Energy can be transferred from one _______ to another and one __________ to another. *
Answer:
Source, form
Explanation:
Answer:
Explanation:
Energy can be transferred from one _source_ to another and one __form____ to another.
earth energy budget is the relationship between how much energy the earth _______ and energy the earth _________
earth energy budget is the relationship between how much energy the earth receive from the sun and energy the earth radiates out.
What is energy?Energy is described as the quantitative property that is displaced to a body or to a physical system, recognizable in the performance of work and in the form of heat and light.
The term earth's energy budget is also described as the balance between of the amount of energy, that gets to the earth. from the Sun and the energy that leaves Earth and returns to the universe.
The earth's energy budget was mainly three types as shown:
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A motorcycle, travelling cast, starts from rest, moves in a straight line with a constant acceleration and covers a distance of 64 m in 4 s.Calculate a) Its acceleration b) Its final velocity c) At what time the motorcycle had covered half the total distance d) What distance the motorcycle had covered in half the total time.
The motorcycle had covered a distance of 16 meters in half the total time.
a) To calculate the acceleration, we can use the formula:
a = (v - u) / t
where a is the acceleration, v is the final velocity, u is the initial velocity (which is 0 since the motorcycle starts from rest), and t is the time.
Given:
u = 0 m/s (initial velocity)
v = ? (final velocity)
t = 4 s (time)
s = 64 m (distance)
Using the equation of motion:
s = ut + 1/2at^2
We can rearrange the equation to solve for acceleration:
a = 2s / t^2
a = 2(64) / (4)^2
a = 128 / 16
a = 8 m/s^2
Therefore, the acceleration of the motorcycle is 8 m/s^2.
b) To find the final velocity, we can use the formula:
v = u + at
v = 0 + (8)(4)
v = 32 m/s
Therefore, the final velocity of the motorcycle is 32 m/s.
c) To determine the time at which the motorcycle had covered half the total distance, we divide the total distance by 2 and use the formula:
s = ut + 1/2at^2
32 = 0 + 1/2(8)t^2
16 = 4t^2
t^2 = 4
t = 2 s
Therefore, the motorcycle had covered half the total distance at 2 seconds.
d) To calculate the distance covered in half the total time, we use the formula:
s = ut + 1/2at^2
s = 0 + 1/2(8)(2)^2
s = 0 + 1/2(8)(4)
s = 0 + 16
s = 16 m
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Which of the following describes the transformation of chemical energy to heat energy?
A.plugging in a blow dryer
B.making toast in a toaster
C.a rock hitting the ground
D.wood burning in a fireplace
Answer:
Burning wood in a fireplace
Explanation:
In a DC generator, the generated emf is directly proportional to the
In a DC generator, the generated electromotive force (emf) is directly proportional to the rotational speed of the generator's armature and the strength of the magnetic field within the generator.
This relationship is described by the equation for the generated emf in a DC generator:
Emf = Φ * N * A * Z / 60
Where:
Emf is the generated electromotive force (in volts),
Φ is the magnetic flux density (in Weber/meter^2\(meter^2\) or Tesla),
N is the number of turns in the armature winding,
A is the effective area of the armature coil (in square meters),
Z is the total number of armature conductors, and
60 is a constant representing the conversion from seconds to minutes.
From this equation, we can see that the generated emf is directly proportional to the magnetic flux density (Φ) and the product of the number of turns (N), effective area (A), and the total number of armature conductors (Z). This means that increasing any of these factors will result in a higher generated emf.
The magnetic flux density (Φ) can be increased by using stronger permanent magnets or increasing the strength of the field windings in the generator.
The number of turns (N) and the effective area (A) are design parameters and can be optimized for a specific generator. Increasing the number of turns or the effective area will result in a higher generated emf.
Similarly, the total number of armature conductors (Z) can be increased to enhance the generated emf.
By controlling and optimizing these factors, the generated emf in a DC generator can be increased, resulting in higher electrical output. However, it is important to note that there are practical limits to these factors based on the design and construction of the generator.
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an object is moving on a horizontal frictionless surface. if the net force applied to the object in the direction of motion is doubled, the magnitude of the acceleration of the object is
1. halved
2. doubled
3. unchanged
4. quadrupled
If a loading ramp is placed next to a truck, at a height of 4 feet, and the ramp is 13 feet long, what angle does the ramp make with the ground extending from the ramp to the truck? (Round your answer to one decimal place.)
Answer:
The angle that the ramp makes with the ground extending from the ramp to the truck is approximately 17.5 degrees.
Explanation:
We can start by drawing a right triangle where the hypotenuse is the ramp, the height is 4 feet, and the base is the distance from the truck to the bottom of the ramp (the horizontal distance).
Since we know the length of the hypotenuse and the height of the triangle, we can use the sine function to find the measure of the angle:
sin(θ) = opposite/hypotenuse
sin(θ) = 4/13
Now, we can solve for θ by taking the inverse sine (sin^-1) of both sides:
θ = sin^-1(4/13)
Using a calculator, we get:
θ ≈ 17.5 degrees
Which has more kinetic energy:
a. A compact car going 70 MPH or a tractor trailer going 15 MPH?
b. An SUV going 30 MPH or a pickup truck going 30 MPH?
c. A school bus going 15 MPH, an SUV going 35 MPH, or a
compact car going 45 MPH?
Answer:
Explanation:
a. The compact car going 70 MPH has more kinetic energy than the tractor trailer going 15 MPH. Kinetic energy is proportional to the square of the velocity, so even though the tractor trailer may have more mass, the higher velocity of the compact car results in greater kinetic energy.
b. The SUV and the pickup truck have the same kinetic energy since they have the same mass and velocity.
c. The compact car going 45 MPH has the most kinetic energy since it has the highest velocity out of the three vehicles. The SUV going 35 MPH has less kinetic energy, and the school bus going 15 MPH has the least kinetic energy.
a radio station broadcast a frequency 90500 Hz. these radio waves travel at speed of 30000 m/s. what is the wavelength of the radio waves
Answer:
0.331m
Explanation:
wave equation: v=f λ
v=30000m/s
f=90500 Hz
λ= \(\frac{v}{f}\)
λ= \(\frac{30000}{90500}\)
λ= 0.311m
Six identical cells with an EDS of 3 V connected in a battery. Resistors R₁ and R₂=16Ω are connected to the battery, the total resistance of the external circuit is R=6Ω and the current flowing in it is 1 A. Determine the resistance of the first resistor and the EDS and internal resistance of the battery.
- The resistance of the first resistor (R₁) is 12 Ω.
- The electromotive force (EMF) of the battery is 18 V.
- The internal resistance of the battery is 12 Ω.
To solve the given problem, we can apply Kirchhoff's laws and Ohm's law to determine the resistance of the first resistor (R₁) and the electromotive force (EMF) and internal resistance of the battery.
Let's start by calculating the resistance of the first resistor (R₁):
1. Apply Ohm's law to find the voltage drop across the external circuit:
V = I * R
V = 1 A * 6 Ω
V = 6 V
2. The voltage drop across the external circuit is equal to the EMF minus the voltage drop across the internal resistance of the battery:
V = E - Ir
6 V = E - (1 A * r) (where r is the internal resistance of the battery)
3. We also know that the EMF of the battery is the sum of the voltage drops across each cell in the battery:
E = 6 cells * 3 V/cell
E = 18 V
4. Substitute the value of E in the equation from step 2:
6 V = 18 V - r
r = 12 Ω
Therefore, the resistance of the first resistor (R₁) is 12 Ω.
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In physics, a system is defined as the portion of the universe that has been chosen for study. Systems may be complex, such as a whole planet, or simple, such as the water inside a pot. The universe outside the system is called the surroundings. A closed system is one that does not exchange matter with its surroundings and does not experience any outside forces. An open system, on the other hand, can exchange matter with its surroundings and does experience outside forces.
The idea of systems and surroundings was not always part of physics. In 1824, the French physicist Nicolas Carnot applied the idea of systems to thermodynamics. A little later, German physicist Rudolf Clausius added the idea of surroundings. Today, system and surroundings are terms applied also to mechanical systems, as well as used in other scientific fields such as biology.
Examples of open systems are common in everyday life. A car driving down a road is a system. The car engine produces exhaust, which is matter passed to its surroundings. Friction between the car and the road is an outside force that acts on the system. Closed systems are rare in everyday life. They are commonly used in physics laboratories to simplify system analysis and calculations.
So, what questions can help someone decide whether the system under consideration is open or closed? The first question to ask is: Does the system exchange matter with its surroundings? If yes, it is an open system. If no, it is a closed system. The second question is: What is the source of the forces experienced by the system? If all forces originate within the system, the system is closed. If forces act on the system from outside of the system, it is an open system.
QUESTION 1
A student has chosen to study a swinging pendulum. The pendulum would be ____________.
OPTIONS
a system
the surroundings
a universe
a force
QUESTION 2
Which of the following statements describes a closed system?
OPTIONS
It exchanges matter with its surroundings.
Its surroundings act on the system.
It experiences only forces originating from within.
None of the above
QUESTION 3
Which of the following statements about cars indicates that they are an open system?
OPTIONS
Friction is present between different parts of the engine.
The car burns gasoline and produces exhaust.
The engine heats up as the car is driven.
The faster the car is driven, the faster its tires turn.
QUESTION 4
What is the most common use of closed systems?
OPTIONS
To minimize environmental damage
To create more efficient systems
To simplify system analysis
To predict system structure and behavior
QUESTION 5
Which of the following questions is important for deciding whether a system is open or closed?
OPTIONS
Does the system exchange matter with its surroundings?
Is the system composed of multiple parts?
Does the system contain more than one state of matter?
Is the system natural or man-made?
The pendulum would be a system. The statements describes a closed system is "It experiences only forces originating from within". The most common use of closed systems is to simplify system analysis
The pendulum would be a systemThe statements describes a closed system is the it experiences only forces originating from withinThe statement that indicates that the car is an open system is that the car burns gasoline and produces exhaustThe most common use of closed systems is to simplify system analysisTo decide whether a system is open or closed, the important question will be "Does the system exchange matter with its surroundings?"A closed system is one that does not exchange matter with its surroundings and does not experience any outside forces. An open system, on the other hand, can exchange matter with its surroundings and does experience outside forces
Therefore, the correct options are
A systemIt experiences only forces originating from withinThe car burns gasoline and produces exhaustTo simplify system analysisDoes the system exchange matter with its surroundings?To know more about open and closed system
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Match the following wave to the correct wave type. **You may use some answers more than once and some not at all*
The following are the correct matches for the waves in Column A and the wave types in Column B:
A - d. mechanical wave - longitudinalB - b. electromagnetic waveC - a. mechanical wave - transverseD - e. spring waveWhat are the wave types?A mechanical wave is a wave that requires a medium to travel through. The two types of mechanical waves are transverse waves and longitudinal waves. A transverse wave is a wave in which the particles of the medium move perpendicular to the direction of the wave. A longitudinal wave is a wave in which the particles of the medium move parallel to the direction of the wave.
An electromagnetic wave is a wave that does not require a medium to travel through. Electromagnetic waves are made up of electric and magnetic fields that oscillate perpendicular to each other.
A matter wave is a wave that describes the probability of finding a particle at a given location. Matter waves are associated with all particles, including electrons, protons, and neutrons.
A spring wave is a type of mechanical wave that travels through a spring. The particles of the spring move back and forth along the length of the spring.
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What is evidence used by Galileo to disprove Aristotle and Ptolemy?
Galileo challenged the Aristotelian-Ptolemaic model, providing support for the heliocentric model and paving the way for a new understanding of the universe.
Galileo Galilei played a crucial role in challenging the prevailing geocentric model of the universe proposed by Aristotle and supported by Ptolemy. He provided several lines of evidence that effectively disproved their theories and supported the heliocentric model proposed by Nicolaus Copernicus. Some of the key evidence used by Galileo includes:
1. Observations through a telescope: Galileo was one of the first astronomers to use a telescope to observe the heavens. His telescopic observations revealed several important discoveries that contradicted the Aristotelian-Ptolemaic worldview. He observed the phases of Venus, which demonstrated that Venus orbits the Sun and not Earth. He also observed the four largest moons of Jupiter, now known as the Galilean moons, which provided evidence for celestial bodies orbiting a planet other than Earth.
2. Sunspots: Galileo's observations of sunspots provided evidence that the Sun is not a perfect celestial body, as suggested by Aristotle. Sunspots indicated that the Sun has imperfections and undergoes changes, challenging the notion of celestial perfection.
3. Mountains on the Moon: Galileo observed the rugged and uneven surface of the Moon, which contradicted Aristotle's belief in celestial spheres made of perfect, unchanging material. The presence of mountains on the Moon suggested that celestial bodies are subject to the same physical laws as Earth.
4. Phases of Venus: Galileo's observations of the phases of Venus provided direct evidence for the heliocentric model. As Venus orbits the Sun, it goes through phases similar to the Moon, ranging from crescent to full. This observation strongly supported the idea that Venus revolves around the Sun.
These lines of evidence presented by Galileo challenged the Aristotelian-Ptolemaic model, providing support for the heliocentric model and paving the way for a new understanding of the universe. His work marked a significant turning point in the history of science and laid the foundation for modern astronomy.
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Which shows evidence of active transport?
A scientist places four identical cells into four different
liquids, each with different concentrations of magnesiuni.
Celll
w
Description of Liquid
Slightly more magnesium than the
cell
The least amount of magnesium
O
O
O
O
cells W and Z
cell W only
cell Y only
cells X and Y
Result
Took in
magnesium
Took in
magnesium
Took in
magnesium
Took in
magnesium
Slightly less magnesium than the
cell
The most amount of magnesium
Answer: D
X and Y
Explanation:
X The least amount of magnesium Took in magnesium
Y Slightly less magnesium than the cell Took in magnesium
Because active transport occurs when ions or molecules move from less concentration region to high concentration region through semi membrane with the help of some energy.
Answer:
Cells X and Y
Explanation:
Active transport occurs when a substance moves across a membrane against its concentration gradient.
Cells W and Z were placed in a liquid containing more magnesium than the cells. Magnesium therefore, diffuses passively down it's concentration gradient into the cells.
However, cells X and Y were placed in a solution containing less magnesium than the cells, yet these cells took in magnesium against this concentration gradient. This, shows that active transport had taken place.
what are 2 advantages to using a pulley to do work
Answer:
reduces the amount of force necessary for lifting heavy items and it redistributes the direction of the force that's necessary to lift the heavy items
A boy starts at rest and slides down a frictionless slide as in the figure below. The bottom of the track is a height h above the ground. The boy then leaves the track horizontally, striking the ground a distance d as shown. Using energy methods, determine the initial height H of the boy in terms of h and d.
The initial height H of the boy can be determined by adding the height of the slide h and the horizontal distance d the boy travels after leaving the track: H = h + d.
To determine the initial height H of the boy in terms of h and d, we can use the principle of conservation of energy. The total mechanical energy of the system remains constant throughout the motion.
At the top of the slide, the boy has gravitational potential energy given by mgh, where m is the mass of the boy, g is the acceleration due to gravity, and h is the height of the slide above the ground.
As the boy slides down the slide, there is no friction or other dissipative forces, so there is no change in mechanical energy. At the bottom of the track, the gravitational potential energy is converted entirely into kinetic energy.
Therefore, we can equate the initial potential energy to the final kinetic energy:
mgh = 1/2 m\(v^{2}\),
where v is the horizontal velocity of the boy when he leaves the track.
Since the boy leaves the track horizontally, the vertical component of his velocity is zero. Therefore, we can use the relationship between horizontal distance d and horizontal velocity v:
d = vt.
Solving these equations, we can express the initial height H in terms of h and d:
H = h + d.
So the initial height H of the boy can be determined by adding the height of the slide h and the horizontal distance d the boy travels after leaving the track.G
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which quanities are scalars
Answer:
they are quantities with magnitude without direction e.g weight,
A brass measuring tape is correct at 20°C. The value obtained when the length of a field is measured with the rule at 50°C appears to be 70.5 m. What is the true length of the field? Linear expansivity of brass = 1.8 x 10-5 K-1.
The true length of the field is 70.538 m.
What is the true length of the field?
The length of the field is calculated by applying the following formula;
ΔL = L₀αΔθ
where;
L₀ is the original lengthΔL is the change in lengthΔθ is the change in temperatureα is the linear expansivityThe change in the length of the field is calculated as;
ΔL = 70.5 x ( 1.8 x 10⁻⁵ ) x ( 50 - 20 )
ΔL = 0.038 m
The true length of the field = 70.5 m + 0.038 m = 70.538 m
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A car has a mass of 900 kg is accelerated from rest at a rate of 1.2 m/s calculate the time taken to reach 30/s
Answer:
12+2=24+30+2=66
Explanation:
In adolescence, friendships become less interethnic. Why might this be? Did this hold true for you in adolescence
Answer:
hi-
Explanation:
During the early teenage years, friendships become more intense, close and supportive. The amount that teenagers communicate with their friends increases. Teenage friendships tend to be based on personal similarity, acceptance and sharing. Same gender friendships are most common during the early high school years.
A cannonball is fired horizontally from the top of a cliff. The cannon is at height H = 55.5 m above ground level, and the ball is fired with initial horizontal speed . The projectile lands at a distance D = 140 m from the cliff. Assume that the cannon is fired at time t = 0 and that the cannonball hits the ground at time . a. What is the value of ? b. What is the y position of the cannonball at the time c. Find the initial speed of the projectile.
a) The value of t u = 140/t`b.
b) The y position of the cannonball at the time t is 55.5 mc.
c) The initial speed of the projectile is 52.4 m/s.
Given that a cannonball is fired horizontally from the top of a cliff. The cannon is at height H = 55.5 m above ground level, and the ball is fired with initial horizontal speed u. The projectile lands at a distance D = 140 m from the cliff. Assume that the cannon is fired at time t = 0 and that the cannonball hits the ground at time t.Now,We have to find the value of t, y position of the cannonball at the time t and the initial speed of the projectile.
a. To find the value of t:Here, we have to use the formula of distance
i.e.,S = ut + (1/2)gt², Where S = 140 m, u = u and g = 9.8 m/s².Hence,140 = u×t ………..(1)We know that, time taken by the cannonball to hit the ground can be calculated as,`(2H)/g`
Since the height of the cannon from the ground is 55.5m, the total height of the cannonball from the ground is
(2H) = 2 × 55.5
= 111 m`2H/g
= 111/9.8`
= 11.32653 s
From equation (1),u×t = 140u = 140/t
Therefore, `u = 140/t`b.
b)To find the y position of the cannonball at the time t:
Here, we have to use the formula of height i.e.,y = u×t – (1/2)gt²,
Where, y = height of the cannonball at time t, u = 140/t, t = time taken by the cannonball to hit the ground and g = 9.8 m/s².
We have already calculated the time taken by the cannonball to hit the ground in the previous step.`
y = 140 - (1/2) × 9.8 × t²`
On substituting the value of t as `t = 11.32653`,
we get,y = 140 - (1/2) × 9.8 × (11.32653)²= 55.5 mc.
c) To find the initial speed of the projectile:
To calculate the initial speed of the projectile, we need to use the formula of range of projectile
.i.e.,R = u²sin2θ/g
Where R = 140 m, g = 9.8 m/s², θ = 0° (horizontal)
u² = R × g/sin2θ
= 140 × 9.8/sin0°
= 2744m²/s²u
= \(\sqrt(2744m^2/s^2)\)
= 52.4 m/s
Hence, the initial speed of the projectile is 52.4 m/s.
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The footballer kicked the ball and it was caught by the opposing goalkeeper, 4 metres above the ground. The ball was travelling at 10 m s¹. (1) Calculate the potential energy of the ball just before it was caught.
1) Potential energy of the ball just before the kick was taken = 0J
2) The potential energy of the ball just before it was caught = 58.8 J
Explanation:1)Since the height of the ball is 0m on the ground, the potential energy of the ball just before the kick was taken is 0 J
2) The mass of the ball, m = 1.5 kg
Acceleration due to gravity, g = 9.8 m/s^2
the height of the ball, h = 4 m
The Potential Energy = mgh
The potential energy of the ball just before it was caught = 1.5 x 9.8 x 4
The potential energy of the ball just before it was caught = 58.8 J
15 POINTSSS PLS ANSWER
Why can't you determine the EXACT age of a layer of rock by simply observing fossils in a rock layer? What constraints you in making this determination?
To determine the exact age of a layer of rock, geologists typically use radiometric dating techniques such as measuring the decay of radioactive isotopes in rocks.
Why can't you determine the EXACT age of a layer of rock by simply observing fossils in a rock layer?While fossils found within a layer of rock can provide important clues about the age of the rock, they cannot determine the exact age of the layer with precision.
This is because the fossil record is incomplete and fossils found in a layer of rock are unlikely to represent all species that existed during a particular time period.
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(100 POINTS AND BRAINLIEST)
Atoms form chemical bonds using:
a. electrons in the innermost energy level
b. electrons in the outermost energy level
c. protons and electrons
Answer:
electron in the outermost
Explanation:
These are the electrons available for bonding or transfer
protons do are not involved in actual bonding
Answer:
b
Explanation:
Atoms form chemical bonds using electrons in the outermost energy level, otherwise known as valence electrons.
For atoms to bond, they must either gain or lose electrons.
By gaining electrons, the atom attains a negative charge.
By losing electrons, the atom attains a positive charge.
Samir is waiting for a slow reaction to finish. What is the best way to make the reaction go faster?
Question 12 options:
Put it in the fridge where it is cold
Cover it with a blanket so it's dark
Warm it up on the stove
There is nothing you can do to change the speed of the reaction
In general, option c - warming it up on the stove - is often an effective method to increase the reaction rate.
Increasing the temperature of a reaction generally leads to faster reaction rates. This is because higher temperatures provide more thermal energy to the reactant particles, causing them to move faster and collide more frequently. The increased collision frequency and energy lead to more successful collisions and a higher likelihood of effective molecular interactions, which speeds up the reaction. On the other hand, options a and b - putting it in the fridge where it is cold or covering it with a blanket to make it dark - are unlikely to have a significant effect on the reaction rate. While temperature can influence reaction rates, cooling the reaction or making it dark typically reduces the kinetic energy of the particles, resulting in slower reaction rates. Option d - there is nothing you can do to change the speed of the reaction - is not accurate. The reaction rate can be influenced by various factors such as temperature, concentration, catalysts, and surface area, among others. By manipulating these factors, it is often possible to control and change the speed of a reaction. Hence option c, is correct
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What type of circuit is shown
=When three resistors are connected in parallel, they form a parallel circuit. In a parallel circuit, each resistor is connected across the same two points, with the current split between the resistors.
In this configuration, the voltage across each resistor is the same, but the current through each resistor can be different. The total resistance of the circuit is calculated using the equation:
1/R_total = 1/R1 + 1/R2 + 1/R3
where R1, R2, and R3 are the resistance values of the individual resistors.
The total current in the circuit is equal to the sum of the currents through each resistor:
I_total = I1 + I2 + I3
where I1, I2, and I3 are the currents through each resistor.
The total power dissipated in the circuit can be calculated using the equation:
P_total = V² / R_total
where V is the voltage across the resistors.
In summary, when three resistors are connected in parallel, they form a parallel circuit, with each resistor connected across the same two points, and the current split between them. The total resistance, current, and power dissipated in the circuit can be calculated using the equations provided.
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Who will create a greater pressure, a heavy person standing on a bed or a lighter person lying on the bed? Explain your answer.
Answer:
a heavy person standing on a bed
Explanation:
The heavy person will have more mass than the lighter person, so they will create greater pressure.
How much heat energy must be added to a 7.6- cm -diameter copper sphere to raise its temperature from -50 ∘C to 190 ∘C ?
Answer:
V = 4/3 π R^3 = 4/3 π 3.8^3 = 230 cm^3
M = ρ V = 8.89 g/cm^3 * 230 cm^3 = 2045 g
ΔQ = C M ΔT = .093 cal /g deg C * 2045 g * 240 deg C
ΔQ = 45,640 cal
TRUE OR FALSE
2 QUESTIONS
NEED HELP ASAP
THX :)
LOTS OF POINTS :>
Answer: Both False
Explanation:
Our Milky Way Galaxy is a spiral galaxy. Some spiral galaxies are what we call "barred spirals" because the central bulge looks elongated
Irregualuar glaxyices are all over the place
Water flows through a cylindrical pipe of varying cross-section. The velocity is 3.0 m/s at a point where the pipe diameter is 1.0 cm. What is the flow rate R
Answer:
The flow rate is \(R =2.357 *10^{-4} \ m^3/s\)
Explanation:
From the question we are told that
The velocity is \(v = 3.0 \ m/s\)
The diameter of the pipe is \(d = 1.0 \ cm = 0.01 \ m\)
The radius of the pipe is mathematically represented as
\(r = \frac{d}{2}\)
substituting values
\(r = \frac{0.01}{2}\)
\(r = 0.005 \ m\)
The flow rate is mathematically represented as
\(R = v * A\)
Where is the cross-sectional area of the pipe which is mathematically evaluated as
\(A = \pi r^2\)
substituting values
\(A = 3.142 * (0.005)^2\)
\(A = 7.855 * 10^{-5} \ m^2\)
So
\(R = 3.0 * 7.855 *10^{-5}\)
\(R = 2.357*10^{-4} \ m^3 /s\)