Answer:
33333.35 kg
Explanation:
I got it right on Acellus, rounded to 33300 sigfigs
When 0.0135 kg of steam at 100°C is cooled, turns it into water at 50.0°C. Then 33,342.45 J of heat has been removed.
What is latent heat?Latent heat is the heat absorbed or released by a substance during a change in its physical state without a corresponding change in temperature. This means that the heat energy is being used to break or form intermolecular bonds between the particles in the substance, rather than raising or lowering the temperature. Examples of processes that involve latent heat include melting, freezing, vaporization, and condensation. The amount of heat required or released during these phase transitions is dependent on the substance and the amount of material undergoing the change.
Here in the question,
To solve this problem, we need to use the formula for the heat required to change the phase of a substance, which is given by:
Q = m * L
where Q is the heat required, m is the mass of the substance, and L is the specific latent heat of the substance.
In this case, we need to find the heat required to change 0.0135 kg of steam at 100°C to water at 100°C, and then cool it down to 50°C.
First, we need to find the heat required to change the phase of the steam to water at 100°C. Using the table given, we can see that the specific latent heat of vaporization for water is 2.26 × 10^6 J/kg. So the heat required to change 0.0135 kg of steam to water at 100°C is:
Q1 = m * L = 0.0135 kg * 2.26 × 10^6 J/kg = 30,510 J
Next, we need to find the heat required to cool the water from 100°C to 50°C. Using the specific heat capacity of water, which is 4186 J/(kg°C), we can calculate the heat required as:
Q2 = m * c * ΔT = 0.0135 kg * 4186 J/(kg°C) * (100°C - 50°C) = 2832.45 J
The total heat removed is the sum of the heat required to change the phase of the steam and the heat required to cool the water:
Q = Q1 + Q2 = 30,510 J + 2832.45 J = 33,342.45 J =33.34245 kJ.
Therefore, 33,342.45 J of heat has been removed.
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An iron nail does not pick up paper clips as a magnet would.
Answer:
Because even if iron is magnetic its not a magnet it self unless rubbed a magnetic object
Roller coasters are popular attractions at amusement parks. A cart on a roller coasterapproaches the highest point on the coaster. As the cart reaches the top, it slows down.Which statement best describes the energy of the roller coaster as it slows down whiletraveling to the top of the coaster?A The cart gains both kinetic and potential energy.B The cart gains kinetic energy and loses potential energy.C The cart loses kinetic energy and gains potential energy.D The cart loses both kinetic and potential energy.
The statement that describes energy of the roller coaster as it slows down while travelling to the top of the coaster is 'The cart loses kinetic energy and gains potential energy.'
Consider three roller coaster points that are each at a different height from the ground. If we disregard all frictional and drag forces and focus just on the conservative forces acting on the roller coaster car, we may assume that all kinetic and potential energy is conserved. As a result, energy only transforms from one form to another.
When the roller coaster vehicle hits the bottom, it will have reached its maximum level of kinetic energy since all of the gravitational potential energy has been transformed into kinetic energy.
At the top of the roller coaster, the object has its maximum gravitational potential energy and none at all (assumed there is no velocity). As the object begins to fall to the bottom, its gravitational potential energy falls and its kinetic energy increases.
Hence, as the cart reaches the top, it slows down because it loses kinetic energy and gains potential energy.
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Helpppp!! I will make you a brainlist Calculate the force exerted on
this test dummy with a mass of 75 kg hits an airbag accelerating at 12m/s2??
Answer:
900 NExplanation:
The force acting on an object given it's mass and acceleration can be found by using the formula
force = mass × acceleration
From the question is we have
force = 75 × 12
We have the final answer as
900 NHope this helps you
Question 7 (1 point)
An air mass exists off the Pacific coast of California. What type of air mass is this and
what are its main characteristics?
Choose ALL that apply
Lesson 1.07
Maritime
Polar
Continental
Polar
Maritime
Polar
Maritime
Tropical
Maritime
Tropical
Continental
Tropical
Maritime
Tropical
forms over warm water
warm, humid air mass
its a polar air mass
brings rainy or muggy weather
Answer:
Forms over water, warm humid air mass, it's a polar air mass
Explanation: I think that's right sorry if it's not..
GL! :)
A 20 N force is necessary to stretch a spring 0.5 m. What is the spring constant of this spring?
Answer: The spring constant of a given spring is \(40 N/m\).
Explanation:
Given,
Force (F) = 20N
The displacement of the spring\(= x = 0.5 m\)
To find: Spring constant (k) = ?
As we know that,
Hook's law states that,
\(F = k\) · \(x\)
Therefore, \(k = \frac{F}{x}\)
\(k = \frac{20}{0.5}\)
\(k = \frac{(20)(10)}{5}\)
\(k = 40 N/m\)
Hence, The spring constant of a given spring is \(40 N/m\).
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A box required 800J of work to lift 5 meters off the ground. How many newtons did the box
weigh?
Answer:
800 Newtons.
Explanation:
Work is defined as the force applied to an object multiplied by the distance over which the force is applied. The formula for work is W = F x d.
In this case, the force required to lift the box is equal to the work done divided by the distance.
F = W / d
F = 800 J / 5 m
To convert Joules to newtons, we need to use the relation 1 Joule = 1 Newton x Meter
F = 800 N
So the box weighed 800 Newtons.
Jen is conducting an experiment involving a device known as a pith-ball electroscope, shown below.
The plastic ball of the electroscope hangs in midair and is uncharged. Charges cannot move along the silk thread that holds the ball in the air.
Jen completes the following steps in her experiment:
1- She collects three identical, uncharged rubber tubes.
2-She holds a magnet to the first tube for 5 minutes.
3-She submerges the second tube in a tank of water for 5 minutes.
4- She rubs the third tube with animal fur for 5 minutes.
Jen's teacher tells her that she can use the pith-ball electroscope to see if any of the rubber tubes are surrounded by an electric field. What should Jen do to test for an electric field surrounding each tube?
Answer:
bring each tube close to the plastic ball and note any movement of the ball
Explanation:
study island
just took the test!!!!!
Answer:
bring each tube close to the plastic ball and note any movement of the ball
Explanation:
Electric fields can exert forces on objects, even if the objects involved are not touching. One way to demonstrate that electric fields exist around charged objects is to observe the effects of their forces at a distance.
Since the plastic ball of the electroscope is made of insulating plastic and is uncharged, it will be attracted to any charged object brought near it. So Jen can observe the effects of the tube's electric fields by bringing each tube close to the plastic ball and noting any movement of the ball. If the ball moves toward a tube, then the process that Jen used on the tube generated an electric field.
Derive an equation for the acceleration of block 3 for any arbitrary values of m3 and m2. Express your answer in terms of m3, m2, and physical constants as appropriate.
Complete question is;
Block 1 is resting on the floor with block 2 at rest on top of it. Block 3, at rest on a smooth table with negligible friction, is attached to block 2 by a string that passes over a pulley, as shown in the attachment below. The string and pulley have negligible mass.
Block 1 is removed without disturbing block 2.
Derive an equation for the acceleration of block 3 for any arbitrary values of m3 and m2. Express your answer in terms of m3, m2, and physical constants as appropriate.
Answer:
a = (m2)g/(m3 + m2)
Explanation:
Looking at the attached image, if we consider the free body diagram for block 3, by using Newton's first law of motion, we will arrive at the formula;
T = (m3)a - - - (eq 1)
where;
T is the tension in the string
a is acceleration
m3 is mass of block 3
Meanwhile doing the same with Block 2, the free body diagram would give us the formula; (m2)g - T = (m2)a
Making T the subject gives us;
T = (m2)g - (m2)a - - - (eq 2)
where;
g is acceleration due to gravity
T is the tension in the string
a is acceleration
m2 is mass of block 2
To solve for the acceleration, we will just substitute (m3)a for T in eq 2.
Thus;
(m3)a = (m2)g - (m2)a
(m3)a + (m2)a = (m2)g
a(m3 + m2) = (m2)g
a = (m2)g/(m3 + m2)
What checks the power of a President?.
A statute may be subject to the President's veto in the executive branch, but with enough votes, the legislative branch can override the veto.
The legislative branch is in charge of approving presidential appointees, overseeing the budget, and having the power to impeach and remove the president. The supervision of the executive branch is the Congressional restraint on the President's power and a balance to his or her discretion in implementing laws and creating regulations. Proceedings are one of the main ways that Congress carries out oversight.There are several ways for the Congress to restrict the president's authority. The first method involves the Congress voting to remove the president from office through impeachment. The following method is "advice and permission." Judges and other officials can be chosen by the president, but the Congress must provide its consent.Thus this is how President's powers are checked.
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a toy car rolls 8 meters in 2 seconds. what is the average speed of the toy car?
Answer:
16m/s
Explanation:
speed = distance multiply be time taken
Answer:
16
Explanation:
8*2
QUESTION 6 Draw the shear force and bending moment diagrams for the simply supported beam loaded in Fig Q6
To draw the shear force and bending moment diagrams for the simply supported beam loaded in Figure Q6, we'll follow these steps:
Step 1: Determine the reactions at the supports.
Step 2: Calculate the shear forces at various points along the beam.
Step 3: Calculate the bending moments at various points along the beam.
Step 4: Plot the shear force diagram (SFD) and the bending moment diagram (BMD).
Step 1: Determine the reactions at the supports:
The beam is simply supported, so the reaction forces at the supports will be vertical. Let's assume the left support reaction as R1 and the right support reaction as R2. Since the beam is in equilibrium, the sum of the vertical forces must be zero:
R1 + R2 = 20 kN (upward forces are positive)
Step 2: Calculate the shear forces at various points along the beam:
We'll consider three sections along the beam: left of the 10 kN point (A), between the 10 kN point and the 20 kN point (B), and right of the 20 kN point (C).
Section A (left of the 10 kN point):
The shear force at point A will be equal to the reaction R1.
V_A = R1
Section B (between the 10 kN point and the 20 kN point):
The shear force at point B will be equal to the reaction R1 minus the 10 kN load.
V_B = R1 - 10 kN
Section C (right of the 20 kN point):
The shear force at point C will be equal to the reaction R1 minus the 10 kN load and the 20 kN load.
V_C = R1 - 10 kN - 20 kN
Step 3: Calculate the bending moments at various points along the beam:
We'll still consider the same three sections: A, B, and C.
Section A (left of the 10 kN point):
The bending moment at point A will be zero, as there are no external loads or reactions to create a moment.
Section B (between the 10 kN point and the 20 kN point):
The bending moment at point B will be equal to the integral of the shear force from the left support (A) to point B.
M_B = ∫(R1 - 10 kN)dx, integration limits: 0 to x
Section C (right of the 20 kN point):
The bending moment at point C will be equal to the integral of the shear force from the left support (A) to point C.
M_C = ∫(R1 - 10 kN - 20 kN)dx, integration limits: 0 to x
Step 4: Plot the shear force diagram (SFD) and the bending moment diagram (BMD):
Using the calculated values of the shear forces and bending moments at various points, we can plot the diagrams.
Shear Force Diagram:
- The SFD will be a horizontal line at the value of R1 until the 10 kN load.
- At the 10 kN load, there will be a downward step change of 10 kN.
- At the 20 kN load, there will be another downward step change of 20 kN.
- The SFD will continue as a horizontal line after the 20 kN load.
Bending Moment Diagram:
- The BMD will be a straight line with zero bending moment from the left support (A) until the 10 kN load (
B).
- At the 10 kN load, there will be a positive bending moment.
- At the 20 kN load, the bending moment will increase further.
- The BMD will continue as a straight line with a decreasing positive slope after the 20 kN load.
Please note that without specific values for R1 and the dimensions of the beam, it's not possible to provide exact numerical values for the shear forces and bending moments or to accurately plot the diagrams. However, the general shape and characteristics of the diagrams can be described based on the given information.
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what does a blue shift in light from stars indicate?
Answer:
If a star is moving towards the earth, its light is shifted to higher frequencies on the color spectrum (towards the green/blue/violet/ultraviolet/x-ray/gamma-ray end of the spectrum). A higher frequency shift is called a "blue shift".
Explanation:
It just means that the entire spectrum is shifted up in frequency.
two students will be working together diluting concentrated acid for their experiment. before beginning, they think about the ramp acronym and quickly assess the risk of their planned procedure. choose the best assessment for each letter.
By using the RAMP acronym, the students can examine and manage the risks connected with their diluting concentrated acid approach, resulting in a safer and more regulated experimental process.
To assess the risk of their planned procedure using the RAMP acronym, the best assessment for each letter would be as follows:
R - Recognize hazards: The students should identify and acknowledge any potential hazards associated with diluting concentrated acid.
A - Assess risks: The students should evaluate the risks associated with the procedure. This involves considering the probability and potential consequences of accidents or mishaps, such as acid splashes, improper handling, or inhalation of fumes.
M - Minimize risks: The students should take measures to minimize the identified risks. This includes implementing safety protocols and precautions.
P - Prepare for emergencies: The students should be prepared to respond to any potential emergencies or accidents that may occur during the procedure.
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How much time does a bike with an acceleration of 2ms-2 take to increase its velocity from 10ms-1 to 30ms-1?
Answer:
\( \boxed{\sf Time \ taken = 10 \ seconds} \)
Given:
Initial velocity (u) = 10 m/s
Final velocity (v) = 30 m/s
Acceleration (a) = 2 m/s²
To Find:
Time taken (t) by bike to increase its velocity from 10 m/s to 30 m/s with an acceleration of 2 m/s²
Explanation:
\(\sf From \ equation \ of \ motion:\)
\( \boxed{ \bold{v = u + at}}\)
Substituting values of v, u & a in the equation:
\( \sf \implies 30 = 10 + 2t\)
Substract 10 from both sides:
\( \sf \implies 30 - 10 = (10 - 10) + 2t\)
\( \sf \implies 20 = 2t\)
20 = 2t is equivalent to 2t = 20:
\( \sf \implies 2t = 20\)
Dividing both sides by 2:
\( \sf \implies \frac{ \cancel{2}t}{ \cancel{2}} = \frac{20}{2} \)
\( \sf \implies t = \frac{10 \times \cancel{2}}{ \cancel{2}} \)
\( \sf \implies t = 10 \: s\)
So,
Time taken (t) by bike to increase its velocity from 10 m/s to 30 m/s with an acceleration of 2 m/s² = 10 seconds
What important role does each play in an exercise regiment?
Answer: There are five principles of fitness out of which two are overload principle and rest and recovery principle. Overload principle is one of the most important principle which tell that to gain and improve the fitness one should do the hard work.
Slowly and gradually the intensity and time of exercise are increased so that our body can adapt to the hard work. Overload principle plays an important role in improving the skills and improving performance during exercise and sports.
Rest and recovery principle is important to relax the body and release the stress that happens due to intense training like in case of weight lifting one day rest should be taken to repair and rebuild the muscles. This allows the body to encounter the fatigue and improve performance.
Explanation:
if a wire of resistance r is stretched uniformly to 2.6 times its initial length, by what factor does the power dissipated in the wire change, assuming it remains hooked up to the same voltage source? assume the wire's volume and density remain constant. express your answer using two significant figures.
The power dissipated in the wire changes by a factor of 6.8.
When a wire of resistance r is stretched uniformly to 2.6 times its initial length, its cross-sectional area reduces.
Since the wire's volume and density remain constant, the new resistance (R') can be found using the formula R' = (2.6)²* r.
This is because resistance is directly proportional to length and inversely proportional to the cross-sectional area. So, R' = 6.76r (approximately).
Now, the power dissipated (P) in a resistor is given by P = V² / R, where V is the voltage. Since the voltage source remains the same, we can find the factor by which the power changes using the ratio of the new resistance to the original resistance:
Factor = (V² / R') / (V² / r) = r / R' = r / (6.76r) ≈ 1 / 6.8.
Thus, the power dissipated in the wire changes by a factor of 6.8.
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A supersonic jet flying at 200. m/s is accelerated uniformly at the rate of 23.1 m/s² for 20.0 seconds.
a. What is its final speed?
b. Physicist Ernst Mach studied the effects of motion faster than sound, and the ratio of a speed to that of sound is called its “Mach number”. The speed of sound itself is 331 m/s (approx. 740 mi/h) at supersonic airplane altitudes. “Mach 1.00" is the ratio 331/331, or the speed of sound. One of the fastest planes was the SR-71 Blackbird. It flew at 1059 m/s, so 1059/331 = 3.20; we say it flew at “M ach 3.20.” Convert the final speed of our jet from m/s into Mach.
Here, the final speed of the supersonic jet having initial speed of 200 m/s and acceleration of 23.1 m/s² within 20 seconds is 662 m/s. The Mach number of the jet is 2.
What is acceleration ?Acceleration of an object is the rate of change in velocity. It is a vector quantity having both direction and magnitude.
a = Δv/t
The initial velocity u = 200 m/s
a =23.1 m/s²
the time t = 20 s
v= u+ a t
then v = 200 m/s + (23.1m/s²) × 20s = 662 m/s
Hence, the final velocity of the supersonic jet is 662 m/s.
The conversion of final velocity to the Mach number is done as follows:
Mach number = speed of jet/speed of sound
= 662 m/s /331 m/s
= 2
Therefore, the Mach number of the jet is 2.
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1. Give practical applications of the reflection of sound waves.
It is used to measure distance and the speed and agility of objects that are underwater.
What are some examples of objects or substances that are magnetic?
Answer:
iron,Cobalt and nickel
A spring with a spring constant of 50 N/m is hanging from a stand. A second spring with a spring constant of 100 N/m is hanging from the first spring. How far do they stretch if a 0.50 kg is hung from the bottom spring?
Answer:
each spring will extend 0.049 m / 2 = 0.024 m.
Explanation:
The total spring constant of the two springs in series is 150 N/m (50 N/m + 100 N/m). The extension of the two springs can be calculated using Hooke's law:
F = kx
where F is the force applied to the spring (in this case, the weight of the 0.50 kg mass), k is the spring constant, and x is the extension of the spring.
So, x = F / k = (0.50 kg * 9.8 m/s^2) / 150 N/m = 0.049 m
This is the total extension of the two springs combined. To find the extension of each spring, we need to divide the total extension by the number of springs. Since there are two springs in series, each spring will extend 0.049 m / 2 = 0.024 m.
How do water vapor, temperature, AND wind cause Galetown to have more severe rainstorms this summer than in previous years?
Please use evidence to support your answer :)
Water vapor, temperature, and wind all play a significant role in the formation of rainstorms. In Galetown, the combination of these factors has led to more severe rainstorms this summer than in previous years.
Firstly, higher temperatures can lead to more water vapor in the air, as warmer air can hold more moisture. This increased moisture can contribute to the formation of thunderstorms and heavy rain. According to the National Oceanic and Atmospheric Administration (NOAA), Galetown experienced above-average temperatures this summer, which could have contributed to the severity of the rainstorms.
Secondly, wind can also impact the formation and intensity of rainstorms. Stronger winds can increase the amount of moisture in the air by bringing in more humid air from other regions. Additionally, wind patterns can influence the movement and organization of storm systems, leading to more concentrated areas of rainfall. The NOAA reports that Galetown experienced above-average wind speeds this summer, which could have contributed to the severity of the rainstorms.
Lastly, the increased water vapor and wind in the region could have led to a greater likelihood of thunderstorms, which are often associated with heavy rainfall. Thunderstorms can occur when warm, moist air rises and cools, causing water vapor to condense into clouds. As these clouds grow, they can generate lightning, thunder, and heavy rain. According to local weather reports, Galetown experienced a higher number of thunderstorms this summer than in previous years.
Evidence to support this answer can come from meteorological data such as records of increased water vapor levels, higher temperatures, and changes in wind patterns in Galetown this summer compared to previous years. Additionally, increased frequency or intensity of rainstorms can be considered as evidence of these factors playing a role in causing more severe rainstorms this summer.
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When sunlight illuminates a page from your Conceptual Physics book it
A) reflects most of it.
B) absorbs at the text lettering.
C) both of these
D) neither of these
When sunlight illuminates a page from your Conceptual Physics book, it undergoes both reflection and absorption. Therefore, the correct answer is C) both of these.
Reflection: When light hits the surface of the page, a portion of it is reflected back into the surrounding environment. This reflected light allows us to see the page and read the text. The page's surface and the ink used for printing contribute to the reflection of light.
Absorption: Another portion of the sunlight is absorbed by the page and the ink on it. The molecules in the page and ink absorb specific wavelengths of light, while others are reflected or transmitted. The absorbed light energy is converted into heat, which is why a page can feel warm when exposed to sunlight for an extended period.
So, when sunlight illuminates a page from your Conceptual Physics book, both reflection and absorption occur.
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a sample of ideal gas is in a sealed rectangular container that has sides of different sizes. side a has an area of 80cm2 and side b has an area of 100cm2 . which of the following correctly compares the pressure p exerted on sides a and b of the container and explains the relationship in terms of net force and molecular collisions with the sides?
a. The pressure is less en side B because the overage force exerted during the individual molecular collions with the sides is the same for both sides A and B and side Bhas a greater area over which the net force is distributed b. P, P. The pressure is greater on side B because although the average force exerted during molecular collisions in the same for both sides, more particles colide with side B c. in a given time, resulting in higher net force and Higher pressure on side B C P.-P. The pressure is the name on both sides because the werage force exerted by individual molecules as they collide with the sides is the same for both sides A and B. and an equal number of particles collide with both sides D. PPA The pressure is the same on both sides because although the average force exerted by the individual molecules as they collide with the sides is the same, the netforce and area are both proportionally greater for tide B 2R R n n
The correct answer is b. The pressure is greater on side B because although the average force exerted during molecular collisions is the same for both sides, more particles collide with side B in a given time, resulting in a higher net force and higher pressure on side B.
Determine the pressure exerted by a gas?The pressure exerted by a gas is a result of the molecular collisions with the container walls. According to the kinetic theory of gases, the average force exerted by individual gas molecules during collisions is the same regardless of the area of the container.
Therefore, the average force exerted during molecular collisions is the same for sides A and B.
However, since side B has a larger area (100 cm²) compared to side A (80 cm²), a greater number of gas particles will collide with side B in a given time.
This means that the net force exerted by the gas molecules on side B is higher due to the larger number of molecular collisions. As a result, the pressure on side B is greater than the pressure on side A, even though the average force per collision is the same.
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What is the weight in newtons of a person who has a mass of 50 kg?
The weight of an object with a mass of 50kg is 490 N. The gravitational force of the earth on an object is referred to as its weight.
How much do I weigh in Newtons on the moon?The gravitational constant on Earth is 9.81 N/Kg (Newtons per kilogram). You would weigh less standing on the Moon because it has around one-sixth the gravity of Earth. The gravitational constant on the moon is 1.622 N/Kg.
Mass: What is it?The amount of matter in a particle or object is represented by its mass, which is denoted by the symbol m. In the International System (SI), the kilogram serves as the default unit of mass (kg).
Given:
Mass (m) = 50 Kg
To find the weight of an object, you simply multiply its mass by the gravitational force.
m = 50kg; g = 9.8
Therefore:
w = mg
= 50 x 9.8
= 490 N
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A student drops a rock from a bridge to the
water 13.1 m below.
With what speed does the rock strike
the water? The acceleration of gravity is
9.8 m/s
2
.
Answer in units of m/s.
Simplify the following expression 4kg. (5) ² - 6kg. (2) ²
Answer: 19kg. (2)^2
Explanation:
4kg (5)^2-6kg (2)^2=
100kg-24kg=
76 kg= 19kg. (2)^2
how is motion with air resistance different than the motion in free fall? give at least two differences.
The two differences between motion with air resistance and motion in free fall are: Free fall motion is an example of uniformly accelerated motion whereas motion with air resistance is an example of non-uniformly accelerated motion.
This means that in free fall, an object experiences a constant acceleration of 9.8 m/s², while in motion with air resistance, the acceleration of the object varies with time and velocity.
Another difference is that in motion with air resistance, there is a presence of a resistive force due to air resistance that acts in the opposite direction of the motion of the object. This force increases with the increase in the velocity of the object.
However, in free fall, there is no such force acting on the object as it falls through the air, assuming there is no significant air resistance.
Hence, above are the two differences between air resistance and free fall.
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In the dark, is the current through an LDR higher or lower than in the light?
Answer:
An LDR's resistance is high in the dark and at low light levels, allowing only a little amount of current to pass through it. An LDR's resistance is low in bright light, allowing more current to flow through it.
what assumptions are made in the rigid-rotor harmonic oscillator (rrho) model for describing the rotational and vibrational motion of a diatomic molecule?
The Rigid Rotor Harmonic Oscillator (RRHO) model is a simplified model that is used to describe the rotational and vibrational motion of a diatomic molecule.
The model makes the following assumptions:
The molecule is treated as a rigid rotor, which means that the distance between the two atoms is fixed and does not change during rotation.The bond between the two atoms is assumed to be a simple harmonic oscillator, which means that the bond can vibrate back and forth around the equilibrium position.The potential energy of the bond is assumed to be parabolic, which means that the potential energy is proportional to the square of the displacement from the equilibrium position.The molecule is assumed to be in the gas phase, which means that intermolecular interactions are negligible.The rotational motion of the molecule is treated as classical, which means that the molecule rotates about its center of mass.The vibrational motion of the molecule is treated as quantum mechanical, which means that the energy levels of the oscillator are quantized.These assumptions allow for a simple and intuitive model that can be used to describe the basic features of the rotational and vibrational spectra of diatomic molecules.
However, the RRHO model is a highly simplified model and does not account for many of the complexities of real molecules, such as anharmonic vibrations, molecular interactions, and the effects of temperature and pressure.
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Give one example which describes Newton's first law of motion.
Answer:
a moving car
Explanation:
a body remains in its constant state unless un extenal force is applied.