12. The following table gives the frequency of simultaneous occurrence for two categorical variables A and B out of 82 measurements. Each variable has two levels marked by A₁ and A₂ for the variab

The energy required to convert 85 kg of ice to water is 2.856 MJ.

The increment in temperature adds up the thermal energy into the object. This energy is Heat energy.

Given is the mass of ice = 85 kg

For a phase change, latent heat of fusion, L = 33600 J/K is required to convert ice into water.

Q =mL

Q = 85 x 33600 J/K

Q = 2856000 Joules.

Q = 2.856 MJ

Thus, the energy required to convert 85 kg of ice to water is 2.856 MJ.

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Answer:

40.8 m North West.

Explanation:

Please see attached photo for diagram.

In the attached photo, R represent the displacement of the dog.

The displacement (R) of the dog can obtained by using the pythagoras theory as illustrated below:

R² = 35² + 21²

R² = 1225 + 441

R² = 1666

Take the square root of both side.

R = √1666

R = 40.8 m North West.

Therefore, the displacement of the dog is 40.8 m North West.

Answer:

\(a=0.1\ m/s^2\)

Explanation:

Given that,

Initial velocity, u = 0

Final velocity, v = 2 m/s

Time, t = 20 s

We need to find the acceleration of the swimmer. The acceleration of an object is equal to the change in velocity per unit time. It can be given by :

\(a=\dfrac{v-u}{t}\\\\a=\dfrac{2\ m/s}{20\ s}\\\\a=0.1\ m/s^2\)

So, her average acceleration of the swimmer is \(0.1\ m/s^2\).

Answer: The ability to do work.

Explanation: Scientists define energy as the ability to do work. There is potential energy (where an object at rest has the capacity to have motion) and kinetic energy (where an object is in motion).

Answer:

The final velocities of the blocks are 3.00 m/s and 8.50 m/s, respectively.

Answer: It is the product of the (force)multiplied by the (perpendicular) distance from the line of action of the force to the pivot

Explanation:

The antenna should be approximately 91.46 meters tall for a station broadcasting at a frequency of 820 kHz

To determine the height of an antenna that is λ/4 tall for a station broadcasting at a frequency of 820 kHz, you will first need to find the wavelength of the radio waves.

Step 1: Convert the frequency to Hz.
Frequency = 820 kHz = 820,000 Hz

Step 2: Use the formula for the speed of light (c) to find the wavelength (λ).
c = λ * frequency, where c is the speed of light (approximately 3 x 10^8 m/s).

Step 3: Rearrange the formula to solve for λ.
λ = c / frequency

Step 4: Calculate the wavelength.
λ = (3 x 10^8 m/s) / (820,000 Hz) ≈ 365.85 meters

Step 5: Find the antenna height.
Antenna height = λ/4 = 365.85 meters / 4 ≈ 91.46 meters

The antenna should be approximately 91.46 meters tall for a station broadcasting at a frequency of 820 kHz.

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The coefficient of static friction between the tires and the road must be at least 0.61 for a car to round a level curve of radius 130 mm at a speed of 118 km/h.

The centripetal force required for a car to negotiate a level curve is provided by the force of friction between the tires and the road. This force is given by the formula:

f = mv²/r

Where f is the centripetal force, m is the mass of the car, v is its velocity, and r is the radius of the curve.

For the car to successfully round the curve, the force of friction between the tires and the road must be greater than or equal to this centripetal force. The maximum force of static friction between the tires and the road is given by:

Fₛ = μsN

Where μs is the coefficient of static friction, and N is the normal force.

The normal force is equal to the weight of the car, which is given by:

N = mg

Where g is the acceleration due to gravity.

Combining the above equations, we get:

μs ≥ v²/(rg)

Substituting the given values, we get:

μs ≥ (118×10³/3600)² / [(130/1000)×9.81]

μs ≥ 0.61

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Answer:

The resistance of a thin wire is greater than the resistance of a thick wire because a thin wire has fewer electrons to carry the current. The relationship between resistance and the area of the cross section of a wire is inversely proportional .

The best way to think about this is:

A thick/wide road, with many lanes, can carry more cars than a thin/narrow road, with only one or two lanes.

A) It takes 2.22 × 10^-6 s until the capacitor is fully discharged.

B) The inductor current at that time is 2.31 × 10^-4 A.

Explanation:-

An LC circuit is built with a 20 mH inductor and an 8.0 pF capacitor.

The capacitor voltage has its maximum value of 25 V at t = 0s, and you need to determine the following:

A)The circuit's resonant frequency, f0 can be calculated by using the following equation:

f0 = 1/2π√LC

Where, L = 20 mH = 20 × 10^-3 H and C = 8.0 pF = 8 × 10^-12 F.

So, f0 = 1/2π√(20 × 10^-3)(8 × 10^-12)

= 1/2π√160 × 10^-15

= 1/2π(4 × 10^-8)

= 1/8π × 10^-8

= 3.98 × 10^6 Hz.

A time constant is given by

τ = 1/2πf0 = 1/2π × 3.98 × 10^6 = 3.98 × 10^-7 s.

The capacitor voltage falls to 0.5 the maximum value in one time constant τ, which is equal to 3.98 × 10^-7 s.

Hence, the time it takes for the capacitor to be fully discharged, tc can be calculated as follows:

ln(V0/Vc) = - tc/τ

Where, V0 is the maximum voltage, Vc is the voltage when the capacitor is fully discharged, τ is the time constant, and tc is the time to fully discharge Vc.

Rearranging the equation gives:

tc = - τ ln(Vc/V0) = - (3.98 × 10^-7) ln(0.5/25)

= 2.22 × 10^-6 s.

B) The current through an LC circuit is given by:

i = Io e-t/τsin(2πft)where i is the current, Io is the initial current, t is the time, τ is the time constant, and f is the frequency.

The current through the inductor is at its maximum value when the capacitor is fully discharged. When the capacitor voltage is maximum, the current through the inductor is zero.The initial current Io can be calculated from the maximum voltage of the capacitor and the capacitive reactance as follows:

Io = Vc/Xc

where, Vc is the maximum voltage of the capacitor and Xc is the capacitive reactance.

Xc can be calculated from the capacitive reactance equation:

Xc = 1/2πf0C = 1/2π(3.98 × 10^6)(8 × 10^-12) = 4.98 × 10^5 Ω

Substituting values,

Io = 25/4.98 × 10^5 = 5.02 × 10^-5 A

Therefore, the current through the inductor when the capacitor is fully discharged is given by:

i = Io e-t/τsin(2πft)

i = 5.02 × 10^-5 e-2.22 × 10^-6/3.98 × 10^-7 sin(2π(3.98 × 10^6)(2.22 × 10^-6))i

= 2.31 × 10^-4 A (rounded to three significant figures).

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When an airplane travels 640 miles from Topeka to Houston in 3. 2 hours, going against the wind. The return trip is with the wind and takes only 2 hours. Then the rate of the airplane with no wind is 260 miles/hr, and the rate of the wind is 100 miles/hr

Let Va is the velocity of the airplane

Va is the velocity of the wind

When flying against the wind then

(Va+Vw)*(3.2 hours) = 640

3.2Va + 3.2Vw = 640

3.2Vw = 640 - 3.2Va

Vw = 200 - Va----------------(1)

When flying with the wind:

(Va-V)*(2 hours) = 640km

2Va - 2Vw = 640

Va - Vw = 320 ----------------(2)

Putting the value of VW in equation (2) we get

Va - (200-Va) = 320

2Va = 320 +200

2Va = 520

Va = 260

Putting this value in equation (2)

Vw =Va - 360

Vw = 100

Therefore the rate of the airplane with no wind is 260 miles/hr, and the rate of the wind is 100 miles/hr

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When a car rounds a curve, it experiences a centripetal acceleration towards the center of the curve. The magnitude of this acceleration depends on the speed of the car and the radius of the curve. The magnitude of the car's acceleration is  \(5.0 m/s^2\), which is option (C).

We can use the centripetal acceleration formula to solve this problem:

a =\(v^2 / r\)

where a is the centripetal acceleration, v is the speed of the car, and r is the radius of the curve.

Plugging in the given values, we get:

a =\((10 m/s)^2 / 20 m\)

a = \(5 m/s^2\)

Therefore, the magnitude of the car's acceleration is \(5.0 m/s^2\),  which is option (C).

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Answer:

2.066 atm

Explanation:

PV = nRT      increase T    volume and n and R remain constant

30 C = 303.15 K      40 C = 313.15

P  prop to T      new P   will be   313.15/303.15 * 2 atm = 2.066 atm

Answer:

mass X velocity

Explanation:

The momentum of a body is the product of its mass and velocity

Answer:

6,400

Explanation:

i made sure  the other person was right and i got the same answer

Answer: It goes inside filling most of it .

Explanation: This happens because the bottle is empty and the bucket is full of water.

The solution to the equation ln(x) = x - 31, correct to six decimal places, is x ≈ 24.662174.

Newton's method, also known as Newton-Raphson method, is an iterative numerical method used to find the roots of a real-valued function. It is a powerful algorithm for finding solutions to equations where it may be difficult or impossible to obtain an analytical solution.

To find the solutions of the equation ln(x) = x - 31 using Newton's method, we start by rearranging the equation to f(x) = ln(x) - x + 31 = 0.

Next, we need to choose an initial guess for the solution, let's say x0 = 20.

Then, we can use the Newton's method iterative formula:

xn+1 = xn - f(xn)/f'(xn)

where f'(x) is the derivative of f(x).

For our equation, f'(x) = 1/x - 1.

Let's perform the iterations:

x1 = x0 - (ln(x0) - x0 + 31) / (1/x0 - 1)

x1 = 20 - (ln(20) - 20 + 31) / (1/20 - 1)

x1 ≈ 24.660633

x2 = x1 - (ln(x1) - x1 + 31) / (1/x1 - 1)

x2 ≈ 24.662174

x3 ≈ 24.662174

Performing additional iterations, we find that the value of x converges to approximately 24.662174.

Therefore, the solution to the equation ln(x) = x - 31, correct to six decimal places, is x ≈ 24.662174.

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Answer:

2.2 s

Explanation:

His vertical initial velocity  u =0

vertical displacement h = 24 m .

vertical acceleration g = 9.8 m /s²

h = ut + 1/2 gt²

24 = 1/2 x 9.8 x t²

t = 2.2 s .

Time of fall = 2.2 s

To solve this we must be knowing each and every concept related to  sound waves. Therefore, a sound waves change as they spread out in a spherical pattern, they go up and down.

A sound is a type of energy or a vibration that moves through a material such as air or water. Sound may pass through with a gaseous medium as well. It is anything that is audible. The speed that sound varies depending on the medium.

A wave is a medium that transmits energy from one location to another. Waves are classified into three types: transverse waves, longitudinal waves, or surface waves. A sound waves change as they spread out in a spherical pattern, they go up and down.

Therefore, a sound waves change as they spread out in a spherical pattern, they go up and down.

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Answer:

\(\large \boxed{\text{761 kJ}}\)

Explanation:

You calculate the energy required to break all the bonds in the reactants.

Then you subtract the energy needed to break all the bonds in the products.

                        N₂  +   O₂   ⟶         2NO

                     N≡N  + O=O ⟶       2O-N=O

Bonds:         2N≡N   1O=O        2N-O + 2N=O

D/kJ·mol⁻¹:     941      495           201      607

\(\begin{array}{rcl}\Delta H & = & \sum{D_{\text{reactants}}} - \sum{D_{\text{products}}}\\& = & 2 \times 941 +1 \times 495 - (2 \times 201 + 2\times 607)\\&=& 2377 - 1616\\&=&\textbf{761 kJ}\\\end{array}\\\text{The enthalpy of reaction is $\large \boxed{\textbf{761 kJ}}$}.\)

By definition, protons are charged particle with positive charge. Protons are held toguether at the atomic nuclues do the strong nuclear force.

Then, you have:

Protons have a positive charge and are held toguether by the strong nuclear force.

Answer:that's 16 I think Explanation:

Answer:

It is either 16 or 17

Explanation:

:)

Answer:

.21

Explanation:

i see everyone got it wrong so ill give you the answer, good luck :)

Answer: How it was created, The frequency of the waves, and is the water salty enough to kill someone.

Explanation:

Just from my brain.

Answer: the ecosystem , differnt species of fish, and ship wrecks

Explanation:

:)

Answer:

BRAINLIEST PLSSSSSSSSSSSSSSSSSSSSSSSS

Thermodynamics

Explanation:

Thermodynamics is the study of energy. First Law of Thermodynamics: Energy can be changed from one form to another, but it cannot be created or destroyed. The total amount of energy and matter in the Universe remains constant, merely changing from one form to another.

Two cars, each having a mass of 1,000 kg are being tested at the Department of Highway Safety facility. Car A is moving at 30 m/s to the north. Car B is moving at 15 m/s to the south. When they collide a- Car A applies a greater force on car B than car B applies on car A.

Momentum, product of the mass of a particle and its velocity. Momentum is a vector quantity; i.e., it has both magnitude and direction. Isaac Newton's second law of motion states that the time rate of change of momentum is equal to the force acting on the particle.

When both the cars will collide , one with greater momentum will applies greater force .

As momentum is calculated  as mass multiplied by velocity , since both the car have same mass then the car with a greater velocity will exert more force on the other car .

since , car A has a velocity of 30 m/s and car B is moving with a velocity of 15 m/s , then car A will have greater momentum and will exert  a greater force on car B.

correct option will be

a- Car A applies a greater force on car B than car B applies on car A.

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