Answer:D
Step-by-step explanation:
√81 - √25 = 9 - 5 = 4
√64 + √25 = 8 + 5 = 13
√64 - 31 = 8 - 31 = -23
Amelia took a taxi from her house to the airport. The taxi company charged a pick-up fee of $4.60 plus $0.50 per mile. The total fare was $13.60, not including the tip. Write and solve an equation which can be used to determine m, the number of miles in the taxi ride.
Answer: 4.6+.5m=13.60 , m=18
Step-by-step explanation:
4.6+.5m=13.60
.5m=13.60-4.6
.5m=9
m=18
pls help will give brainliest when i can
A number cube has sides labeled 1 to 6. Gia rolls the number cube. What is the probability that she rolls a 4?
Group of answer choices
A number cube has sides labeled 1 to 6. Gia rolls the number cube. What is the probability that she rolls a 4?
Group of answer choices
Answer:
1/6
Step-by-step explanation:
There are six possible values of her roll...if is a fair die '4' will have a 1 out of 6 chance of being rolled
Answer:
There is a 1 in 6 chance (1/6) chance Gia lands on 4
Step-by-step explanation:
A worker in a silver mine descends 26 feet use an integer to represent the change in the workers position
Answer: -26 feet
Step-by-step explanation:
Prove that a median in a right triangle joining the right angle to the hypothenuse has the same length as the segment connecting midpoints of the legs. Hint: You may want to show first that this median equals half the hypotenuse.
A median in a right triangle joining the right angle to the hypothenuse has the same length as the segment connecting the midpoints of the legs.
The median equals half the hypotenuse
In triangle ABC where ∠B = 90° BD is median
AD = DC median divides into two equal part
DX ⊥ BC
BX = XC = BC/2
DX = AB/2
By Pythagorean theorem
BD² = DX² + BX²
BD² = BC²/4 + AB²/4
BD² = AC²/4
BD = AC/2
Now in triangles BXD and DXC
DX = DX ( common )
AB║ DX
∠BXD = ∠DXC (as corresponding angles )
BX = XC (corresponding side)
By SAS congruency
ΔBXD ≅ ΔDXC
BD = DC
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PLEASE HELP !!!! Give an example of
Slove for y9/4y-12=1/4y-4
we have the expression
\(\frac{9}{4}y-12=\frac{1}{4}y-4\)Solve for y
That means
Isolate the variable y
so
step 1
Multiply by 4 both sides to remove the fractions
\(9y-48=y-16\)step 2
subtract y both sides
\(\begin{gathered} 9y-48-y=y-16-y \\ 8y-48=-16 \end{gathered}\)step 3
Adds 48 both sides
\(\begin{gathered} 8y-48+48=-16+48 \\ 8y=32 \end{gathered}\)step 4
Divide by 8 both sides
\(\begin{gathered} y=\frac{32}{8} \\ y=4 \end{gathered}\)therefore
the value of y=4a A Straight line passes through A(-2,1) and B(2,-k). The
line is perpendicular to a line 3y+2x=5 . determine k
Given :
A Straight line passes through A(-2,1) and B(2,-k).
The line is perpendicular to a line 3y+2x=5 .
To Find :
The value of k.
Solution :
Let, slope of line is m.
We know, product of slope of in straight line is -1.
\(m \times \dfrac{-2}{3} = -1\\\\m = \dfrac{3}{2}\)
We know, slope is given by :
\(\dfrac{y_2-y_1}{x_2-x_1} = \dfrac{3}{2}\\\\\dfrac{1-(-k)}{-2 - 2} = \dfrac{3}{2}\\\\\dfrac{1+k}{-4} = \dfrac{3}{2}\\\\k = -7\)
Therefore, the value of k is -7.
The average of Landry’s test scores must be at least 92 for her to make an A in Algebra class. She got a 95 on her first test. What grade can Landry get on her second test to make an A in the class?
Average is determined by the sum of test scores divided by total number of tests. This can be represented in this equation:
95 + X / 2 = 92 ⇒ Multiply both sides by 2 to get of the divided by 2
95 + X /2 (2) = 92 (2)
95 + X = 184 ⇒ Subtract 95 from both sides to isolate x
95 -95 + X = 184 -95
X = 89
Therefore, they must get at least 89% to maintain an A.
for what values of x and y are the triangles congruent by HL?
For the given congruent triangles, the values of x = -1 and y = 3.
What do you mean by congruence of triangle?Two triangles are congruent if all three corresponding sides are equal and all three corresponding angles are equal. These triangles can be moved, rotated, flipped, and flipped to look identical. When rearranged they match each other.
The congruence symbol is "≅".As both the triangles are congruent therefore their corresponding sides will be equal.
3y + x = y + 5 ...........(1)
y - x = x + 5 ..............(2)
Equation
1:3y + x = y + 5
3y - y = 5 - x
2y = 5 - x
x = 5 - 2y ..............(3)
Substitute this value of x in equation (2)
y - x = x + 5 y = x + x + 5y
= 2x + 5 y = 2(5 - 2y) + 5y
= 10 - 4y + 54y + y = 15
5y = 15 y = 15/ 5
y = 3
Substitute this value of y in equation (3) x = 5 - 2(3) = 5 - 6 = -1
Therefore, x = -1 and y = 3
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solve the linear equation 4x-(2x-1)=x+5+x-6
The linear equation doesn't have a solution.
How to compute the value?The linear equation given is illustrated as: 4x-(2x-1) = x+5+x-6
This will be solved thus:
4x - 2x + 1 = x+5+x-6
4x - 2x + 1 = 2x - 1.
2x + 1 = 2x - 1
Collect like terms
2x - 2x = -1 - 1
0 = -2
This illustrates that the equation doesn't have a solution.
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A circular plate has a diameter of 18 inches. What is the area of the plate? *
A) 81 square inches
B) 81 square inches
C) 18 square inches
D) 9 square inches
Answer:
254 inches squared
Step-by-step explanation:
Hi there!
\(A=\pi r^2\) where r is the radius of the circle
The radius is equal to half the diameter. Given that the diameter is 18 inches, we know that the radius of the circular plate is 9 inches. Plug this into the equation:
\(A=\pi (9)^2\\A=81\pi \\A=254\)
Therefore, the area of the plate is approximately 254 inches squared.
If this is not an answer choice, the question may have been asking for the radius of the circle rather than the area.
I hope this helps!
Consider the points below. P(θ),−4,0),Q(5,1,−2),R(6,4,1) (a) Find a nonzero vector orthogonal to the plane through the points P,Q, and R. (b) Find the area of the triangle PQR.
(a) A nonzero vector orthogonal to the plane through the points P, Q, and R is (9, -17, 35). (b) The area of triangle PQR is \(\sqrt\)(811) / 2.
(a) To determine a nonzero vector orthogonal to the plane through the points P, Q, and R, we can first find two vectors in the plane and then take their cross product. Taking vectors PQ and PR, we have:
PQ = Q - P = (5, 1, -2) - (-4, 0, 0) = (9, 1, -2)
PR = R - P = (6, 4, 1) - (-4, 0, 0) = (10, 4, 1)
Taking the cross product of PQ and PR, we have:
n = PQ x PR = (9, 1, -2) x (10, 4, 1)
Evaluating the cross product gives n = (9, -17, 35). Therefore, (9, -17, 35) is a nonzero vector orthogonal to the plane through points P, Q, and R.
(b) To determine the area of triangle PQR, we can use the magnitude of the cross product of vectors PQ and PR divided by 2. The magnitude of the cross product is given by:
|n| = \(\sqrt\)((9)^2 + (-17)^2 + (35)^2)
Evaluating the magnitude gives |n| = \(\sqrt\)(811).
The area of triangle PQR is then:
Area = |n| / 2 = \(\sqrt\)(811) / 2.
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Find the missing side.
09
9.5
10
C
7 cm
10.6
8 cm
HELP PLEASE
Answer:a
Step-by-step explanation:
i know
What is the volume of a
cube that has one side of ||
cm?
Answer:
5
Step-by-step explanation:
633 yess sjs this is rhe im doing this for points
Answer: V=a3
Step-by-step explanation:
how many ways are there to win the jackpot? how many ways are there to match 5 of 6 numbers? how many ways are there to match 4 of 6 numbers? how many ways are there to match 3 of 6 numbers?
The number of ways to match 5 of 6 numbers is 6 ways
The number of ways to match 4 of 6 numbers is 15 ways
The number of ways to match 3 of 6 numbers is 20 ways
To calculate number of ways to match 5 of 6 numbers we have to use to formula:
\(nCr =\frac{n!}{(n - r)! . r !}\)
\(6C5=\frac{6!}{(6-5)! . 5!}\)
\(6C5=\frac{6!}{(1)! . 5!}\)
\(6C5=\frac{6.5.4.3.2.1}{1.5.4.3.2.1}\)
\(6C5=\frac{6}{1}\)
\(6C5= 6 \ ways\)
∴ 6 ways are to match 5 of 6 numbers
To calculate number of ways to match 4 of 6 numbers we have to use to formula:
\(nCr =\frac{n!}{(n - r)! . r !}\)
\(6C4=\frac{6!}{(6-4)! . 4!}\)
\(6C4=\frac{6!}{(2)! . 4!}\)
\(6C4=\frac{6.5.4.3.2.1}{2.1.4.3.2.1}\)
\(6C4=\frac{30}{2}\)
\(6C4= 15 \ ways\)
∴ 15 ways are to match 4 of 6 numbers
To calculate number of ways to match 4 of 6 numbers we have to use to formula:
\(nCr =\frac{n!}{(n - r)! . r !}\)
\(6C3=\frac{6!}{(6-3)! . 3!}\)
\(6C3=\frac{6!}{(3)! . 3!}\)
\(6C3=\frac{6.5.4.3.2.1}{3.2.1.3.2.1}\)
\(6C3=\frac{120}{6}\)
\(6C3= 20 \ ways\)
∴ 20 ways are to match 3 of 6 numbers
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Please help me! Thank youuu
Answer: 3,600
dont quote me on it doing it the way i learned how to lol
Step-by-step explanation: Volume = length x width x height.
Answer:
917.33
Step-by-step explanation:
Top conic volume formula: ⅓ r²h=⅓(16/2)²*(18-12.5)
=⅓8²*5.5
=⅓352
=117.33
Volume formula of a cylinder: V=r²h
=8²*12.5
=800
117.33+800=917.33
Suppose you borrowed $45,000 at a rate of 8.5% and must repay it in 5 equal installments at the end of each of the next 5 years. By how much would you reduce the amount you owe in the first year? Select the correct answer. a. $7,594.46 b. $7,600.46 c. $7,618.46 d. $7,612.46 e. $7,606.46
The correct answer is option a. $7,594.46.
To calculate the amount you would reduce the amount you owe in the first year, we can use the formula for the equal installment of a loan. The formula is:
Installment = Principal / Number of Installments + (Principal - Total Repaid) * Interest Rate
In this case, the principal is $45,000, the number of installments is 5, and the interest rate is 8.5%.
Let's calculate the amount you would reduce the amount you owe in the first year:
Installment = $45,000 / 5 + ($45,000 - $0) * 0.085Installment = $9,000 + $3,825
Installment = $12,825
Therefore, you would reduce the amount you owe by $12,825 in the first year.The correct answer is option a. $7,594.46.
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deer ticks can be carriers of either lyme disease or human granulocytic ehrlichiosis (hge). based on a recent study, suppose that 18% of all ticks in a certain location carry lyme disease, 7% carry hge, and 7% of the ticks that carry at least one of these diseases in fact carry both of them. if a randomly selected tick is found to have carried hge, what is the probability that the selected tick is also a carrier of lyme disease?
Therefore, the probability that the selected tick is also a carrier of Lyme disease, given that it carries HGE, is approximately 0.999 or 99.9%.
To find the probability that the selected tick is also a carrier of Lyme disease given that it carries HGE, we can use the concept of conditional probability.
Let's define the following events:
A: The tick carries Lyme disease
B: The tick carries HGE
We are given:
P(A) = 0.18 (probability of a tick carrying Lyme disease)
P(B) = 0.07 (probability of a tick carrying HGE)
P(A ∩ B) = 0.07 (probability of a tick carrying both Lyme disease and HGE)
The probability we want to find is P(A|B), the probability of the tick carrying Lyme disease given that it carries HGE.
We can use Bayes' theorem to calculate this:
P(A|B) = (P(B|A) * P(A)) / P(B)
P(B|A) represents the probability of a tick carrying HGE given that it carries Lyme disease. We are not given this information directly, so we need to calculate it.
P(B|A) = P(A ∩ B) / P(A)
= 0.07 / 0.18
= 0.3889
Now we can substitute this value into Bayes' theorem:
P(A|B) = (0.3889 * 0.18) / 0.07
= 0.999
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please help me find the value of x
Answer:
x=105 hope it helps ur day will nice
A theater company has raised $930.75 by selling 25 floor seat tickets. Each ticket costs the same.
Part A: Write an equation with a variable that can be solved to correctly find the price of each ticket. Explain how you created this equation. (5 points)
Part B: Solve your equation in Part A to find the price of each floor seat ticket. How do you know your solution is correct? (5 points)
Part A - 25 tickets sold, and the product of the price per ticket and the number of tickets sold should give the total amount raised.
Part B - The price of each floor seat ticket is 37.23.
Part A: Let x be the price of each floor seat ticket. Since the theater company sold 25 tickets and raised 930.75, we can create the equation:
25x = 930.75
We use 25x because there were 25 tickets sold, and the product of the price per ticket and the number of tickets sold should give the total amount raised.
Part B: To solve for x, we can divide both sides of the equation by 25:
25x/25 = 930.75/25
x = 37.23
Therefore, the price of each floor seat ticket is 37.23.
We can check that our solution is correct by substituting x=37.23 back into the original equation:
25(37.23) = 930.75
This equation is true, which confirms that our solution is correct.
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The top of hill rises 554 feet above -207 what is the altitude of the top of the hillside
Kirby is trying to hypnotize Chrissy by swinging a pendulum at an angle of 80°.the length of chain attached is 10 inches long. What is the total are length AB that the pendulum travels
The total arc length AB that the pendulum travels is approximately 13.96 inches.
To find the total arc length traveled by the pendulum, we can use the formula for the arc length of a pendulum given by:
Arc length (s) = θ × r
where θ is the angle in radians and r is the length of the pendulum.
However, in this case, we are given the angle in degrees, so we need to convert it to radians. The formula for converting degrees to radians is:
θ (in radians) = (π/180) × θ (in degrees)
Given that the angle is 80°, we can convert it to radians as follows:
θ (in radians) = (π/180) × 80° = (4π/9) radians
Now, we can calculate the arc length:
Arc length (s) = (4π/9) radians × 10 inches
The total arc length traveled by the pendulum is therefore:
Arc length (s) = (40π/9) inches
To approximate the answer, we can use the value of π as approximately 3.14:
Arc length (s) ≈ (40 × 3.14/9) inches
Arc length (s) ≈ 13.96 inches
Therefore, the total arc length AB that the pendulum travels is approximately 13.96 inches.
Please note that this calculation assumes that the pendulum swings in a perfect arc without any friction or external factors affecting its motion. In reality, there may be slight variations due to factors such as air resistance or imperfections in the pendulum's motion.
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3 folders cost $2.91. How much do 2 folders cost? Provide explanation.
Calculating brilliance in epidemiology Context. What follows is a data table showing the development of brilliance among a small class of PHE 450 students. NOTE: Student #8 came in as an existing case of brilliance and did not develop brilliance as a result of exposure to PHE 450. Student WK 1 WK 2 WK 3 WK 4 WK 5 WK6 WK 7 WK 8 WK 9 WK 10 CASE CASE CASE CASE DROP 1 2 3 4 5 6 7 8 9 10 11 12 CASE CASE CASE DROP CASE DROP ASSIGNMENT Referring to the data above, please answer the following questions What is the point prevalence of brilliance at the end of Week 1? What is the point prevalence of brilliance at the end of Week 2? • What is the point prevalence of brilliance at the end of Week 3? • Using person-weeks as your denominator, what is the incidence of brilliance over the course of the 10-week course?
The point prevalence of brilliance at the end of Week 1 is 0.08 or 8%.
The point prevalence of brilliance at the end of Week 2 is 0.17 or 17%.
The point prevalence of brilliance at the end of Week 3 is 0.33 or 33%.
Using person-weeks as denominator, the incidence of brilliance over the course of the 10-week course is 0.017 or 1.7%
In epidemiology context, brilliance can be calculated through calculating point prevalence, cumulative incidence, and incidence rate. The provided data table can be used to determine the point prevalence, incidence, and incidence rate of brilliance among PHE 450 students. So, the calculations of point prevalence, cumulative incidence, and incidence rate based on the provided data are as follows:
The point prevalence of brilliance at the end of Week 1 can be calculated by the following formula; Point prevalence = Total number of existing cases at a given time ÷ Total population at that time
Student #8 was the only existing case of brilliance at the beginning of Week 1, so the point prevalence of brilliance at the end of Week 1 is; Point prevalence = 1 ÷ 12 = 0.08 or 8%.
The point prevalence of brilliance at the end of Week 2 can be calculated by the following formula; Point prevalence = Total number of existing cases at a given time ÷ Total population at that time
Student #3 and Student #8 were existing cases of brilliance at the beginning of Week 2, so the point prevalence of brilliance at the end of Week 2 is; Point prevalence = 2 ÷ 12 = 0.17 or 17%.
The point prevalence of brilliance at the end of Week 3 can be calculated by the following formula; Point prevalence = Total number of existing cases at a given time ÷ Total population at that time
Student #3, #4, #6, and #8 were existing cases of brilliance at the beginning of Week 3, so the point prevalence of brilliance at the end of Week 3 is; Point prevalence = 4 ÷ 12 = 0.33 or 33%.
The incidence of brilliance can be calculated by the following formula; Incidence = Total number of new cases ÷ Total person-weeks of observation
Student #5 and Student #7 developed brilliance during the 10-week course, so the incidence of brilliance over the course of the 10-week course is; Incidence = 2 ÷ 120 = 0.017 or 1.7%.
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In a class, 60% of the students are girls. There are 18 girls in the class.
a. How many students are in the class?
b.How many boys are in the class?
Answer:
a. Total of 45 students.
b. 18 Boys.
Answer:
There are 45 students and 18 boys in the class
Arrange the equations in the correct sequence to find the inverse of f(2)=y==
33z-zy=y-4
33z +4=y(1+z)
33z-zy=y+4
33x+4=y+zy
1+z
y=f¹ (2) = 33274
+4
33z-zy = y +4
A =
33-
y=f-¹ (z) = 332+4
z (33-y)=y-4
↓
↓
↓
↓
Į
c ccccccccccccccccccccccccccccc
what is 2 and 3 fourths times 5 and 1 third
Answer:
(2 and 3 fourths)(5 and 1 third)
=14.66
Charles offers 7% over dealer cost on a BMW that has a sticker price of $63,000 and a dealer cost of $56,904
Answer:
The right solution is "$ 60,887.28". A further explanation is provided below.
Step-by-step explanation:
The given values are:
Sticker price,
= $63,000
Dealer cost,
= $56,904
Offer,
= 7%
Now,
The 7% dealer cost will be:
= \(\frac{7}{100}\times 56,904\)
= \(3,983.28\) ($)
hence,
Amount offered will be:
= \(56,904+3,983.28\)
= \(60,887.28\) ($)
Slope:
Y-Intercept:
Equation:
pls help
Answer:
Slope: 4
Y-interecept: -2
Step-by-step explanation:
To find the slope, use rise over run. Go up from the y-intercept and over until you hit another exact point.
To find the y-intercept, just find the point that is on the y-axis.