1. how much is the increase in temperature from 1880 to 2010?
2. what happened to the amount of carbon dioxide from 1880 to 2010?
3. what is the relationship between the amount of carbon dioxide and global temperature?
4. when was temperature at its highest and at its lowest?

please help neep asap....

Therefore, for a bias current of 0.5 mA, g ≈ 1.92 mA/V, rr ≈ 200 kΩ, and re ≈ 52 Ω. For a bias current of 50 μA, g ≈ 0.192 mA/V, rr ≈ 2 MΩ, and re ≈ 520 Ω.

To solve this problem, we can use the following equations for a common-emitter amplifier:

g = β * Ic / Vt

rr = Vaf / Ic

re = Vt / Ie

where β is the current gain, Ic is the collector current, Vt is the thermal voltage (≈ 26 mV at room temperature), Vaf is the early voltage, and Ie is the emitter current.

(a) For Ic = 0.5 mA:

g = β * Ic / Vt = 100 * 0.5 mA / 26 mV ≈ 1.92 mA/V

rr = Vaf / Ic (assume Vaf = 100 V) = 100 V / 0.5 mA = 200 kΩ

re = Vt / Ie (assume Ie ≈ Ic) = 26 mV / 0.5 mA ≈ 52 Ω

(b) For Ic = 50 μA:

g = β * Ic / Vt = 100 * 50 μA / 26 mV ≈ 0.192 mA/V

rr = Vaf / Ic (assume Vaf = 100 V) = 100 V / 50 μA = 2 MΩ

re = Vt / Ie (assume Ie ≈ Ic) = 26 mV / 50 μA ≈ 520 Ω

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a. The probability that a tire will be too narrow is approximately 0.0918 or 9.18% , b. The probability that a tire will be too wide is approximately 0.0918 or 9.18% , c. The probability that a tire will be defective is approximately 0.8164 or 81.64%.

In order to determine the probabilities for the width of the cyclocross tires, we can use the concept of standard normal distribution. The mean width of the tires is 23 mm, and the standard deviation is 0.15 mm.

a. To find the probability that a tire will be too narrow (below 22.8 mm), we need to calculate the z-score corresponding to this lower specification limit. The z-score is given by the formula:

z = (x - μ) / σ

where x is the lower specification limit, μ is the mean, and σ is the standard deviation. Plugging in the values, we get:

z = (22.8 - 23) / 0.15 = -1.33

Using a standard normal distribution table or a statistical software, we can find that the probability of a z-score being less than -1.33 is approximately 0.0918. Therefore, the probability that a tire will be too narrow is approximately 0.0918 or 9.18%.

b. Similarly, to find the probability that a tire will be too wide (above 23.2 mm), we calculate the z-score corresponding to the upper specification limit:

z = (23.2 - 23) / 0.15 = 1.33

Using the same table or software, we find that the probability of a z-score being greater than 1.33 is approximately 0.0918. Thus, the probability that a tire will be too wide is approximately 0.0918 or 9.18%.

c. To calculate the probability that a tire will be defective, we need to find the area under the normal curve outside the specification limits. This can be done by subtracting the sum of the probabilities obtained in parts a and b from 1:

P(defective) = 1 - P(narrow) - P(wide)

P(defective) = 1 - 0.0918 - 0.0918

P(defective) = 0.8164

Therefore, the probability that a tire will be defective is approximately 0.8164 or 81.64%.

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Answer:

A) Sue is lifting the bucket by a force of 49.035 newtons.

B) The bucket has an acceleration of 8.207 meters per square second on the Moon.

Explanation:

A) According to the First Newton's Law, a system is at equilibrium when it is either at rest or travelling at constant velocity. In this case, Sue must exert an external force on the bucket, whose magnitude is equal to the weight of the bucket but direction is opposed to it. By Second Newton's Law, we find that:

\(\Sigma F = F - m\cdot g = 0\) (1)

Where:

\(F\) - Lifting force, measured in newtons.

\(m\) - Mass of the bucket, measured in kilograms.

\(g\) - Gravitational acceleration, measured in meters per square second.

If we know that \(m = 5\,kg\) and \(g = 9.807\,\frac{m}{s^{2}}\), then the lifting force is:

\(F = m\cdot g\)

\(F = (5\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)\)

\(F = 49.035\,N\)

Sue is lifting the bucket by a force of 49.035 newtons.

B) By the Second Newton's Law, we have the following model:

\(\Sigma F = F-m\cdot g = m\cdot a\) (2)

Where \(a\) is the net acceleration of the bucket, measured in meters per square second.

If we know that \(F = 49.035\,N\), \(m = 5\,kg\) and \(g = 1.6\,\frac{m}{s^{2}}\), then the net acceleration of the bucket is:

\(a = \frac{F}{m} -g\)

\(a = \frac{49.035\,N}{5\,kg}-1.6\,\frac{m}{s^{2}}\)

\(a = 8.207\,\frac{m}{s^{2}}\)

The bucket has an acceleration of 8.207 meters per square second on the Moon.

(a) The force applied by Sue in lifting the bucket at a constant velocity is 49 N.

(b) The acceleration of the bucket when lifted on the moon is 8.2 m/s².

The given parameters;

The force applied by Sue in lifting the bucket at a constant velocity is calculated as;

\(F = m(a + g)\)

\(F= mg\\\\F = 5 \times 9.8\\\\F = 49 \ N\)

The acceleration of the bucket when lifted on the moon with the calculated force is;

\(F = m(a + g)\\\\a+g = \frac{F}{m} \\\\a = \frac{F}{m} - g\\\\a = \frac{49}{5} - 1.6\\\\a = 8.2 \ m/s^2\)

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The linear speed of the electron is 7.03 x 10¹³ m/s and the angular speed of the electron is 5.6 x 10¹³ rev/s.

The speed of the electron is calculated as follows;

F = ma = mv²/r  ---(1)

F = qvB  ----- (2)

mv²/r = qvB

mv/r = qB

mv = qBr

v = qBr/m

where;

v = (1.6 x 10⁻¹⁹ x 2 x 10³ x 0.2) / (9.1 x 10⁻³¹)

v = 7.03 x 10¹³ m/s

ω = v/r

ω = (7.03 x 10¹³ m/s) / (0.2 m) = 3.51 x 10¹⁴ rad/s

ω = 3.51 x 10¹⁴ rad/s  x 1 rev/2π rad

ω = 5.6 x 10¹³ rev/s

Thus, the linear speed of the electron is 7.03 x 10¹³ m/s and the angular speed of the electron is 5.6 x 10¹³ rev/s.

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Answer: the answer is storing properly in refrigeration.

Explanation:

Answer: I believe it may be 18m/s I apologize if it isn't but have a great day :DDD

The surface charge density of the hollow metal sphere is 1.37 × 10⁻⁷ C/m².

Surface charge density is defined as the amount of charge per unit area of a surface. It is denoted by σ. The charge on the surface of a hollow metal sphere can be expressed as:

Q = 19.9 nC = 19.9 × 10⁻⁹ C

The radius of the hollow metal sphere is r = 3.4 cm = 0.034 m

Surface area of a sphere is given as:

A = 4πr² = 4 × π × (0.034 m)² = 0.0145 m²

The surface charge density σ is given by the ratio of the charge to the surface area of the sphere, so:

σ = Q / A

σ = (19.9 × 10⁻⁹ C) / (0.0145 m²)

σ = 1.37 × 10⁻⁷ C/m²

Therefore, the surface charge density of the hollow metal sphere is 1.37 × 10⁻⁷ C/m².

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Answer:

The motion of a ball falling down through the atmosphere, or a model rocket being launched up into the atmosphere are both examples of Newton's first law. The motion of a kite when the wind changes can also be described by the first law

Ps ......

Is that the kind of newtons law you were looking for because your question doesn't really make sense  

The solution would be to either replace the ballasts with ones designed for a 60-hz system or to use lights that are designed to operate on a 60-hz system.

When answering questions on Brainly, it is important to always be factually accurate, professional, and friendly. Answers should be concise and relevant to the question being asked. Typos and irrelevant parts of the question should be ignored.

Here is the answer to the student question:If you are an electrician installing fluorescent lights and notice that the lights were made in Europe and the ballasts are rated for operation on a 50-hz system, they will not be harmed by overcurrent if they are connected to a 60 hz system.

However, there may be a problem with these lights because they are designed to operate on a 50-hz system and not a 60-hz system. This could cause the lights to flicker, not turn on, or burn out prematurely.The most likely cause of the problem is that the ballasts are not designed to operate on a 60-hz system.

The solution would be to either use lights made to work on a 60 hz system or replace the ballasts with ones made for a 60 hz system.

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If the frequency of the block is 0.44 hz , the earliest time after the block is released that its kinetic energy is exactly one-half of its potential energy is: (1/0.44)√2P/m

At the time the block is released, its potential energy is at a maximum and its kinetic energy is zero. The block then moves down, and its potential energy decreases while its kinetic energy increases.

At any given time, the total energy of the block is equal to the sum of its potential energy and its kinetic energy. So, when the kinetic energy is exactly one-half of the potential energy, the total energy of the block is equal to three halves of the initial potential energy.

To calculate the earliest time at which the kinetic energy is one-half of the potential energy, we must use the equation P = ½mv^2. Rearranging, we get: v = √2P/m. We also know that the frequency of the block is 0.44 Hz, which is equal to one divided by the period, T. Thus, the velocity of the block can be calculated by multiplying both sides of the equation with T: v = √2P/(mT).

Therefore, the earliest time after the block is released that its kinetic energy is exactly one-half of its potential energy is equal to:  \(T = \sqrt{2}P/(mv) = \sqrt{2} P/(m*(1/f)) = (1/f)\sqrt{2} P/m\)

Plugging in the values given in the question, the earliest time after the block is released that its kinetic energy is one-half of its potential energy is equal to: T = (1/0.44)√2P/m.

To sum up, the earliest time after the block is released that its kinetic energy is one-half of its potential energy is equal to (1/f)√2P/m, where f is the frequency of the block, P is its potential energy, and m is its mass. In this case, the earliest time is equal to (1/0.44)√2P/m.

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Answer:

Relative age-dating involves comparing a rock layer or rock structure with other near-by layers or structures. Using the principles of superposition and cross-cutting relationships, and structures such as unconformities, one can determine the order of geological events.

At every location along the string, the amplitudes of two waves that interfere with one another are added. The two separate waves combine to form the final wave.

Two transverse waves are present in this instance, one traveling to the right and the other to the left. The waves will interact destructively when they meet since their motions are in opposition.

The resultant wave f(x) at any point x on the string may be calculated by summing the two amplitudes if we let f1(x) represent the amplitude of the wave going to the right and f2(x) represent the amplitude of the wave moving to the left:

f(x) = f1(x) + f2(x)

The amplitudes of the two waves will be equal in size and facing in opposite directions when they collide. As a result, the amplitude that results will be zero, and the string will then be at rest.

The resulting wave will alternate between constructive and destructive interference as the waves continue to travel past one another.

As a result, the string will develop a pattern of nodes (points of zero displacements) and antinodes (points of maximum displacement).

The combined frequency and wavelength of the various waves as well as the rate of wave propagation along the string will determine the final wave's frequency and wavelength.

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Answer:

The acceleration is - 3 m/s2.

Explanation:

initial speed, u = 54 km/h = 15 m/s

final speed, v = 0

time, t = 5 s

Let the acceleration is a.

use first equation of motion

v = u + at

0 = 15 + a x 5

a = - 3 m/s2

Hi There, Buddy!

To solve this problem, let us divide the entire motion into 2 phases

1.) When the elevator is moving with an acceleration

2.) When the elevator has a deceleration

For the first half -

u = 0 , a = 0.6 , t = t1

v = 0.6(t1)  ---------- ( 1 )

s = 1/2 x 0.6 x (t1)^2 = 0.3(t1^2) -------- ( 2 )

For the second half -

u = 0.6(t1) , a = -0.8 , v = 0

0.6 x (t1) = 0.8 (t2) ----> 3(t1) = 4(t2) ---------- ( 3 )

0.36(t1)^2 = 1.6 s2 ---------- ( 4 )

Now, we know that the total time taken is 10 seconds

------- t1 + t2 =10 , 3t1 = 4t2 ---- t1 = 40/7 , t2 = 30/7

Now, substitute values of t1 and t2 in s1 and s2 and add both s1 and s2 to get total distance travelled.

PLEASE MARK AS BRAINLIEST!

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Answer:

Is it possible for a system to have negative energy.  yes, since the choice of the zero of potential energy is arbitrary.

Explanation:

The main advantage multistage rockets have over conventional rockets is they get lighter by dropping empty sections that held fuel. So, option D is the correct answer.

Multistage rockets have an advantage over conventional rockets since they are outlined to drop off empty segments that held fuel as the rocket gains height. This diminishes the weight of the rocket, making it less demanding to realize elude speed and reach the circle. As each organizes is utilized, it is discarded, diminishing the general weight of the rocket and making it more effective.

Multistage rockets are more flexible and can be utilized for a more extensive extend of missions. They can be custom fitted to meet the particular necessities of a mission by including or evacuating stages, which permits them to carry payloads to diverse heights and speeds. In differentiation, conventional rockets carry all of their fuel and engines with them through the complete mission, making them heavier and less proficient. 

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A wrecking ball has a mass of 315 kg. If it is moving at a speed of 5.12 m/s, the kinetic energy is 4128.8 J.

Kinetic energy is defined as an object is the energy it has as a result of movement. A person walking, a baseball being thrown, a piece of food falling from a table, or a charged particle in an electric field are all examples of moving objects that consume kinetic energy. The most important property of kinetic energy is its ability to do work. Work is the force exerted on an object while it is in motion.

Kinetic energy can be expressed as

KE = 1/2 mv²

Given m = 315 kg

v = 5.12 m/s

KE = 1/2 x 315 x (5.12)²

KE = 1/2 x 315 x 26.2144

KE = 4128.8 J

Thus, a wrecking ball has a mass of 315 kg. If it is moving at a speed of 5.12 m/s, the kinetic energy is 4128.8 J.

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The ladder will slip at the point where the reaction at the wall is just over

the force due to friction.

Response:

The given parameter are;

The coefficient of friction, μ = 0.753

Length of the ladder = 9.9 m

Mass of the ladder = 39 kg

Required:

The minimum height below which the ladder will slip.

Solution:

Assumption: The friction of the wall on the ladder is 0.

The weight of the ladder, W = The normal reaction = N

The friction force, \(F_f\) = The reaction force of the wall, \(F_w\)

\(F_f\) = W × μ

Which gives;

\(F_f\) = 39 × 9.81  × 0.753 ≈ 288.09

The friction force, \(F_f\) ≈ 288.09 N = \(F_w\)

Taking moments about the contact between the ladder and the ground, we have;

\(F_w\) × h = W × x

Where;

\(h = \mathbf{L \times sin(\theta)}\)

\(x = \mathbf{\dfrac{L}{2} \times cos(\theta)}\)

Which gives;

\(x = \dfrac{9.9}{2} \times cos(\theta) = \mathbf{4.95 \cdot cos(\theta)}\)

\(h = 9.9 \cdot sin(\theta)\)

θ = The angle made by the ladder and the ground

Therefore;

288.09 × 9.9·sin(θ) =  39 × 9.81 × x  = 382.59 × 4.95·cos(θ)

\(\dfrac{sin(\theta)}{cos(\theta)} = tan(\theta) = \dfrac{382.59 \times 4.95}{288.09 \times 9.9}\)

\(\theta = arctan \left(\dfrac{382.59 \times 4.95}{288.09 \times 9.9} \right) \app\)

Which gives;

\(h = \mathbf{9.9 * sin\left(arctan \left(\dfrac{382.59 \times 4.95}{288.09 \times 9.9} \right) \right)} \approx 5.48\)

The minimum height below which the ladder will slip, h ≈ 5.48 m

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Answer:

The concentration of hydrogen ion at pH is equal to 2 :\(= [H^+]=0.01 mol/L\)

The concentration of hydrogen ion at pH is equal to 6 : \([H^+]'=0.000001 mol/L\)

There are 0.009999 more moles of  \(H^+\) ions in a solution at a pH = 2 than in a solution at a pH = 6.

Explanation:

The pH of the solution is the negative logarithm of hydrogen ion concentration in an aqueous solution.

\(pH=-\log [H^+]\)

The hydrogen ion concentration at pH is equal to 2 = [H^+]

\(2=-\log [H^+]\\\)

\([H^+]=10^{-2}M= 0.01 M=0.01 mol/L\)

The hydrogen ion concentration at pH is equal to 6 = [H^+]

\(6=-\log [H^+]\\\\\)

\([H^+]=10^{-6}M= 0.000001 M= 0.000001 mol/L\)

Concentration of hydrogen ion at pH is equal to 2 =\([H^+]=0.01 mol/L\)

Concentration of hydrogen ion at pH is equal to 6 = \([H^+]'=0.000001 mol/L\)

The difference between hydrogen ion concentration at pH 2 and pH 6 :

\(= [H^+]-[H^+]' = 0.01 mol/L- 0.000001 mol/L = 0.009999 mol/L\)

Moles of hydrogen ion in 0.009999 mol/L solution :

\(=0.009999 mol/L\times 1 L=0.009999 mol\)

There are 0.009999 more moles of  \(H^+\) ions in a solution at a pH = 2 than in a solution at a pH = 6.

Answer:

there are a number of types of asexual reproduction including fission, fragmentation, budding, vegetative reproduction, spore formation and gamogenesis. Spore formation occurs in plants, and some algae and fungi, and will be discussed in additional concepts

the production of new living organisms by combining genetic information from two individuals of different types (sexes). In most higher organisms, one sex (male) produces a small motile gamete which travels to fuse with a larger stationary gamete produced by the other (female)

The advantages of sexual reproduction: produces genetic variation in the offspring. the species can adapt to new environments due to variation, which gives them a survival advantage. a disease is less likely to affect all the individuals in a population.

Explanation:

Answer:

By opening the door, Elijah is using the chemical energy, which he obtained from eating food to do work. Thus, he is converting chemical energy to mechanical energy.

Stretching the spring by opening the screen door convert the potential energy which is stored in the spring to kinetic energy.

Overall there is conversion of chemical energy to potential energy.

By letting the door go, Elijah is using chemical energy. By snapping shut, the door is converting potential energy to kinetic energy. The overall energy change is conversion of chemical energy to kinetic energy.

Explanation:

Answer: Reflecting telescopes focus light with a series of mirrors, while refracting telescopes use lenses.

Explanation:

RS is a composition of rotation and reflection in the Euclidean plane E². The precise description of RS depends on the specific properties of the rotation R and reflection S.

In general, if R and S have the same axis or line of symmetry, the composition RS results in a translation. If R and S have intersecting lines of symmetry, RS yields a glide reflection. If R and S have perpendicular lines of symmetry, RS produces a rotation.

It is important to consider special cases, such as parallel lines of symmetry, coinciding axes, or perpendicular lines of reflection, as they may lead to different outcomes. The classification of isometries in E² involves understanding how rotations and reflections combine to create different transformations in the plane.

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The rated electric potential difference of the battery is 4.177 V which is calculated using the equation emf = IR

The electric potential difference (emf) of a battery is defined as the voltage across it when it is discharging through a resistance. The emf of a battery can be calculated using the equation:

emf = IR

where I is the current flowing through the resistance and R is the resistance of the battery.

In this case, the battery is supplying a current of 0.17 A to a 6.12Ω resistor, so the current through the battery is:

I = V / R = (4 V) / (0.17 Ω) = 226.7 A

The resistance of the battery can be calculated using Ohm's law:

R = V / I = (4 V) / (226.7 A) = 0.001847 Ω

Substituting these values into the emf equation, we get:

emf = IR = (0.001847 Ω) x (226.7 A) = 4.177 V

Therefore, the rated emf of the battery is 4.177 V.

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The correct option is (e) 1,020 N/C.

The maximum value of the electric field at the upper atmosphere of the earth can be calculated using the formula:

E = c*sqrt(I/(2*ε0))

Where c is the speed of light, I is the intensity of sunlight, and ε0 is the permittivity of free space.

Substituting the given values, we get:

E = 3 x 10^8 m/s * sqrt(1,380 W/m^2 / (2 * 8.85 x 10^-12 F/m))

E ≈ 1,020 N/C

Therefore, the maximum value of the electric field at the upper atmosphere of the earth is approximately 1,020 N/C.

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The situation B describes the highest rate of power. The value of power in the situation A IS 1600 Watt.

Average power is a ratio of total work done by the body to the total time. Its unit is the watt. It is also defined as the rate of total work done by the body.

Power is defined as the rate of work done. Mathematically found as;

\(\rm P = \frac{W}{t} \\\\ P=\frac{800}{0.5} \\\\ p= 1600 \ Watt\)

Hence, the situation B describes the highest rate of power. The value of power in the situation A is 1600 Watt.

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Answer:

yea its D  .

Explanation:

Answer:

B.

assuming and holding a stretch position

Explanation:

The characteristics of static stretching is assuming and holding a stretch position.

Static stretching is a type of stretch exercises in which the person involved is static position and he stretched out.

The person does not move out of his position but the person move his moves as many times as it can without experiencing any pain.

Therefore, The characteristics of static stretching is assuming and holding a stretch position.

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