-1/4 divided by (-7/9)

Step-by-step explanation:

everything can be found in the picture

Answer:

II only

Step-by-step explanation:

2x+4>8

2x>4

x>2

It can't be 2 or -5

It can only be I. if the inequality sign is > or = too

To find the mass of the box, we need to use the formula:
Work = force x distance
Power = work / time
We know the power used by Jake is 1,074 W and the distance he lifted the box is 1.7 m. Therefore, the work done by Jake is:
Work = power x time
Work = 1,074 W x 6.04 s
Work = 6,494.96 J
Next, we need to find the force used by Jake to lift the box. We can do this by rearranging the first formula:
Force = work / distance
Force = 6,494.96 J / 1.7 m
Force = 3,823.50 N
Finally, we can find the mass of the box by using the formula:
Force = mass x gravity
where gravity is approximately 9.81 m/s².
Mass of the box = Force / gravity
Mass of the box = 3,823.50 N / 9.81 m/s²
Mass of the box = 389.52 kg

Therefore, the mass of the box that Jake lifted is approximately 389.52 kg.

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Answer:

scale factor of 1/3 from the big rectangle to the small rectangle

Step-by-step explanation:

Hope this helps! Please mark me as brainliest:)

The largest integer function is a function that returns the largest integer less than or equal to a given number.

The maximum integer function is also called the step function. Rounds a number up to the nearest integer less than or equal to a specified number. The largest integer function has a step curve. This will be explained in the next section. The domain of the largest integer function is ℝ and its range is ℤ.

Therefore, the greatest-integer function simply truncates a given number to the largest integer less than or equal to the given number. The largest integer less than or equal to number x is represented as ⌊x⌋. A specified number is rounded to the nearest integer less than or equal to that number. Mathematically, the largest integer function ⌊x⌋ can be defined as:

⌊x⌋ = n, where n ≤ x < n + 1, and 'n' is an integer.

The largest integer function has its domain as the set of all real numbers (ℝ), but its domain is the set of all integers (ℤ).

The maximum integer function has many properties. Some of the important properties are listed below.

Maximum Function Graph:

Graphs of maximal integer functions are known as staircase curves because of the staircase structure of the curve. Let's draw a maximum integer function graph. First consider f(x) = ⌊x⌋. If x is an integer, then the value of f is just x. If x is not an integer, then the value of x is the integer just before (to the left of) x.

For example,

The value of f is 0 for all numbers in the interval [0, 1).

f assumes a value of 1 over the interval [1, 2).

In the interval [−1, 0), f takes the value -1, and so on.

Therefore, for an integer n, all numbers in the interval [n, n+1) have values ​​of integer functions greater than n. The function has a constant value between any two integers. As soon as the next integer comes, the function value jumps one unit. This means that the value of f at x = 1 is 1 (not 0), so there is an empty dot at (1, 0) and a filled dot at (1, 1) . Empty dots contain no value and filled dots represent values. These observations lead to the following graph.

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the pH of the buffer is 3.74

To calculate the pH of a buffer containing 0.13 M lactic acid and 0.10 M sodium lactate, we will use the Henderson-Hasselbalch equation:

pH = pKa + log10([A-]/[HA])

Here, [A-] represents the concentration of the conjugate base, which is sodium lactate, and [HA] represents the concentration of the weak acid, which is lactic acid. Ka is given as 1.4 × 10⁻⁴.

First, we need to find the pKa. Since pKa = -log10(Ka):

pKa = -log10(1.4 × 10⁻⁴) = 3.85

Now, we can plug the values into the Henderson-Hasselbalch equation:

pH = 3.85 + log10(0.10 / 0.13)
pH = 3.85 + log10(0.769)
pH = 3.85 - 0.11 (approximately)

pH = 3.74

The pH of the buffer is approximately 3.74.

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Answer:

a/8 or a over 8 hope this helps

Step-by-step explanation:

Answer:

n

8

→

I used

n

as the unknown number

Explanation:

The quotient is the result of division between two numbers.

The quotient of a number (I used

n

) and

8

would be

n

8

The Poisson probability model is most nearly appropriate to describe the number of burned-out fluorescent tubes. So, the correct answer is B.

The Poisson distribution is the probability distribution of independent events that occur at a continuous rate within a fixed interval of time or space. It is a probability distribution used to determine the likelihood of a specific number of events occurring in a set amount of time or space.

For instance, the number of misprints in a book or the number of cars that pass through a particular crossroads in a minute are typical Poisson distribution examples.

The Poisson distribution is appropriate when the following assumptions are met:

The events are independent of one another, meaning that one occurrence does not influence the probability of another occurrence occurring. The event rate is stable, which means that the event rate is constant throughout the observed interval. The events are random and isolated.

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Answer:

Train A weights 475 tons and Train B weights 26 pounds

Step-by-step explanation:

475 - 449 = 26

26 is the weight of Train B

475 is the weight of Train A

This is true because

475 + 26 = 501

Answer:

Domain: { 2,3,4,5}

Step-by-step explanation:

The domain is the inputs to the function

In this case it is the x values

Domain: { 2,3,4,5}

Answer:

C. (2,3,4,5)

Step-by-step explanation:

The domain is x and the range is y.

The value of tensions are:

T₁ = 231/74

T₂ = -329/66

T₃ = 8/33

We can use Gaussian elimination to solve the system of equations:

5T₁ + 3T₂ + 5T₃ = 70

T₁ + 2T₂ + 4T₃ = 24

4T₁ + 2T₂ = 40

First, we'll use the third equation to eliminate T₂ from the first two equations:

4T₁ + 2T₂ = 40   (equation 3)

T₁ + 2T₂ + 4T₃ = 24   (equation 2)

Multiplying the third equation by 2 and subtracting it from the second equation:

T₁ + 2T₂ + 4T₃ = 24   (equation 2)

- 8T₁ - 4T₂ = -80   (2 × equation 3)

------------------------

-7T₁ + 4T₃ = -56

Now we have two equations:

5T₁ + 3T₂ + 5T₃ = 70   (equation 1)

-7T₁ + 4T₃ = -56   (from previous step)

Multiplying the first equation by 7/5 and adding it to the second equation:

5T₁ + 3T₂ + 5T₃ = 70   (equation 1)

-7T₁ + 4T₃ = -56   (from previous step)

------------------------

T₁ + 7T₃ = 14

Now we can use the third equation to eliminate T₂ from the first equation:

4T₁ + 2T₂ = 40   (equation 3)

5T₁ + 3T₂ + 5T₃ = 70   (equation 1)

Multiplying the third equation by 3/2 and subtracting it from the first equation:

4T₁ + 2T₂ = 40   (equation 3)

-11T₁ - T₃ = -35   (3 × equation 3 - 5 × equation 1)

Now we have two equations:

T₁ + 7T₃ = 14   (from previous step)

-11T₁ - T₃ = -35   (from this step)

Multiplying the second equation by -7 and adding it to the first equation:

T₁ + 7T₃ = 14   (from previous step)

74T₁ = 231

Therefore, T₁ = 231/74.

Substituting this value back into the equation T₁ + 7T₃ = 14, we get:

(231/74) + 7T₃ = 14

7T₃ = (74/231) × 20

T₃ = 8/33

Finally, substituting T₁ = 231/74 and T₃ = 8/33 into the equation -11T₁ - T₃ = -35, we get:

-11(231/74) - (8/33) = -329/66

Therefore, T₂ = -329/66.

So, the tensions are: T₁ = 231/74 T₂ = -329/66 T₃ = 8/33

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Since 66 is closer to 72.25 than 81, we can conclude that the best approximation of the value of √66 is approximately 8.15.

An approximation is a value or estimate that is close enough to the true value of a quantity or measurement, without being exact or precise. It is often used when it is difficult or impractical to find the exact value, or when an approximate value is sufficient for a particular purpose. Approximations are commonly used in mathematics, science, engineering, finance, and many other fields, and there are various methods and techniques for making approximations, such as rounding, truncation, estimation, and numerical methods.

Here,

The best approximation of the value of √66 is between 8 and 9, since 8²=64 and 9²=81. To get a more precise approximation, we can take the average of 8 and 9:

(8 + 9)/2 = 8.5

Now, we can check whether √66 is closer to 8.5 or 9 by squaring each number and comparing to 66:

8.5² = 72.25

9² = 81

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Answer:

B. 66.7 cm^2

Step-by-step explanation:

A= b x h

A= 11.5 x 5.8

A= 66.7

The number of hours Jackson worked washing cars is 8 hours and the number of hours he worked landscaping is 6 hours

The payment of car washing per hour = $10

The payment for landscaping = $12

Total number of hours worked = 14  hours

Number of hours worked in car washing = x

Number of hours worked in landscaping = y

Then the first equation will be

x + y = 14

x = 14 - y

Total amount he earned = $152

Next equation will be

10x + 12y = 152
Here we have to use substitution method

10(14-y) + 12y = 152

140 - 10y +12y = 152

140 + 2y = 152

2y = 152 - 140

2y = 12

y = 12/2

y = 6 hours

Then

x = 14 - y

x = 14 -6

x = 8  hours

Hence, the number of hours Jackson worked washing cars is 8 hours and the number of hours he worked landscaping is 6 hours

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Answer:

Line h is y = -(1/14)x + (8/7)

Step-by-step explanation:  A perpendicular line will have a slope that is the negative inverse of the reference line.  The reference line in this problem is y=14x-44.  The slope of 14 is inverted to 1/14 and multiplied by -1 to yield a new slope of -(1/14) for the perpendicular line.  The perpendicular line will have the form of y = -(1/14)x + b.

Any value of b will still result in a line perpendicular to y=14x-44.  But we want a line for h that goes through point (-2,1).  To find a value of b that moves the line so that it intersects (-2,1), substitute the value (-2,1) for (x,y) in the equation y = -(1/14)x + b, and then solve for b.

 y= -(1/14)*(x)  + b

 1 = -(1/14)*(-2)  + b     for (-2,1)  

 1 = (2/14) + b

   1- (1/7) = b

 b = (6/7)

The equation for line h  becomes y = -(1/14)x + (6/7)                                                

See the attached worksheet.

Answer: x+14y=12

Step-by-step explanation: got this off an assignment on mcgrawhill still dont know how to get that tho good luck

Answer:

12/3=16/p hsjsjnaoanw

a) The range of the given data is 251 - 170 = 81. b) Therefore, the variance is approximately equal to 128.891. c) Therefore, the standard deviation is approximately equal to √128.891 = 11.347 units.

To find the variance, we first need to find the mean. Sum of the given scores = 232 + 185 + 199 + 202 + 177 + 251 + 170 + 225 = 1651. The mean of the given data is 1651/8 = 206.375. Now, we can find the variance using the formula: Variance = (Σ(xᵢ - μ)²)/n where Σ denotes the sum, xᵢ represents each data point, μ represents the mean, and n represents the number of data points. Substituting the values, we get: Variance = ((232 - 206.375)² + (185 - 206.375)² + (199 - 206.375)² + (202 - 206.375)² + (177 - 206.375)² + (251 - 206.375)² + (170 - 206.375)² + (225 - 206.375)²)/8= (625.5 + 441.9844 + 49.8906 + 18.1406 + 903.8906 + 1906.8906 + 1398.8906 + 336.8906)/8= 1031.125/8= 128.890625. The standard deviation is the square root of the variance. The given data represents the scores of an avid bowler Spacey Tracey. We are required to find the range, variance and standard deviation of the sample scores. The range of the data is 81, variance is approximately equal to 128.891 and standard deviation is approximately equal to 11.347 units. The variance was found using the formula ((Σ(xᵢ - μ)²)/n) and the standard deviation is the square root of the variance.

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Given that,

Then,

Therfore,

In a boxplot, potential outliers are data points that are more than 1.5 Interquartile Ranges (IQRs) from the edges of the box. A boxplot visually represents the distribution of a dataset, with the box containing the middle 50% of the data and the edges representing the lower and upper quartiles.

To answer your question, potential outliers in a boxplot are points that are more than 1.5 times the interquartile range (IQR) away from the edges of the box. The IQR is the difference between the third quartile (75th percentile) and the first quartile (25th percentile) of the data. The box in a boxplot represents the IQR, with the median (50th percentile) marked by a line inside the box. The whiskers of the boxplot extend to the minimum and maximum values that fall within 1.5 times the IQR from the edges of the box. Any points outside this range are considered potential outliers and are plotted as individual points beyond the whiskers. However, it is important to note that potential outliers do not necessarily indicate errors or incorrect data, and further investigation may be needed to determine their validity. Overall, boxplots are a useful tool for visualizing the spread and distribution of numerical data.

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The correct statement is that Joe performed worse than Eric.

To determine which student performed better, we need to compare their standardized scores. Joe's math score of 160 in class A has a mean (μ) of 150 and a standard deviation (σ) of 20. We calculate the z-score for Joe's score as follows:

z = (160 - 150) / 20 = 0.5

On the other hand, Eric's verbal score in class B is 80, with a mean (μ) of 72 and a standard deviation (σ) of 8. The z-score for Eric's score is calculated as:

z = (80 - 72) / 8 = 1

Comparing the z-scores, we find that Eric has a larger standardized score (z = 1) compared to Joe's score (z = 0.5).

This indicates that Eric's score is relatively higher compared to the mean and standard deviation of his class, suggesting better performance.

Therefore, the correct statement is that Joe performed worse than Eric.

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Answer:

90

Step-by-step explanation:

Given

Number of questions in an english exam = 10

Find

Number of different sets of 4 questions are available.

Explanation

as we have given that a student must choose 4 of the 10 questions.

so , number of different set of 4 questions are available =

so ,

Final Answer

Hence , the number of different sets of 4 questions are available are 210

Answer:

\(16\)

Step-by-step explanation:

\( {x}^{2} - 8x + c\)

\( {x}^{2} + c - 8x\)

To find the c value \(c = ( \frac{b}{2})^{2} \) , divide the coefficient of x by 2 and square the result.

\(( - 1 \times 4 {)}^{2} \)

\(( - 4 {)}^{2} \)

\(16\)

1968 of the $10 dollar ticket were sold by jazz & 6873  of the $20 dollar ticket were sold by jazz.

Jazz total amount received = $157,437

Total tickets sold = 8,856

Let the $10 tickets sold = x

The $20  tickets sold = 8,856 - x

Here the solution below :

$10(x) + 8,856 - x($20) = $157,437

$10x + $177120 - $20x = $157,437

-$10x = $157,437 - $177120

-$10x = - $19683

x = 1968.3

1968 of the $10 dollar ticket were sold by jazz & 6873  of the $20 dollar ticket were sold by jazz.

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Answer:

m= -9

Step-by-step explanation:

Hope this helps

Answer:

416, I believe this is the answer.

Step-by-step explanation:

483 - 67 = 416

Foram vendidos 416 hambúrgueres na quinta-feira

I assume you mean β in place of 8.

Remember that tangent is defined as

tan(β) = sin(β) / cos(β)

so that

cos(β) = sin(β) / tan(β) = (-4/5) / (4/3) = -3/5 … … … [D]

The total number of boxes of canned food brought in by the three grades is 5.75 + 6.5 + 713 = 725.25 boxes.

To calculate the total number of boxes of canned food brought in by the three grades, we add the quantities brought in by each grade.

The 6th graders brought in 5.75 boxes of canned food. The 7th graders brought in 6.5 boxes of canned food. And the 8th graders brought in 713 boxes of canned food.

To find the total, we add these quantities: 5.75 + 6.5 + 713 = 725.25.

The sum, 725.25, represents the total number of boxes of canned food brought in by the three grades.

It's important to note that the total number of boxes is not a whole number but includes a fraction, as indicated by the decimal .25. This could be due to partial boxes or fractional contributions from the students.

Therefore, the total number of boxes of canned food brought in by the three grades is 725.25 boxes.

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The percent of decrease in his reading is 75%

What is Percentage Decrease?

Percrntage Decrease is the change from one amount to a lesser amount in terms of percent decrease.

Percentage decrease = (Starting value - Ending value) / Starting value x 100

where Starting value = 8

Ending value = 2

Percentage decrease = 8 - 2 /8 * 100

Percentage decrease = 6/8 *100

Percentage decrease = 75%

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