1. Clara opens a savings account with $500 and deposits $75 each month thereafter. Write a
linear function that models the monthly balance.

Answer:

i think c

Step-by-step explanation:

Answer:C

Step-by-step explanation:

(y^3)^2

=y^3*2

=y^6

So therefore, the one that contained y^6 is the answer which is C.

By the way, you’re really smart

Answer:

Step-by-step explanation:

the answer is 48

Theorem 4.4.1, also known as the positive divisor theorem, states that for all positive integers a and b, if a divides b, then a is less than or equal to b. In other words, if a is a factor of b, then a is smaller than or equal to b.

To prove this theorem, we can use the definition of divisibility, which states that if a divides b, then there exists an integer k such that b = ak. Since a and b are both positive, k must also be positive.

Multiplying both sides of the equation b = ak by the positive integer 1/a, we get b/a = k, which means that k is a positive integer. Therefore, a ≤ b/a, or equivalently,\(a^2 ≤ ab\). Since a is positive, we can divide both sides of this inequality by a to get a ≤ b.

Thus, we have shown that if a divides b, then a is less than or equal to b, which proves Theorem 4.4.1. This theorem is a fundamental property of divisibility and is often used in number theory and other mathematical areas.

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Answer:

2x + 3y = 6

Step-by-step explanation:

The equation of a line in slope- intercept fprm is

y = mx + c ( m is the slope and c the y- intercept )

Given

2x + 3y = 5 ( subtract 2x from both sides )

3y = - 2x + 5 ( divide terms by 3 )

y = - \(\frac{2}{3}\) x + \(\frac{5}{3}\) ← in slope- intercept form

with slope m = - \(\frac{2}{3}\)

Parallel lines have equal slopes, then

y = - \(\frac{2}{3}\) x + c ← is the partial equation

To find c substitute (3, 1 ) into the partial equation

1 = - 2 + c ⇒ c = 1 + 2 = 3

y = - \(\frac{2}{3}\) x + 3 ( multiply through by 3 to clear the fraction )

3y = - 2x + 6 ( add 2x to both sides )

2x + 3y = 6 ← equation of parallel line

a) The probability of selecting a blue marble is P ( B ) = 1/4

b) The probability of selecting a green marble is P ( G ) = 1/6

c) The probability of selecting not a green marble is P' ( G ) = 5/6

The probability that an event will occur is measured by the ratio of favorable examples to the total number of situations possible

Probability = number of desirable outcomes / total number of possible outcomes

The value of probability lies between 0 and 1

Given data ,

Let the number of blue marbles = 3

Let the number of red marbles = 6

Let the number of green marbles = 2

Let the number of black marbles = 1

So , the total number of marbles = 12

So , the probability is given as

The probability of selecting a blue marble is P ( B ) = 1/4

The probability of selecting a green marble is P ( G ) = 1/6

The probability of selecting not a green marble is P' ( G ) = 5/6

Hence , the probability is solved

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The complete question is attached below :

There are 3 blue marbles, 6 red marbles, 2 green marbles and 1 black marble in a bag. Suppose you select one marble at random. Find the probability for each of the following.

First, we want to note two things:

We can describe this with an inequality:  x ≥ -10
Be sure you use ≥ and not >, since -10 is included.

We can describe this with interval notation: [ -10, infty )
Be sure you use [ and not ( on -10, since -10 is included.

You can also use set-builder notation: { x | x ≥ -10 }

If from total of 28 students, 12 has clock, 16 have calculator and 4 do not have these items, then the number of students that have clock and a calculator are (b) 4.

The total number of students are 28 students,

The number of students who has a clock is = 12 students,

The number of students who has a calculator is = 16 students,

The number of students who do not have any of these is = 4 students,

Let the number of students who has-both clock and calculator be = x,

So, the number of students having only clock are = 12-x,

the number of students having only calculator are = 16-x,

The equation for total students is written as :

⇒ 12-x + x + 16-x + 4 = 28,

⇒ 32 - x = 28,

⇒ x = 32 - 28,

⇒ x = 4,

Therefore, 4 students have a clock and calculator, Option(b) is correct.

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The slope of line r is -1/2

The equation of line q is given as

\(-2x + y =1\)

Make y the subject

\(y =1 + 2x\)

Rewrite the equation, as follows:

\(y =2x + 1\)

The slope of the above equation is:

\(m = 2\)

Line r is perpendicular to line q.

So, the slope (m2) of line r is calculated as:

\(m_2 = -\frac 1m\)

This gives

\(m_2 = -\frac 12\)

Hence, the slope of line r is -1/2

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The Analyst can use COALESCE function to eliminate the null values from the results.

The SQL Coalesce functions is used to handle NULL values. During the expression evaluation process the NULL values are replaced with the user-defined value. It  returns the first non-NULL value from a series of expressions.

The SQL Coalesce function evaluates the arguments in order and always returns first non-null value from the defined argument list.

Few Properties of COALESCE Function

SYNTAX -

COALESCE ( expression [ ,...n ] )  

Hence, the analyst can use COALESCE function to eliminate the null values from the results.

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The value of derivative f''(2) is 8/3 .

Given,

\(\int\limit {\sqrt{t} } \, dt\)

Limit varies from 2 to x²

Now ,

Perform integration

\(\int\limit {\sqrt{t} } \, dt\)

Limit of integration varies from 2 to x² . 2 will be the lower limit of integration and x² will be the upper limit of integration .

Use property:

∫\(x^{n}\) = \(x^{n+1}/ n+1\)

So,

\(t^{3/2} /3/2\)

Limit varies from 2 to x²

Substitute the limits ,

Limits will be solved by upper limit - lower limit .

2/3(x³ - 4)

Now,

f''(2)

= 2/3(2³ - 4)

= 8/3

Hence the value of f''(2) is 8/3 .

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Correct expression:

\(\int\limit {\sqrt{t} } \, dt\)

Limit varies from 2 to x²

The interval estimate of the population mean when a random sample is taken of the speed on highway is 59.5<h<64.1. Option C is correct.

The probability or the chances of error while choosing or calculating a sample in a survey is called the margin of error.

The interval estimate of the population mean can be found out using the following formula:

\(\overline X\pm MOE\)

Here, \(\overline X\) is the average mean, and the MOE is the margin of error.

On a highway, a random sample is taken of the speed, in mph, of 50 cars.

Put the values in the above formula as,

\(61.8\pm 2.3\\59.5,641\)

Thus, the interval estimate of the population mean

\(59.5 < h < 61.8\)

Hence, the interval estimate of the population mean when a random sample is taken of the speed on highway is 59.5<h<64.1. Option C is correct.

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Answer:

  2010

Step-by-step explanation:

If the numbers are x and y, you have ...

  x +y = 97

  x -y = 37

Adding these two equations gives ...

  2x = 134

  x = 67

  y = 67 -37 = 30

The product is then ...

  xy = (67)(30) = 2010

__

Alternate solution

There is no need to find the actual numbers. We can go directly to their product.

  (x+y)² = x² +2xy +y² = 97² = 9409

  (x-y)² = x² -2xy +y² = 37² = 1369

Subtracting the second equation from the first gives ...

  4xy = 9409 -1369 = 8040

  xy = 8040/4 = 2010

Of course the difference of squares can be factored, so we could compute ...

  (97² -37²)/4 = (97 +37)(97 -37)/4 = 134(60)/4 = 134(15) = 2010

Answer:

c is it

Step-by-step explanation:

a p e x

Answer:

m∠JKM = 63°

m∠MKL = 27°

Step-by-step explanation:

Since ∠JKL is a right angle. This means that by summing up both m∠JKM and m∠MKL will result in the same as ∠JKL figure. Thus, m∠JKM + m∠MKL = m∠JKL which is 90° by a right angle definition.

\(\displaystyle{\left(12x+3\right)+\left(6x-3\right) = 90}\)

Solve the equation for x:

\(\displaystyle{12x+3+6x-3 = 90}\\\\\displaystyle{18x=90}\\\\\displaystyle{x=5}\)

We know that x = 5. Next, we are going to substitute x = 5 in m∠JKM and m∠MKL. Thus,

m∠JKM = 12(5) + 3 = 60 - 3 = 63°

m∠MKL = 6(5) - 3 = 30 - 3 = 27°

Based on the provided information, there is not enough information to determine the standard deviation of the scores. (Option B)

A standard deviation is defined as a measure of the data dispersion in relation to the mean. Low standard deviation indicates that the data are clustered around the mean while high standard deviation indicates data are more spread out from the mean.

In the given case, for a sample of 17 score with positive and negative values has a mean of zero. When these values are squared, the negative values become positive values and the sum of the score is 256. The formula for standard deviation of a sample is given by:

σ= √((∑(xi- μ)^2)/(N-1))

Where σ is the standard deviation, xi is the ith value of the score, µ is the mean of the score, and N is the number of sample.

In the given case, the number of th sample is given and mean can be calculated, but as xi cannot be determined, hence there is not enough information for calculate standard deviation.

Note: The question is incomplete. The complete question probably is: A sample of 17 deviation scores (some positive and some negative) has a mean of zero. Each of the scores in the sample is squared, and the sum of those squared scores is found to be 256. What is the standard deviation of the scores? A) 2.7 B) Not enough information to determine. C) 3.94 D) 0.23.

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Answer:

Step-by-step explanation:

\((x-4) (3x^{3} -6x+2)\)

= \(3x^{4} -6x^{2} +2x -12x^{3} +24x-8\)

= \(3x^{4} -12x^{3} -6x^{2} +26x-8\)

I hope this helps and the working out is clear.  :)

Answer: 57

Step-by-step explanation: 86 + 37 = 123, then subract 123 from 180

The entry required to account for the change in office supplies would depend on the accounting method used. Assuming the company follows the periodic inventory system, where office supplies are expensed as they are used, the entry would be as follows:

At the beginning of the period:

Debit: Office Supplies Expense - $4,000

Credit: Office Supplies - $4,000

At the end of the period:

Debit: Office Supplies - $3,900

Credit: Office Supplies Expense - $3,900

Explanation:

1. At the beginning of the period, the company records the office supplies as an asset (Office Supplies) and recognizes an expense (Office Supplies Expense) for the same amount. This reduces the value of the asset and reflects the cost of supplies used during the period.

2. At the end of the period, when it is determined that $3,900 worth of supplies remains, the company adjusts the office supplies account by reducing it by the remaining amount. This adjustment is necessary to reflect the correct value of supplies on hand at the end of the period.

The entry ensures that the net effect of the transactions is an expense of $100 ($4,000 - $3,900), which represents the cost of supplies consumed during the period.

The amount of fencing needed to surround the perimeter of the picnic area of the park is 107 yards. Hence, the second option is the right choice.

In the question, we are informed that the triangle KLM, represents a section of a park set aside for picnic tables. We are also informed that the picnic area will take up approximately 400 square yards of the park.

We are asked for the amount of fencing needed to surround the perimeter of the picnic area of the park.

We know the area of a triangle can be found using the trigonometric area formula, Area = (1/2)ab sin C.

Using this in the given triangle KLM, we get:

Area = (1/2)(KL)(KM)(sin K),

or, 400 = (1/2)(KL)(45)(sin 25°),

or, KL = (400*2)/(45*sin 25°) = 800/(45*0.42262) = 800/19.017822 = 42.0658 ≈ 42 yd.

Thus, we get KL = 42 yards.

Now, the perimeter of the picnic area = the perimeter of the triangle KLM = KL + LM + MK = 42 + 20 + 45 yards = 107 yards.

Thus, the amount of fencing needed to surround the perimeter of the picnic area of the park is 107 yards. Hence, the second option is the right choice.

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Answer: b

Step-by-step explanation:

Answer:

you have to solve the first step and up and down

Step-by-step explanation:

with times hait

The correct sequence of project phases is Definition - Planning  - Performance. The correct answer is B.

This is the typical order of project phases in a traditional project management approach. It starts with the definition phase, where the project's goals, the scope, and the requirements are established.

Then comes the planning phase, where the project plan is developed, including the allocation of resources, scheduling, and budgeting.

Finally, the performance phase begins, during which the project activities are executed, monitored, and controlled to ensure the successful project completion.

Therefore the sequence of project phase is  Definition - Planning  - Performance The correct answer is B.

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Answer: 2/3

Step-by-step explanation:

First you multiply both numerators which equals 8

Then, you multiply the denomerators which is 24

This gives you 8/24

Since both 8 and 24 are divisible by 8, you divide them by 8 and you get 1/3

Since two negative numbers equal a positive one, the answer is positive

The amount will become zero after 400 months.

Given that, Mr. Tallchief have $400,000 in his account after his retirement,

He intends to withdraw 4,000 from the account every month after the retirement,

We need to find the equation that represents the amount in the account n months after his retirement.

So,

f(n) = 400,000 - 4000n

This equation will give the withdrawal of money each month,

Now, when the account will have no money in it,

A = 0,

0 = 400,000 - 4000n

400,000 = 4000n

n = 400

Hence, the amount will become zero after 400 months.

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Answer:

Neither of them are right

Step-by-step explanation:

First, let's actually solve this equation:

8 ( x - 5 ) = 8x + 40

Distribute on the left:

8 ( x - 5 )

( 8 x X ) + ( 8 x ( -5 ) )

8x - 40

8x - 40 = 8x + 40

Add 40 to each side:

8x = 8x + 80

Subtract 8x from both sides:

0 = 80

0 ≠ 80

There are no solutions to the equation

Answer:

joe    

joe mama

++

Step-by-step explanation:

Answer:

</html>

Step-by-step explanation:

This is so because remember when programming in HTML once u put a code word after <html> always close it off with </html>

Answer:

Step-by-step explanation:

The person above me is right

Answer:

-39.65

Step-by-step explanation:

3 1/4 ⋅ (-12.2)

First, we must change the first fraction to a decimal.

3 1/4 = 3.25.

Now, we just multiply using standard algorithm.

3.25 ⋅ (-12.2) = -39.65.

Anytime you multiply a positive number by a negative number, the answer will ALWAYS be negative.

The rate of change of the area of the triangle at the given instant is 4 cm²/s. Thus, the correct answer is (B) 4. The rate of change of the area of the triangle can be determined using the formula for the area of a triangle, which is A = (1/2) * base * height.

We are given that the base is increasing at a constant rate of 2 cm/s and the height is decreasing at a rate of 1 cm/s.

At the instant when the height is 5 cm and the area is 5 cm², we can substitute these values into the formula to solve for the rate of change of the area. Let's denote the rate of change of the area as dA/dt.

A = (1/2) * base * height

5 = (1/2) * base * 5

Simplifying the equation, we have:

base = 2

Now, we can differentiate both sides of the equation with respect to time (t):

dA/dt = (1/2) * (dbase/dt) * height + (1/2) * base * (dheight/dt)

Substituting the given rates of change:

dA/dt = (1/2) * (2 cm/s) * 5 cm + (1/2) * 2 cm * (-1 cm/s)

Simplifying further:

dA/dt = 5 cm^2/s - 1 cm^2/s

dA/dt = 4 cm^2/s

Therefore, the rate of change of the area of the triangle at the given instant is 4 cm^2/s. Thus, the correct answer is (B) 4.

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0.60792 liters x 1000 = 607.92 mL

Multiplying the volume in liters by 1000 converts it to milliliters.

The risk of a vehicle crash at a BAC of 0.10% is almost seven times higher than the risk of a vehicle crash at a BAC of 0.00%. The risk of a vehicle crash at a BAC of 0.16% is almost thirty times higher than the risk of a vehicle crash at a BAC of 0.00%.


The Effect of Blood Alcohol Concentration on Motor Vehicle Crashes shows that the relative likelihood of causing a crash increases when the blood alcohol concentration is above 0.08. The risk of a vehicle crash at a BAC of 0.10% is almost seven times higher than the risk of a vehicle crash at a BAC of 0.00%. Therefore, it is not safe to drink and drive.

The risk of a vehicle crash at a BAC of 0.16% is almost thirty times higher than the risk of a vehicle crash at a BAC of 0.00%. It is illegal in all states to drive with a BAC of 0.08 or higher. One drink can increase the blood alcohol concentration, and thus, the risk of a vehicle crash.

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Answer:

below

Step-by-step explanation:

the yearly multiplier

= 1.07

After 6 years revenue wii, b 563878 * 1.07^6

= $846,228.83.