1. Mr. Terry had $70 to purchase school supplies
for his class. He bought 24 glue sticks and 10
packs of pencils. Each glue stick cost $1.15 and
each pack of pencils cost $0.58. How much money
did Mr. Terry have left after these purchases?
Answers
Answer:
Mr. Terry has $36.60 left after these purchases.
Step-by-step explanation:
1. Multiply the amount of glue sticks purchased by their singular cost.
24 x 1.15= 27.6
2. Multiply the amount of pencil packs purchased by their singular cost.
10 x 0.58= 5.8
3. Add the solutions.
27.6+5.8=33.4
4. Subtract 33.4 from 70.
70-33.4=36.60
Related Questions
Is ABC similar to DEF? why or why not
Answers
Answer:
What is the triangle?
Can you edit your question to contain a picture of the triangle so I can give you a definite answer?
Step-by-step explanation:
May I have brainliest please? :)
[IMAGE] is this linear or not and why? if it is what’s the equation?
![[IMAGE] is this linear or not and why? if it is whats the equation?](https://i5t5.c14.e2-1.dev/h-images-qa/contents/attachments/6uQOzItiqSfg61gcsRlfGP8SZbHcl5XS.png)
Answers
Answer:
Linear, equation: y = -2x + 1
Given that ΔJKL ≅ ΔUVW and ΔUVW ≅ ΔABC, complete the following statements. Triangle JKL is congruent to triangle . Side LK corresponds to sides . Angle JLK corresponds to angles
Answers
Answer:
Triangle JKL is congruent to triangle
✔ ABC
.
Side LK corresponds to sides
✔ WV and CB
.
Angle JLK corresponds to angles
✔ UWV and ACB
.
Step-by-step explanation:
just did it on edge 2020
Triangle JKL is congruent to triangle ABC.
Side LK corresponds to sides BC.
Angle JLK corresponds to angles BAC.
What is congruent?In geometry, two figures or objects are said to be congruent if their shapes and sizes match, or if one is the mirror image of the other.
As per the given information,
ΔJKL ≅ ΔUVW: This means that triangle JKL is congruent to triangle UVW. Congruent triangles have the same shape and size, so their corresponding angles and sides are equal in measure and length, respectively.
ΔUVW ≅ ΔABC: This means that triangle UVW is congruent to triangle ABC.
Combining these two pieces of information, we can conclude that:
ΔJKL ≅ ΔABC: This is because if two triangles are congruent to the same triangle, then they must be congruent to each other. Therefore, triangle JKL is congruent to triangle ABC.
Side LK corresponds to sides BC: Corresponding sides of congruent triangles are equal in length. In this case, side LK corresponds to side VW (since JKL ≅ UVW), which corresponds to side BC (since UVW ≅ ABC).
Angle JLK corresponds to angles BAC: Corresponding angles of congruent triangles are equal in measure. In this case, angle JLK corresponds to angle UVW (since JKL ≅ UVW), which corresponds to angle BAC (since UVW ≅ ABC).
So, we can say that triangle JKL is congruent to triangle ABC, side LK corresponds to sides BC, and angle JLK corresponds to angles BAC.
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Create pattern with the rule n x 2
Answers
Step-by-step explanation:
n×2=?
The n means 1 then. 1×2 series
1 × 2 = 2
Which best describes a cone?
Answers
Answer:A cone is a 3-dimensional solid object that has a circular base and a single vertex
Step-by-step explanation:
dolphinsproduction on insta
Answer:
A cone have a point a the top with a round end which is a circle at the bottom.
Look at the graph below. Is it a function or not a function? Explain your reasoning.
Answers
Can you show how to do this
Answers
Answer:
3
Step-by-step explanation:
You use a method called KCF (Keep, change, flip), which means that you keep the first fraction, change the division sign to a multiplication sign, and flip the fraction of 3/4 to 4/3. After that you can just multiply \(\frac{9}{4}\) into \(\frac{4}{3\\}\) which gives you \(\frac{36}{12}\) and can be simplified to give you 3.
Answer:
3
Step-by-step explanation:
keep change flip
keep 9/4
change the divide symbol to a multiplication symbol
flip 3/4 to 4/3
work:
9 4
__ X __
4 3
36
___ = 3
12
5. Jamal is taking a road trip. He plans to travel a total of 350 miles over the course of 8 days. If he plans on driving an equal amount each day, how far will he travel each day? Solve and check!
Answers
Answer: 43.75 miles per day.
Step-by-step explanation: All you have to do is divide 350 by 8, when you divide you basically just split the number evenly 8 times, which is what 350 divided by 8 is. He will have to drive 43.75 miles a day.
Given the polynomial 2xcube + 5xsquare + 3x +4 what is it’s value when x= 10
Answers
Answer:
2534
Step-by-step explanation:
2x^3+5x^2+3x+4
x=10, so:
2(10)^3+5(10)^2+3(10)+4
2000+500+30+4
Answer: 2534
Marbles question:
John is told to find 3 specific marbles within a box of 60 marbles. The room is dark and he can’t see the marbles properly. He pours out 20 of these marbles, and blindly chooses 3 of them.
What are the chances he chooses the 3 specific marbles he was told to find?
Answers
The chances he chooses the 3 specific marbles he was told to find is 1/20.
How to calculate the probability?It should be noted that there are 60 marbles and he wants to find 3.
In this case, he poured out 20. Therefore, his chances of picking the three marbles will be 1 out of 20.
Therefore, the chances will be 1/20.
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Charlie will run at most 35 miles this week. So far, he has run 17 miles. What are the possible numbers of additional miles he will run?
please help can not figere out 9th grade math
by matthew
Answers
Step-by-step explanation: We may determine the range of potential further miles Charlie will run by deducting his present mileage from the maximum mileage if he has already run 17 miles and will only cover 35 miles this week.
Maximum mileage - current mileage = potential extra miles.
17 miles minus 35 miles equals 18 miles.
As a result, Charlie may run somewhere between 0 and 18 additional miles.
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Answer:
18 possible numbers
Step-by-step explanation:
If Charlie has already run 17 miles and he will run at most 35 miles this week.
We can calculate the possible numbers of additional miles he will run by subtracting the distance he has already run from the maximum distance he can run.
Maximum distance Charlie can run = 35 miles
Distance Charlie has already run = 17 miles
Possible additional miles he will run = Maximum distance - Distance already run
= 35 miles - 17 miles
= 18 miles
Therefore, there are 18 possible numbers of additional miles Charlie will run.
A fraternity charge $2.00 admission for dudes and $1.00 admission for ladies. They made $45 and sold 35 tickets how many ladies attended the party
Answers
After solving the equations, we know that a total of 25 ladies attended the party.
What are equations?A mathematical statement that has an "equal to" symbol between two expressions with equal values is called an equation.
As in 3x + 5 Equals 15, for instance.
Equations come in a variety of forms, including linear, quadratic, cubic, and others.
So, take dudes as x and ladies as y.
Now, form the required 2 equations as follows:
2x + y = 45 ...(1)
x + y = 35 ...(2)
Work on equation (2):
x + y = 35
x = 35 - y
Now, substitute x = 35 - y in equation (1):
2x + y = 45
2(35-y) + y = 45
70 - 2y + y = 45
-y = -25
y = 25
Since ladies were charged $1 for each ticket, then 25 ladies attended the party.
Therefore, after solving the equations, we know that a total of 25 ladies attended the party.
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Find the indicated measure HELP!
Answers
=4*13 ft
=52ft
4/n = 4/5
a. n=5
b. n = 5/16
c. n= 3 1/5
d. n=50
Answers
Answer:
a. n=5
Step-by-step explanation:
The 4 of numerator cancels each other. So, 1/5=1/n is what you finally have.
Therefore, n=5.
Hope this helps!!
Question 2
No calculations are necessary to answer this question.
3/01
3/02
$1.7420 $1.7360
Date
July GBP Futures
Contract Price
O long; long
Based on the closing prices of July GBP Futures Contract over the 3-day period in March 20XX as shown above, you shou
position on 3/01 and a position on 3/02.
O long; short
O short; short
3/03
short; long
$1.7390
Answers
The given information does not provide any clear indication for determining the position that should be taken on 3/01 and 3/02. Without additional information, it is not possible to make a decision. The table only displays the closing prices of the July GBP Futures Contract on different days, and it is unclear what trading strategy or what scenario is being considered. Additional information about the goals and objectives, the market conditions, and other relevant factors would be necessary to make a decision about trading positions.
If m angle JMK =67, find the m angle JKM
Answers
SOLUTION:
Step 1:
In this question, we are given the following:
If m angle JMK =67, find the m angle JKM
Step 2:
From step 1, we can see that:
\(\begin{gathered} \angle JMK=67^0 \\ \text{and } \\ \angle MJK=90^0 \\ \text{Then , we have that:} \end{gathered}\)\(\angle JKM=90^0-67^{0\text{ }}=23^0\)CONCLUSION:
From the above solution, we can see clearly that the final answer is:
\(\angle JKM=23^0\)
800 * 600 + 200+ 100=?
Solve show that your smart
Answers
Answer: 480300
Step-by-step explanation:
800 * 600 + 200 + 100
480000 + 200 + 100
480000 + 300
480300
Answer:
480300
Step-by-step explanation:
Because 6*8=48 then 800*600=480000
Then 200+100=300
Then 480000+300=480300
Hope this helps!
I think i'm right
Pls help
I need help asap
Answers
6. Journalise the following transactions
1. Bricks for Rs 60,000 and timber for Rs 35,000 purchased for
the construction of building. The payment was made by cheque.
2. Placed in fixed deposit account at bank by transfer from current
account Rs 13,000.
3. Appointed Mr. S.N. Rao as Accountant at Rs 300 p.m. and
Received Rs 1000 as security Deposit at 5% p.a. interest.
4. Sold goods to shruti for Rs 80,000 at 15% trade discount and
4% cash discount. Received 75% amount immediately through a
cheque.
5. Purchased goods from Richa for Rs 60,000 at 10% trade
discount and 5% cash discount. 60% amount paid by cheque
immediately.
6.
On 18th jan,Sold goods to shilpa at the list price of Rs 50,000
20% trade discount and 4% cash discount if the payment is made
within 7 days. 75% payment is received by cheque on Jan 23rd.
7. On 25th jan, sold goods to garima for Rs 1,00,000 allowed her
20% trade discount and 5% cash discount if the payment is made
within 15 days. She paid 1/4th of the amount by cheque on Feb 5th
and 60% of the remainder on 15th in cash.
8. Purchased land for Rs 2,00,000 and paid 1% as brokerage and
Rs 15,000 as registration charges on it. Entire payment is made by
cheque.
9. Goods worth Rs 25,000 and cash Rs 40,000 were taken away
by the proprietor for his personal use.
10. Sold goods costing Rs 1,20,000 to charu at a profit of 33% 3 %
on cost less 15% trade discount.
9
11. Paid rent of building Rs 60,000 by cheque. Half the building is
used by the proprietor for residential purpose.
12. Sold goods costing Rs 20,000 to sunil at a profit of 20% on
sales less 20% trade discount .
13. Purchased goods for Rs 1000 from nanda and supplied it to
helen for Rs 1300. Helen returned goods worth Rs 390, which in
turn were returned to nanda.
14. Received invoice at 10% trade discount from rohit and sons
and supplied these goods to madan, listed at Rs 3000.
Answers
1.Bricks and timber purchased for construction. (Debit: Bricks - Rs 60,000, Debit: Timber - Rs 35,000, Credit: Bank - Rs 95,000)
2.Transfer of Rs 13,000 to fixed deposit account. (Debit: Fixed Deposit - Rs 13,000, Credit: Current Account - Rs 13,000)
3.Appointment of Mr. S.N. Rao as Accountant. (Debit: Salary Expense - Rs 300, Debit: Security Deposit - Rs 1,000, Credit: Accountant - Rs 300)
4.Goods sold to Shruti with discounts. (Debit: Accounts Receivable - Shruti - Rs 80,000, Credit: Sales - Rs 80,000)
5.Goods purchased from Richa with discounts. (Debit: Purchases - Rs 60,000, Credit: Accounts Payable - Richa - Rs 60,000)
6.Goods sold to Shilpa with discounts and received payment. (Debit: Accounts Receivable - Shilpa - Rs 50,000, Credit: Sales - Rs 50,000)
7.Goods sold to Garima with discounts and received partial payment. (Debit: Accounts Receivable - Garima - Rs 1,00,000, Credit: Sales - Rs 1,00,000)
8.Purchase of land with additional charges. (Debit: Land - Rs 2,00,000, Debit: Brokerage Expense - Rs 2,000, Debit: Registration Charges - Rs 15,000, Credit: Bank - Rs 2,17,000)
9.Proprietor took goods and cash for personal use. (Debit: Proprietor's Drawings - Rs 65,000, Credit: Goods - Rs 25,000, Credit: Cash - Rs 40,000)
10.Goods sold to Charu with profit and discount. (Debit: Accounts Receivable - Charu - Rs 1,20,000, Credit: Sales - Rs 1,20,000)
11.Rent paid for the building. (Debit: Rent Expense - Rs 60,000, Credit: Bank - Rs 60,000)
12.Goods sold to Sunil with profit and discount. (Debit: Accounts Receivable - Sunil - Rs 24,000, Credit: Sales - Rs 24,000)
13.Purchased goods from Nanda and supplied to Helen. (Debit: Purchases - Rs 1,000, Debit: Accounts Payable - Nanda - Rs 1,000, Credit: Accounts Receivable - Helen - Rs 1,300, Credit: Sales - Rs 1,300)
14.Purchased goods from Rohit and Sons and supplied to Madan. (Debit: Purchases - Rs 2,700, Credit: Accounts Payable - Rohit and Sons - Rs 2,700, Debit: Accounts Receivable - Madan - Rs 3,000, Credit: Sales - Rs 3,000)
Here are the journal entries for the given transactions:
1. Bricks and timber purchased for construction:
Debit: Bricks (Asset) - Rs 60,000
Debit: Timber (Asset) - Rs 35,000
Credit: Bank (Liability) - Rs 95,000
2. Transfer to fixed deposit account:
Debit: Fixed Deposit (Asset) - Rs 13,000
Credit: Current Account (Asset) - Rs 13,000
3. Appointment of Mr. S.N. Rao as Accountant:
Debit: Salary Expense (Expense) - Rs 300
Debit: Security Deposit (Asset) - Rs 1,000
Credit: Accountant (Liability) - Rs 300
4. Goods sold to Shruti:
Debit: Accounts Receivable - Shruti (Asset) - Rs 80,000
Credit: Sales (Income) - Rs 80,000
5. Goods purchased from Richa:
Debit: Purchases (Expense) - Rs 60,000
Credit: Accounts Payable - Richa (Liability) - Rs 60,000
6. Goods sold to Shilpa:
Debit: Accounts Receivable - Shilpa (Asset) - Rs 50,000
Credit: Sales (Income) - Rs 50,000
7. Goods sold to Garima:
Debit: Accounts Receivable - Garima (Asset) - Rs 1,00,000
Credit: Sales (Income) - Rs 1,00,000
8.Purchase of land:
Debit: Land (Asset) - Rs 2,00,000
Debit: Brokerage Expense (Expense) - Rs 2,000
Debit: Registration Charges (Expense) - Rs 15,000
Credit: Bank (Liability) - Rs 2,17,000
9. Goods and cash taken away by proprietor:
Debit: Proprietor's Drawings (Equity) - Rs 65,000
Credit: Goods (Asset) - Rs 25,000
Credit: Cash (Asset) - Rs 40,000
10. Goods sold to Charu:
Debit: Accounts Receivable - Charu (Asset) - Rs 1,20,000
Credit: Sales (Income) - Rs 1,20,000
Credit: Cost of Goods Sold (Expense) - Rs 80,000
Credit: Profit on Sales (Income) - Rs 40,000
11. Rent paid for the building:
Debit: Rent Expense (Expense) - Rs 60,000
Credit: Bank (Liability) - Rs 60,000
12. Goods sold to Sunil:
Debit: Accounts Receivable - Sunil (Asset) - Rs 24,000
Credit: Sales (Income) - Rs 24,000
Credit: Cost of Goods Sold (Expense) - Rs 20,000
Credit: Profit on Sales (Income) - Rs 4,000
13. Goods purchased from Nanda and supplied to Helen:
Debit: Purchases (Expense) - Rs 1,000
Debit: Accounts Payable - Nanda (Liability) - Rs 1,000
Credit: Accounts Receivable - Helen (Asset) - Rs 1,300
Credit: Sales (Income) - Rs 1,300
14. Goods received from Rohit and Sons and supplied to Madan:
Debit: Purchases (Expense) - Rs 2,700 (after 10% trade discount)
Credit: Accounts Payable - Rohit and Sons (Liability) - Rs 2,700
Debit: Accounts Receivable - Madan (Asset) - Rs 3,000
Credit: Sales (Income) - Rs 3,000
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6.139 rounded to the nearest hundredth?
Answers
Answer:
Step-by-step explanation: 6.140
Find the product.
902 x 27
A. 18,054
B. 20,354
C. 25,254
D. 24,354
Answers
your welcome
distance between points on a coordinate plane=(y2−y1)2+(x2−x1)2−−−−−−−−−−−−−−−−−−√
Find the distance when y2=9, y1=13, x2=4,
and x1=0
.
A. 5.66
B. 5.36
C. 4.12
D. 6.95
Answers
The distance between the two points is approximately 5.66 units
A. 5.66How to find the distanceUsing the formula for the distance between two points on a coordinate plane:
Distance = √[(y2 - y1)^2 + (x2 - x1)^2]
We can plug in the given values into the distance formula:
given that
y2 = 9, y1 = 13, x2 = 4, and x1 = 0
= √[(9 - 13)^2 + (4 - 0)^2]
= √[(-4)^2 + (4)^2]
= √(16 + 16)
= √32
= 4√2
= 5.6569
= 5.66
Therefore, the distance between the two points is approximately 5.66 units, which corresponds to option A.
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Assume that x and y are both differentiable functions of t. Find dx/dt when x=11 and dy/dt=-4 for the equation xy=99 .
Answers
Differentiating both sides of
xy = 99
with respect to t yields
x dy/dt + y dx/dt = 0
When x = 11, we have
11y = 99 ==> y = 9
and we're given that dy/dt = -4 at this point, which means
11 (-4) + 9 dx/dt = 0 ==> dx/dt = 44/9
help!!!!!!!!!!!!!!!!!!!!!!!!!!!!! due in 5 min will mark brainliest if corect
Answers
You model your investment account using the formula y = 20000(1.035)x where x represents the
number of years and y represents the account balance after x years. What is the growth rate of your
investment?
Answers
Answer:
Step-by-step explanation:
The growth rate of the investment is represented by the constant multiplier in the exponential term of the formula y = 20000(1.035)x. In this case, the constant multiplier is 1.035, which represents the annual growth rate of the investment account.
To calculate the growth rate as a percentage, we can subtract 1 from the constant multiplier, and then multiply the result by 100.
So, the growth rate of the investment is:
1.035 - 1 = 0.035
0.035 * 100 = 3.5%
Therefore, the growth rate of the investment is 3.5%.
The growth rate of the investment can be found by subtracting 1 from the base of the exponential function and converting the result to a percentage:
growth rate = (base - 1) x 100%
growth rate = (1.035 - 1) x 100%
growth rate = 0.035 x 100%
growth rate = 3.5%
Therefore, the growth rate of the investment is 3.5%.
5t+7+8b
I need also help on -2(x+3)=_-6
Answers
The solution to the equation -2(x + 3) = -6 is x = 0.
To simplify the expression 5t + 7 + 8b, we can combine like terms.
There are two like terms in the expression: 5t and 8b.
Combining the like terms gives us:
5t + 8b + 7
Therefore, the simplified form of the expression 5t + 7 + 8b is 5t + 8b + 7.
Regarding the equation -2(x + 3) = -6:
To solve this equation, we can follow these steps:
Distribute the -2 to the terms inside the parentheses:
-2 * x + (-2) * 3 = -6
This simplifies to:
-2x - 6 = -6
Move the constant term to the right side by adding 6 to both sides of the equation:
-2x = 0
Divide both sides of the equation by -2 to isolate the variable x:
x = 0 / -2
Simplifying the right side of the equation gives us:
x = 0
The solution to the equation -2(x + 3) = -6 is x = 0.
The simplified expression 5t + 7 + 8b remains as 5t + 8b + 7, and the solution to the equation -2(x + 3) = -6 is x = 0.
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lender requires a minimum down payment of 18% of the value of the home. You have $29,000 cash available to use as a down payment toward a home. Determine the maximum home value that you can finance.
Answers
The maximum home value that can be financed is approximately $35,365.85.
Let's represent the maximum home value that can be financed by H.
If the minimum down payment is 18%, the amount financed is 100% - 18% = 82%.
Therefore, we have:
H × 82% = $29,000
Multiplying both sides by (1/82%), we get:
H = $29,000 / 82%
= $35,365.85
Hence, the maximum home value that can be financed is approximately $35,365.85.
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The table below shows the cost per pound of different vegetables. Prices of Vegetables Vegetable Cost (per pound) Potatoes $3.89 Squash $4.68 Carrots $1.67 Cucumbers $2.59 What is the estimated cost for 4.5 pounds of cucumbers? O $10 O $15 0 $16 O $25
Answers
Answer:
$10
Step-by-step explanation:
The exact number is $11.65 which is closet to $10
Answer:
The answer is $10
Step-by-step explanation:
Hope this helped! :)
A family of four went to dinner at a local restaurant. Three of the family members ordered the special dinner that costs $12.88 each and the fourth family member ordered the hamburger and fries combo that costs $6.78. If they want to leave a 15% tip, which of the following expressions represents the amount of tip they should leave?
A. (12.88+6.78)×0.15
B. (3×12.88+6.78)×0.15
C. 3×12.88+6.78
D. [3×(12.88+6.78)]×0.15
Answers
Paul has $78 in the bank and saves $30 each week. What is the initial value? Be sure to use negative signs if needed.
Answers
Answer:
The initial value is $78
Step-by-step explanation:
Given
\(Base\ Amount = \$78\)
\(Additional = \$30\) (weekly)
Required
Determine the initial value
The initial value is the amount he has in its bank account before making his weekly savings.
From the question, we have that his initial balance is $78.
Hence, the initial value is $78
However, his weekly balance can be expressed as:
\(Balance = Base\ Amount + Additional * number\ of weeks\)
Represent number of weeks with x; So, we have:
\(Balance = 78 + 30 * x\)
\(Balance = 78 + 30 x\)