1)
You travel east at 50 km/hr and then north at 75 km/hr. What is your Resultant Velocity in km/h?
(Remember the angle) (5pts)

Answer:

the three gases our atmosphere is mainly composed of are nitrogen oxygen and carbon

The image distance is 0.65 cm and the image is real but diminished.

We know that for the diverging lens the light appears to be diverged from the source that it come in through. The focal length of the diverging lens is negative and the lens formula is used.

We have;

1/f = 1/u + 1/v

f = focal length

u = object distance

v = image distance

-1/2.5 = 1/4 + 1/v

1/v = 1/4 + 1/2.5

v = 0.25 + 0.4

v = 0.65 cm

The image is real but it is smaller than the object.

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Answer:

D

Explanation:

Answer:

No, positive charges cannot be liberated by the photoelectric effect.

Explanation:

Answer:

A. 40 N

Explanation:

To find force with acceleration and mass we use the equation f=ma

f stands for force

m stands for mass

a stands for acceleration

Now we substitute

f=50*0.8

f= 40

Remember that force is measured in newtons. So A. 40 N is the correct answer.

Use the formula a = v / t to determine acceleration, where v stands for the change in velocity and t for the time it took for the change to take place. Use SI units for force (newtons), mass (kg), and acceleration when utilizing this formula (meters per second squared). Thus, option A is correct.

The acceleration of an object is equal to the net force exerted on it divided by its mass, or a = F m, in accordance with Newton's second rule of motion. When the mass of an item and the net force acting on it are known, the acceleration of that object can be determined using this equation for acceleration.

Therefore, An object's force is equal to its mass times its acceleration, or F = m a. To apply this formula, you must use SI units for force (newtons), mass (kilograms), and acceleration (meters per second squared).

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Answer:nh

0.750 kg hammer is moving horizontally at 7.00 m/s when it strikes a nail and comes to rest after driving it 1.00 cm into a board.

Answer:

According to Newton's third law of motion, for every action, there is an equal and opposite reaction. When the man jumps from a boat, he applies force on the boat due to which boat moves backward. An equal force is exerted by the boat on the man which helps the man to jump out of the boat.

Answer:

the person on the bottom has the answer i was going to put it but he got it first soo ya

Explanation:

If the separation between the batter and the ball is 0.71 m and the gravitational force exerted on the batter by the ball is 13 N have mass  3.13 \(*10^{5}\) kg.

A force in physics is an effect that has the power to alter an object's motion. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.

Given that in the question the separation between the batter and the ball is 0.71 m and the gravitational force exerted on the batter by  ball is 13 N

F = Gmm/r²

G = 6.67\(*10^{-11}\)N-m²/Kg²

13 N = 6.67\(*10^{-11}\)m²/(0.71)²

m = 3.13 \(*10^{5}\)

The mass of the batter  3.13 \(*10^{5}\) kg.

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Answer: (0.17 * 6) + ( 0.16 * 0 ) = (0.17 * 0) + ( 0.16 *  v2)

v2 = 6.375 m/s

Explanation:

The answer is v2 = 6.375 m/s

(I did the equation and everything but just in case, check with someone else so you don't get the wrong answer)

Answer:

1) A.  0.44 m/s East + 0.33 m/s North

2) A.  0 m/s²

3) A.  a scalar calculated as distance divided by time.

4) B.  31 km per hour

Explanation:

1) Velocity is DISPLACEMENT over time.

at 1 m/s, total time of walking is 9000 seconds

displacement is 3000 m north and 5000 - 1000 = 4000 m east

4000 m/ 9000 s = 0.44 m/s E

3000 m/ 9000s = 0.33 m/s N

2) constant speed means no acceleration

3) A. a scalar calculated as distance divided by time.

4) displacement 50 km N and 80 km W

v = √(50² + 80²) / (1 + 2) = 31.446603... km/hr

Answer:

  h’ = 1/9 h

Explanation:

This exercise must be solved in parts:

* Let's start by finding the speed of sphere B at the lowest point, let's use the concepts of conservation of energy

starting point. Higher

         Em₀ = U = m g h

final point. Lower, just before the crash

         Em_f = K = ½ m \(v_{b}^2\)

energy is conserved

         Em₀ = Em_f

         m g h = ½ m v²

         v_b = \(\sqrt{2gh}\)

* Now let's analyze the collision of the two spheres. We form a system formed by the two spheres, therefore the forces during the collision are internal and the moment is conserved

initial instant. Just before the crash

         p₀ = 2m 0 + m v_b

final instant. Right after the crash

         p_f = (2m + m) v

the moment is preserved

         p₀ = p_f

         m v_b = 3m v

         v = v_b / 3

          v = ⅓ \(\sqrt{2gh}\)

* finally we analyze the movement after the crash. Let's use the conservation of energy to the system formed by the two spheres stuck together

Starting point. Lower

          Em₀ = K = ½ 3m v²

Final point. Higher

          Em_f = U = (3m) g h'

          Em₀ = Em_f

          ½ 3m v² = 3m g h’

we substitute

         h’=  \(\frac{v^2}{2g}\)

         h’ =  \(\frac{1}{3^2} \ \frac{ 2gh}{2g}\)

         h’ = 1/9 h

(a) To find the average frictional force that stops the bullet, we can use the work-energy principle, which states that the work done by all forces on an object is equal to the change in its kinetic energy.

In this case, the work done by the frictional force is equal to the change in the bullet's kinetic energy from its initial speed of 540 m/s to zero when it comes to a stop.

The initial kinetic energy of the bullet is given by (1/2)mv², where m is the mass of the bullet and v is its initial speed. Substituting the given values, we get

Ki = (1/2)(0.0078 kg)(540 m/s)²

     = 1.4916 kJ

The final kinetic energy of the bullet is zero, so the work done by the frictional force is equal to -1.4916 kJ. The negative sign indicates that the work is done against the direction of motion of the bullet.

The distance over which the frictional force acts is equal to the depth to which the bullet penetrates the tree trunk, which is 6.30 cm. Therefore, the work done by the frictional force is also equal to the force times the distance, or W = Fd.

Equating the work done by the frictional force to the change in kinetic energy, we get

-Fd = Kf - Ki

where Kf is the final kinetic energy, which is zero. Solving for the frictional force F, we get

F = (Ki)/d = 1.4916 kJ / 0.063 m

   = 23,651 N

Therefore, the average frictional force that stops the bullet is 23,651 N.

(b) Assuming the frictional force is constant, we can use the equation of motion for constant acceleration to determine the time it takes for the bullet to come to a stop.

The distance traveled by the bullet before coming to a stop is equal to the depth to which it penetrates the tree trunk, which is 6.30 cm. The initial speed of the bullet is 540 m/s, and the acceleration is equal to -F/m, where F is the frictional force and m is the mass of the bullet. Substituting the given values, we get

d = (1/2)at² + vit

0.063 m = (1/2)(-23,651 N) / 0.0078 kg t² + 540 m/s t

Simplifying and solving for t, we get

t = 0.0229 s

Therefore, the time it takes for the bullet to come to a stop is 0.0229 seconds.

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Answer:

-969.06

-286.74

698.7

-115.6, 12.9

-139.9, 12.9

Explanation:

Given that

Speed v, wrt y = -24.3 m/s

Speed v, wrt x = 12.9 m/s

time t, = 11.8 s

a

Using the formula

H(t) = ut - 1/2gt², where u = v wrt y

H(t) = -24.3 * 11.8 - 1/2 * 9.8 * 11.8²

H(t) = -286.74 - 682.28

H(t) = -969.06 m

b

H = ut, where u = v wrt y

H = -24.3 * 11.8

H = -286.74 m

H(1) = -969.06 - -286.74 = -682 m

c

Horizontal displacement, x = vt. Where v = v wrt x

x = 12.9 * 11.8

x = 152.22 m

d = √(H1² + x²)

d = √682² + 152²

d = 465124 + 23104

d = √488228

d = 698.7 m

d

Vertical component =

-gt - 0 =

-9.8 * 11.8 = -115.6

Horizontal component =

v wrt x - 0

12.9 - 0 = 12.9

e

Vertical component =

-gt - v wrt y =

-9.8 * 11.8 - 24.3 = -139.9

Horizontal component =

v wrt x - 0 =

12.9 - 0 = 0

The boat's final velocity can be determined using the work-energy principle. Since the boat starts at rest, the work done on it will be equal to its change in kinetic energy.

Using the equation:

Work = Change in Kinetic Energy

300 J = (1/2) * m * v^2

where m is the mass of the boat and v is the final velocity, we can solve for v.

Plugging in the values:

300 J = (1/2) * 4.5 kg * v^2

Simplifying the equation:

v^2 = (2 * 300 J) / 4.5 kg

v^2 = 200 J / 4.5 kg

v^2 = 44.44 m^2/s^2

Taking the square root of both sides:

v = √(44.44 m^2/s^2)

v ≈ 6.66 m/s

Therefore, the boat's final velocity is approximately 6.66 m/s.

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The angular acceleration of the pulley is given by the expression α = (MgR - mgr) / I.

The forces acting on the system are the gravitational forces on the turkey and the pumpkin, which are Mg and mg, respectively. T

These forces create torques on the pulley, with the torque on the large disk being MgR and the torque on the small disk being -mgr. The negative sign on the torque of the small disk indicates that it is acting in the opposite direction of the torque on the large disk.
The sum of these torques is equal to the moment of inertia of the pulley times its angular acceleration, which can be written as:
MgR - mgr = Iα
Solving for the angular acceleration, α, we get:
α = (MgR - mgr) / I
This is the expression for the angular acceleration of the pulley in terms of the system parameters. It shows that the angular acceleration depends on the masses of the turkey and the pumpkin, the radii of the large and small disks, and the moment of inertia of the pulley.

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Answer:

A) its internal (thermal) energy does not change.

Explanation:

When a fixed amount of ideal gas goes through an isothermal expansion

Answer:

conduction

Explanation:

Answer:

The formula, which is fairly easy to derive, is:

The sine of the critical angle = refractive index of the “refracting medium” divided by refractive index of the “incident medium”.

In this case the “refractive medium” is air and the “incident medium” is glass.

The refractive index of air is about 1 (almost exactly).

So, in this case, the sine of the critical angle is 1 divided by 1.5 = 0.6667.

You will find the answer, from sine tables, to be approximately 41.81 degrees.

Remember that the refractive index of air is slightly more than 1. Using a better value for refractive index of air, I get the critical angle to be about

Answer:

Ca = 2

Cl = 2

O = 6

Explanation:

Element given from the question above include = 2CaClO₃

NOTE: The 2 in front of CaClO₃ is affecting Ca, Cl and O.

Thus, the number of each atom of element present in 2CaClO₃ can be obtained as follow:

Ca = 1 × 2 = 2

Cl = 1 × 2 = 2

O = 3 × 2 = 6

Thus,

Ca = 2

Cl = 2

O = 6

1. because A is more negative than B. A is -1000 V (we can imagine that A has excess 1000 electrons), in other, B which +3000 V can be assume that B need 3000 elctrons to be neutral. So, the electron will flow from A to B.

2. Electrons being negatively charged flow from the negative terminal to the positive terminal of the voltage source. So, the actual direction of current should be from negative to positive terminal. However, the conventional direction had already been established. So, the current flow is considered in the direction opposite to the direction of flow of electrons. (from topperlearning dot com)

This question involves the concepts of the law of conservation of energy, Pythagora's Theorem, kinetic energy, and potential energy.

The rope makes an angle of "26.2°" with the vertical when the ball's kinetic energy is halved.

First, we will find the initial kinetic energy of the ball:

\(K.E = \frac{1}{2}mv^2\\\\K.E=\frac{1}{2}(m)(1.1\ m/s)^2\\\\K.E = (0.605\ m^2/s^2) m\)

Now, half of this kinetic energy is left at the final point. Therefore, according to the law of conservation of energy, the other half must be converted to the potential energy of the ball:

\(P.E=\frac{1}{2}K.E\\mgh'=\frac{1}{2}(0.605\ m^2/s^2)m\\\\h'=\frac{0.3025\ m^2/s^2}{9.81\ m/s^2}\\\\h' = 0.031\ m\)

This h' is the height of the ball above the ground the final position, as shown in the picture attached.

Applying Pythagora's Theorem to the right angled triangle shown in the attached picture we have:

\(Cos\theta = \frac{Base}{Hypotenuse}=\frac{h}{l}\)

where,

θ = angle of rope with vertical = ?

l = legth of rope = 0.3 m

h = l - h' = 0.3 m - 0.031 m = 0.27 m

Therefore,

\(Cos\theta=\frac{0.27\ m}{0.3\ m}\\\\\theta = Cos^{-1}(0.89721)\)

θ = 26.2°

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sorry, it's B, not a made a mistake in the approximation

Answer:

it is safe to stand at the end of the table

Explanation:

For this exercise we use the rotational equilibrium condition

         Στ = 0

         W x₁ - w x₂ - w_table x₃ = 0

         M x₁ - m x₂ - m_table x₃ = 0

where the mass of the large rock is M = 380 kg and its distance to the pivot point x₁ = 850 cm = 0.85m

the mass of the man is 62 kg and the distance

            x₂ = 4.5 - 0.85

            x₂ = 3.65 m

the mass of the table (m_table = 22 kg) is at its geometric center

            x_{cm} = L/2 = 2.25 m

            x₃ = 2.25 -0.85

            x₃ = 1.4 m

let's look for the maximum mass of man

            m_{maximum} = \(\frac{ M x_1 -m_{table} x_3}{ x_2}\)

let's calculate

             m_{maximum} = \(\frac{ 380 \ 0.85 - 22 \ 1.4}{3.65}\)(380 0.85 - 22 1.4) / 3.65

             m_{maximum} = 80 kg

we can see that the maximum mass that the board supports without turning is greater than the mass of man

             m_{maximum}> m

consequently it is safe to stand at the end of the table

The correct answer is accommodation.

The process of accommodation, according to Piaget's theory, comprises altering one's preexisting conceptions (schemas) about how the world functions in response to new information and encounters. This process of adaptation is universal and is applicable to both adults and children.

According to Piaget's theory of cognitive development, humans pass through the sensorimotor, preoperational, formal operational, and cognitive stages. Processes like accommodation help these steps along.

Assimilation and the process of accommodation are at odds with one another. Assimilation aims to connect new information to outdated cognitive frameworks, whereas accommodation aims to construct new schemas (schemas). Organisms must strike a balance between assimilation and accommodation in order to develop intelligence.

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Answer: Velocity

Explanation: velocity is expressed in m/s; km/hr is just a unit conversion. It cannot be acceleration because the time unit is not squared. It cannot be time because there is a mass unit in the numerator.

Answer:

a

Explanation:

How long would it take a machine to do 5.000

joules of work if the power rating of the machine

is 100 watts?

The given machine will take 50 s to complete the work. the power is the rate of performing work.

It can be defined as the rate of performing work. It can also be written as the amount of work divided by the time it takes to complete the work.

\(p = \dfrac wt\)

So

\(t = \dfrac w p\)

Where,

\(p\) - power = 100 watt  = 100 J/s

\(t\) - time = ?

\(w\)- work = 5000 J

Put the values in the formula,

\(t = \dfrac{ 5000 \rm \ J} {100 \rm \ J/s}\\\\t = 50 \rm \ s\)

Therefore, the given machine will take 50 s to complete the work.

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The maximum height the object reaches be 5.81 m.

The object's final velocity as it hits the ground be 10.67 m/s.

The rate at which a body's displacement changes in relation to time is known as its velocity. Velocity is a vector quantity with both magnitude and direction. SI unit of velocity is meter/second.

Given that:

An object starts with an initial height of 5 meters above the ground. It is thrown upward with an initial velocity of 4 m/s.

So, maximum height obtained by it be: H  = 5 m + (4²/2×9.8) m = 5.81 m.

The object's final velocity as it hits the ground = √(2gH)

= √(2×9.8×5.81) m/s

= 10.67 m/s.

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ANSWER

5.77

EXPLANATION

Given:

• The diameter of the input cylinder, d₁ = 3.2 in

• The input force, F₁ = 485 lb

• The diameter of the output cylinder, d₂ = 9.2 in

• The output force, F₂ = 2800 lb

Find:

• The actual mechanical advantage, AMA

The mechanical advantage is given by,

Replace the known values and solve,

Hence, the actual mechanical advantage of this jack is 5.77, rounded to the nearest hundredth.

The magnitude of the action–reaction pair between the two boxes (A and B) will be "18.2 N".

According to the question,

Mass of box A,

Mass of box B,

Horizontal force,

From the Newton's law,

→ \(F_{app} = (\frac{F_{app}}{m_A+m_B} )a\)

or,

→      \(a = \frac{F_{app}}{(m_A+m_B)}\)

Bu substituting the values, we get

→         \(= \frac{100}{9+2}\)

→         \(= \frac{100}{11}\)

→         \(9.10 \ m/s^2\)

We can see that between the two boxes, the action-reaction pair exist.

then,

→ \(F_{action-reaction} = m_b \ a\)

→                          \(=2\times 9.10\)

→                          \(= 18.2 \ N\) (magnitude)

Thus the above solution is appropriate.

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