0.4(-1.08) = ?

what is the product?

Answer:

45 men

Step-by-step explanation:

A job takes 30 men for 15 days to complete so it takes x men to do the same job in 10 days

30(15) = x(10)

450 = 10x

x = 450/10

x = 45

Answer:

45 days

Step-by-step explanation:

30men=15days

1man=15×30

1man=450days

10men=450÷10

10men=45days

I think that's it

Answer:

Step-by-step explanation:

0.33$

The second option shows a pair of triangles which are congruent by the SSS congruence theorem.

The SSS (Side - Side - Side) congruence theorem states that if two triangles have three sides that are congruent to each other, then the two triangles are congruent by the SSS theorem.

The congruent sides for the second option are given as follows:

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Answer:

39.5 astronomical units

Step-by-step explanation:

Answer:

POINT A

Step-by-step explanation:

it is 4 units to the left and 6 units up of the origin

80 miles must be driven in a day to make the rental cost for company A a better deal than company B

according to the question

company A for $90 a day plus $0.30 per mile

company B charges $50 a day plus $0.80 per mile to rent the same truck

90+0.30m = 50 +0.80m

0.50 m= 40

m =40/0.50

m = 4000/50

m= 80 miles

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Answer:

2x+y=5 ----eq(1)

4x+y=6 ----eq(2)

(a) x=?

eq(1)+(2)

2x + y = 5

4x + y = 6

(-). (-). (-)

___________

-2x =-1

x=1/2

(b) y= ?

eq(1)×2

4x + 2y =10

4x + y. =6

(-). (-). (-)

__________

y. =4

Answer:x=1/2

y=4

Answer: the height of this triangle is 55.4 mm

Step-by-step explanation:

\(\displaystyle\\Area\ of\ a\ triangle:\ A =\ \frac{ah}{2} \\\\Hence,\\\)

Multiply both parts of the equation by 2:

\(2A=ah\)

Divide both parts of the equation by a:

\(\displaystyle\\\frac{2A}{a} =h\\\\Thus,\ h=\frac{2A}{a} \\\\h=\frac{2(227.14)}{8.2} \\\\h=\frac{454.28}{8,2} \\\\h=55.4\ mm\)

Answer:

DCC

Step-by-step explanation:

CDDCDC

Different type of spaghetti dinners is 8

What is combination ?

"The number of possible arrangements in a collection of items where the order does not matter."

For 4 different shaped of noodles = ⁴c₁

                                             ⁴c₁ = 4        

For two kinds of cheese = ²c₁

                                         ²c₁ = 2

Now , multiplying these  4×2 = 8

Hence, 8 type of spaghetti dinners

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The required length of the tangent PQ is given as 16.73 units.

The circle is the locus of a point whose distance from a fixed point is constant i.e center (h, k). The equation of the circle is given by

(x - h)² + (y - k)² = r²

where h, k is the coordinate of the center of the circle on the coordinate plane and r is the radius of the circle.

Here,

PQ² = QS·RS
PQ = √[7 × 40]
PQ = 16.73

Thus, the required length of the tangent PQ is given as 16.73 units.

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Answer:

C

Step-by-step explanation:

There is a difference of 16 between consecutive terms, that is

259 - 243 = 275 - 259 = 291 - 275 = 16

This indicates the sequence is arithmetic with nth term

\(a_{n}\) = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here a₁ = 243 and d = 16 , then

\(a_{n}\) = 243 + 16(n - 1) = 243 + 16n - 16 = 227 + 16n → C

Answer: The answer is C) parallel

(a)We have to use a continuous exponential growth model to write a formula relating to t and N(t), where t is the time (in years) since the initial population is introduced, and N(t) is the number of fish at time t. Continuous exponential growth models can be expressed as;
N(t) = N₀ * e^(kt)
where N₀ is the initial population, t is the time elapsed, k is the continuous growth rate, and e is Euler's number.

(b)Given that the initial population is introduced into a lake and it grows according to a continuous exponential growth model. The number of fish in the lake is 300 after 4 years. Using N(t) = N₀ * e^(kt);300 = N₀ * e^(4k)So, the formula relating to t and N(t) is;
N(t) = N₀ * e^(kt)
Putting the values into the formula;
N(t) = 300/ e^(4k)We know the number of fish in the lake after 4 years is 300.
Therefore;300 = N₀ * e^(4k)
Dividing by N₀; 300/N₀ = e^(4k)
We have; N(t) = N₀ * e^(kt)
Putting the values into the formula;
N(t) = N₀ * e^(kt)N₀ = N(t) / e^(kt)
At t = 0; N₀ = N(0) / e^(k*0)N₀ = N(0) / e^0
N₀ = N(0)
Now we can substitute the value of N₀ into the formula;
N(t) = N(0) * e^(kt)
Substituting the values in N(t) = N₀ * e^(kt);
N(t) = 1000 * e^(0.23t)

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The probability of flipping a heads on the coin and rolling a 5 on the die is 1/12 if a coin is flipped and die is rolled once.

The sample space for the coin toss is  {H,T}, so there are two possible outcomes. The favorable one is  H.

The probability of flipping a heads on the coin is equal to 1/2.

Die has six faces, meaning six possible outcomes, but we’re only interested in one of those outcomes: that roll of a 5. That means that only 1 in 6 outcomes is desirable and we can write it as  1/6

The probability of rolling a 5 on the die is equal to 1/6.

Since a coin is flipped and die is rolled independently, the joint probability is a product of above probabilities.

Therefore, the probability of flipping a heads on the coin and rolling a 5 on the die equals

\(\frac{1}{2} \times \frac{1}{6}\\= \frac{1}{12}\)

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There would be 3.00 mg of iron-59 remaining. 132 days is equivalent to 3 half-lives because 132/44 = 3. So, we can use the formula to find the amount of iron-59 remaining after 3 half-lives, which is 3.00 mg.

We can use the formula for half-life to determine how much iron-59 remains after 132 days:
Amount remaining = initial amount * (1/2)^(t/h)
Where:
- t is the time that has passed
- h is the half-life of the substance
So, after 132 days, there would be 3.00 mg of iron-59 remaining.

Iron-59 is a radioactive isotope, which means that its nucleus is unstable and will eventually decay into a more stable form. When an isotope decays, it releases energy in the form of radiation (such as alpha, beta, or gamma particles) and transforms into a new element.  The half-life of an isotope is the amount of time it takes for half of the initial amount to decay. For example, if you start with 24 mg of iron-59, after one half-life (44 days), you would have 12 mg remaining. After two half-lives (88 days), you would have 6 mg remaining. And after three half-lives (132 days), you would have 3 mg remaining.

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We have shown that for any connected graph G with at least one cycle, we can remove some edges such that the resulting subgraph is bipartite and connected.

A graph is a graphic or visual representation of facts or values. The points on a graph are frequently used to depict the relationships between two or more objects.

To prove the statement, let's consider a connected graph G with at least one cycle.

Case 1: G is already bipartite.

If G is already bipartite, then the statement is trivially true. We don't need to remove any edges because G is already bipartite and connected.

Case 2: G is not bipartite.

If G is not bipartite, it means that there exists at least one odd cycle in G. In order to make G bipartite, we can remove any one of the edges from the odd cycle. Removing a single edge will break the cycle and create two separate connected components.

Let's denote the original graph with the odd cycle as G', and the resulting subgraph after removing one edge as G''. By removing a single edge, G'' will consist of two connected components, each of which is bipartite. This is because removing one edge from the odd cycle creates two separate paths, and each path can be assigned a different color to form a bipartite graph.

Since G'' is the result of removing one edge from G', it is still connected because all the vertices in G' are still connected through the remaining edges. Thus, G'' is a connected subgraph of G and is also bipartite.

Therefore, we have shown that for any connected graph G with at least one cycle, we can remove some edges such that the resulting subgraph is bipartite and connected.

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Answer:

1)  \(\mathbf{5^{-3}=\frac{1}{125}}\)

2)  \(\mathbf{-5^{-3}=-\frac{1}{125}}\)

3)  \(\mathbf{(-5^{-3})^{-1}=-125}\)

4)  \(\mathbf{(-5^{-3})^0=1}\)

Step-by-step explanation:

We need to solve the exponents

1) \(5^{-3}\)

We know that: \(a^{-1}=\frac{1}{a}\)

\(5^{-3}\\=\frac{1}{5^3}\\=\frac{1}{125}\)

So, we get \(\mathbf{5^{-3}=\frac{1}{125}}\)

2) \(-5^{-3}\)

We know that: \(a^{-1}=\frac{1}{a}\)

\(-5^{-3}\\=-\frac{1}{5^3}\\=-\frac{1}{125}\)

So, we get \(\mathbf{-5^{-3}=-\frac{1}{125}}\)

3) \((-5^{-3})^{-1}\)

We know that: \((a^m)^n=a^{m*n}\)

Using this rule:

\((-5^{-3})^{-1}\\=-5^{-3*-1}\\=-5^{3}\\=-125\)

So, we get \(\mathbf{(-5^{-3})^{-1}=-125}\)

4)  \((-5^{-3})^0\)

We know that: \((a^m)^n=a^{m*n}\)

Using this rule:

\((-5^{-3})^0\\=-5^{-3*0}\\=-5^{0}\\We\:know\:a^0=1\\=1\)

So, we get \(\mathbf{(-5^{-3})^0=1}\)

Answer: it’s the third option

Step-by-step explanation:

Answer:

y – 7 = 4(x – 1)

Step-by-step explanation:

Third option

Answer:

P(x) = 35,900 + 2,800(x-1)

Step-by-step explanation:

P(x)

P(1) = $35,900

P(4) = $44,300

Difference in profits

P(4) - P(1)

= P(3)

= $44,300 - $35,900

= $8,400

Rate of change per year = $8,400 / 3

= $2,800 per year

The linear equation

P(x) = 35,900 + 2,800(x-1)

Where

x = number of years

The number of players the team can bring to the tournament would be = 24 players

The softball game is the type of game that involves two teams which is made up of 9. - 10 players.

The total amount of money raised by a softball team=

$2089.50

The amount of money spent on rented bus = $1087.50

The amount left after rent deductions= 2,089.50 - 1,087.50 = 1,002

The amount budgeted for meals for each player= $41.75

The number of players that would be brought for tournament= 1,002/41.75

= 24 players.

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The distance between Points A and B is 12 units. If we were to draw a number line with Point A at -5 and Point B at 7, we could count the number of units between them.

In order to determine the distance between points A and B on a number line, we need to know the values of each point and then calculate the absolute value of the difference between them.

Point A has a value of -5 and Point B has a value of 7. The absolute value of the difference between -5 and 7 is 12.

Therefore, the distance between Points A and B is 12 units. If we were to draw a number line with Point A at -5 and Point B at 7, we could count the number of units between them.

However, it is more efficient to simply subtract the values of the two points and take the absolute value of the result.

This gives us the distance between the two points, regardless of which one is greater or smaller. In this case, the distance between Points A and B on the number line is 12 units.

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Answer:

1/3

Step-by-step explanation:

The left side of FA is 6 units.

The left side of FB is 2 units.

From 6 to 2, you divide by 3.

Same for the top,

FA is 9 units, while FB is 3 units.

I hope this helps!

pls ❤ and mark brainliest pls!

Answer:

\(x=7\)

Step-by-step explanation:

We can add the same quantity to both sides of the equations, and still have an equivalent equation. Let's add \(x+2\) to both sides, then sum like terms

\(5-x +x+2 = -2 +x+2\\5+2 = x\\7=x\)

(this is the rule that allows us to move items from one side do the other of the equal sign by changing its sign)

At this point we have a solution, let's replace it to verify

\(5-(7) = -2\\-2=-2\)

The exterior angle of a triangle is equal to the sum of 2 opposite interior angles of the triangle.

Here,

2 opp. interior angles = 30° & (4x + 2)°

Exterior angle = (8 + 6x)°

So,

8 + 6x = 4x + 2 + 30

8 + 6x = 4x + 32

8 - 32 = 4x - 6x

-24 = -2x

=》 12 = x

________

꧁✿ ᴿᴬᴵᴺᴮᴼᵂˢᴬᴸᵀ2222 ✬꧂

The probabilities for the ace cards are 0.1433, 0.0045, 0.0905, 0.0482.

what is a blackjack card game?

It derives from the Twenty-One line of gambling banking games and utilises 52-card decks.

Face cards and number 10: 16 cards have point value 10 Ace cards:

4 cards have point value 1 or 11 total number of cards =

Part a)

P(Ace or 10 point card has following cases)

case l: both are Ace cards = (4/52)*3/51 =

0.0045

Case II: both are 10 point cards = (16/52)*(15/51) =

0.0905

Case III: first card Ace, second card 10 point = (4/52)*(16/51 0.0241 Case IV: first card 10 pt, second card Ace: = (16/52)"(4/51) = 0.0241

Total = 0.1433

Part b) P(both cards are Ace) = (4/52)*(3/51) = 0.0045

Partc) P(both cards have point value 10) = (16/52) * (15/51) = 0.0905

Part d) P(Ace and 10 point) = 0.0241+0.0241 = 0.0482

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The largest value of the sum based on the information will be 1055.

From the information given, the digits are 2, 3, and and 5 but not necessarily in the same order. The numbers that can be formed will be:

235

253

325

352

523

532

Therefore, the largest value of the sum will be:

= 532 + 523

= 1055

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After considering the given data we conclude that the answer for the sub questions are
a) Jeff consumes 33.33 units of good x.
b) the compensating variation is:
\(CV=W'-W=2(50)-200=-100CV\)
c) The income effect is negative, indicating that Jeff will consume less of good x due to the decrease in purchasing power caused by the price increase.

a. To find Jeff's demand function for good x, we can use the following equation:
\(\frac{\partial U}{\partial x}=\frac{1}{x}=\frac{p_x}{p_y}=\frac{1}{2}\)
Solving for x, we get:
\(x=\frac{1}{2}y\)
Substituting the given values, we get:
\(x=\frac{1}{2}(200/3)=33.33\)
Therefore, Jeff consumes 33.33 units of good x.
b. If Px increases to 2, the new demand function for good x is:
\(x'=\frac{1}{2}y'\)where y'  is the amount of good y consumed at the new prices and income. To find the compensating variation, we need to find the amount of income Jeff would need at the original prices to achieve the same level of utility as he does at the new prices. We can use the following equation:
\(W'=W+CV\) where W is the original income, W' is the new income, and CV is the compensating variation.
Substituting the given values, we get:
\(8.51=\ln(33.33)+\ln(66.67)8.51=ln(33.33)+ln(66.67)\)
\(y'=\frac{W'}{2}\)
\(x'=\frac{1}{2}y'\) Solving for y', we get:
y'=100
Solving for x', we get:
x'=50
Therefore, the compensating variation is:
\(CV=W'-W=2(50)-200=-100CV\)
c. To calculate the total effect, substitution effect, and income effect of the price change, we can use the following equations:
\(TE=\frac{\Delta U}{U_0}\)
\(SE=\frac{\Delta x_s}{x_0}\)
\(IE=\frac{\Delta x_i}{x_0}\)where \(\Delta U\)is the change in utility, \(U_0\) is the initial utility,\(\Delta x_s\) is the change in consumption due to the substitution effect, \(x_0\) is the initial consumption, and \(\Delta x_i\) is the change in consumption due to the income effect.
The change in consumption due to the price change can be calculated as:
as:
\(\Delta x=x'-x_0=\frac{1}{2}y'-\frac{1}{2}y_0\)
where \(y_0=2x_0\) and \(y'=2x'\)
Substituting the given values, we get:
\(\Delta x=x'-x_0=50-33.33=16.67\)
The substitution effect can be calculated as:
\(SE=\frac{\Delta x_s}{x_0}=\frac{x_s'-x_0}{x_0}=\frac{1}{2}\frac{y_0-y_s'}{x_0}=\frac{1}{2}\frac{p_x}{p_y}\frac{y_0}{x_0}\)
Substituting the given values, we get:
\(SE=\frac{1}{2}\frac{1}{2}\frac{2x_0}{4x_0}=\frac{1}{4}\)
The income effect can be calculated as:
\(IE=\frac{\Delta x_i}{x_0}=\frac{\Delta W}{W_0}=\frac{CV}{W_0}\)
Substituting the given values, we get:
\(IE=\frac{-100}{200}=-0.5\)
The total effect can be calculated as:
\(TE=SE+IE=\frac{1}{4}-0.5=-0.25\)
Therefore, the total effect of the price change is negative, indicating that Jeff will consume less of good x as a result of the price increase. The substitution effect is positive, indicating that Jeff will consume more of good x due to the relative price change. The income effect is negative, indicating that Jeff will consume less of good x due to the decrease in purchasing power caused by the price increase.
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