hence, the final speed of the car is 7.80 m/s

Answer:

Explanation:

according to the graph at B the potential energy of the particle is 2J

therefore we can use the kinetic energy equation to calculate the particle's velocity or speed.

\(E_{k} =1/2mv^{2}\)

2J= 1/2*1/2kg*v^2

8=v^2

v= 2√2 ms-1

The tangential acceleration of the short player's ball is twice the tangential acceleration of the tall player's ball.

The ball of the shorter player experiences twofold of the ball of the taller player's tangential acceleration. The reason behind this is that the magnitude of the tangential acceleration correlates directly with the radius of the circle.

The ball belonging to the smaller player is positioned nearer to the elbow, resulting in a decreased radius. It can be deduced from this statement that the ball of the short player experiences twice the magnitude of tangential acceleration compared to the ball of the tall player.

The answer is: ashort = 2atall

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The Complete Question

A short tennis player hits a ball that is r meters from their elbow with an angular acceleration a. A tall tennis player hits a ball with the same angular acceleration where the ball is 2r from their elbow. How does the tangential acceleration of the short player's ball Ashort compare with the tall player's ball a tall? Choose 1 answer: ashort 2atall ashort Otall ashort 1 atall 2

The de- Broglie wavelength of 2.80× 10⁻¹⁰ m is associated with a momentum of 2.36 × 10⁻²⁴ Kg m/s. The kinetic energy will be 3.07 × 10⁻¹⁸ J which is equal to 19.015 ev.

De-Broglie proposed  the dual nature of matter which stated that matter can behave as both wave and particle. For a matter wave, the wavelength of the wave will be the ratio of the Planck's' constant h and its momentum p.

thus, λ = h/p

Given the wavelength = 2.80× 10⁻¹⁰ m.

momentum p = h/λ

= 6.62 × 10 ⁻³⁴ / (2.80× 10⁻¹⁰ m)

=  2.36 × 10⁻²⁴ Kg m/s

The kinetic energy ke = 1/2 mv² = p² /2m.

mass of an electron = 9.1 × 10 ⁻³⁴ Kg.

hence, Ke =  (2.36 × 10⁻²⁴ Kg m/s )² /  9.1 × 10 ⁻³⁴ Kg

                 = 3.07 × 10⁻¹⁸  J.

1 J = 6.24 × 10¹⁸ ev.

thus, KE in ev = 3.07 × 10⁻¹⁸  J ×  6.24 × 10¹⁸ ev = 19 ev.

Therefore, the kinetic energy of the electron is 19 ev.

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Explanation:

We need to add 28.97 and 45.876.

Here, the first no is 28.97 and other no is 45.876

Here, 28.97 is the least precise value and 45.876 is most precise.

28.97 + 45.876 = 74.846

We need to write the final answer such that there is two digit after the decimal. So, 28.97 + 45.876 = 74.85 because 6 is more than 5 i.e. we add 1 to 4.

Answer:

 28.97

+ 45.876

 74.846

Explanation:

Because 28.97 has only two decimal places, round off the answer to two decimal places: 74.85.

The velocity of particle 2 when it is 1cm away from particle 1 is determined as 62.18 m/s.

The electrostatic force between the two charges is calculated as follows;

F = (kq1q2)/(r²)

F = (9 x 10⁹ x 4.5 x 10⁻⁶ x 3.1 x 10⁻⁶)/(0.037)²

F = 91.71 N

F = ma

a = F/m

a = (91.71 N)/(0.0069 kg)

a = 13,291.2 m/s²

v² = u² + 2as

v² = 60² + 2(13,291.2)(0.01)

v² = 3865.82

v = 62.18 m/s

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Answer: Hope this helps ;) don't forget to rate this answer !

Explanation:

There are two correct answers:

A) A corporation leader makes direct payment to the candidate.

D) A corporation contributes to a Super PAC that a PAC accepts contributions for a candidate.

Option A describes a scenario where a corporation directly donates money to a presidential candidate, which is allowed as long as it is done within the limits set by campaign finance laws.

Option D describes a scenario where a corporation donates money to a Super PAC, which is a type of political action committee that can accept unlimited donations from individuals, corporations, and other organizations. The Super PAC can then use the money to support or oppose a particular candidate, but it is not allowed to coordinate directly with the candidate or the candidate's campaign.

I hope this helps! Let me know if you have any other questions.

A wire perpendicular to the screen carries a current and then the direction of the magnetic field at point Z is upward

To determine the direction of the magnetic field at point Z, we need to apply the right-hand rule for current-carrying wires. The right-hand rule states that if you point your right thumb in the direction of the current flow, then the direction in which your fingers curl represents the direction of the magnetic field around the wire.

In the given scenario, the wire is perpendicular to the screen, and the current is flowing in the direction shown by the arrow (from left to right). To determine the magnetic field at point Z, we can imagine wrapping our right hand around the wire such that our fingers curl in the direction of the current (from left to right). When we do this, our thumb points in the upward direction.

Therefore, the direction of the magnetic field at point Z is upward. This means that the magnetic field lines around the wire at point Z are oriented in a counterclockwise direction when viewed from above the screen.

It's important to note that the direction of the magnetic field depends on the direction of the current flow. If the current were flowing in the opposite direction (from right to left), the direction of the magnetic field at point Z would be downward.

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Answer:

Electric and gravitational forces have many similar features because they follow idenitical mathematical formulas. In particular, Charge in electricity plays the equivalent role of mass in gravity, while electric field, plays a role corresponding to free-fall acceleration. Because of this kinematics describing projectiles in gravity would carry over to electricity, but the main difference is that in electricity we have positive and negative charges, while in gravity mass is always positive, which means gravity is always attractive, but electricity could be attractive and repulsive.

Explanation:

The formulas of Electric and gravitational fields are as follow

Electric Field

F(electric)=kq1q2/r^2

Gravitationlal Fieeld

F(grav)=GMm/r^2

As you see both follow the inverse square law in the formula

Both of these act between two bodies without having any contact. The gravitational field acts on the mass of an object Whereas the electric field acts on the charge.

The gravitational field can only attractive while the electric field can be attractive or repulsive.

Normally electric field is stronger than the gravitational field.

In particular, Charge in electricity plays the equivalent role of mass in gravity, while electric field,

Newton's law of gravity states that each particle having mass in the universe attracts each other particle with a force known as the gravitational force.

Gravitational force is proportional to the product of the masses of the two bodies and inversely proportional to the square of their distance.

Electric and gravitational forces have many similar features because they follow identical mathematical formulas.

In particular, Charge in electricity plays the equivalent role of mass in gravity, while electric field,

Plays a role corresponding to free-fall acceleration. Because of these kinematics describing projectiles in gravity would carry over to electricity,

but the main difference is that in electricity we have positive and negative charges, while in gravity mass is always positive,

which means gravity is always attractive, but electricity could be attractive and repulsive.

Hence, in particular, Charge in electricity plays the equivalent role of mass in gravity, while electric field,

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