0.45 g of hydrogen chloride ( HCl ) is dissolved in water to make 6.0 L of solution. What is the pH of the resulting hydrochloric acid solution

Answer:

yes

Explanation:

CO2 is soluble because water molecules are attracted to these polar areas. The bond between carbon

Answer:

nuclear war ;P

Explanation:

Answer:

Explanation:

i think c

According to molar concentration, 30 ml of water  should be added to 15 ml of 12 M HCl  to make it to 6 M solution.

Molar concentration is defined as a measure by which concentration of chemical substances present in a solution are determined. It is defined in particular reference to solute concentration in a solution . Most commonly used unit for molar concentration is moles/liter.

The molar concentration depends on change in volume of the solution which is mainly due to thermal expansion. Molar concentration is calculated by the formula, molar concentration=mass/ molar mass ×1/volume of solution in liters.

In terms of moles, it's formula is given as molar concentration= number of moles /volume of solution in liters.

In the given example,volume required is calculated as, V₂=M₁V₁/M₂

V₂=12×15/6

V₂=30 ml.

Thus, 30 ml of water is added to 15 ml of 12 M HCl to make it to 6 M solution.

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Explanation:

The question had been explained.

Answer:

Hello

there are 8 protons in oxygen atom

Explanation:

thanks...hope it helps

To prepare 128.2ml of a 0.364 M aqueous solution of NaCl.the mass in grams, of NaCl need to use to make the solution is 2.723 gm.

Molarity is defined as the no. of moles of solute per liter of solution.

Here,

Molarity =  moles of solute / Liter of solution

0.36 M solution will contains 0.364 moles of NaCl.

therefore, volume of solution in L =  ( 128.2 / 1000 ) L × 1 L

                                                 = 0.1282 L

that means, it will contain, no. of moles of NaCl

= (0.1282 L of solution × 0.364 ) / 1 L of solution      

= 0.0466 moles of NaCl

now, molar mass of NaCl  = 58.44 g/mol    

so, 1 mol of NaCl has a mass of  58.44 g/mol

therefore, 0.0466 moles of NaCl will have mass of

= ( 0.0466 moles of NaCl × 58.44 g ) / 1 mole of NaCl

= 2.723 g

Thus,To prepare 128.2ml of a 0.364 M aqueous solution of NaCl .the mass in grams, of NaCl need to use to make the solution is 2.723 gm.

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Answer:

the answer is C Ozone

hope that helps

The states of the individual compounds is missing in the chemical equation.

The given compounds:

Na₂S  +  2HCl  → 2NaCl  +  H₂S

When metal sulfides such as the given sodium sulfide, react which acids, they form salt and hydrogen sulfide gas.

The complete chemical equation with the states of the compounds is written as;

\(Na_2 S_{(aq)} \ + \ 2HCl _{(aq)} \ \ --> \ \ 2NaCl_{(aq)} \ + \ H_2S_{(g)}\)

where;

aq --- aqueous for liquid state

g --- gaseous state

Thus, we can conclude that, the states of the individual compounds is missing in the chemical equation.

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Answer:

Metal is a better conductor than plastic so its going to absorb any cooler temperatures while the plastic stays the same.

Explanation:

The molarity of the hydrogen peroxide solution is calculated to be 0.367875 M.

To determine the molarity of the hydrogen peroxide solution, we can use the balanced chemical equation for the reaction between hydrogen peroxide and permanganate ion:

2MnO4– + 5H2O2 + 6H+ → 2Mn2+ + 5O2 + 8H2O

From the equation, we can see that the ratio of MnO4– to H2O2 is 2:5. Since it takes 13.5 mL of 0.109 M MnO4– to reach the equivalence point, we can calculate the moles of MnO4– used:

moles MnO4– = volume (L) × molarity (mol/L)

= 0.0135 L × 0.109 mol/L

= 0.0014715 mol

Using the ratio, we can calculate the moles of H2O2:

moles H2O2 = (moles MnO4–) × (5/2)

= 0.0014715 mol × (5/2)

= 0.00367875 mol

To find the molarity of the H2O2 solution, we divide the moles of H2O2 by the volume (in L) of the solution titrated:

molarity H2O2 = moles H2O2 / volume (L) = 0.00367875 mol / 0.010 L = 0.367875 M

Therefore, the molarity of the hydrogen peroxide solution is 0.367875 M.

In this question, we are given the volume and molarity of the permanganate ion solution used in the titration of hydrogen peroxide. We can use stoichiometry and the balanced chemical equation to determine the moles of hydrogen peroxide. By dividing the moles of hydrogen peroxide by the volume of the solution titrated, we can find the molarity of the hydrogen peroxide solution.

To begin, we calculate the moles of permanganate ion used by multiplying the volume (in L) of the solution titrated by its molarity. Next, we use the stoichiometric ratio from the balanced chemical equation to calculate the moles of hydrogen peroxide. The ratio shows that for every 2 moles of permanganate ion, there are 5 moles of hydrogen peroxide.

By multiplying the moles of permanganate ion by (5/2), we obtain the moles of hydrogen peroxide. Finally, we divide the moles of hydrogen peroxide by the volume (in L) of the hydrogen peroxide solution titrated to determine its molarity.

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The control tube that is used to compare to test broths 1, 2, and 3 in order to evaluate the effectiveness of the germicide is the positive control tube.

This control tube contains bacteria that are not exposed to the germicide and serves as a reference for the growth and viability of the bacteria in the absence of the germicide.

By comparing the growth and viability of the bacteria in the positive control tube to the growth and viability of the bacteria in the test broths, researchers can determine the effectiveness of the germicide in killing or inhibiting the growth of the bacteria.

It is important to use a positive control tube in order to establish a baseline for comparison and ensure accurate and reliable results

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As ice is melted, there is what is known as Latent heat, the heat is hidden, during phase changes, energy enters or leaves a system without creating a temperature change.

Latent heat is energy that a body or a thermodynamic system releases or absorbs during a constant-temperature process. The latent heat of fusion (melting) and the latent heat of vaporization (boiling) are two main types of latent heat.

It could be from a gas to a liquid or from a liquid to a solid and vice versa. Enthalpy is a heat characteristic linked to latent heat.

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All the chemical equations of this question has been balanced for the  given observed reactions.

Equal numbers and types of each atom appear on both sides of balanced chemical equations. A balanced equation must have coefficients that are the simplest whole number ratio. Chemical reactions always conserve mass.

A. Ba(NO₃)₂+ Na₂CO₃ → BaCO₃ + 2NaNO₃

B. Ba₂⁺ + 2NO₃⁻ + 2Na⁺ +CO₃²⁻→ BaCO₃(s) +2Na⁺ +2NO³⁻

C. Net ionic equation-

   Ba²⁺(aq) + CO₃²⁻(aq)→ BaCO₃(s)

D. overall reaction-

   3Ba(NO₃)₂(aq) + 2Na₃PO₄→ Ba₃(PO₄)₂(s) + 6NaNO₃(aq)

E. Ionic equation-

   Ba(NO₃)₂(aq) + 2NaCl(aq)→ BaCl₂(aq) + 2NaNO₃(aq)

  ∴ No reaction

F- Ba(NO₃)₂(aq) + 2NaOH(aq) → Ba(OH)₂(aq) +2NaNO₃(aq)

 ∴No net ionic equation.

Thus, all equations are balanced above.

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Answer:

The answer is B.

Explanation:

In the reaction above, Sulphuric acid is an acid and Sodium hydroxide is an alkaline. It will produce salt and water in the product side.

Answer:

the answer is C

Hope this will help you ❤️

Answer:2, 7, 4, 6

Explanation:

2 C2H6 + 7 O2 → 4 CO2 + 6 H2O

The right answer is b. Negative ion.

The number of protons in an atom determines its atomic number and its identity as an element. In this case, the oxygen atom has 8 protons, indicating that it is an oxygen atom with atomic number 8.

The number of electrons in a neutral atom is equal to the number of protons, meaning that a neutral oxygen atom would have 8 electrons. However, the given oxygen atom has only 7 electrons, indicating that it has gained one electron to become a negative ion or an anion.

Therefore, the correct answer is b. Negative ion.

In summary, the given oxygen atom with 8 protons, 8 neutrons, and 7 electrons is classified as a negative ion or an anion since it has gained one electron to become negatively charged.

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The number of moles of charge contributed to a solution by one mole of dissolved ions is called the Faraday constant (F). It represents the charge of one mole of electrons and is essential in electrochemical calculations involving charge transfer and electrolysis.

In a solution, when one mole of ions dissolves, each ion can carry a certain charge.  For example, if a particular ion carries a charge of +1, then one mole of that ion would contribute +1 Faraday of charge to the solution. The Faraday constant is crucial in various electrochemical calculations, such as determining the amount of charge transferred during an electrochemical reaction or calculating the amount of substance produced or consumed in an electrolysis process.

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Using significant figures 0.00296 moles of helium can be calculated to be contained in the balloon.

You might have learnt in school that at STP (Standard Temperature and Pressure), the temperature is 273.15 K and the pressure is 1 atm. The molar volume of any given gas at STP will always be 22.4 L/mol. This will perhaps be known to you as Avogadro's Law.

You are having 75.000 mL of helium, which is 0.075 L. To find the number of moles of helium, you will make use of the ideal gas law:

PV = nRT

The notations are commonly known as P for pressure, V for volume, n is for number of moles, R for gas constant, and T for temperature in Kelvin scale.

At STP, P = 1 atm and T = 273.15 K. The gas constant R is 0.08206 L·atm/mol·K.

So you will then have:

n = PV/RT = (1 atm)(0.075000 L)/(0.08206 L·atm/mol·K)(273.15 K)

n = 0.00296 mol

Using significant figures, you can then round this to three significant figures:

n = 0.00296 mol

The numbre of moles is 0.00296. This is your final answer.

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Answer: There are nine atoms in carbon monoxide (CO). One atom of carbon (C) and one atom of oxygen (O).

Explanation:

Answer:

A mixture

Explanation:

A pure substance must have only one element . But it contains two types of elements . One is iron and the other is sulphur . So it is not pure substance .

A compound must have at least two element joined with chemical bond . So they are not easily separable . But here iron and sulphur are easily separated . so it is not a compound.

It is not a solution because a solution must have two elements out of which one should be in liquid form . But here none of the elements involved ie iron or sulphur is in liquid form so it is not solution .

Hence , it is a mixture.

The number of losses in a given period of time is known as loss frequency. Loss frequency refers to the rate at which losses occur within a specific timeframe.

Loss frequency is an important measure in risk management and insurance. It helps to assess the likelihood and frequency of potential losses or incidents. By analyzing historical data and trends, organizations can estimate the expected number of losses over a given period. This information is crucial for determining appropriate insurance coverage, setting premiums, and implementing risk mitigation strategies.

Loss frequency is often combined with loss severity, which measures the magnitude or financial impact of each loss event. Together, loss frequency and loss severity contribute to the overall understanding of an organization's risk profile. By analyzing both aspects, businesses can develop effective risk management strategies to minimize the potential impact of losses on their operations and financial performance.

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The chlorine molecules, cl2, would behave if mixed with water is best described by the polarity concept.

Polarity is a phenomena by which the dissolving power of any molecule can be known if they are polar will completely dissociate in water and if non polar will partially dissociate in water

Here chlorine is very poorly dissolve in water due to its non polar nature and water is polar. Some compounds are polar for short time of period and attend a partially positive and a partially negative charge within them.

Therefore,  Cl2 is a non polar compound describes the polarity.

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Answer:

Partial pressure of H₂ = 0.9556 atm

Explanation:

Given:

Barometric pressure = 753 torr

Vapor pressure of water = 26.74 torr

FInd:

Partial pressure of H₂

Computation:

Partial pressure of H₂ = Barometric pressure - Vapor pressure of water

Partial pressure of H₂ = 733 - 26.74  

Partial pressure of H₂ = 726.26 torr

1 atm = 760 torr

So,

Partial pressure of H₂ = 726.26/760

Partial pressure of H₂ = 0.9556 atm

Answer:

It represents the noble gas that precedes the period before Potassium.

Explanation:

Period before potassium is 3, the noble gas in that period is Ar (Argon). So when condensing the electron configuration of Potassium, Argon can account for 18 electrons instead of writing out 18 electrons in full form from 1s2, 2s2 etc.

Answer:

20

Explanation:

To write the three balanced redox reactions for the three ions that can be oxidized by permanganate, we will use the half-reaction method. In all cases, permanganate is reduced in acidic conditions to Mn2+.1. Sulfide ions (S2-) to elemental sulfur (S):
The balanced redox reaction is:
2S2- + 5H2O + 2MnO4- → 2SO4^2- + 4H+ + 2Mn2+

The half-reactions involved are:
S2- → S
MnO4- → Mn2+
In the first half-reaction, sulfide ions (S2-) are oxidized to elemental sulfur (S). In the second half-reaction, permanganate ions (MnO4-) are reduced to manganese ions (Mn2+). Iodide ions (I-) to iodine (I2):
The balanced redox reaction is:
2I- + 6H2O + 5MnO4- → I2 + 10OH- + 5Mn2+

The half-reactions involved are: I- → I2, MnO4- → Mn2+ In the first half-reaction, iodide ions (I-) are oxidized to iodine (I2). In the second half-reaction, permanganate ions (MnO4-) are reduced to manganese ions (Mn2+).

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Answer:

✔ octane

CH3CH2CH2CH2CH2CH2CH2CH3

✔ butane

CH3CH2CH2CH3

✔ methane

CH4

✔ decane

CH3CH2CH2CH2CH2CH2CH2CH2CH2CH3

✔ ethane

CH3CH3

Explanation:

An alkane contains only carbon and hydrogen. The following are the accurate names of the compounds;

An alkane is a compound whose only functional group is the carbon - carbon single bond. This compounds contain only carbon and hydrogen.

The correct names of the compounds are;

CH3CH2CH2CH2CH2CH2CH2CH3 - octane

CH3CH2CH2CH3 - butane

CH4 - methane

CH3CH2CH2CH2CH2CH2CH2CH2CH2CH3 - decane

CH3CH3 - ethane

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