1/5 of 45 is what number?

Multicollinearity refers to the situation where two or more predictors in a statistical model are highly correlated with each other.

Multicollinearity occurs when there is a high correlation between predictor variables in a regression model. The option D, "Two or more predictors are highly correlated with each other," best describes multicollinearity. When multicollinearity is present, it becomes difficult to determine the individual effects of each predictor on the response variable. The presence of multicollinearity can lead to unstable estimates and inaccurate inferences.

In a regression model, the predictors should be independent of each other to provide reliable and interpretable results. When two or more predictors are highly correlated, it indicates that they are capturing similar information or have redundant information. This can cause problems in the model as it becomes challenging to determine the unique contribution of each predictor. High correlation between predictors can lead to unstable coefficient estimates and inflated standard errors.

Detecting multicollinearity is important in regression analysis. Methods such as calculating correlation coefficients, variance inflation factors (VIF), or conducting hypothesis tests for individual predictors can help identify the presence of multicollinearity. If multicollinearity is detected, potential solutions include removing one of the correlated predictors, transforming variables, or collecting additional data to reduce the correlation. Handling multicollinearity appropriately is crucial to ensure the reliability and validity of regression analysis results.

Learn more about multicollinearity here:

https://brainly.com/question/32706933

#SPJ11

Answer:

----------------------

The perimeter is the sum of all 5 sides.

Set up equation and solve for h:

Answer: 0.1      

0.1<0.104

Step-by-step explanation:

Based on the results of the simulation, the probability that Michaela will walk animals on:

a. both days = 1/6

b. one day only = 2/3

c. at least one day = 5/6

Probability is simply how likely something is to happen.

Grooming = 0, 1, 2

Walking = 3, 4, 5, 6, 7

Cleaning = 8, 9

Based on the data generated in simulation, categorizing it into "Michael will walk animals zero days/ one day only/ both days based on the digit categorization given above.

(2,9) - zero days

(5,2) - one day

(3,9) - one day

(0,1) - zero days

(8,3) -one day

(0,5) - one day

(8,3) - one day

(6,8) - one day

(4,7) - two days

(7,4) - two days

(1,5) - one day

Probability that Michaela will walk animals both days = \(\frac{2}{12} = \frac{1}{6}\)

Probability that Michaela will walk animals one day only = \(\frac{8}{12} = \frac{2}{3}\)

Probability that Michaela will walk animals at least one day = Probability that Michaela will walk animals one day only + Probability that Michaela will walk animals two days only  = \(\frac{8}{12}+ \frac{2}{12} = \frac{10}{12} = \frac{5}{6}\)

Learn more about probability here

https://brainly.com/question/11234923

#SPJ2

Answer:

50%

Step-by-step explanation:

yeah-ya......... right?

The statement "the first step in the sampling design process is to determine the sample size" is false because according to the text, the first step in the sampling design process is to clearly define the target population.

The first step in the sampling design process is typically to define the target population and the research objectives.

This involves specifying the characteristics of the population under study and identifying the specific research questions or objectives that the sampling will address.

Once the target population and research objectives are established, the next steps in the sampling design process typically involve determining the appropriate sampling method (such as random sampling, stratified sampling, or cluster sampling) and selecting the sampling frame (the list or source from which the sample will be drawn).

After these initial steps, researchers can then consider factors such as the desired level of precision, confidence level, and variability in the population to determine the appropriate sample size.

The determination of the sample size usually comes after clarifying the research objectives and selecting the appropriate sampling method.

To know more about sampling design refer here:

https://brainly.com/question/32283666#

#SPJ11

Answer:

it would be graph A/ the light blue one

Step-by-step explanation:

Answer:

The two answers are the light blue data and the green data.

Step-by-step explanation:

:)

Answer:

27

Step-by-step explanation:

Multiply 8×.75 (6)

Add that to 21

The coefficient of determination is 0.588 and the percentage of the total variation is 58.8%.

The coefficient of determination (r^2) refers to a measurement used to explain how much variability of one variable can be caused by its relationship to another related variable. It is the fit of goodness and measures how well a statistical model fits the observed data and is a number between 0 and 1. When the value of linear correlation coefficient r is known, the coefficient of determination can be computed simply by squaring r.

Hence if r = 0.767, then the coefficient of determination = r^2 = 0.588

As percentage of the total variation is same as the coefficient of determination (given in percentage) and is given by the R² value = 58.8%. Hence, about 58.8% of variation is explained by the linear relationship between the two variables.

Note: The question is incomplete. The complete question probably is: Use the value of the linear correlation coefficient r to find the coefficient of determination and the percentage of the total variation that can be explained by the linear relationship between the two variables. r = 0.767.

Learn more about Coefficient of determination:

https://brainly.com/question/24297732

#SPJ4

Answer:

\(\textsf{1)} \quad x=\dfrac{y-b}{a}\)

\(\textsf{2)} \quad x=\dfrac{y+b}{a}\)

\(\textsf{3)} \quad x=2y-2\)

Step-by-step explanation:

\(\boxed{\begin{aligned}&\textsf{Given}: \quad &y & =xa+b\\\\&\textsf{Subtract $b$ from both sides}: \quad & y-b&=xa+b-b \\\\&\textsf{Simplify}: \quad &y-b&=xa \\\\&\textsf{Divide both sides by $a$}: \quad &\dfrac{y-b}{a} &=\dfrac{xa}{a} \\\\&\textsf{Simplify}: \quad &\dfrac{y-b}{a} &=x\\\\&\textsf{Switch sides}: \quad & x&=\dfrac{y-b}{a}\end{aligned}}\)

\(\boxed{\begin{aligned}&\textsf{Given}: \quad &y & =xa-b\\\\&\textsf{Add $b$ to both sides}: \quad & y+b&=xa-b+b \\\\&\textsf{Simplify}: \quad &y+b&=xa \\\\&\textsf{Divide both sides by $a$}: \quad &\dfrac{y+b}{a} &=\dfrac{xa}{a} \\\\&\textsf{Simplify}: \quad &\dfrac{y+b}{a} &=x\\\\&\textsf{Switch sides}: \quad & x&=\dfrac{y+b}{a}\end{aligned}}\)

\(\boxed{\begin{aligned}&\textsf{Given}: \quad & y&=\dfrac{x+2}{2} \\\\&\textsf{Multiply both sides by $2$}: \quad & 2 \cdot y&=2 \cdot \dfrac{x+2}{2} \\\\&\textsf{Simplify}: \quad & 2y&=x+2 \\\\&\textsf{Subtract $2$ from both sides}: \quad & 2y-2&=x+2-2 \\\\&\textsf{Simplify}: \quad & 2y-2&=x \\\\&\textsf{Switch sides}: \quad &x&=2y-2\end{aligned}}\)

(a) Option A, if its value is a large positive number, statistic A x2 provides strong evidence for the alternative hypothesis.

(b) Option B, the null hypothesis that gender is not related to personal goals and the alternative hypothesis that gender is related to personal goals.

(c) Option B, the variables considered in the chi-square test for the evaluation of contingency table B are categorical variables.

(a) If the x2 statistic is a large positive number, it provides strong evidence for the alternative hypothesis. The x2 statistic is used in hypothesis testing to determine if there is a significant difference between observed and expected frequencies. Large positive values ​​indicate that the observed frequency is significantly different from the expected frequency, supporting the alternative hypothesis.

(b) The hypotheses tested in the chi-square test for the contingency table are the null hypothesis that gender is not related to personal goals and the alternative hypothesis that gender is related to personal goals. personal goals. This test determines whether there is a significant relationship between two categorical variables.

(c) The variables considered in the chi-square test used to evaluate the contingency table are categorical variables. These variables cannot be assumed to be mean or normally distributed. The chi-square test is used to analyze the relationship between two or more categorical variables, where each variable has a discrete set of categories.

Complete Question:

For each problem, select the best response (a) A x2 statistic provides strong evidence in favor of the alternative hypothesis if its value is A. a large positive number. OB. exactly 1.96 c. a large negative number. D. close to o E. close to 1. (b) A study was performed to examine the personal goals of children in elementary school. A random sample of students was selected and the sample was given a questionnaire regarding achieving personal goals. They were asked what they would most like to do at school: make good grades, be good at sports, or be popular. Each student's sex (boy or girl) was also recorded. If a contingency table for the data is evaluated with a chi-squared test, what are the hypotheses being tested? A. The null hypothesis that boys are more likely than girls to desire good grades vs. the alternative that girls are more likely than boys to desire good grades. OB. The null hypothesis that sex and personal goals are not related vs. the alternative hypothesis that sex and personal goals are related. C. The null hypothesis that there is no relationship between personal goals and sex vs. the alternative hypothesis that there is a positive, linear relationship. OD. The null hypothesis that the mean personal goal is the same for boys and girls vs. the alternative hypothesis is that the means differ. O E. None of the above. (C) The variables considered in a chi-squared test used to evaluate a contingency table A. are normally distributed. B. are categorical. C. can be averaged. OD. have small standard deviations. E. have rounding errors.

Learn more about Variables:

https://brainly.com/question/2403687

#SPJ4

The estimated area under the graph of f(x) = 5 cos(x) from x = 0 to x = π/2 using four approximating rectangles and right endpoints is approximately 0.8916.

To estimate the area under the graph of f(x) = 5 cos(x) from x = 0 to x = π/2 using four approximating rectangles and right endpoints, we can use the right Riemann sum method.

The width of each rectangle, Δx, is given by the interval width divided by the number of rectangles.

In this case, Δx = (π/2 - 0)/4 = π/8.

To calculate the right endpoint values, we evaluate f(x) at the right endpoint of each rectangle.

For the first rectangle, the right endpoint is x = π/8.

For the second rectangle, the right endpoint is x = π/4.

For the third rectangle, the right endpoint is x = 3π/8.

And for the fourth rectangle, the right endpoint is x = π/2.

Now, let's calculate the area for each rectangle by multiplying the width (Δx) by the corresponding height (f(x)):

Rectangle 1: Area = f(π/8) * Δx = 5cos(π/8) * π/8

Rectangle 2: Area = f(π/4) * Δx = 5cos(π/4) * π/8

Rectangle 3: Area = f(3π/8) * Δx = 5cos(3π/8) * π/8

Rectangle 4: Area = f(π/2) * Δx = 5cos(π/2) * π/8

Now, let's calculate the values:

Rectangle 1: Area = 5cos(π/8) * π/8 ≈ 0.2887

Rectangle 2: Area = 5cos(π/4) * π/8 ≈ 0.3142

Rectangle 3: Area = 5cos(3π/8) * π/8 ≈ 0.2887

Rectangle 4: Area = 5cos(π/2) * π/8 ≈ 0

Finally, to estimate the total area, we sum up the areas of all four rectangles:

Total Area ≈ 0.2887 + 0.3142 + 0.2887 + 0 ≈ 0.8916

Therefore, the estimated area under the graph of f(x) = 5 cos(x) from x = 0 to x = π/2 using four approximating rectangles and right endpoints is approximately 0.8916.

To know more about endpoints refer here:
https://brainly.com/question/31398203#

#SPJ11

Given that John climbs a height of \($(x + 5)$\) miles in \($(x - 1)$\) hours and Jane climbs a height of \($(x + 11)$\) miles in \($(x + 1)$\) hours. We know that the distance covered by both John and Jane are equal.

Distance covered by John = Distance covered by Jane

Therefore, \($(x + 5) = (x + 11)$\)

Thus, x = 6

Now, we need to find the speed of both, which is given by the formulae:

Speed = Distance / Time

So, speed of John = \($(x + 5) / (x - 1)$\) Speed of John =\($11 / 5$\) mph

Similarly, speed of Jane = \($(x + 11) / (x + 1)$\)

Speed of Jane = \($17 / 7$\) mph

Since both have to be equal, Speed of John = Speed of Jane Therefore,

\($(x + 5) / (x - 1) = (x + 11) / (x + 1)$\)

Solving this equation we get ,x = 2Speed of John = \($7 / 3$\) mph

Speed of Jane = \($7 / 3$\) mph

Thus, their speed was \($7 / 3$\) mph.

To know more about distance visit:

https://brainly.com/question/15172156

#SPJ11

Answer:

The value of (f+g)(x) is x^2 + 3x - 11

You can combine this by simply adding the like terms. Start by adding together all of the x^2 terms. Since only g(x) has one of those, we use that in its entirety.

x^2

Next we add together the x terms. f(x) has 7x and g(x) has -4x.

7x + -4x = 3x

Finally, we add together the constants. f(x) has -3 and g(x) has -8.

-3 + -8 = -11

With all of the like terms combined, we simply take the answers and put them together.

x^2 + 3x - 11

Step-by-step explanation:

The difference between the two given temperature values is 24 °F

We have got an equation that can relate these three units of measurement of temperature, as given below:

c/5 = (F - 32)/9= (K - 273)/5

where C represents the measurement of a fixed temperature in celsius, F represents the measurement of that same intensity temperature in fahrenheit, and K represents the measurement of equally intense temperature in kelvin.

The given parameter the lowest temperature = -3 °F

the highest temperature = 21 °F

To determine the difference between the two given temperature values.

The range or difference between the two given temperature values is calculated as follows;

Range = highest - lowest

Range = 21 °F -(-3 °F)

Range = 24 °F

Thus, the difference between the two given temperature values will be 24 °F

Learn more about temperature scale here:

https://brainly.com/question/2919967

#SPJ1

To improve the fairness of a passenger survey on a railway line, it would be ideal to over-sample data from groups that are less likely to be represented in the regular ridership during peak hours of 7:00 am to 5:00 pm. One such group could be passengers who use the railway line during off-peak hours, such as early mornings or late evenings.

Over-sampling these groups will provide a more comprehensive picture of the ridership patterns and preferences of all passengers, rather than just those who use the railway line during peak hours. This approach will lead to a more accurate assessment of the passenger experience and needs and, therefore, allow for better decision-making when it comes to improving services and amenities.

Other groups that could be over-sampled include passengers with disabilities, seniors, and students who may have different transportation needs and experiences compared to the general ridership. By considering the unique experiences and needs of all passengers, railway companies can work towards creating a more inclusive and accessible transportation system.

To know more about Passenger visit :

https://brainly.com/question/30949265

#SPJ11

Do they both open in the same direction and which function is more narrow: A. They both open in the same direction, the function that is graphed is more narrow.

By critically observing the graph of the two absolute value function, we can logically deduce that they both open in the same direction because the coefficient of the absolute value term is positive and their functions are both absolute value functions.

In order to determine which absolute value function is more narrow, we would examine the positive side of both absolute value functions and then determine their minimum point and then the slope as follows;

Slope = (7 - 5)/(4 - 3) = 2/1 = 2.

Therefore, the slope of this graph is equal to 3 while the slope of the absolute value function is equal to 2. So, the graph would rise sharper, and its width would be less (more narrow).

Read more on absolute value function here: brainly.com/question/28308900

#SPJ1

Answer:

Step-by-step explanation: aaaaaaaaaaaaaaaa

Answer:

Step-by-step explanation:

5 - 2t > -4

- 5       - 5

-2t > -9

___  __

 2      2

t = -4.5

Pls mark Brainliest with the crown

Answer:

As shown in picture,

perimeter of inside pentagon: p1 = n + n + n + n + n = 5n

ratio between inside pentagon and outside pentagon: r = 6/(6 + 6) = 1/2

=> perimeter of outside pentagon: p2 = 2 x p1 = 2 x 5n = 10n

=> Option B is correct

Hope this helps!

:)

The 90% confidence interval for the standard deviation of the population is between `2.29` and `4.67`.

To calculate a 90% confidence interval for standard deviation with a sample size of 20, we can use the chi-squared distribution.  

Step 1: Find the chi-squared critical valuesFor a 90% confidence interval, we need to find the chi-squared critical values with 19 degrees of freedom. We can use a chi-squared table or a calculator to find the critical values.

Using a calculator, we can use the following formula: `X²α/2, n-1` and `X²1-α/2, n-1`. Plugging in the values, we get: `X²0.05, 19` = 30.144 and `X²0.95, 19` = 10.117

Step 2: Calculate the confidence interval Now we can calculate the confidence interval using the formula: `sqrt((n-1) × s²) / sqrt(X²α/2, n-1) ≤ σ ≤ sqrt((n-1) × s²) / sqrt(X²1-α/2, n-1)`

Plugging in the values, we get: `sqrt((20-1) × 3.55²) / sqrt(30.144)` ≤ σ ≤ `sqrt((20-1) × 3.55²) / sqrt(10.117)` Simplifying the equation, we get: `2.29` ≤ σ ≤ `4.67`

To know more about standard deviation visit:
brainly.com/question/32083480

#SPJ11

Answer:

Given volume= 32/3 π

Now, we know that volume of sphere = 4/3 π r³ according to the question.

\(\frac{4}{3} \pi r^{3} =\frac{32}{3} \pi\)

Both π and 3 are canceled from both sides

Now,

\(4r^{2} =32\)

Divide both sides by 4

\(r^{3} =\frac{32}{4} =8\)

\(r^{3} =8\)

\(r=(8)^{1/3} =(2\times 2 \times 2)^{1/3}\)

\(r=(2^{3} )^{1/3} =2^{3\times1/3}\)

\(r=2 \; cm\)

Radius of sphere = 2 cm

OAmalOHopeO

A relationship might exist in a sample even though it does not exist in the population, because of b) Sampling error

In statistical analysis, a relationship might appear in a sample even though it does not exist in the population due to sampling error. This occurs when the sample is not fully representative of the population, leading to discrepancies between the sample statistics and the true population parameters.

Sampling error can cause random fluctuations that mistakenly suggest a relationship, which may not be present in the larger population. It is important to consider the limitations and potential sources of error when generalizing findings from a sample to the broader population. So b option is correct.

For more questions like Sampling click the link below:

https://brainly.com/question/29974523

#SPJ11

Answer: 22

Step-by-step explanation:

(7x+5) + (3x-5) + 90 = 180

10x + 90 =180

        -90   -90

10x          =90

_               _

10             10

x = 9  

3(9)-5

27-5

22

Answer:

x = 75

Step-by-step explanation:

\((x + 15) \degree = 90 \degree \\ (corresponding \: \angle s) \\ \\ x + 15 = 90 \\ \\ x = 90 - 15 \\ \\ x = 75\)

Answer:

x=75

Step-by-step explanation:

Both angles are right angles. Right angles are 90 degrees.

step 1: x+15=90

step 2: x+15=90

               -15  -15

step 3: x=75

Inscribed angles are formed when two chords have 1 common endpoint. The measure of \(\angle ACB\) and \(\overset{\huge\frown}{AC}\)  are:

\(\angle ACB = 32^o\)

\(\overset{\huge\frown}{AC} = 146^o\)

Given that:

\(\overset{\huge\frown}{AB} = 64^o\)

\(\angle ABC = 73^o\)

See attachment

First, we calculate \(\angle ACB\) using:

\(\angle ACB = \frac{1}{2} \times \overset{\huge\frown}{AB}\) ----- An inscribed angle is half the arc it intercepts

So, we have:

\(\angle ACB = \frac{1}{2} \times 64^o\)

\(\angle ACB = 32^o\)

Using the same theorem, we calculate \(\overset{\huge\frown}{AC}\) as follows:

\(\angle ABC = \frac{1}{2} \times \overset{\huge\frown}{AC}\)

So, we have:

\(73^o = \frac{1}{2} \times \overset{\huge\frown}{AC}\)

Multiply both sides by 2

\(2 \times 73^o = 2 \times \frac{1}{2} \times \overset{\huge\frown}{AC}\)

\(2 \times 73^o =\overset{\huge\frown}{AC}\)

\(146^o =\overset{\huge\frown}{AC}\)

Hence:

\(\overset{\huge\frown}{AC} = 146^o\)

Read more about inscribed angles at:

https://brainly.com/question/15899344

Answer:

your correct answers are 32 and 146

Step-by-step explanation:

to get 32, divide 64 by 1/2

To get 146, multiply 73 by 2

Hope I helped, got it right on test:)

Answer:

-3

Step-by-step explanation:

Based on his weekly salary and commission, we can calculate that Mr. Randall sold goods worth $1,800.

In the formula given, sales is represented as s. To find the total sales, you can solve the equation:

300 + 0.07s = 426

0.07s = 426 - 300

s = 126 / 0.07

= $1,800

In conclusion, Mr. Randall sold $1,800 worth of goods.

Find out more at https://brainly.com/question/19297414.

Answer:

3.50 × 12 = 42

Therefore, she spent 42 dollars.

Answer:

d = 5\(\sqrt{2}\) +  5\(\sqrt{2}\)  = 10 \(\sqrt{2}\)

Step-by-step explanation:

A = πr²

50π = πr²

50 = r²

\(\sqrt{50}\) = r

\(\sqrt{25}\)· \(\sqrt{2}\) = radius

2(5\(\sqrt{2}\)) = diameter

10\(\sqrt{2}\) = diameter

Answer:

A

Step-by-step explanation:

Expressing the identity in terms of a and b

(a + b)³ = a³ + b³ + 3ab(a + b)

Subtract 3ab(a + b) from both sides , then

a³ + b³ = (a + b)³ - 3ab(a + b) ← substitute given values

a³ + b³ = 12³ - 3(7)(12) = 1728 - 252 = 1476

Step-by-step explanation:

I hope you get it. you have to substitute and also find the value of a3 + b3

Answer:

-250

Step-by-step explanation:

It was right on edge

Answer:

The answer is -250

Step-by-step explanation:

it was on edge and i got it right