2.) _____ is the measurement of kinetic energy (1 point)

\(\lambda=\frac{v}{f}=\frac{400}{200}=2[m]\)

Answer:

ELECTRONICS

Explanation:

Answer:

Technological

Explanation:

Answer:

cc

Explanation:

Answer:

1/5 km/min

Explanation:

the formula for velocity is distance/time

so if i plug in the distance and time i get 5/25 or 1/5

Hope this helps!

The frequency of a wave is the speed of the wave divided by its wavelength. The frequency of the wave travelling through at 2.6 m/s with the wavelength of 1.3 meters is 2 Hz.

Frequency of a wave is the number of wave cycles travelling per unit time. It is the inverse of the time period thus has the unit of s⁻¹ which is equivalent to the unit Hz.

The frequency of a wave is inversely proportional to the wavelength of the wave. The speed of the wave is related to its frequency and wavelength as:

c = νλ

given, c = 2.6 m/s

wavelength, λ = 1.3 m.

then, frequency ν = c/λ

ν  = 2.6 m/s / 1.3 m

   = 2 Hz.

Therefore, the frequency of the wave is 2 Hz.

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Answer:

375J of wasted energy

Explanation:

Efficiency=work output/work input×100%

50=w.o/750×100

750×50=100w.o

w.o=750×50/100

w.o=75×5

w.o=375J

Wasted energy=750J-375J

=375J

Aliter

If the machine is 50% efficient then it is also 50% inefficient

50%×750J=375J

To determine the mass enclosed within a radius of 25 kiloparsecs (kpc) in a spiral galaxy, additional information is needed, such as the rotation curve or the distribution of mass within the galaxy. Without this information, it is not possible to calculate the mass accurately.

The rotational speed of the gas in the disk of a spiral galaxy can provide insights into the overall mass distribution, but to determine the enclosed mass, the specific mass profile or the gravitational forces at different radii are required. A full understanding of the galaxy's mass distribution, including the contributions from visible matter (stars, gas) and dark matter, is necessary for accurate calculations.

Without more details or assumptions about the galaxy's mass distribution, it is not possible to determine the mass enclosed within a specific radius.

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Answer:

The height of the apple from the ground is at 49552.61071 m or is approximately at 5.0 × 10 m

Explanation:

The type of galaxy that has a stellar disk but without gas and dust is an **elliptical galaxy**.

Elliptical galaxies are characterized by their smooth and featureless appearance, lacking the distinct spiral arms seen in disk galaxies like the Milky Way. They are composed mostly of old stars and have little to no ongoing star formation. As a result, they have depleted their interstellar gas and dust reservoirs over time, leaving behind primarily stellar populations. Elliptical galaxies can vary in size from small to massive, and their shape ranges from nearly spherical to elongated ellipsoids. They are commonly found in dense regions of galaxy clusters, where interactions and mergers between galaxies have stripped away their gas and disrupted their original disk structures.

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Answer:

Year wise Percentage of Attendance in Senior Secondary Schools of India The given graph shows that the percentage of attendance is recorded with a gap of 5 years. The given table depicts, across time, from the year 2000 to 2015. During the 15 years, there is a steady and healthy increase in the percentage of attendance in ll the four types of schools. The increase in Convent-run schools is much higher compared to the other three types of schools. Initially, the village schools show a noticeably poor percentage of attendance and the General English Medium schools show less percentage of attendance compared to the Convent-run schools. All in all the continuous higher percentage indicates that the relevant authorities are learned about improving the education of the country. The poor attendance in the 2010 in the Government-run village schools shows a big leap in the year 2015, indicating that the Government must have taken an effective measure to improve literacy in the villages. Noteworthy increase in the attendance indicates solid infrastructure and focus towards the healthy growth of the corresponding authorities.

Explanation:

hope it helps you<3

Answer:

Friction

Explanation:

In the event that the power is applied toward the path inverse to the bearing of movement, it goes against the movement of the item and henceforth the speed of the article diminishes.

Then, in the event that the thing continues to move one way, grinding will dominate and go about as the moving variable.

So, the moving factor would be friction.

Let consider the whole system to be at equilibrium where the net force is zero. The forces \(F_A\) and \(F_B\) are acting in the upward direction while the weight (w) of the crate is acting in the downward direction.

The force at equilibrium in the y-direction is computed as:

\(\sum F_y = ma_y\)

\(F_A +F_B= mg\)

\(\mathbf{F_A = mg -F_B}\)  ---- (1)

Recall that the weight w = mg

where;

w = 200 × 9.8

w = 1960 N

The torque about the bottom end is also zero. i.e.

\(\sum \tau=0\)

∴

\(F_B L_Z - wL_w = 0\) --- (2)

\(F_B L_Z= wL_w\)

\(F_B = \omega (\dfrac{L_w}{L_z})\)

\(F_B =1960\times (\dfrac{0.375\times cos 45^0}{1.25\times cos 45^0})\)

\(F_B =1960\times (0.3)\)

\(\mathsf{F_B = 588 \ N}\)

Replacing the value for the force of B into equation (1); we have:

\(F_A = mg - F_B\)

\(F_A = 1960 - 588\)

\(\mathsf{F_A = 1372 N}\)

Thus, we can conclude that the magnitude of these forces i.e force B and force A are 588 N and 1372 N respectively.

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The implied annualized risk-free rate of return for holding the futures contract is approximately 8.51%.

In this scenario, the futures price of the ABC index is higher than the spot price, indicating a positive cost of carry. To calculate the implied annualized risk-free rate of return, we can use the formula:

Implied Annualized Risk-free Rate = (Futures Price - Spot Price) / Spot Price * (365 / Time to Expiration)

Given the spot price of 1302, the futures price of 1335, and a 6-month expiration period, we can plug these values into the formula:

Implied Annualized Risk-free Rate = (1335 - 1302) / 1302 * (365 / 0.5)

Calculating the expression yields approximately 0.0851 or 8.51%. This implies that holding the futures contract on the ABC index would yield an annualized risk-free return of 8.51% if the current market conditions persist.

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The above given question is incomplete, below a complete question is written:

The (hypothetical) ABC index spot price is currently at 1302, and the continuously compounded risk-free rate is 6% per annum. The 6-month observed futures price on the index is 1335. What is the implied annualized risk-free rate of return for holding the futures contract?

Taking the measurements more than once can help improve the accuracy of the density value because the more measurements that are taken, the more accurate the average of those measurements will be.

Density is a measure of mass per unit of volume. It is an intensive property of a material, which means that it is independent of the amount of material present. In other words, the density of a material is the same regardless of how much material there is. Density is usually expressed in units of grams per cubic centimeter (g/cm3). The higher the density of a material, the greater its mass per unit of volume.

For example, if the student only takes one measurement and it is slightly off due to human error, the resulting density value may be inaccurate. However, if the student takes multiple measurements and averages them together, any errors in individual measurements will be cancelled out, resulting in a much more accurate density value.

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Answer:

  cue ball final: 0.85 m/s at N65°W

  8-ball final: 1.27 m/s at N12°E

Explanation:

In a perfectly elastic collision, both momentum and energy are conserved. The momentum is the sum of products of mass and velocity. The energy is half the product of mass and the square of velocity. The difference of "particle" velocities changes sign as a consequence of the collision.

__

If we let the masses be m1 and m2, the corresponding initial velocities be v1 and v2, and the final velocities be u1 and u2, we have ...

  m1·u1 +m2·u2 = m1·v1 +m2·v2 . . . . . . . conservation of momentum

  u1 -u2 = v2 -v1 . . . . . . . . . . . . . . . relative velocity sign changes

This pair of linear equations can be solved for u1 and u2 in any of the usual ways to give ...

  u1 = v1(m1 -m2)/(m1 +m2) + v2(2·m2)/(m1 +m2)

  u2 = v2(m2 -m1)/(m1 +m2) +v1(2·m1)/(m1 +m2)

__

Using angle measures as clockwise from north, we are given ...

  cue ball: m1 = 0.17 kg, v1 = 1.2∠10° m/s

  eight ball: m2 = 0.15 kg, v2 = 0.89∠-70° m/s

A suitable calculator can find the final velocities using the above equations.

The first attachment shows the calculations using a TI-84 work-alike calculator.

  cue ball final: 0.85 m/s at N65°W

  8-ball final: 1.27 m/s at N12°E

The second attachment shows a vector diagram of the velocities.

The correct answer is E

"Neve/Firn."

Neve/Firn is granular snow that compacts and recrystallizes over time to form glacial ice.

The correct answer is "Neve/Firn."

Neve or firn is the granular snow that accumulates over time and undergoes compaction and recrystallization.

As more snow accumulates on top, the underlying neve/firn becomes more compacted, and the air between the snow grains is forced out.

This process causes the neve/firn to become denser and transform into glacial ice.

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Answer:

C. Gamma Rays

Explanation:

A P E X

Answer:

C. Gamma rays

Explanation:

got it right

To determine the force constant (k) of a spring, we need to perform an experiment which requires a retort stand and clamp, a spiral spring, a meter rule and different weights.

Force constant of the spring or the spring constant can be defined as the stiffness of the spring.

The setup is arranged as shown in the image attached as Fg.1.

The natural length of the spring is first recorded. Different weights are added to the spring one after the other and the extension is recorded, each time when the different weights are added simultaneously

The weight is now plotted on the vertical axis and the extension is plotted on the horizontal axis. The slope of the graph is the force constant of the spring.

The graph is shown in the image attached as Fig.2

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The spring constant, k, in Hooke's Law has units of Newton per meter since it is a constant for the force applied per unit of length. The spring constant measures how strong and stiff the spring is. Hope this answers the question. Have a nice day.

Answer:

True

Explanation:

The object is at rest, which means it's not moving, so there is no net force on it, according to Newton's First Law.

Answer:

a. The acceleration due to gravity on the Moon is approximately 1.6 ft/s²

b. The height from which the hammer was dropped is 1.253 feet

Explanation:

a. Whereby the unit of velocity is in ft/s, we have

Acceleration = Rate of change of velocity with time

Therefore, acceleration, a = Slope of the velocity to time graph

Whereby the graph is a straight line graph, we proceed to find the slope as follows;

We consider two points, (x₁, y₁) and (x₂, y₂), where (x₁, y₁) is the origin as follows

x₁ = 0 seconds

x₂ = 0.94 seconds

y₁ = 1.5 ft/s

y₂ = 0 ft/s

The two points are therefore;

(0, 0) and (0.94, 1.5)

The slope of the graph, a is given as follows;

\(Slope\, of \, the\, graph = a = \dfrac{y_{2}-y_{1}}{t_{2}-t_{1}} = \dfrac{1.5-0}{0.94-0} = 1.596 \, ft/s^{2}\)

The acceleration due to gravity on the Moon = 1.596 ft/s² ≈ 1.6 ft/s²

The unit of the acceleration is ft/s²

b. The height, h, from which the hammer was dropped is found using the following relation;

v² = u² + 2×a×h

Where:

v = Final velocity = Maximum value of the velocity = 2.0 ft/s

u = Initial velocity = 0 ft/s for an object starting from rest

a = Acceleration due to gravity ≈ 1.6 ft/s²

Therefore;

h = (v² - u²)/(2×a) = (2.0² - 0²)/(2×1.6) = 1.253 ft

The height, h, from which the hammer was dropped = 1.253 ft

This question is incomplete; here is the complete question:

Marco is conducting an experiment. He knows the wave that he is working with has a wavelength of 32.4 cm. If he measures the frequency as 3 hertz, which statement about the wave is accurate?

A. The wave has traveled 32.4 cm in 3 seconds.

B. The wave has traveled 32.4 cm in 9 seconds.

C. The wave has traveled 97.2 cm in 3 seconds.

D. The wave has traveled 97.2 cm in 1 second.

The answer to this question is D. The wave has traveled 97.2 cm in 1 second.

Explanation:

The frequency of a wave, which is in this case 3 hertz, represents the number of waves that go through a point during 1 second. According to this, if the frequency of the wave is 3 hertz this means in 1 second there were 3 waves. Moreover, if you multiply the wavelength (32.4cm) by the frequency (3) you will know the distance the wave traveled in 1 second: 32.4 x 3 =  97.2 cm. This makes option D the correct one as the distance in 1 second was 97.2 cm.

Answer:Is D!

Explanation:TEAT(Sorry) -_-*

The answer to your question is that the proton needs to be fired with an initial kinetic energy of 106 MeV to have 53 MeV of kinetic energy as it impacts the 2Pb nucleus.

It is important to understand the concept of conservation of energy in this scenario. The proton initially has some amount of kinetic energy, which is converted into various forms of energy as it interacts with the target nucleus. The kinetic energy of the proton can be calculated using the equation KE = 1/2 mv^2, where KE is kinetic energy, m is the mass of the proton, and v is its velocity.

In this experiment, the proton needs to have 53 MeV of kinetic energy as it impacts the 2Pb nucleus. Since we know the mass of the proton and the target nucleus, we can calculate the velocity needed for the proton to have this kinetic energy. Once we have the velocity, we can then use the kinetic energy equation to find the initial kinetic energy of the proton. Using these calculations, we find that the proton must be fired with an initial kinetic energy of 106 MeV to have 53 MeV of kinetic energy as it impacts the 2Pb nucleus.

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Answer:It's B energy is absorbed by the reaction,hope this helps

Explanation:

Any reaction in which energy is absorbed is said to be endothermic. Hence, option B is correct, but the rest are not correct.

In every chemical process, energy is involved. When new bonds form in products, energy is produced. Reactant bonds are broken using energy. Exothermic reactions are those that produce more energy when new bonds form in the products than is needed to break existing bonds in the reactants.

In contrast, endothermic reactions are the opposite. Endothermic reactions release more energy when new bonds form in the products than is required to break bonds in the reactants.

During the reaction, a large amount of energy is absorbed.

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Transport externalities, such as congestion, emissions, crashes, and noise, have impacts that extend beyond the immediate users. Mitigating these externalities involves aligning private costs with social costs through measures like taxes or regulations.

Transport externalities can be valued using techniques like direct costing, hedonic pricing, contingent valuation, or control costs. Externalities can occur due to both insufficient and excessive capacity, and they affect third parties beyond the primary parties involved in transportation activities.

a. Correct. Examples of transport externalities include congestion, emissions, crashes, and noise. These are negative impacts that extend beyond the direct users of transportation systems.

b. Partially correct. Mitigating transport externalities often involves internalizing the costs by making private costs align with social costs. This can be achieved through measures such as taxes, fees, or regulations that increase the private costs associated with the negative externalities.

c. Partially correct. Transport externalities can indeed be valued using direct costing or hedonic pricing techniques. These methods aim to estimate the monetary value of externalities by assessing factors such as property values, health costs, or time lost due to congestion.

d. Incorrect. Transport externalities can occur in various situations, including both when too little or too much capacity is provided. For example, congestion can result from inadequate capacity, while environmental impacts can arise from excessive capacity or vehicle usage.

e. Incorrect. Transport externalities can be valued using contingent valuation or control costs techniques, among others. Contingent valuation involves surveying individuals to elicit their willingness to pay or accept compensation for specific externalities. Control costs techniques assess the costs associated with implementing measures to control or mitigate the externalities.

f. Incorrect. Externalities by definition impact third parties, beyond the immediate users or providers involved. Externalities refer to the costs or benefits that affect individuals or entities not directly involved in a transaction or activity. These impacts can be positive or negative, but they extend beyond the primary parties involved.

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Answer:

C) mass number

Explanation:

I got it correct on edge

Answer:  c

Explanation:

Answer:

3520

Explanation: Force = Mass x Acceleration [∴ or F = ma]. Given values. mass, m = 1600 kg; initial velocity, u = 8 m/s; final velocity, v = 30 m/s; time taken, t = 10 s.

During sewer pipe installation using a laser, a laser beam is projected through the pipe until it hits a target beam(c).

The target beam acts as a reference point or marker that helps align the pipe correctly during installation. By hitting the target beam, the laser beam indicates the desired direction and position for the pipe, ensuring accurate installation.

The target beam is often placed at the other end of the pipe or at specific intervals along the pipe's path, allowing the construction crew to adjust the alignment and slope as necessary. This process helps ensure the proper installation of the sewer pipe, minimizing potential issues and ensuring efficient drainage.

So c is correct option.
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