app will diagnose a particular disease and suggest the appropriate measures and helps in booking an appointment with the doctor.
Let us assume that self-inventory is a health care application.
It is useful in the domain of health care.
the app will diagnose a particular disease and suggest the appropriate measures and helps in booking an appointment with the doctor.
so this is a computer engineering student's invention he/she can show this in the workplace and can explain them.
this would increase the chances of getting hired.
This also adds to our experience.
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You push a 15N cat in a box horizontally across the floor for 5m. What is the work done on the cat? W=Fx
Answer:
w=fx
w=(15)(5)
w=75
the angle between the deplacement and N is 0
The refractive indices of materials A and B have a ratio of nA/nab=1,33. The speed of light in material A is 1.25 times 10^8m/s. What is the speed of light in material B?
The speed of light in material B is 1.6625 × 108 m/s.
The refractive index of a material is its optical density relative to that of a vacuum.
Material B has a refractive index of nB, and its speed of light is vB.
The speed of light in material A is given as 1.25 x 108 m/s.
The refractive indices of materials A and B have a ratio of nA/nB = 1.33.
We will use the formula:
nA/nB = vB/vA = nA/nB.
Therefore, nA/nB = vB/1.25 x 108 m/s.
This equation can be rearranged to give the speed of light in material B:
vB = nA/nB × 1.25 x 108 m/s.
Therefore, vB = 1.33 × 1.25 × 108 m/s.
We will perform this calculation:
vB = 1.6625 × 108 m/s.
Therefore, the speed of light in material B is 1.6625 × 108 m/s.
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What would the current be for a circuit that has a voltage of 0.8 V and a resistance of 0.01 Q?
0 1 = 0.01 A
0 1 = 0.8 A
0 1 = 80 A
O I = 0.08 A
Answer:
80 A
Explanation:
Hi there!
Ohm's law states that \(V=IR\) where V is the voltage, I is the current and R is the resistance.
Plug the given information into Ohm's law (V=0.8, R=0.01) and solve for I
\(V=IR\\0.8=I(0.01)\)
Divide both sides by 0.01 to isolate I
\(0.8=I(0.01)\\\frac{0.8}{0.01}= \frac{I(0.01)}{0.01} \\80=I\)
Therefore, the current for this circuit would be 80 A.
I hope this helps!
if 400g is 1kg find the ratio in the simplest form
2:5
Explanation:
400g : 1kg
400g: 1000g
4 : 10
2 : 5
Three different objects, all with different masses, are initially at rest at the bottom of a set of steps. Each step is of uniform height
. The mass of each object is a multiple of the base mass
: object 1 has mass 4.60
, object 2 has mass 2.21
, and object 3 has mass
. When the objects are at the bottom of the steps, define the total gravitational potential energy of the three-object system to be zero.
Each answer requires the numerical coefficient to an algebraic expression that uses some combination of the variables , , and , where is the acceleration due to gravity. Enter only the numerical coefficient. (Example: If the answer is 1.23 , just enter 1.23)
Image showing three masses, 1, 2, and 3, and three steps, each of height D. The three masses are shown at the base of the steps. Arrows indicate that mass 1 is placed on the top step at height 3 D, mass 2 is placed on the middle step at height 2 D, and mass 3 is placed on the bottom step at height D.
If the objects are positioned on the steps as shown, what is gravitational potential energy ,system of the system?
If you redefine the reference height such that the total potential energy of the system is zero, how high ℎ0 above the bottom of the stairs is the new reference height?
Now, find a new reference height ℎ′0 (measured from the base of the stairs) such that the highest two objects have the exact same gravitational potential energy.
a) The gravitational potential energy of the system of three masses at the given positions is 188.36md.
(b) The redefined reference height is h₀ = 0.55d.
(c) The new reference height measured from the base is h₀' = 0.96d.
What is the gravitational potential energy of the system?
(a) The gravitational potential energy of the system of three masses at the given positions is calculated as;
total gravitational potential energy = P.E(mass 1) + P.E(mass 2) + P.E(mass 3)
T.G.P.E = m₁gh₁ + m₂gh₂ + m₃gh₃
where;
mass of object 1, m₁ = 4.6mmass of object 2, m₂ = 2.21mmass of object 3, m₃ = mh₁ = 3dh₂ = 2dh₃ = dT.G.P.E = (4.6m x 9.8 x 3d) + (2.21m x 9.8 x 2d) + (m x 9.8 x d)
T.G.P.E = 135.24md + 43.32md + 9.8md
T.G.P.E = 188.36md
(b) The redefined reference height is calculated as follows;
0 = (4.6m x 9.8 x h₀) + (2.21m x 9.8 x (h₀ - d) + (m x 9.8 x (h₀ - 2d)
0 = 45.08mh₀ + 21.66mh₀ - 21.66md + 9.8mh₀ - 19.6md
0 = 45.08h₀ + 21.66h₀ - 21.66d + 9.8h₀ - 19.6d
0 = 76.54h₀ - 41.26d
76.54h₀ = 41.26d
h₀ = 41.26d/75.54
h₀ = 0.55d
(c) The new reference height measured from the base such that the highest two objects have the exact same gravitational potential energy is calculated as follows;
m₂gh₂ = m₁gh₁
2.21m x 9.8 x h₂ = 4.6m x 9.8 x h₁
21.66mh₂ = 45.08mh₃
21.66h₂ = 45.08h₁
h₁ = 21.66h₂/45.08
h₁ = 0.48h₂
h₀' = 0.48 x (2d)
h₀' = 0.96d
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Which ideas did you include in your answer? Check all that apply.
Scientists use relative and absolute dating to determine age of rocks.
Scientists can organize the rocks layers based on their age on the geologic time scale.
The type of rocks and the fossils in the rock layers tell scientists about Earth’s history.
By contrasting a fossil with related rocks and fossils of known ages, relative dating can estimate the fossil's age.
By utilising radiometric dating to track the isotope decay inside the fossil or, more frequently, the rocks it is linked with, absolute dating may pinpoint an object's exact age.
What are the benefits of using relative and absolute dating of rocks?It is possible to identify whether one artefact, fossil, or stratigraphic layer is older than another using relative dating, which does not provide particular dates.
Absolute dating techniques offer more precise dates and times of origin, such as a range in age in years.
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Using the Wien’s formula calculate λmax for the following cases [note that the visible spectra goes from 400 nm (violet) to 700 nm (red)]:
The peak wavelengths (λmax) for the visible spectrum range are approximately 7.245 × 10^(-6) K for violet and 4.140 × 10^(-6) K for red.
Wien's formula is used to calculate the peak wavelength (λmax) of blackbody radiation based on its temperature. The formula is given by:
λmax = (b / T)
Where λmax is the peak wavelength, b is Wien's displacement constant (approximately 2.898 × 10^(-3) m·K), and T is the temperature in Kelvin.
To calculate λmax for the visible spectrum range (400 nm to 700 nm), we need to convert these values to meters. The conversion factor is 1 nm = 1 × 10^(-9) m.
For violet (400 nm), λmax = (2.898 × 10^(-3) m·K) / (400 × 10^(-9) m) = 7.245 × 10^(-6) K.
For red (700 nm), λmax = (2.898 × 10^(-3) m·K) / (700 × 10^(-9) m) = 4.140 × 10^(-6) K.
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A truck accelerates from rest at a rate of 2.3 m/s2 for 12 seconds and then the driver hits the brakes and the truck accelerates at a rate of -1.6 m/s2 for 9 seconds. What is the A) final velocity and B) final displacement?
The final velocity of the truck is determined as 13.2 m/s.
The final displacement of the truck is determined as 183.6 m.
Velocity of the truck after 12 seconds
The velocity of the truck after 12 seconds is calculated as follows;
v = u + at
where;
v is the final velocity of the truck after 12 seconds
u is the initial velocity of the truck
t is the time of motion
a is the acceleration of the truck
v = 0 + 2.3(12)
v = 27.6 m/s
Final velocity of the truckThe velocity of the truck after 9 seconds is calculated as follows;
v = u + at
where;
v is the final velocity of the truck after 9 secondsu is the velocity of the truck after 12 secondst is the time of motiona is the deceleration of the truckv = 27.6 m/s + (-1.6)(9)
v = 13.2 m/s
Final displacement of the truckv² = u² + 2as
13.2² = 27.6² + 2(-1.6)s
174.24 = 761.76 - 3.2s
3.2s = 761.76 - 174.24
3.2s = 587.52
s = 587.52/3.2
s = 183.6 m
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Where is the near point of an eye for which a spectacle lens of power +2 D is prescribed for reading purpose?
The near point of a human eye is about a distance of 25 cm.
The closest distance that an object may be viewed clearly without straining is known as the near point of the eye.
This distance (the shortest at which a distinct image may be seen) is 25 cm for a typical human eye.
The closest point within the accommodation range of the eye at which an object may be positioned while still forming a focused picture on the retina is also referred to as the near point.
In order to focus on an item at the average near point distance, a person with hyperopia must have a near point that is further away than the typical near point for someone of their age.
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Complete ▼ Part A Rank in order, from the most to the least, the number of significant figures in the tollowing numbers. For example, ifb has more than c, c has the same number as a and a has more than d you would give your answer as b>c=a»d a 8200 b 00052 c 0430 d 4321 x 10" Completed O Type here to search
The correct response for the number of significant digits in the following numbers, from most to least, is d>c>b=a.
The number of digits in a particular value or measurement required to determine the accuracy and precision of measurement are known as significant figures (or significant digits).They are crucial for technical or scientific measurements.Significant denotes significance. In the supplied number, they make reference to the trustworthy digits that are adequate to transmit precise information. They also aid in the rounding off of measurement readings and calculating results.The quantity of digits necessary to assess the accuracy and precision of a measurement, such as length, mass, or volume, is known as significant figures (or significant digits).
Complete question: Rank in order, from the most to the least, the number of significant figures in the following numbers. For example, ifb has more than c, c has the same number as a and a has more than d you would give your answer as b>c=a»d a) 8200 b) 00052 c) 0430 d )4321 x 10" Completed O Type here to search
a)d>c>b=a b)a=d>c>b c)d>c>a>b d)b=d>c>a e)a=b=d>c
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A bullet travels 240m in just 0.2 seconds. Find it’s velocity (in m/sex
Given data,
Distance, d = 240 m
Time in seconds, t = 0.2 seconds
Formula to calculate the velocity.
\(v=\frac{d}{t}\)Substitute the given values in the above formula.
\(undefined\)A car starts from rest and reaches a speed of 14/s in 10 s Its acceleration is what?
Answer:
acceleration = change in velocity / change in time
acceleration = 14/10
acceleration = 1.4/s^2
2)To reach an absolute pressure of 3atm, you must dive down (in water) to depth of approximately 20m.Why might someone think that the answer was 30m
Answer:
Someone might think the answer is 30 m when the person cannot distinguish between absolute pressure and gauge pressure.
Explanation:
Given absolute pressure at a depth of 20 m = 3 atm.
When you drive down 30 m in water, the gauge pressure experienced is calculated as;
P = ρgh
Where;
ρ is density of water = 1000 kg/m³
g is acceleration due to gravity, = 9.8 m/s²
h is the depth of water = 30 m
P = (1000)(9.8)(30)
P = 294000 Pa
in atm = \(\frac{294000}{101325} = 2.9 \ atm\) ≅ 3 atm.
Thus, someone might think the answer is 30 m when the person cannot distinguish between absolute pressure and gauge pressure.
Someone might think the height (depth) is 30 meters, if he or she is unable to distinguish between gauge pressure and absolute pressure.
Given the following data:
Atmospheric pressure A = 3 atm.Height (depth) A = 20 meters.Height (depth) B = 30 meters.Scientific data:
Acceleration due to gravity = 9.8 \(m/s^2\)Density of water = 1000 \(kg/m^3\)To calculate the gauge pressure at a depth below the surface of a water:
Mathematically, gauge pressure is given by this formula:
\(P = \rho gh\)
Where:
g is the acceleration due to gravity.h is the height (depth) of water.Substituting the given parameters into the formula, we have;
\(P = 1000 \times 9.8 \times 30\)
Gauge pressure = 294000 Pa
Next, we would convert the value in Pascals to atmosphere.
Conversion:
1 atm = 101325 Pa
X atm = 294000 Pa
Cross-multiplying, we have:
\(X = \frac{294000}{101325}\)
X = 2.90 ≈ 3.0 atm.
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Diesel fuel is used in the engine of trucks that carry dirt fruit and other cargo. Fuel is burned in engines to make the motor move. Which of these is the main energy transformation as the truck engines use the fuel?
Answer: Fuel is burned in engines to make the motor move.
( Chemical to Mechanical )
Explanation:
during combustion of the diesel ( when the fuel is burnt in the engine of the vehicle, the diesel ( chemical energy ) is transformed or converted to Mechanical energy. This mechanical energy is what the truck uses in moving. Without the combustion of the fuel the vehicle won’t move and the combustion of diesel is achieved through compression unlike that of fuel.
A box with a mass of 2 kg is pushed by a 10 N force. The acceleration
is
_m/s^2?
Answer:
a = 5 m/s^2
Explanation:
First, we look at Newton's 2nd Law:
F = ma
We now plug in the values,
10 N = 2 kg * a
10 N/2 kg = a
5 m/s^2 = a
As gas rises the temperature gets hotter?
True or False
Answer:
i think its true
What are some possible factors that can be the X
and Y axis of a motion graph?
Answer:
x-Speed/velocity
y-time.
Explanation:
because Speed is a rate of change of distance while time how long it takes a a car to move to a specific point
Which is an example of positive peer pressure?
O A parent telling her son to wear his seatbelt.
O A student asking others to join the leadership club.
O a teen encouraging a friend to drink alcohol.
O A teacher telling his students to have a safe weekend.
Answer:
B. A student asking others to join the leadership club.
Explanation:
A parent isn't a peer, therefore can't be peer pressure. Drinking is negative for your body, therefore not positive peer pressure. A teacher isn't a peer, therefore the only answer left is B.
2. Assume that the barrels stay intact and that the car forms a combined moving unit with the barrels for a few moments after the collision before it swerves out and drives away with the speed calculated in 2.3. Calculate the mass of water needed in the barrels to bring the 1200 kg-car down
The car needs to slow down to a minimum velocity before the collision, which is 0.789 meters per second (m/s), to avoid a fatal crash., and the mass of water needed in the barrels to bring the 1200 kg car down to the required speed is 42,344.1 kg.
To determine the minimum velocity the car can slow down to during a collision without the crash being fatal, we need to consider the concept of deceleration and the forces involved.
Deceleration and Minimum Velocity:
Let's assume the car slows down uniformly with a deceleration, denoted as 'a', until it comes to a stop. We can use the equation of motion to relate the initial velocity (100 km/h) with the final velocity (0 m/s), deceleration (a), and the distance traveled (unknown in this case).
The equation of motion is:
v^2 = u^2 + 2as
where:
v = final velocity (0 m/s)
u = initial velocity (100 km/h or approximately 27.78 m/s)
a = deceleration
s = distance traveled
Substituting the values into the equation, we have:
0^2 = (27.78)^2 + 2a(s)
Simplifying, we get:
0 = 771.84 + 2as
Since the car comes to a stop, the final velocity is 0, and we're left with:
771.84 = 2as
Now, we need to consider the impact force experienced by the car during the collision. This force is related to the deceleration and the mass of the car by Newton's second law of motion:
F = ma
We want to find the minimum velocity at which the crash won't be fatal, so we need to determine the maximum acceptable force the car can withstand without causing severe harm.
The maximum acceptable force depends on various factors, including the design and safety features of the car, but let's assume a commonly used threshold of 50 g's (where g is the acceleration due to gravity, approximately 9.8 m/s^2).
Converting 50 g's to m/s^2, we have:
50 g's * 9.8 m/s^2 = 490 m/s^2
Thus, we want to limit the deceleration to 490 m/s^2.
Now we can rearrange the equation 771.84 = 2as to solve for 's' (the distance traveled):
s = 771.84 / (2a)
Substituting the maximum acceptable deceleration (490 m/s^2) into the equation:
s = 771.84 / (2 * 490)
s ≈ 0.789 m
Therefore, the car needs to slow down to a minimum velocity before collision, which is approximately 0.789 meters per second (m/s), to avoid a fatal crash.
Mass of Water in Barrels:
To calculate the mass of water needed in the barrels to bring the 1200 kg car down to the required speed, we need to consider the conservation of momentum.
The initial momentum of the car is given by:
initial momentum = mass of the car * initial velocity
The final momentum of the car-barrels system is given by:
final momentum = mass of the car-barrels system * final velocity
Since the car forms a combined moving unit with the barrels after the collision, their final velocity will be the same. We can equate the initial and final momentum to find the mass of the car-barrels system.
initial momentum = final momentum
mass of the car * initial velocity = mass of the car-barrels system * final velocity
Solving for the mass of the car-barrels system:
mass of the car-barrels system = (mass of the car * initial velocity) / final velocity
Substituting the given values:
mass of the car-barrels system = (1200 kg * 27.78 m/s) / 0.789 m/s
mass of the car-barrels system ≈ 42344.1 kg
To bring the car-barrels system to a stop, an equal and opposite force needs to act on it. In this case, we assume the force is provided by the water in the barrels.
The force required to decelerate the car-barrels system is given by:
force = mass of the car-barrels system * deceleration
We can use this force to calculate the mass of water needed in the barrels. Let's assume the deceleration required is the maximum acceptable deceleration we determined earlier (490 m/s^2).
mass of water = force / deceleration
mass of water = (mass of the car-barrels system * deceleration) / deceleration
mass of water = mass of the car-barrels system
So, the mass of water needed in the barrels to bring the 1200 kg car down to the required speed is approximately 42,344.1 kg.
Hence, To avoid a fatal collision, the car must slow down to a minimum velocity of 0.789 metres per second (m/s) before the collision, and the mass of water required in the barrels to bring the 1200 kg car down to the required speed is 42,344.1 kg.
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Complete the sentence: Congruent means ____________________.
too long
opposite
uneven
equal
Answer:
equal
Explanation:
If all three corresponding sides are equal and all three corresponding angles are identical in measure, two triangles are said to be congruent. These triangles can be slides, rotated, flipped and turned to be looked identical. If repositioned, they coincide with each other. The symbol of congruence is' ≅'.
Congruent means equal, as it is a term used to describe two or more objects or figures that have the same shape and size.
When two or more figures or things have the same size and shape, they are said to be congruent.
When we state that two things or figures are congruent, we mean that their lengths, angles, and proportions are all the same.
The idea of congruence is that there should be no distinction or contrast between the things being compared. It denotes complete equality and a perfect match.
Congruence informs us that all geometric shapes, including line segments, angles, triangles, and others, are the same and can be placed on one another without overlap or gaps.
Thus, a fundamental idea in geometry called congruence enables us to evaluate and contrast geometric forms and their characteristics.
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write the dimensional formula of gravitational constant and specific heat capacity.
Answer:
SEE EXPLANATION
Explanation:
The dimensional formula of gravitational constant is given by,
M^-1 L^3 T^-2
Where,
M = Mass
L = Length
T = Time
Dimensional formula of Specific Heat Capacity =[ M^0L^2T^-2K^-1]
Why is math so hard?
Answer:
its just built different
I could give you a big, fancy scientific answer, but it often comes down to the fact that the way that most instructors teach math is not the way the student(s) can most easily understand it.
g if the distance between the Earth and the Sun were increased by a factor of 2.87, by what factor would the strength of the force between them change
We have that the the strength of the force between the Sun and the moon is mathematically given as
F2=0.12140F1N
Strength of the ForceQuestion Parameters:
Distance between the Earth and the Sun were increased by a factor of 2.87,
Generally the equation for the Gravitational Force is mathematically given as
\(F=\frac{Gm1m2}{d^2}\\\\Where\\\\f1/f2=d1^2/d2^2\\\\Therefore\\\\F2=\frac{F1*d1}{3.23^2}\\\\F2=\frac{F1*1}{2.87^2}\\\\\)
F2=0.12140F1N
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A cart with mass m subscript 1 equals 0.25 space k g is at rest on a track. A second cart of mass m subscript 2 equals 0.35 space k g is pushed down the track and collides with it. The carts stick together after the collision. The second cart's speed immediately before the collision is v subscript 02 equals 6.17 space m divided by s. The overall magnitude of the carts' common final velocity is _______________ (enter the numerical value only, in m/s).
After considering the given data and information we come to the conclusion that overall magnitude of the carts' common final velocity is 3.6 m/s, under the condition that a cart with mass m subscript 1 equals 0.25 space k g is at rest on a track.
Then, we can apply the law of conservation of momentum to evaluate the common final velocity of the carts.
The law of conservation of momentum projects that the total momentum of an isolated system stays constant if no external forces act on it. For this required case, the system is the two carts.
Before the collision, the first cart is in the rest and the second cart has a velocity of 6.17 m/s. Hence, the total momentum of the system before the collision is
p = m₁v₁ + m₂v₂
Here,
m1 and m2 are the masses of the carts and `v1` and `v2` are their velocities.
Staging the given values,
p = (0.25 kg)(0 m/s) + (0.35 kg)(6.17 m/s)
Applying simplification this expression
p = 2.16 kgm/s
Post the event of collision, the two carts stick along each other and move with a common final velocity `v`. The total momentum of the system after the collision is
p = (m₁ + m₂)v
Staging the given values, and evaluate for v
v = p / (m₁ + m₂)
Staging the given values
v = (2.16 kgm/s) / (0.25 kg + 0.35 kg)
v = 2.16/0.6
Applying simplification this expression
v ≈ 3.6 m/s
Then, the overall magnitude of the carts' common final velocity is approximately 3.6 m/s.
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Suppose a 3000 cm3 container holds 7.0 g of nitrogen gas at a pressure of 200 kPa. The gas can be heated at constant pressure if a piston moves outward to let the gas expand as it's heated. Alternatively, the gas can be heated at constant volume if the piston is locked in place to prevent expansion. How does the heat required for one of these processes compare to the heat required for the other process?
1. What is the starting temperature of the gas?
2. With the piston locked in place, the gas is heated until the pressure doubles. What is the final temperature?
1) The starting temperature of the gas is 288 K
b) When the pressure is doubled, the temperature is 576 K
What is the temperature?We know that we have to use the ideal gas equation so as to be able to obtain the temperature of the starting of the gas and we know that;
Pressure = 200 kPa or 1.97 atm
Volume = 3000 cm3 or 3 L
Temperature = ?
Number of moles = mass/molar mass = 7 g/28 g/mol = 0.25 moles
Then we have;
PV = nRT
T = PV/nR
T = 1.97 * 3/0.25 * 0.082
T = 5.91/0.0205
T = 288 K
If the pressure doubles and we have;
P1/T1 = P2/T2
P1T2 = P2T1
T2 = 2(1.97) * 288/1.97
T2 = 576 K
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4. S. crossirostris's wings were made of a delicate flap of skin. If this flap of skin
tore, the animal could not fly. Use this information to explain how
S. crassirostris might have had trouble competing with bird species living during
the Mesozoic era.
Birds underwent significant diversification and adaptation during the Mesozoic epoch, allowing them to develop into effective and adaptable flyers.
What are the birds?The wings of S. crossirostris, also referred to as the "delicate-winged pterosaur," were constructed of a delicate flap of skin called the patagium. This delicate membrane was prone to breaking, unlike the stiff feathers of birds.
In terms of flight prowess and ecological success, S. crossirostris would not have been able to compete with birds due to the restrictions imposed by its delicate wing structure.
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If you pour liquid into a tall, narrow glass, you may hear sound with a steadily rising pitch. What is the source of the sound
Answer:
the vibration of the glass tube creating sound waves within itself. reason is the rising pitch is that the liquid rise shortens the length of the vibrating area within the tube.
Explanation:
A horizontal force of 100 N is required to push a 50 kg crate across a factory floor at a constant speed. What is the acceleration on the cart?
Answer:
a = 2m/s^2
Explanation:
Force (F) = 100 N
Mass (m) = 50 kg
Here,
F = m×a
100 = 50 × a
a = 100÷50
a = 2m/s^2
Thus, the acceleration on the cart is a = 2m/s^2
-TheUnknownScientist
A roller-coaster car with a mass of 900 kg starts at rest from a point 22 m above the ground. At point B, it is 8 m above the ground. [Express your answers in kilojoules (kJ).]
What is the potential energy at point B?
Answer: 317.52
Explanation:
I'm just him, so I just know
What is heat energy ? Plz
Answer:
Heat is the form of energy that is transferred between systems or objects with different temperatures.