1. Using triangle method, determine the resultant of vectors:
A= 15 units 20 degrees SW
B= 20 units 50 degrees NW
2. Using parallelogram method, determine the resultant of vectors:
A= 100 units 40 degrees
NW B= 300 units 80 degrees NE
3. The equilibrant of vectors A=(-6,-2) is vector E. What is E?

The following is how Kirchhoff's voltage law is used to analyze a circuit, Assume the circuit's current will flow in a certain direction. (The right path is preferred but not required.) Assign voltage polarities to all resistors that the current passes through using the direction of the current as a guide.

Therefore, on conclusion we can said as, Kirchhoff's Voltage Law (KVL), is concerned with energy conservation in a closed circuit channel. According to his voltage law, the algebraic total of all the voltages around any closed loop in a circuit is equal to zero for a closed loop series path.

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The net upward force on an airplane wing area is 20 m² if the speed of airflow is 300 m/s across the top of the wing and 280 m/s across the bottom is 1.496 × 10⁵ Newton.

Force is the influence of either pull or pushes in the body. Basically, gravitation forces, nuclear forces, and friction forces are the types of forces. For e.g. when the wall is hit by a hand then a force is exerted by the hand on the wall as well as the wall also exerts a force on the hand. There are different laws given to Newton to understand force.

Given:

The area of plane wings, A = 20 m²,

The speed of airflow on the top wing, V₁ = 300 m/s,

The speed of airflow on the bottom wing, V₂ = 280 m/s,

The density of air, α = 1.29 kg/m³,

Calculate the net force by the following formula,

\(F = 1/2\alpha A[V_1 ^2 - V^2_2]\)

Here, F is the net force.

Substitute the values,

F = 1/2 × 1.29 × 20[300² - 280²]

F = 149640 N or 1.496 × 10⁵ Newton.

Therefore, the net upward force on an airplane wing area is 20 m² if the speed of airflow is 300 m/s across the top of the wing and 280 m/s across the bottom is 1.496 × 10⁵ Newton.

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Answer:

486,750 kg*m/s

Explanation:

Momentum is mass*velocity

M = m*v

M = 8850kg*55m/s

M = 486,750 kg*m/s

The momentum of an 8850 kg medium truck that is traveling with a velocity of 55 m/s west on the highway is 486750 kg m / s.

Momentum is the result of a particle's mass and velocity. Being a vector quantity, momentum possesses both magnitude and direction. According to Isaac Newton's second equation of motion, the force acting on the particle equals the time rate of change of momentum.

According to Newton's second law, if a particle is subjected to a constant force for a specific amount of time, the result of the force and time (referred to as the impulse) is equal to the change in momentum.

Given:

The mass of the truck is, m = 8850 kg,

The velocity of the truck is, v = 55 m/s,

Calculate the momentum of the truck as shown below,

Momentum = m × v

Momentum = 8850 × 55

Momentum = 486750 kg m / s

Thus, the Momentum of the truck is 486750 kg m / s.

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Answer:

Centripetal acceleration = 0.79 m/s²

Explanation:

Given the following data;

Radius, r = 2.6 km

Time = 360 seconds

Conversion:

2.6 km to meters = 2.6 * 1000 = 2600 meters

To find the magnitude of centripetal acceleration;

First of all, we would determine the circular speed of the car using the formula;

\( Circular \; speed (V) = \frac {2 \pi r}{t}\)

Where;

Substituting into the formula, we have;

\( Circular \; speed (V) = \frac {2*3.142*2600}{360} \)

\( Circular \; speed (V) = \frac {16338.4}{360} \)

Circular speed, V = 45.38 m/s

Next, we find the centripetal acceleration;

Mathematically, centripetal acceleration is given by the formula;

\( Centripetal \; acceleration = \frac {V^{2}}{r}\)

Where;

Substituting into the formula, we have;

\( Centripetal \; acceleration = \frac {45.38^{2}}{2.6}\)

\( Centripetal \; acceleration = \frac {2059.34}{2600}\)

Centripetal acceleration = 0.79 m/s²

Total mass lost by the comet is 30.24 x 10¹⁰ kg.

Rate at which mass is lost, R = 35 x 10⁴ kg/s

Time period, T = 100 days = 8.64 x 10⁶s

Therefore,

Total mass lost by the comet, m = R x T

m = 30.24 x 10¹⁰ kg

So,

The fraction of loss = (30.24 x 10¹⁰)/(5 x 10¹⁵) = 60.48 x 10⁻⁵

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Answer: A. New, high-tech materials are used to make prosthetic limbs for  people who need them

Explanation:

Engineering is an immensely important science to us as humans for through its development of tools, machines, engines and structures, human lives have been made better in just about every field.

One of these fields is the medical field. In the past people who lost limbs could say good bye to a normal life or at least a semblance of one but now, due to advancements in Engineering, high-tech materials can now be used to make prosthetic limbs for people who need them.

Answer:

Impulse is defined as change in momentum of an object divided by time interval.

at t= 0s

initial velocity = u , initial momentum = mu

at some time t .

final velocity = V, final momentum= mv.

now, change in momentum= ( final - initial) = ( mv-mu)

time interval = (t-0) = t

impulse force = (mv-mu)/ ( t)

Ft = (mv-mu) proved .

this law is known as Newton's second law.

Answer:

9.42 m/s

Explanation:

a) Using Newton's law of motion formula:

\(\theta=\frac{(\omega+\omega_o)}{2}t\\\\where \ \theta=angular\ displacement=1\ rev =2\pi, w_o=initial\ velocity\ of\ discus\\=0\ rad/s, \omega=angular\ speed\ of\ discus\ at\ release,t=time\ = 1.2\ s.\\\\Hence:\\\\2\pi=\frac{(0+\omega)}{2}(1.2)\\\\\omega=\frac{2*2\pi}{1.2} \\\\\omega=10.47\ rad/s\\\)

The speed of the discus at release (v) is:

v = ωr; where r = radius of discus

diameter = 1.8 m, r = diameter / 2= 1.6 / 2 = 0.9 m

v = ωr = 10.47 * 0.9

v = 9.42 m/s

The velocity of the center of mass of the system is the same as the velocity of the bullet, which is v. The total angular momentum of the system about the center of mass is  Lhoop + Lbullet. he kinetic energy of the system, before and after collision Khoop + Kbullet and Khoop_after + Kbullet_after respectively. The axis of rotation, which is the center of the hoop, will remain at rest after the collision.

The center of mass of the system is at point Q, which is a distance d from point O, where:d = (mP + mO)/(2*m).The velocity of the center of mass is the derivative of the position with respect to time. Since the bullet is moving with constant velocity, the position of its center of mass is also moving with constant velocity. The position of the center of mass of the hoop is not changing, so its velocity is zero. Therefore, the velocity of the center of mass of the system is the same as the velocity of the bullet, which is v.

The angular momentum of the bullet about the center of mass is:Lbullet = Ibulletw + md*v where Ibullet is the moment of inertia of the bullet about its center of mass, and d is the distance from the center of mass to the point of contact between the bullet and the hoop. The total angular momentum of the system about the center of mass is the sum of the angular momenta of the hoop and the bullet: Ltotal = Lhoop + Lbullet

Since angular momentum is conserved, this change in angular momentum must be due to the change in the angular momentum of the hoop. Therefore, we can set the change in angular momentum of the hoop equal to Ltotal and solve for the angular velocity w:

Ltotal = Lhoop + Lbullet

Ltotal = Ihoopw + mRv + Ibulletw + mdv

Ltotal = (Ihoop + Ibullet)w + (mR + md)v

w = Ltotal/(Ihoop + Ibullet) - (mR + md)*v/(Ihoop + Ibullet).

kinetic energy is conserved, this means that the change in kinetic energy of the hoop must be equal to the change in kinetic energy of the bullet. Therefore, we can set the change in kinetic energy of the hoop equal to the change in kinetic energy of the bullet and solve for the kinetic energy of the hoop after the collision:

Khoop_after - Khoop = Kbullet - Kbullet_after

Khoop_after = Khoop + Kbullet - Kbullet_after

The kinetic energy of the system after the collision is the sum of the kinetic energies of the hoop and the bullet after the collision:

Ktotal_after = Khoop_after + Kbullet_after

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1. The maximum height above its launch level is 1.45 m

2. The time of flight of the ball is 1.1 s

1. How do I determine the maximum height?

From the question given above, the following data were obtained:

The maximum height can be obatianed as follow:

H = u²Sine²θ / 2g

H = [5.5² × (Sine 76)²] / (2 × 9.8)

Maximum height = 1.45 m

How do I determine the time of flight?

The time of flight of the ball can be obtained as follow:

T = 2uSineθ / g

T = [2 × 5.5 × Sine 76] / 9.8

Time of flight = 1.1 s

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The slope of the graph represent for ohmic material is as per the graph is that the current will increases with increase in potential.

Ohmic material is defined as anything that complies with Ohm's law, according to which the current flowing through a device is proportional to the applied voltage. Ohmic materials are those that adhere to Ohm's law.

Ohm's Law describes the relationship between voltage and current, and the resistance in a circuit is represented by the slope of the line from a graph of the two quantities. The slope of the distance-time plot, or the speed of the body, is the ratio of the distance traveled by the body to the time required for travel.

Thus, the slope of the graph represent for ohmic material is as per the graph is that the current will increases with increase in potential.

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The car is moving at approximately 12.5 meters per second.

The kinetic energy (KE) of an object can be calculated using the formula:

KE = 1/2 * m * \(v^2\)

where

KE = kinetic energy,

m =Mass of the object, and

v = velocity.

In this case, we are given the mass (m) of the car as 1600 kg and the kinetic energy (KE) as 125,000 J. To find the velocity .

Substituting the  values , we have:

125,000 J = 1/2 * 1600 kg *\(v^2\)

Now, we can solve for v by rearranging the equation:

\(v^2\) = (2 * 125,000 J) / 1600 kg

\(v^2\) = 156.25 \(m^2/s^2\)

Taking the square root, we find:

v = √156.25\(m^2/s^2\)

v ≈ 12.5 m/s

Therefore, the car is moving at approximately 12.5 meters per second.

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Answer:

Ethyl butyrate is used as an artificial flavoring resembling orange juice or pineapple in alcoholic beverages, as an ingredient of fragrance, and as a solvent and plasticizer for cellulose. It is also used in the production of polyvinyl butyral (PVB).

Explanation:

First off, no known chemical, physical, or environmental approach can change the half-life of a radioactive species so option c. is the correct choice.

Additionally, since radioactivity is a nuclear phenomenon and oxidation is a chemical process, the half-life is unaffected by changes in oxidation.

Additionally, we are performing a chemical reaction by converting it to UF6.

Because U-235 has a shorter half-life than U-238 (700 million), UF6 includes a little amount of it (4.7 billion).

Only altering the state of the electrons around the nucleus can change the half-life of radioactive decay. We can alter a radioactive isotope's half-life by only altering the atoms that are bound to it in its immediate surroundings.

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Answer:

The correct options are:

B) They have the same wave speed as visible light

D) They have a lower frequency than gamma rays.

Explanation:

B) Ultraviolet rays, commonly known as UV rays, are a type of electromagnetic ways. As electromagnetic waves, in the layman's term, are all kinds of life that can be identified, all electromagnetic waves (UV rays, visible light, infrared, radio etc) all travel with the same velocity, that is the speed of light, given as v = 3 × 10⁸ m/s

D) The frequency of all electromagnetic rays can be found by electromagnetic spectrum (picture attached below).

We can clearly see in the picture that the frequencies of UV rays lie at about 10¹⁵ - 10¹⁶ Hz which is lower than the frequency of Gamma ray, which lie at about 10²⁰ Hz.

Answer:

Explanation:

.....make me brainlyest

Answer:\(60^{\circ}\)

Explanation:

Given

\(\mid\Vec{A}\mid=1\)

\(\mid\Vec{B}\mid=2\)

And \(A\cdot B=1\)

We know \(\vec{A}\cdot \vec{B}=\mid\Vec{A}\mid\mid\Vec{B}\mid\cos \theta\)

Where \(\theta\) is the angle between them

Substituting the values

\(1=1\times 2\cos \theta\)

\(\cos \theta =\dfrac{1}{2}\)

\(\theta =60^{\circ}\)

Thus the angle between \(A\) and \(B\) is  \(60^{\circ}\)

Answer:

This refers when a spiker quickly strides towards the net before they jump in the air for an attack.

Given that the force between two charged particles, we'll call charge 1 and 2 is, \(\vec F_{0}=200 \ N\). The question asks us to find the new force between charges 1 and 2 if the charge on 1 increases by 3 times and the charge on 2 decreases by 4 times.

Equation to calculate the electric force between two charged particles:

\(\vec F_e=k_e\frac{q_1q_2}{r^2} \\\\ k_e=Coulomb's \ Constant= 8.99 \times 10^9 \ \frac{Nm^2}{C^2}\\\)

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

\(\vec F_0=k_e\frac{q_1q_2}{r^2} =200 \ N \ and \ \boxed{\vec F_f=k_e\frac{(3 q_1)(\frac{1}{4} q_2)}{r^2} }\)

\(\Longrightarrow \vec F_f=k_e\frac{(3 q_1)(\frac{1}{4} q_2)}{r^2} \Longrightarrow \vec F_f=\frac{3}{4} k_e\frac{q_1 q_2}{r^2} \Longrightarrow \vec F_f=\frac{3}{4}(200) \Longrightarrow \boxed{\boxed{\vec F_f=150 \ N}}\)

Thus, the new force would be 150 N.

The new force will be 150N

The force between two charged objects is given by Coulomb's law, which states that the force is proportional to the product of the charges and inversely proportional to the square of the distance between them. Mathematically, Coulomb's law can be expressed as:

F = k * (q1 * q2) / r^2

where F is the force, k is Coulomb's constant, q1 and q2 are the charges of the two objects, and r is the distance between them.

In this problem, we are given that the force between the two objects is 200N. Let us assume that the charges of the two objects are q1 and q2, respectively. Using Coulomb's law, we can write:

200 = k * (q1 * q2) / r^2

Now, we are told that the charge of one object increases by a factor of 3, and the charge of the other object decreases by a factor of 4. Let us call the new charges q1' and q2', respectively. We can write:

q1' = 3 * q1

q2' = (1/4) * q2

Substituting these expressions into Coulomb's law, we get:

F' = k * (q1' * q2') / r^2

= k * [(3 * q1) * ((1/4) * q2)] / r^2

= k * (3/4) * (q1 * q2) / r^2

= (3/4) * F

Therefore, the new force between the two charged objects is 3/4 times the original force, or 150N.

In summary, the force between two charged objects is proportional to the product of the charges and inversely proportional to the square of the distance between them. If one charge increases by a factor of 3 and the other charge decreases by a factor of 4, the new force between them will be 3/4 times the original force. This is because the product of the charges is multiplied by (3/4) in Coulomb's law.

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During a Type II supernova explosion, a Red Giant star collapses in on itself and the core of the star undergoes a rapid implosion, causing it to form a compact neutron star.

During a Type II supernova explosion, a Red Giant star collapses in on itself and the core of the star undergoes a rapid implosion, causing it to form a compact neutron star. This process involves a large amount of angular momentum being conserved, meaning that the rotation speed of the star will increase significantly.

This is due to the conservation of angular momentum, which states that the total angular momentum of a system remains constant unless acted upon by an external torque. The Red Giant star has a large moment of inertia due to its size and rotation, and when it collapses into a much smaller neutron star, the moment of inertia decreases significantly.

In order to conserve angular momentum, the rotational speed of the neutron star must increase significantly to compensate for the decreased moment of inertia. This increase in rotational speed can be quite dramatic, with some neutron stars rotating hundreds of times per second.

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A cell of inter resistance of 0.5 ohm is connected to coil of resistance 4 ohm and 8 ohm joined in parallel.If there is current of 2A in 8 ohm, the electromotive force (emf) of the cell is approximately 14.5 volts.

To find the emf of the cell, we can apply Ohm's Law and Kirchhoff's laws to analyze the circuit.

Given:

Resistance of the coil, R1 = 4 ohm

Resistance of the other resistor, R2 = 8 ohm

Current passing through the 8-ohm resistor, I = 2A

First, let's analyze the parallel combination of the 4-ohm and 8-ohm resistors.

The total resistance of two resistors in parallel can be calculated using the formula:

1/Rp = 1/R1 + 1/R2

Substituting the given values, we have:

1/Rp = 1/4 + 1/8

1/Rp = 2/8 + 1/8

1/Rp = 3/8

Rp = 8/3 ohm

Now, let's consider the total resistance in the circuit, which includes the internal resistance of the cell (0.5 ohm) and the parallel combination of the resistors (8/3 ohm).

R_total = R_internal + Rp

R_total = 0.5 + 8/3

R_total = 1.833 ohm

Now, we can find the emf of the cell using Ohm's Law:

emf = I * R_total

emf = 2 * 1.833

emf ≈ 3.667 volts

Therefore, the emf of the cell is approximately 3.667 volts.

However, it is worth noting that the given current of 2A passing through the 8-ohm resistor does not affect the emf calculation since the emf of the cell is independent of the current in the circuit.

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Answer:  

a) 1m

b) 2μs

c) 3mm

Explanation:

The potential energy of the roller coaster is 176,400 J (joules).

The potential energy of an object is given by the formula PE = mgh, where PE is the potential energy, m is the mass of the object, g is the acceleration due to gravity, and h is the height or vertical position of the object.

In this case, the roller coaster is at a peak of 20m and has a mass of 900kg. The acceleration due to gravity, g, is approximately 9.8 \(m/s^2\).

Using the formula, we can calculate the potential energy:

PE = mgh

= (900 kg)(9.8 \(m/s^2\))(20 m)

= 176,400 J

Therefore, the potential energy of the roller coaster is 176,400 J (joules).

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Answer:

I believe the answer is specific gravity

Explanation:Hope this helps :)

The formula is:

Potential energy = mass x height x gravity

So, the correct answer is Position ( height)

Two American football players running towards each other with masses m1 and m2. Let m1 = 70 kg and m2 = 100 kg, respectively. These players move towards each other at speeds v1 and v2 respectively before they collide and get stuck together to form a single body.

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The speed of the ball just after striking the floor a second time, is 30.0 m/s.

Initial height (h) = 45 m

Acceleration due to gravity (g) = 10 m/s²

Energy loss per collision (k) = 19% = 0.19

At each collision with the floor, the ball loses 19% of its kinetic energy, which means the remaining kinetic energy is 81% (100% - 19%).

When the ball reaches the floor for the first time, it has converted all its potential energy into kinetic energy. So, the initial kinetic energy (K₁) is equal to the potential energy (PE) at the initial height:

K₁ = PE = mgh

Now, let's consider the ball's motion from the initial height to the first collision point. The ball undergoes free fall, so we can use the equations of motion:

h = (1/2)gt²

t = sqrt(2h/g)

Using this time, we can calculate the initial kinetic energy (K₁):

K₁ = mgh = m * 10 m/s² * 45 m

Since the ball loses 19% of its kinetic energy at each collision, the remaining kinetic energy is 81%:

K₂ = K₁ * 0.81

The ball then rebounds elastically from the floor, conserving both kinetic energy and speed. Therefore, the speed just after striking the floor for the second time (v₂) is equal to the speed just before the first collision (v₁):

v₂ = v₁

To find the speed just before the first collision (v₁), we can use the equation of motion:

v = gt

Substituting the time (t) we found earlier, we have:

v₁ = g * sqrt(2h/g)

Now, we can substitute the known values and calculate the speed just after striking the floor for the second time:

v₁ = 10 m/s² * sqrt(2 * 45 m / 10 m/s²)

v₂ = v₁

By evaluating the expression, we find:

v₁ ≈ 30.0 m/s

v₂ ≈ 30.0 m/s

Therefore, the speed of the ball just after striking the floor for the second time is 30.0 m/s.

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When you put on sunglasses and looks at the outside view, the sky is a little dark, but the reflection from a pond is much darker because Pond reflection is polarized. Option (A) is correct.

In the field of physics, polarization is referred to as a phenomena brought on by the fact that electromagnetic radiation is a wave.

Moving across space, electric and magnetic fields interact to form light. Light waves vibrate electrically and magnetically in perpendicular to one another. The magnetic field and electric field both move perpendicular to one another in different directions.

As a result, the direction of motion is perpendicular to both the plane occupied by the electric field and the plane of the magnetic field that is perpendicular to it.

These magnetic and electric vibrations can take place on a variety of planes. Unpolarized light is a type of light wave that vibrates in more than one plane. The sun, a lamp, and a tube light are all examples of unpolarized light sources.

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