The critical value(s) of Function f(x) = 2x√(3x+4) are -2 and -4/3.
To find the critical values, we need to find the points where the derivative of f(x) is equal to zero or undefined. The derivative of f(x) is given by:
f'(x) = 2√(3x+4) + 2x/[√(3x+4)]
Setting f'(x) = 0 and solving for x, we get:
2√(3x+4) + 2x/[√(3x+4)] = 0
Multiplying both sides by √(3x+4), we get:
2(3x+4) + 2x = 0
Simplifying, we get:
8x + 8 = 0
Solving for x, we get x = -1, which is not a critical value since the derivative is defined at x = -1.
Now, we need to check for the values of x that make the derivative undefined. The derivative is undefined when the denominator of the second term is equal to zero, which happens when:
3x + 4 = 0
Solving for x, we get x = -4/3, which is a critical value.
Finally, we need to check the sign of the derivative on each interval to determine where f(x) is increasing or decreasing. We can create a sign chart for f'(x) as follows:
Interval (-∞, -4/3) (-4/3, -2) (-2, ∞)
f'(x) + - +
Thus, f(x) is increasing on (-∞, -4/3) U (-2, ∞) and decreasing on (-4/3, -2). Using interval notation, we can write:
Increasing: (-∞, -4/3) U (-2, ∞)
Decreasing: (-4/3, -2)
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You have been asked to cut a 1.5m roll of bubble wrap into 30 cm lengths, which are used to wrap CDs before posting to clients. How many pieces of bubble wrap will you end up with?
a. 3
b. 4
c. 5
d. 6
Answer:
c. 5
Step-by-step explanation:
1.5m = 1.5*100 cm = 150 cm
Divide 150 cm by 30 cm,
150/30 = 5
25, 20, 18, _____, 11, _____,_____ what number is missing in this pattern
A basic skill needed to do simulation is to be able to correctly assign random numbers to a probability distribution. Do this for the circumstances described below. In each instance identify all possible outcomes and the probabilties associated with those outcomes before assigning random numbers according to the scheme described in Chapter 5. a. Rolling a dice. b. Flipping a coin.
(a) For Rolling a dice the outcomes and probabilities are,
Outcomes = {1, 2, 3, 4, 5, 6}
Probability to get 1 on the face = p(1) = 1/6
Probability to get 2 on the face = p(1) = 1/6
Probability to get 3 on the face = p(1) = 1/6
Probability to get 4 on the face = p(1) = 1/6
Probability to get 5 on the face = p(1) = 1/6
Probability to get 6 on the face = p(1) = 1/6
(b) For Flipping a coin the outcomes and probabilities are,
Outcomes = {Head, Tail}
Probability of getting Head = 1/2
Probability of getting Tail = 1/2
(a) Here the event is Rolling a dice.
So the possible outcomes under the event rolling a dice are each of the face values on the dice.
So outcomes are = {1, 2, 3, 4, 5, 6}
Now, the probabilities are,
Probability to get 1 on the face = p(1) = 1/6
Probability to get 2 on the face = p(1) = 1/6
Probability to get 3 on the face = p(1) = 1/6
Probability to get 4 on the face = p(1) = 1/6
Probability to get 5 on the face = p(1) = 1/6
Probability to get 6 on the face = p(1) = 1/6
(b) Here the event is Flipping a coin.
So the possible outcomes under this event can be getting a Head or getting a Tail.
Outcomes = {Head, Tail}
Probability of getting Head = 1/2
Probability of getting Tail = 1/2
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Solve. 4x−y−2z=−8 −2x+4z=−4 x+2y=6 Enter your answer, in the form (x,y,z), in the boxes in simplest terms. x= y= z=
Answer:
(-2, 4, 2)
Where x = -2, y = 4, and z = 2.
Step-by-step explanation:
We are given the system of three equations:
\(\displaystyle \left\{ \begin{array}{l} 4x -y -2z = -8 \\ -2x + 4z = -4 \\ x + 2y = 6 \end{array}\)
And we want to find the value of each variable.
Note that both the second and third equations have an x.
Therefore, we can isolate the variables for the second and third equation and then substitute them into the first equation to make the first equation all one variable.
Solve the second equation for z:
\(\displaystyle \begin{aligned} -2x+4z&=-4 \\ x - 2 &= 2z \\ z&= \frac{x-2}{2}\end{aligned}\)
Likewise, solve the third equation for y:
\(\displaystyle \begin{aligned} x+2y &= 6\\ 2y &= 6-x \\ y &= \frac{6-x}{2} \end{aligned}\)
Substitute the above equations into the first:
\(\displaystyle 4x - \left(\frac{6-x}{2}\right) - 2\left(\frac{x-2}{2}\right)=-8\)
And solve for x:
\(\displaystyle \begin{aligned} 4x+\left(\frac{x-6}{2}\right)+(2-x) &= -8 \\ \\ 8x +(x-6) +(4-2x) &= -16 \\ \\ 7x-2 &= -16 \\ \\ 7x &= -14 \\ \\ x &= -2\end{aligned}\)
Hence, x = -2.
Find z and y using their respective equations:
Second equation:
\(\displaystyle \begin{aligned} z&=\frac{x-2}{2} \\ &= \frac{(-2)-2}{2} \\ &= \frac{-4}{2} \\ &= -2\end{aligned}\)
Third equation:
\(\displaystyle \begin{aligned} y &= \frac{6-x}{2}\\ &= \frac{6-(-2)}{2}\\ &= \frac{8}{2}\\ &=4\end{aligned}\)
In conclusion, the solution is (-2, 4, -2)
Answer:
x = -2
y =4
z=-2
Step-by-step explanation:
4x−y−2z=−8
−2x+4z=−4
x+2y=6
Solve the second equation for x
x = 6 -2y
Substitute into the first two equations
4x−y−2z=−8
4(6-2y) -y -2 = 8
24 -8y-y -2z = 8
-9y -2z = -32
−2(6-2y)+4z=−4
-12 +4y +4z = -4
4y+4z = 8
Divide by 4
y+z = 2
z =2-y
Substitute this into -9y -2z = -32
-9y -2(2-y) = -32
-9y -4 +2y = -32
-7y -4 = -32
-7y =-28
y =4
Now find z
z = 2-y
z = 2-4
z = -2
Now find x
x = 6 -2y
x = 6 -2(4)
x =6-8
x = -2
Find the zeros of functions.Enter the solutions from least to greatest.
F(x)=-(x+6)^2 -49
Lesser x=
Greater x=
The zeros of the function F(x) = -(x+6)^2 - 49 are -6 - 7i and -6 + 7i.
To find the zeros of the function F(x) = -(x+6)^2 - 49, we need to find the values of x when F(x) = 0.
Step 1: Set the function equal to 0.
0 = -(x+6)^2 - 49
Step 2: Isolate the squared term.
49 = -(x+6)^2
Step 3: Divide both sides by -1 to remove the negative sign.
-49 = (x+6)^2
Step 4: Take the square root of both sides.
√(-49) = x+6
Since the square root of a negative number is a complex number (involving an imaginary unit 'i'), there are no real zeros for this function. The zeros are complex and can be written as:
Lesser x = -6 - 7i
Greater x = -6 + 7i
Your answer: The zeros of the function F(x) = -(x+6)^2 - 49 are -6 - 7i and -6 + 7i.
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What is the volume of the pyramid?
Answer:
It’s a blank page sorry
Step-by-step explanation:
1.Let x, y be any two numbers that satisfies the conditions x ≠0, y ≠0, and x 0
C.y/x>1
D.x/y<1
2.A pickup truck that can hold up to 3000 pounds is carrying a big machine that is 300 pounds and a few smaller ones that each weigh 60 pounds.
At least how many small machines can you fit so that it will not exceed the weight limit of the truck?
A.no more than 50
B.no less than 50
C.no less than 45
D.no more than 45
3.It usually takes Claude 40 minutes driving at 48 miles per hour to go from home to work. But due to road maintenance today, Claude has to take a detour, which makes the trip 8 miles longer than usual. What is the minimum speed Claude should travel so that he can reach the destination in less than 48 minutes?
A.30 miles per hour
B.56 miles per hour
C.50 miles per hour
D.64 miles per hour
*please make sure you answer all the questions please and thank you.
Answer:
x and y can be any two numbers greater than zero such that y is also greater than x
D.no more than 45
C.50 miles per hour
Step-by-step explanation:
Let the two numbers be such that x< y because we have been given y/x>1 and x/y< 1 .
Suppose we take y= 9 and x= 3 then
9/3 > 1
3>1
Also
3/9 < 1
1/3 < 1
x and y can be any two numbers greater than zero such that y is also greater than x
2. Total weight that can be carried is 3000 pounds.
The big machine is 300 pounds. The weight that the truck can carry beside the big machine is 3000-300= 2700 pounds.
The smaller machines weigh 60 pounds
The number of smaller machines that can be carried is 2700 ÷ 60= 45 other than the big machine.
3. Total distance = Speed * time
= 48 * (40/60) = 32 miles
New distance = 32+ 8= 40 miles
New time = 48 minutes
Speed = distance / time = 40/ 48/60= 50 miles per hour
3 squares = 27 feet
How many feet represent 1 square?
Answer:9
Step-by-step explanation:
27 divided by 3
Answer:
9 feet represent 1 square
Step-by-step explanation:
27 divided by 3 is 9
Therefore, your answer is 9 feet ;)
Hope this helped!
geometric term that describes two edges that form a square corner
Answer:
Perpendicular lines
Step-by-step explanation:
Brainliest plz
Hope this helped
Ty
Please help with this, I have no clue what it means.
Answer:
LN = 4.326
Step-by-step explanation:
dropping a perpendicular from point k to LM
call that point on line LM, point X
angle KLM = 47 degrees so angle NKL = 28 degrees
sin 47 = KX/8.9
KX = 6.509
angle LKX = 90-47-28 = 15 degrees
tan 15 = XN/6.509
XN = 1.744
cos 47 = XL/8.9
XL = 6.070
XL-XN=LN
LN = 6.070-1.744 = 4.326
Help what is it i cant do whatever peganroym therom thing is
Answer:
13.4
Step-by-step explanation:
use a^2+b^2=c^2
longest side=18 so c=18
other leg= 144
plug it in: 12^2+b^2=18^2
144+b^2=324
144+b^2=324-144
180 square root= 13.4
Find (f + g)(x) and (f – g)(x).
f(x) = 2x2 – 3+ 7x, g(x) = 11 + 4x²
Answer:
(f + g)(x) = 2x² - 3 + 7x + 11 + 4x² = 6x² + 7x + 8
(f - g)(x) = 2x² - 3 + 7x - 11 - 4x² = -2x² +7x - 14
find f(3) if f(x) = -4x + 1?
Answer:
f (3) equals -11
Step-by-step explanation:
f (x) = -4x + 1
For f(3), just substitute 3 in the place of x:-
f (3) = -4 x 3 + 1
f (3) = -12 + 1
f (3) = -11Answer:
-11
Step-by-step explanation:
where x is out -3 so it would look like
-4(3)+1
which is -11
you do -4 * 3 first which = -12 than add one you will get -11
Prove that sec square theta is equals to cosec squared theta equals to bracket tan theta + cot theta × (tan theta minus cot theta post) IMO number 1 + cos theta + 1 over 1 minus cos theta equals to cosec squared theta
It is proved that LHS = RHS
i.e., (secθ−cosθ)(cotθ+tanθ) = tanθ secθ
Trigonometry is the branch of mathematics that studies the relationship between angles and the ratio of lengths. The field originated in the Hellenistic world in the 3rd century BC, from the application of geometry to the study of astronomy. The Greeks focused on calculating chords, while Indian mathematicians created the first known tables of values for equational sine ratios, also called trigonometric functions.
According to the Question:
L.H.S = (secθ−cosθ)(cotθ+tanθ)
= (1/ cosθ −cosθ)( cosθ/sinθ + sinθ/cosθ )
= (1−cos²θ/ cosθ)( cos²θ +sin²θ / sinθcosθ)
since we know that:
sin²θ+cos ²θ = 1
=sin²θ/cosθ(1/sinθ cosθ)
= sinθ/ cosθcosθ
= tanθ secθ
= R.H.S
Complete Question:
Prove that:
(secθ−cosθ)(cotθ+tanθ) = tanθsecθ
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An object is translated by (x-2, y-6). If one point in the pre-image has the coordinates (-3, 7,) what would be the coordinates of this image
Answer:
(- 5, 1 )
Step-by-step explanation:
Given the translation rule
(x, y ) → (x - 2, y - 6 )
This means subtract 2 from the original x- coordinate and subtract 6 from the original y- coordinate, that is
(- 3, 7 ) → (- 3 - 2, 7 - 6 ) → (- 5, 1 )
A groundhog raided the garden and ate 10 carrots then at 2 carrots after that how many hours was the ground hog in the garden if it ate a total of 30 carrots use the equation 2c+10=30
Answer:
18
Step-by-step explanation:
if there were 30 carrots at first, and 10 were gone, then 2 after that
The equation would be 30 - 10 - 2 = 18
State at least one non-trevial subgroup of the group U. Show and explain a) U=Z_4+′′
b) U=G_2(r), ′′X ′′
a) A non-trivial subgroup of U = Z₄+′′ is {1}. b) A non-trivial subgroup of U = G₂(r), ′′X ′′ is the subgroup generated by a prime divisor of r, denoted as <p>.
a) The group U = Z₄+′′ refers to the group of units modulo 4 under addition. The elements of this group are {1, 3}.
To find a non-trivial subgroup of U, we need to find a subset of U that is closed under the operation and satisfies the group axioms.
One example of a non-trivial subgroup of U is {1}, which consists of the identity element. This subset is closed under addition and satisfies the group axioms. It is non-trivial because it is not the entire group U.
b) The group U = G₂(r), ′′X ′′ represents the group of units in the ring G₂(r), where r is a positive integer greater than 2. The elements of this group are the positive integers less than r and coprime to r.
To find a non-trivial subgroup of U, we need to find a subset of U that is closed under the operation and satisfies the group axioms.
One example of a non-trivial subgroup of U is the subgroup generated by a prime divisor of r. Let p be a prime divisor of r. The subgroup generated by p, denoted as <p>, consists of all positive powers of p modulo r. This subset is closed under multiplication (which is the operation in this case) and satisfies the group axioms. It is non-trivial because it is a proper subset of U and contains at least two elements (1 and p).
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What is the answer -10b-7=9?
i think it should be -1.6
if you add 7 to 9 it'll be 16.
if you divide -10 by 16 it'll give you -16/10.
simplify it and you should get -8/5 or -1.6.
−7(4x−2)+7x simplified
Answer:
-21x + 14
Step-by-step explanation:
Hope this helps! Pls give brainliest!
Someone please help i can’t find the answer.
Answer:
f(3) = 4
Step-by-step explanation:
Give x = 3 in the interval x ≥ 1 then f(x) = x + 1 , and
f(3) = 3 + 1 = 4
in order to ensure optimal health (and thus accurate test results), a lab technician needs to feed the rabbits a daily diet containing a minimum of 24 grams (g) of fat, 36 g of carbohydrates, and 4 g of protein. but the rabbits should be fed no more than five ounces of food a day. rather than order rabbit food that is customblended, it is cheaper to order food x and food y, and blend them for an optimal mix. food x contains 8 g of fat, 12 g of carbohydrates, and 2 g of protein per ounce, and costs $0.20 per ounce. food y contains 12 g of fat, 12 g of carbohydrates, and 1 g of protein per ounce, at a cost of $0.30 per ounce. what is the optimal blend of food x and food y?
According to the unitary method, the lab technician can save money by blending 1.09 ounces of food x and 3.91 ounces of food y to meet the rabbits' nutritional needs.
First, let's determine the total minimum amount of each nutrient that the rabbits need per day. According to the requirements, the rabbits need a minimum of 24 g of fat, 36 g of carbohydrates, and 4 g of protein per day. Using a unitary method, we can find out how much of each nutrient is required per ounce of food:
For fat: 24 g ÷ 5 oz = 4.8 g/oz
For carbohydrates: 36 g ÷ 5 oz = 7.2 g/oz
For protein: 4 g ÷ 5 oz = 0.8 g/oz
Now we can compare these requirements to the nutrient content of food x and food y to determine the optimal blend. Let's use the variables x and y to represent the number of ounces of food x and food y, respectively, in the blend. We can set up the following equations:
8x + 12y = 4.8x + 7.2y + 24 (equation for fat)
12x + 12y = 7.2x + 4.8y + 36 (equation for carbohydrates)
2x + y = 0.8x + 0.8y + 4 (equation for protein)
We also know that the total amount of food in the blend should not exceed five ounces, so we can add the following constraint:
x + y ≤ 5 (equation for total food limit)
Now we can solve for x and y by using any method of solving a system of equations. In this case, it's easiest to use substitution. Let's use the equation for protein to solve for y:
2x + y = 0.8x + 0.8y + 4
1.2y = 1.2x + 4
y = x + 3.33
Now we can substitute y in the other equations:
8x + 12(x + 3.33) = 4.8x + 7.2(x + 3.33) + 24
20.67x = 22.62
x ≈ 1.09
12x + 12(x + 3.33) = 7.2x + 4.8(x + 3.33) + 36
21.99x = 26.61
x ≈ 1.21
Therefore, the optimal blend is 1.09 ounces of food x and 3.91 ounces of food y. Let's check if this blend meets the nutritional requirements:
Fat: (8 g/oz x 1.09 oz) + (12 g/oz x 3.91 oz) = 64.28 g > 24 g (minimum required)
Carbohydrates: (12 g/oz x 1.09 oz) + (12 g/oz x 3.91 oz) = 59.28 g > 36 g (minimum required)
Protein: (2 g/oz x 1.09 oz) + (1 g/oz x 3.91 oz) = 5.09 g > 4 g (minimum required)
As we can see, the optimal blend meets all the nutritional requirements and stays within the daily food limit of five ounces. The cost of the blend can be calculated as follows:
Cost of food x: 1.09 oz x $0.20/oz = $0.218
Cost of food y: 3.91 oz x $0.30/oz = $1.173
Total cost: $0.218 + $1.173 = $1.391
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All of the answers in the picture. With work please.
Given that:
1. The brown family paid $170 for 3 children and 2 adults
2. The Rodriguez family paid $360 for 4 children and 6 adults
a. if x is the price of a child's ticket and y is the price of an adult's ticket, then the system of equations that models the situation would be:
\(\begin{gathered} 3x+2y=170\ldots\ldots\text{.}(1) \\ 4x+6y=360\ldots\ldots\text{.}(2) \end{gathered}\)Note that:
Equation (1) and (2) are the model equations for the Brown family and Rodriguez family respectively
b.
Note that, the red and blue line represents the first and second model equations respectively
c. The coordinates of the point intersection is:
\((x,y)=(30,40)\)d.
The coordinate of the point of intersection (30, 40) means that the price of a child's ticket for the Brown and Rodriguez family is $30, and the cost of an adult's ticket for the Brown and Rodriguez family is $40
What is the surface area for a box with 12 as length, 10 as height and 3 as width.
Answer: 372 units²
Step-by-step explanation:
We can use this formula to solve for the surface area:
Surface Area = 2lw + 2lh + 2hw
We will substitute the known values and solve:
Surface Area = 2lw + 2lh + 2hw
Surface Area = 2(12)(3) + 2(12)(10) + 2(10)(3)
Surface Area = 372 units²
Given that ∠3≅∠5 .
Which theorem proves that d∥e?
alternate exterior angles theorem
converse of the alternate interior angles theorem
converse of the alternate exterior angles theorem
alternate interior angles theorem
By alternate interior angles theorem ∠3≅∠5, d║e. Therefore, option D is the correct answer.
From the given figure ∠3≅∠5.
What are alternate angles?The alternate exterior angle theorem states that if two lines are parallel and are intersected by a transversal, then the alternate exterior angles are considered as congruent angles or angles of equal measure.
From the given figure, 46° + ∠3 =180°
⇒ ∠3 =134°
∠3 = ∠5 =134° (alternate interior angles)
By alternate interior angles theorem ∠3≅∠5, d║e. Therefore, option D is the correct answer.
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Help pleasee. I have no idea how to do this
On a coordinate grid, both point (−4, −1) and (2, 6) points are reflected across the y-axis. What are the coordinates of the reflected points?
(4, 1) and (−2, −6)
(−4, 1) and (−2, 6)
(−4, 1) and (2, −6)
(4, −1) and (−2, 6)
Answer:
option 4
Step-by-step explanation:
Under a reflection in the y- axis
a point (x, y ) → (- x, y ) , then
(- 4, - 1 ) → (4, - 1 )
(2, 6 ) → (- 2, 6 )
What is the solution to the equation Negative 3 (h + 5) + 2 = 4 (h + 6) minus 9?
h = –4
h = –2
h = 2
h = 4
Answer:
h=-4
Step-by-step explanation:
Use the Distributive law:
1. -3(h+5) gives us -3h-15 then you add your two(2).
the whole of your left side of the equation will give you -3h-13
2. 4(h+6) gives us 4h+24 then you subtract nine(9).
the whole of the right side of the equation will give you 4h+15
3. equate the two like this:
-3h-13=4h+15
4. group like terms of each side:
-13-15=4h+3h
5. Add and Subtract
-28=7h
6. Decide both sides by 7 to make h the subject of the formula
7. Congratulations you got your answer as h=-4
Answer:
a. h = -4
Step-by-step explanation:
What is the base area.
Answer:
Area of the base is 10.5 cm².
Step-by-step explanation:
Formula for the volume of the given oblique prism = Area of the triangular base × Vertical height between two triangular bases
Vertical height = 6 cm
Volume = 63 cm³
From the formula,
63 = Area of the triangular base × 6
Area of the base = \(\frac{63}{6}\)
= 10.5 cm²
Therefore, area of the base is 10.5 cm².
which method represents a correct way to solve the equation 2(t−5)=48?
The solution to the equation 2(t - 5) = 48 is t = 29.
To solve the equation 2(t - 5) = 48, we can use the following steps:
Distribute the 2 to the terms inside the parentheses:
2t - 10 = 48
Add 10 to both sides of the equation to isolate the variable term:
2t = 58
Divide both sides of the equation by 2 to solve for t:
t = 29
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PLZ HELP! I WILL GIVE BRAINLIEST
Answer:
hi so can you explain it better i will know what to do thanks i will let you know when i have it
Step-by-step explanation:
Answer:
both are parallel to each other
Step-by-step explanation: