1) which is more acidic 0.10m hydrochloric acid or 0.10m acetic acid? balanced eqn: | eq. expression: | ph of each: | 2) which is more acidic 0.0010m hydrochloric acid or 0.010m acetic acid? balanced eqn: | eq. expression: | ph of each: | 3) which is more acidic 0.00010m hydrochloric acid or 0.0010m acetic acid? balanced eqn: | eq. expression: | ph of each: | 4) what is the percent ionization for each of the above solutions? a) 0.10m hydrochloric acid b) 0.10m acetic acid c) 0.10m hydrochloric acid d) 0.10m acetic acid e) 0.10m hydrochloric acid f) 0.10m acetic acid
Answers
1) Among 0.10M hydrochloric acid or 0.10M acetic acid, the more acidic one is 0.10M hydrochloric acid;
2) For for 0.0010M hydrochloric acid or 0.010M acetic acid, the more acidic one is 0.010M acetic acid;
3) For 0.00010M hydrochloric acid or 0.0010M acetic acid, it is 0.0010M acetic acid;
4) The percent ionization of a) 0.10m hydrochloric acid is 100% b) 0.10m acetic acid is 1.8% c) 0.10m hydrochloric acid is 100% d) 0.10m acetic acid is 1.3% e) 0.10m hydrochloric acid is 100% f) 0.10m acetic acid
is 1.3%.
How to determine the more acidic solution and percent ionization?As per the question, which is more acidic, 0.10M hydrochloric acid or 0.10M acetic acid, the answer is 0.10M hydrochloric acid. The higher the concentration of hydrogen ions (H+), the stronger the acid is. Hydrochloric acid ionizes completely in water and provides more H+ ions than acetic acid. However, acetic acid is a weak acid, and it only partially dissociates in water. Hence the concentration of H+ ions in acetic acid is less than the concentration of H+ ions in hydrochloric acid.
Similarly, for 0.0010M hydrochloric acid or 0.010M acetic acid, the answer is 0.010M acetic acid. Since this concentration is greater than 0.0010M hydrochloric acid, the concentration of H+ ions is more in acetic acid. Hence it is more acidic than hydrochloric acid.
For 0.00010M hydrochloric acid or 0.0010M acetic acid, the answer is 0.0010M acetic acid. For this, we again consider the concentration of H+ ions. The concentration of H+ ions in acetic acid is more than that in hydrochloric acid. Hence it is more acidic than hydrochloric acid.
Now let's calculate the percent ionization for each of the above solutions.
a) 0.10M hydrochloric acid:
Hydrochloric acid ionizes completely in water. Hence, the percent ionization is 100%.
b) 0.10M acetic acid:
The ionization constant for acetic acid \(CH_{3}COOH\) is Ka = 1.8 × \(10^{-5}\)
\(CH_{3}COOH\) ⇌ \(CH_{3}COO^{-}\) + \(H^{+}\)
0.10 0.10-x x
Initial concentration of \(CH_{3}COOH\) is 0.10M and the equilibrium concentration would be 0.10 - x and x for \(CH_{3}COO^{-}\) and \(H^{+}\) respectively. Since the concentration of x is less than 5% of the initial concentration of acetic acid, we can assume that it is negligible. Hence, the percent ionization is (x/0.10) × 100% = 1.8%.
c) 0.0010M hydrochloric acid:
Hydrochloric acid ionizes completely in water. Hence, the percent ionization is 100%.
d) 0.010M acetic acid:
The ionization constant for acetic acid \(CH_{3}COOH\) is Ka = 1.8 × \(10^{-5}\)
\(CH_{3}COOH\) ⇌ \(CH_{3}COO^{-}\) + \(H^{+}\)
0.010 0.010-x x
Initial concentration of \(CH_{3}COOH\) is 0.010 and the equilibrium concentration is 0.010 - x and x for \(CH_{3}COO^{-}\) and \(H^{+}\) respectively. Since the concentration of x is less than 5% of the initial concentration of acetic acid, we can assume that it is negligible. Hence, the percent ionization is (x/0.010) × 100% = 1.3%.
e) 0.00010M hydrochloric acid:
Hydrochloric acid ionizes completely in water. Hence, the percent ionization is 100%.
f) 0.0010M acetic acid:
The ionization constant for acetic acid\(CH_{3}COOH\) is Ka = 1.8 × \(10^{-5}\)
\(CH_{3}COOH\) ⇌ \(CH_{3}COO^{-}\) + \(H^{+}\)
0.0010 0.0010-x x
Initial concentration of \(CH_{3}COOH\) is 0.0010 and the equilibrium concentration 0.0010 - x and x for \(CH_{3}COO^{-}\) and \(H^{+}\) respectively. Since the concentration of x is less than 5% of the initial concentration of acetic acid, we can assume that it is negligible. Hence, the percent ionization is (x/0.0010) × 100% = 1.3%.
Hence, the percent ionization of each solution is:a) 100%b) 1.8%c) 100%d) 1.3%e) 100%f) 1.3%.
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Related Questions
how many moles are in 7.1x10^21 atoms of iron?
Answers
Answer:
0.011 moles
Explanation:
There are about 6.02*10^23 atoms in a mole, so in the given sample, there are
\( \frac{7.01 \times {10}^{21} }{6.02 \times {10}^{23} } \)
which is about 0.011 moles.
Why can’t neon store energy in this way?
Answers
Answer:
Neon is a noble gas, it is monoatomic in nature, which implies that it has only one atom present. If we compare neon with water, water has three atoms present, two hydrogen atoms and one oxygen atom. Hence water stores more energy than neon because it is polyatomic and contains chemical bonds.
a. Consider the following system at equilibrium:
D(aq)+E(aq)<=>F(aq)
Classify each of the following actions by whether it causes a leftward shift, a rightward shift, or no shift in the direction of the net reaction.
Increase D
Increase E
Increase F
Decrease D
Decrease E
Decrease F
Triple D and reduce E to one third
Triple both E and F
b. The following system is at equilibrium:
2X(s)+4Y(g)<=>Z(g)
Classify each of the following actions by whether it causes a leftward shift, a rightward shift, or no shift in the direction of the net reaction.
add more X
remove some X
double the volume
halve the volume
c. For a certain chemical reaction:
?H�=-156kJ
Assuming the reaction is at equilibrium, classify each of the following actions by whether it causes a leftward shift, a rightward shift, or no shift in the direction of the net reaction.
increase the temperature
decrease the temperature
Answers
a) Rightward shift: 3 shifts. Leftward shift: 4 shifts b) Rightward shift: 1. Leftward shift: c) Rightward shifts: 1 shifts. Leftward shifts: 1, in Equilibrium condition.
a.
- Increase D: rightward shift
- Increase E: rightward shift
- Increase F: leftward shift
- Decrease D: leftward shift
- Decrease E: leftward shift
- Decrease F: rightward shift
- Triple D and reduce E to one third: leftward shift
- Triple both E and F: no shift (because the stoichiometric coefficients are the same for both reactants and products)
b.
- Add more X: no shift (because the reaction is at equilibrium and the concentrations of the reactants and products are already balanced)
- Remove some X: leftward shift
- Double the volume: leftward shift
- Halve the volume: rightward shift
c.
- Increase the temperature: leftward shift
- Decrease the temperature: rightward shift (because according to Le Chatelier's principle, a change in temperature will cause the equilibrium to shift in the direction that absorbs or releases heat)
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Say I grab a bunch of aluminum foil (9.5g) and ball it up. Aluminum has a specific heat of .9J/g*C. How much would the aluminum’s temperature change if I added 67Joules of energy (Q) to it?
Answers
Answer:
ΔT = 0.78 °C
Explanation:
Given data:
Mass of Al = 9.5 g
Specific heat capacity of Al = 0.9 J/g.°C
Temperature change = ?
Heat added = 67 J
Solution:
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
67 J = 9.5 g × 0.9 j/g.°C × ΔT
67 J = 85.5 j/°C × ΔT
ΔT = 67 J / 85.5 j/°C
ΔT = 0.78 °C
You need to prepare 100.0 mL of a pH 4.00 buffer solution using 0.100M benzoic acid (pK
a
=4.20) and 0.240M sodium benzoatc. How many milliliters of each solution should be mixed to prepare this buffer? benzoic acid:
Previous question
Answers
To prepare the pH 4.00 buffer solution, you should mix approximately 61.35 mL of the 0.100 M benzoic acid solution with 38.65 mL of the 0.240 M sodium benzoate solution.The ratio of benzoic acid to sodium benzoate in the buffer solution using the Henderson-Hasselbalch equation.
To prepare a pH 4.00 buffer solution using benzoic acid and sodium benzoate, we need to calculate the appropriate volumes of the 0.100 M benzoic acid and 0.240 M sodium benzoate solutions.
First, we need to determine the ratio of benzoic acid to sodium benzoate in the buffer solution. The Henderson-Hasselbalch equation can help us with this calculation:
pH = pKa + log([A-]/[HA])
Given that the pH is 4.00 and pKa is 4.20, we can rearrange the equation:
log([A-]/[HA]) = pH - pKa
log([A-]/[HA]) = 4.00 - 4.20
log([A-]/[HA]) = -0.20
Next, we take the antilog of -0.20 to find the ratio of [A-] to [HA]:
[A-]/[HA] = antilog(-0.20)
[A-]/[HA] = 0.63
The ratio of [A-] to [HA] is 0.63.
Now, let's calculate the volumes of each solution needed. Let's assume x represents the volume (in mL) of the 0.100 M benzoic acid solution and y represents the volume (in mL) of the 0.240 M sodium benzoate solution.
Since the total volume is 100.0 mL, we have the equation: x + y = 100
Considering the ratio of [A-] to [HA] as 0.63, we can write the equation: y/x = 0.63
Solving these two equations simultaneously will give us the volumes of each solution:
x + y = 100
y/x = 0.63
By substituting y = 0.63x from the second equation into the first equation, we get:
x + 0.63x = 100
1.63x = 100
x = 61.35 mL (rounded to two decimal places)
Substituting this value back into the equation x + y = 100, we find:
61.35 + y = 100
y = 38.65 mL (rounded to two decimal places)
Therefore, to prepare the pH 4.00 buffer solution, you should mix approximately 61.35 mL of the 0.100 M benzoic acid solution with 38.65 mL of the 0.240 M sodium benzoate solution.
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for the titration of 50.0 ml of 0.020 m aqueous salicylic acid with 0.020 m koh(aq), calculate the ph after the addition of 55.0 ml of koh(aq). for salycylic acid, pka = 2.97.
Answers
In the titration of 50.0 ml of 0.020 M aqueous salicylic acid with 0.020 M KOH(aq), the pH after the addition of 55.0 ml of KOH(aq) can be calculated.
Salicylic acid is a weak acid with a pKa value of 2.97. After the addition of 55.0 ml of KOH(aq), the solution will contain an excess of OH- ions due to the neutralization reaction between salicylic acid and KOH. The OH- ions will react with the weak acid, converting it to its conjugate base, salicylate. The pH of the resulting solution will depend on the relative concentrations of the acid and its conjugate base, as well as the pKa value.
To calculate the pH, we need to determine the concentrations of the acid and its conjugate base. The initial moles of salicylic acid can be calculated using the given volume and concentration. Since the acid and base react in a 1:1 ratio, the moles of KOH added will be equal to the moles of salicylic acid at the equivalence point.
Next, we calculate the moles of salicylic acid remaining after the reaction. Since 55.0 ml of KOH(aq) is added to the initial 50.0 ml of salicylic acid, the total volume becomes 105.0 ml. We subtract the moles of KOH added from the initial moles of salicylic acid to find the moles of salicylic acid left.
Using the moles of salicylic acid and its conjugate base, we can determine their concentrations. The concentration of the acid is obtained by dividing the moles of acid remaining by the final volume of the solution. The concentration of the conjugate base is determined in a similar manner.
Finally, we can calculate the pH using the Henderson-Hasselbalch equation:
pH = pKa + log10([conjugate base]/[acid])
Substituting the calculated values, we can find the pH of the solution after the addition of 55.0 ml of KOH(aq) to the titration of salicylic acid.
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You mix 250 ml of 2.1 m hbr with 200 ml of 2.5 m KOH. What is the ph of the resulting solution?
Answers
The pH of the resulting solution when 250 mL of 2.1 M HBr is mixed with 200 mL of 2.5 M KOH is 12.7.
This can be calculated by first finding the moles of each of the reactants, and then using the ICE table to determine the concentration of ions in the solution. The equation for the ICE table is:
[H3O+] x [OH-] = KW, where KW is the ion product of water.The concentration of H3O+ can then be determined by taking the square root of the KW, and the concentration of the OH- can be calculated by dividing the KW by the H3O+ concentration. The pH can then be calculated by taking the negative log of the H3O+ concentration.
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The density of a material depends on
of
O a.
Select one:
its weight
O b. its mass and volume
O c. its mass only
O d. its volume only
estion
Answers
b. Its mass and volume
Hope it helps u!
What is the molarity of a sodium hydroxide that contains 125 g NaOH in 2.00 L of solution?
Answers
The molarity of the sodium hydroxide that contains 125 g NaOH in 2.00 L of solution is 1.5625 M
How do I determine the molarity?First, we shall obtain the number of mole of NaOH in the solution. This is shown below:
Mass of NaOH = 125 grams Molar mass of NaOH = 40 g/molMole of NaOH =?Mole = mass / molar mass
Mole of NaOH = 125 / 40
Mole of NaOH = 3.125 moles
Finally, we shall determine the molarity of the sodium hydroxide solution as follow:
Mole of NaOH = 3.125 molesVolume = 2.00 LMolarity = ?Molarity = mole / volume
Molarity = 3.125 / 2
Molarity = 1.5625 M
Thus, the molarity of the sodium hydroxide is 1.5625 M
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Suppose the interaction between two atoms by the Lennard-Jones potential: ULJ = B/r^12 - A / r^6 where the values of A and B are known to be A = 10^-77 J x m^6 and B = 10^-134 J x m^12.
What does the Lennard-Jones potential predict for the separation r=r eq
hen the energy is at the minimum (equilibrium) value, U min. What is the u min fot this interaction at T=298 K ? What is the ratio of U min to the purely attractive van der Waals component of the interaction potential at r eq.
What is the ratio of r eq to r 0 defined by u(r 0 )=0. 4. What is the ratio of r s to r 0 , where r s is the separation where the magnitude of the (attractive adhesion) force is maximum, F max . What is the value for F max between the two atoms?
Answers
a) The Lennard-Jones potential predicts the separation r_eq at the minimum energy U_min.
b) The U_min for this interaction at T=298 K is the value obtained from the Lennard-Jones potential equation when r=r_eq.
c) The ratio of U_min to the purely attractive van der Waals component of the interaction potential at r_eq can be calculated by comparing the attractive part (-A/r^6) to the total potential energy U_min.
d) The ratio of r_eq to r_0, where u(r_0)=0.4, can be determined by finding the value of r_eq where the potential energy is equal to 0.4 times the total potential energy at r=r_0.
e) The ratio of r_s to r_0, where r_s is the separation where the magnitude of the attractive adhesion force is maximum, can be determined by finding the value of r where the derivative of the potential energy with respect to r is equal to zero.
f) The value of F_max between the two atoms can be obtained by taking the negative derivative of the potential energy equation with respect to r and evaluating it at r=r_s.
a) The Lennard-Jones potential provides information about the relationship between energy and separation between two interacting atoms.
At the minimum energy (U_min), the potential predicts the separation r_eq, which corresponds to the equilibrium distance between the atoms. This is the distance at which the energy of the system is at its lowest point.
b) To determine the value of U_min at a given temperature (T=298 K), you can substitute the equilibrium separation r_eq into the Lennard-Jones potential equation and calculate the resulting energy value.
This will give you the U_min for the interaction.
c) The Lennard-Jones potential consists of two components: an attractive component (-A/r^6) and a repulsive component (B/r^12).
The ratio of U_min to the purely attractive van der Waals component of the interaction potential at r_eq can be calculated by comparing the magnitude of the attractive component to the total potential energy at the equilibrium separation.
This ratio provides insights into the relative contribution of the attractive force to the overall potential energy at equilibrium.
d) The ratio of r_eq to r_0 can be determined by finding the value of r_eq where the potential energy is equal to 0.4 times the total potential energy at r=r_0.
In other words, you need to solve the Lennard-Jones potential equation for r_eq when the potential energy is equal to 0.4 times the potential energy at r=r_0.
e) The ratio of r_s to r_0 is obtained by finding the value of r where the magnitude of the attractive adhesion force is maximum.
This can be determined by finding the separation r where the derivative of the potential energy equation with respect to r is equal to zero.
The value of r_s represents the separation at which the attractive force between the atoms is strongest.
f) The value of F_max between the two atoms can be obtained by taking the negative derivative of the Lennard-Jones potential energy equation with respect to r and evaluating it at r=r_s.
This will give you the magnitude of the maximum attractive adhesion force between the atoms.
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he long run equilibrium condition for perfect competition is:
a. P=AVC=MR=MC.
b. Q=AVC=MR=MC.
c. Q=ATC=MR=MC.
d. P=ATC=MR=MC.
Answers
Option (d), P=ATC=MR=MC, accurately represents the long-run equilibrium condition for perfect competition, reflecting the balance between price and cost for firms operating in a competitive market.
The long-run equilibrium condition for perfect competition is that price (P) is equal to average total cost (ATC), which is also equal to marginal cost (MC), and marginal revenue (MR).
Option (d), P=ATC=MR=MC, best represents the long-run equilibrium condition for perfect competition. In perfect competition, firms operate at the minimum point of their average total cost curve, where price equals both average total cost and marginal cost. This condition ensures that firms are earning zero economic profit and are producing at an efficient level.
In the long run, if firms are earning economic profit, new firms will enter the market, increasing competition and driving prices down. Conversely, if firms are experiencing losses, some firms may exit the market, reducing competition and causing prices to rise. This process continues until firms reach a state where price equals average total cost, marginal cost, and marginal revenue, ensuring a long-run equilibrium.
Therefore, option (d), P=ATC=MR=MC, accurately represents the long-run equilibrium condition for perfect competition, reflecting the balance between price and cost for firms operating in a competitive market.
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Which element has chemical properties that are most similar to potassium?
Answers
Answer: Elements found in group 1 (Alkaline Metals)
Explanation: Any element found in group 1, such as Lithium, Sodium, Caesium, or Francium, have similar properties as potassium. Atoms that are found in the same group on the periodic table have similar chemical properties.
The electron configuration 1s2 2s2 2p6 3s2 3p6 4s1 3d10 describes the electron configuration of what neutral element?
Answers
Answer:
Copper
Explanation:
Copper has this electronic configuration.
You can count the total number of electrons
= 29
Cu is the 29 th in the periodic table.( atomic number = 29)
Two or more than two atoms with different physical or chemical properties can not combine together to form an element. Therefore, the given electronic configuration represents copper element.
What is element?Element generally consist of atoms or we can atoms combine to form element. Atoms of an element is always same, means all the properties of all atoms of one type of element is same.
The systematic distribution of electrons in the various atomic orbitals is called its electronic configuration. The atomic number of copper is 29. The electronic configuration of copper is 1s² 2s² 2p⁶ 3s² 3p⁶ 4s¹ 3d¹⁰. 1,2,3 represents the number of shells and s and represents the orbitals. The superscripts represents the number of electrons in each orbitals.
Therefore, the given electronic configuration represents copper element.
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what electrical science term did benjamin franklin coin?
Answers
Answer:
The term "Battery"
Explanation:
Describe the journey that a carbon atom from inside a volcano will take to become a carbon atom inside carbonate rock.
Answers
The journey of a carbon atom from inside a volcano to inside a carbonate rock is as follows:
Throughout this journey, the carbon atom undergoes various chemical reactions and changes in form, but ultimately ends up as a component of carbonate rock.
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Directions: Predict the products in words for the following double replacement reactions:
1. Barium chloride + sodium phosphate →
2. Lithium sulfate + magnesium nitrate →
3. Potassium oxide + calcium chlorate →
Answers
The products in words for the following double replacement reactions are:
1. Barium chloride + sodium phosphate → Barium phosphate + sodium chloride
2. Lithium sulfate + magnesium nitrate → Lithium nitrate + magnesium sulfate
3. Potassium oxide + calcium chlorate → Potassium chlorate + calcium oxide
A salt metathesis reaction, also known as a double displacement reaction, is a chemical reaction that involves the exchange of bonds between two reacting chemical species, producing products having comparable or equal bonding affiliations.
AB + CD = AD + BC is a general formula for a double-displacement reaction. Here are some examples of double-displacement reactions: When sodium hydroxide (a base) interacts with ammonium chloride (a salt), sodium chloride, hydrochloric acid, and water are formed. A Double displacement reaction is a chemical process in which reactant ions switch positions to generate new products. Precipitate is often formed as a result of a twofold displacement process. Covalent or ionic chemical bonds can exist between the reactants.
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QUICK PLEASE IM TIMED
A summary table may contain __________ categories than the original data table.
A) many more
B) a few more
C) fewer
D) none of the above
Answers
Balance the chemical equation Au,O, --> Au + O2
Answers
Explanation:
Don't you mean ½O2+Au-->AuO
dispersion forces are a type of intermolecular force that exists between only polar molecules . dispersion forces are the strongest type of intermolecular force. however, dispersion forces are stronger for choose... molecules because they are more choose... .
Answers
Dispersion forces are a type of intermolecular force that exists between only polar molecules . dispersion forces are the strongest type of intermolecular force. however, dispersion forces are stronger for larger molecules because they are more polarizable .
What is dispersion forces?
The least powerful intermolecular force is the London dispersion force. When the electrons in two nearby atoms occupy positions that cause the atoms to temporarily form dipoles, the consequence is the London dispersion force, a transient attractive force. The term "induced dipole-induced dipole attraction" is frequently used to describe this effect. When the temperature is sufficiently dropped, London forces—attractive forces—cause nonpolar substances to condense into liquids and to freeze into solids.
When an atom or molecule's electrons are dispersed asymmetrically around the nucleus, an instantaneous (temporary) dipole can form due to the electrons' continual mobility.
Whether they are polar or nonpolar, all molecules exhibit dispersion forces.
Atoms and molecules that are bigger and heavier show larger dispersion forces than those that are smaller and lighter.
The valence electrons are, on average, farther from the nucleus in a larger atom or molecule than in a smaller atom or molecule. They can more easily create transient dipoles because they are not held as tightly.
The term "polarizability" refers to how easily the electron distribution around an atom or molecule can be altered.
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What is the major alkene formed when compound a is dehydrated with pocl3 and pyridine?
Answers
An alkene is formed from a dehydration reaction.
What is the major alkene formed?An alkene is formed from a dehydration reaction. Dehydration involves the loss of water from a molecule. In this case, we have compound A as shown in the image attached to this answer.
The dehydration is carried by the use of the reagents pocl3 and pyridine. Let us recall that the dehydration would occur at the point where the HOH would depart. The entire reaction is shown in the image attached.
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a) Propose a structure for a compound with molecular formula C5H10Cl2, that fits the following spectroscopic data:1H NMR: 0.97δ (triplet, I=6), 1.81δ (quartet, I=4)b) A compound with molecular formula C5H10Br2 displays the following 13C NMR along with the DEPT-90 and DEPT-135 13CNMR spectra. What is the structure for this compound?
Answers
a. The structure for a compound with molecular formula C₅H₁₀Cl₂, that fits the following spectroscopic data:1H NMR: 0.97δ (triplet, I=6), 1.81δ (quartet, I=4) is Cl-CH₂-CH(Cl)-CH₂-CH₃
b. The structure for a compound with molecular formula C₅H₁₀Br₂ displays the following 13C NMR along with the DEPT-90 and DEPT-135 13CNMR spectra is Br-CH₂-CH(Br)-CH₂-CH₃.
Based on the 1H NMR data, the compound has two types of protons, with chemical shifts at 0.97δ (triplet, I=6) and 1.81δ (quartet, I=4). The triplet at 0.97δ is likely to be the methyl protons (CH₃) that are attached to a carbon atom with two other chlorine atoms. The quartet at 1.81δ could correspond to the methylene protons (CH₂) that are adjacent to the chlorine atoms. Therefore, the structure of the compound could be:
Cl-CH₂-CH(Cl)-CH₂-CH₃
The DEPT-90 13C NMR spectrum indicates the presence of three types of carbon atoms, with signals at 28.8δ, 32.1δ, and 70.2δ. The DEPT-135 13C NMR spectrum confirms the presence of two methyl groups (CH₃) and two methylene groups (CH₂). Based on the molecular formula and the NMR data, the compound could be:
Br-CH₂-CH(Br)-CH₂-CH₃
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compare and contrast the lanthanide series and the actinide series
Answers
The lanthanide series and Actinide series are two rows of elements present in the periodic table. The Lanthanide series elements have atomic numbers ranging from 57-71, and the Actinide series elements have atomic numbers ranging from 89-103. Both series are part of the f-block of the periodic table.
What are the similarities between Lanthanide and Actinide series? The elements of both series are heavy metals.The electronic configuration of both series ends in a 6s2 sub-shell.There are no stable isotopes of elements present in both series.Both series are known for their radioactive nature.The oxidation state of the elements in both series is commonly found as +3.What are the differences between Lanthanide and Actinide series?The first difference is the number of elements in each series. The Lanthanide series has 14 elements, whereas the Actinide series has 14 elements.The next difference is in the stability of their nuclei. The nuclei of Actinide series elements are unstable compared to Lanthanide series elements.Actinides tend to be more reactive than Lanthanides.Actinides have a higher degree of complexation ability than Lanthanides.Lanthanides have a smaller atomic size than Actinides.Actinides are highly radioactive due to the fact that their nuclei are unstable.In conclusion, both series are unique, yet share many similarities. The most apparent difference is the number of elements in each series and the stability of their nuclei. Actinides are generally more reactive and are highly radioactive, which gives them many practical uses, such as in nuclear reactors.
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please help with these 5 questions if they physical or chemical as well as intensive or extensive i will be giving brainliest thank u
Answers
Before categorizing each of the properties into physical or chemical, intensive or extensive, we need to understand the terms:
Physical property: This is any characteristic that can be determined without changing the substance’s chemical identity.
Chemical property: This is any characteristic that can be determined by simply changing the molecular structure of a substance
1) For the property: Its melting point is 112 degrees Celcius is a Physical property and intensive since extensive property depends on the amount of matter being measured.
2) If a substance burns in a presence of oxygen, it is a chemical property since the molecular structure of the resulting compound will be changed. This is also an intensive property.
3) If a substance is yellow solid is a physical property since the first is the color yellow and solid shows the state of the element. Neither property implies that the substance is changing its composition. Therefore, both properties are physical properties. This physical property is Intensive properties since it does not depend on the amount of the substance present.
4) If the substance is combustible, it is a chemical property and intensive property
5) For the sample of a substance that measures 75cm^3, this is a Physical property since the volume of a substance can be determined without changing its identity. This is also an extensive property since examples of these properties include mass, weight, and volume.
Which statement best describes how light and lenses work together?
Do someone no the answer
Answers
Answer:
Answer A
Explanation:
When light enters a lense it bends and changes direction, and then does this again when it leaves. leaving the correct image in the center
Mrs. Keep burns a walnut under a beaker of water. The beaker contains 100 g of water which warms from 25oC to 30oC. Assuming that all the heat from the burning walnut goes into the water and none of the heat is lost to the air or the beaker, how many calories are in the walnut?
a 2100 calories
b 10,500 calories
c not enough information is given
d 500 calories
Answers
The amount of heat gained by the water is 500 calories. Thus, option D is correct.
Given:
Mass of water (m) = 100 g
Change in temperature (ΔT) = 30°C - 25°C = 5°C
The specific heat capacity of water (c) is approximately 1 calorie/gram°C.
Now, the amount of heat gained by the water,
Q = mcΔT
Where:
Q is the heat gained or lost by the substance
m is the mass of the substance
c is the specific heat capacity of the substance
ΔT is the change in temperature
Plugging in the values into the formula:
Q = 100 × 1 × 5
Q = 500 calories
Therefore, the amount of heat gained by the water is 500 calories.
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Frankie earns $5 each time he babysits his little sister. He has saved $30. Frankie wants to save $52 to buy a new skateboard. How many more times will Frankie need to babysit to have enough money to buy the skateboard?
Answers
Answer:
52- the 30 he has already = $22
22/5= 4.4
he will have to babysit 5 times
What is the chemical p2?
Answers
The chemical P2 refers to the diphosphorus molecule, which is a compound made up of two phosphorus atoms bonded together.
Diphosphorus, also known as P2, is a chemical compound composed of two phosphorus atoms covalently bonded together. It is a highly reactive and unstable molecule that is rarely encountered in its pure form. Diphosphorus is an allotrope of phosphorus, meaning it is a different structural form of the same element.
At room temperature, diphosphorus exists as a colorless, odorless gas with a molecular weight of 60.98 g/mol. It is highly reactive and can easily ignite when exposed to air, making it a fire and explosion hazard. Diphosphorus is also highly toxic and can cause severe burns and respiratory problems if inhaled.
Diphosphorus has a unique electronic structure with a triple bond between the two phosphorus atoms. This triple bond makes the molecule highly reactive and unstable, as it seeks to break apart and form more stable bonds with other atoms. As a result, diphosphorus is a useful starting material for the synthesis of other phosphorus-containing compounds.
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You create a solution for a lab, in which you weigh 0. 81 g of nacl and dissolve it in water. The volume of the resulting aqueous nacl solution is 12. 2 ml. Assuming the molar mass of nacl is 58. 443 g/mol, how many moles of nacl did you use?.
Answers
This volume will therefore be X. X is equivalent to 1.369 divided by 1, or 0.1. Thus, this is equivalent to run 369 and almost 14 liters.
At 80 degrees Celsius, 40 grams of sodium chloride are soluble in 100 grams of water. The mass of the solvent and the mass of the solute together make up the total mass of the solution. Use a lab scale to weigh the masses or use the density formula D = m/V to convert the solvent volume to mass. To determine your final volume, multiply the mass of the solvent by the mass of the solute. A 10% solution of NaCl is 10 grams of NaCl in 100 ml of water because in this situation, the% solution is the number of grams of solute in 100 ml of solvent.
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provide the structure of the major fragment that results when the molecular ion of ch3ch2ch2ch2oh undergoes fragmentation via alpha cleavage. i ii iii iv v
Answers
When CH₃CH₂CH₂CH₂OH undergoes alpha cleavage (See Pic2), the major fragment produced is CH₃CH₂CH₂CH₂.
The act of disassembling a molecule's molecular structure into smaller parts or fragments is referred to as fragmentation. Chemical processes, collision-induced dissociation, and photodissociation are just a few of the mechanisms that might cause this. By causing molecular ion fragmentation and examining the resultant fragments, fragmentation is a frequently used technique in mass spectrometry to ascertain the structure of a molecule. The distribution and intensity of the fragments can reveal crucial details about the chemistry and make-up of the original molecule.
By eliminating the alpha carbon and the hydrogen that is connected to it, alpha cleavage causes the carbonyl carbon and the beta carbon to establish a new carbon-carbon bond.
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The complete question is:
Provide the structure of the major fragment that results when the molecular ion of ch3ch2ch2ch2oh undergoes fragmentation via alpha cleavage (See Pic1).
1) I
2) II
3) III
4) IV
5) V
JANKS is looking under a microscope and sees a colony of green cells living on a spherical structure. She is most likely to be observing a...
A. volvox
B. Amoeba
C. Paramecium
D, Euglena
Answers
Answer:
euglena
Explanation:
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